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Solid-State Reaction and Diffusion Behaviors of CaFe 2 O 4 and TiO 2 at 1373 K to 1473 K
Metallurgical and Materials Transactions B ( IF 2.4 ) Pub Date : 2021-03-18 , DOI: 10.1007/s11663-021-02111-y
Mingrui Yang , Junyi Xiang , Chenguang Bai , Xuangeng Zhou , Zhongci Liu , Xuewei Lv

The solid-state reaction and diffusion behaviors of CaFe2O4 and TiO2 were investigated using a diffusion couple method at 1373 K to 1473 K under air atmosphere, and an in situ XRD method was used to analyze the solid-state reaction process. The reactions between calcium ferrite and TiO2 in the solid state are displacement reactions that produce perovskite and Fe2O3. The diffusion interface was divided into three layers based on phase analysis: layer I was composed of CaTiO3; layer II was composed of Fe2O3, CaTiO3, CaFe2O4, and Ca2Fe2O5; and layer III was composed of CaTiO3, Fe2O3, CaFe2O3, and CaFe4O7. The interface was formed in three stages. In stage I, CaTiO3 formed at the interface. In stage II, the gradual thickening of layers I and II was accompanied by the growth of the amount of CaTiO3 phase. In stage III, CF decomposed into CF2, and layer III formed. Micropores were formed in layer II due to the Kirkendall effect, and the diffusion rate of Ca2+ in CaFe2O4 was greater than that in CaTiO3. The squared thickness of layer I was found to depend linearly on time, and the expression for predicting the thickness of layer I was proposed:

$$ \Delta x = ( 1. 1 7 3 1\times 10^{ - 18} T^{2} - 3.0206 \times 10^{ - 15} T + 1.9652 \times 10^{ - 12} )^{{\frac{1}{2}}} \cdot t^{{\frac{1}{2}}} $$


中文翻译:

CaFe 2 O 4和TiO 2在1373 K至1473 K的固相反应和扩散行为

采用Cafe 2 O 4和TiO 2的固相反应和扩散行为,在大气气氛下于1373 K至1473 K下采用扩散耦合法进行了研究,并采用原位XRD方法对固相反应过程进行了分析。固态的铁氧体钙和TiO 2之间的反应是置换反应,产生钙钛矿和Fe 2 O 3。根据相分析,将扩散界面分为三层:第一层由CaTiO 3组成;第二层由CaTiO 3组成。第二层由Fe 2 O 3,CaTiO 3,CaFe 2 O组成4和Ca 2 Fe 2 O 5 ; 第三层由CaTiO 3,Fe 2 O 3,CaFe 2 O 3和CaFe 4 O 7组成。界面分为三个阶段。在阶段I中,在界面处形成CaTiO 3。在阶段II中,层I和II的逐渐增厚伴随着CaTiO 3相量的增长。在阶段III中,CF分解为CF 2,并且形成层III。由于柯肯德尔效应和Ca 2+在CaFe 2中的扩散速率,在第二层中形成了微孔O 4大于CaTiO 3中的O 4。发现层I的平方厚度与时间呈线性关系,并提出了预测层I厚度的表达式:

$$ \ Delta x =(1. 1 7 3 1 \ times 10 ^ {-18} T ^ {2}-3.0206 \ times 10 ^ {-15} T + 1.9652 \ times 10 ^ {-12})^ { {\ frac {1} {2}}} \ cdot t ^ {{\ frac {1} {2}}} $$
更新日期:2021-03-19
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