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On the problem of zero-divisors in Artinian rings
Communications in Algebra ( IF 0.6 ) Pub Date : 2021-06-18 , DOI: 10.1080/00927872.2021.1933998
Ganesh S. Kadu 1
Affiliation  

Abstract

Let R be a commutative Artinian ring and let ΓE(R) be the compressed zero-divisor graph associated to R. The question of when the clique number ω(ΓE(R))< was raised by J. Coykendall, S. Sather-Wagstaff, L. Sheppardson, and S. Spiroff. They proved that if (R)4 (where (R) is the largest length of any of its chains of ideals), then ω(ΓE(R))<. When (R)=6, they gave an example of a local ring R where ω(ΓE(R))= is possible by using the trivial extension of an Artinian local ring by its dualizing module. The question of what happens when (R)=5 was stated as an open question. We show that if (R)=5 then ω(ΓE(R))<. We first reduce the problem to the case of a local ring (R,m,k). We then enumerate all possible Hilbert functions of R and show that the k-vector space m/m2 admits a symmetric bilinear form in some cases of the Hilbert function. This allows us to relate the orthogonality in the bilinear space m/m2 with the structure of zero-divisors in R. For instance, in the case when m2 is principal and m3=0, we show that R is Gorenstein if and only if the symmetric bilinear form on m/m2 is non-degenerate. Moreover, in the case when (R)=4, our techniques also yield a simpler and shorter proof of the finiteness of ω(ΓE(R)) avoiding, for instance, the Cohen structure theorem.



中文翻译:

关于Artinian环的零因数问题

摘要

R为可交换的 Artinian 环,并令Γ(电阻)是与R关联的压缩零除数图。团号什么时候出的问题ω(Γ(电阻))<由 J. Coykendall、S. Sather-Wagstaff、L. Sheppardson 和 S. Spiroff 抚养长大。他们证明,如果(电阻)4 (在哪里 (电阻) 是其任何理想链的最大长度),然后 ω(Γ(电阻))<. 什么时候 (电阻)=6,他们给出了一个本地环R的例子,其中ω(Γ(电阻))=通过其二元化模块使用 Artinian 局部环的平凡扩展是可能的。什么时候发生的问题(电阻)=5被表述为一个开放性问题。我们证明如果(电阻)=5 然后 ω(Γ(电阻))<. 我们首先将问题归结为局部环的情况 (电阻,,).然后我们枚举R 的所有可能的希尔伯特函数并证明k向量空间/2在 Hilbert 函数的某些情况下允许对称双线性形式。这允许我们关联双线性空间中的正交性/2R 中的零除数结构。例如,在这种情况下2 是主要的和 3=0,我们证明R是 Gorenstein 当且仅当对称双线性形式/2是非退化的。此外,在这种情况下(电阻)=4, 我们的技术还产生了一个更简单和更短的证明的有限性 ω(Γ(电阻)) 例如,避免 Cohen 结构定理。

更新日期:2021-06-18
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