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A Separator Theorem for Hypergraphs and a CSP-SAT Algorithm
arXiv - CS - Computational Complexity Pub Date : 2021-05-14 , DOI: arxiv-2105.06744 Michal Koucký, Vojtěch Rödl, Navid Talebanfard
arXiv - CS - Computational Complexity Pub Date : 2021-05-14 , DOI: arxiv-2105.06744 Michal Koucký, Vojtěch Rödl, Navid Talebanfard
We show that for every $r \ge 2$ there exists $\epsilon_r > 0$ such that any
$r$-uniform hypergraph on $m$ edges with bounded vertex degree has a set of at
most $(\frac{1}{2} - \epsilon_r)m$ edges the removal of which breaks the
hypergraph into connected components with at most $m/2$ edges. We use this to
give an algorithm running in time $d^{(1 - \epsilon_r)m}$ that decides
satisfiability of $m$-variable $(d, k)$-CSPs in which every variable appears in
at most $r$ constraints, where $\epsilon_r$ depends only on $r$ and $k\in
o(\sqrt{m})$. Furthermore our algorithm solves the corresponding #CSP-SAT and
Max-CSP-SAT of these CSPs. We also show that CNF representations of
unsatisfiable $(2, k)$-CSPs with variable frequency $r$ can be refuted in
tree-like resolution in size $2^{(1 - \epsilon_r)m}$. Furthermore for Tseitin
formulas on graphs with degree at most $k$ (which are $(2, k)$-CSPs) we give a
deterministic algorithm finding such a refutation.
中文翻译:
超图的分离定理和CSP-SAT算法
我们证明,对于每个$ r \ ge 2 $,都存在$ \ epsilon_r> 0 $,这样,在$ m $边上具有受限顶点度的任何$ r $-均匀超图最多具有一组$(\ frac {1} {2}-\ epsilon_r)m $边的去除将超图分解为具有最多$ m / 2 $边的连接的分量。我们使用它来给出运行时间为$ d ^ {(1-\ epsilon_r)m} $的算法,该算法确定$ m $变量$(d,k)$-CSP的可满足性,其中每个变量最多出现在$ r $约束,其中$ \ epsilon_r $仅取决于o(\ sqrt {m})$中的$ r $和$ k \。此外,我们的算法可解决这些CSP的相应#CSP-SAT和Max-CSP-SAT。我们还表明,具有不定频率的$ r $的$(2,k)$-CSP的CNF表示可以用树状分辨率$ 2 ^ {((-\ epsilon_r)m} $来驳斥。
更新日期:2021-05-17
中文翻译:
超图的分离定理和CSP-SAT算法
我们证明,对于每个$ r \ ge 2 $,都存在$ \ epsilon_r> 0 $,这样,在$ m $边上具有受限顶点度的任何$ r $-均匀超图最多具有一组$(\ frac {1} {2}-\ epsilon_r)m $边的去除将超图分解为具有最多$ m / 2 $边的连接的分量。我们使用它来给出运行时间为$ d ^ {(1-\ epsilon_r)m} $的算法,该算法确定$ m $变量$(d,k)$-CSP的可满足性,其中每个变量最多出现在$ r $约束,其中$ \ epsilon_r $仅取决于o(\ sqrt {m})$中的$ r $和$ k \。此外,我们的算法可解决这些CSP的相应#CSP-SAT和Max-CSP-SAT。我们还表明,具有不定频率的$ r $的$(2,k)$-CSP的CNF表示可以用树状分辨率$ 2 ^ {((-\ epsilon_r)m} $来驳斥。