The moduli space ${\bar{M}}_{0,n}$ may be embedded into the product of projective spaces ${\mathbb{P}}^1\times {\mathbb{P}}^2\times \cdots \times {\mathbb{P}}^{n-3}$, using a combination of the Kapranov map $|{\psi }_n|:{\bar{M}}_{0,n}\to {\mathbb{P}}^{n-3}$ and the forgetful maps ${\pi }_i:{\bar{M}}_{0,i}\to {\bar{M}}_{0,i-1}$. We give an explicit combinatorial formula for the multidegree of this embedding in terms of certain parking functions of height $n-3$. We use this combinatorial interpretation to show that the total degree of the embedding (thought of as the projectivization of its cone in ${\mathbb{A}}^2\times {\mathbb{A}}^3\cdots \times {\mathbb{A}}^{n-2}$) is equal to $(2(n-3)-1)!!=(2n-7)(2n-9)\cdots (5)(3)(1)$. As a consequence, we also obtain a new combinatorial interpretation for the odd double factorial.

模空间 ${\stackrel{〜}{\mathrm{中号}}}_{0，ñ}$ 可能嵌入到射影空间的产品中 ${\mathbb{P}}^{\mathrm{1个}}\times {\mathbb{P}}^{\mathrm{2个}}\times \cdots \times {\mathbb{P}}^{ñ-3}$，结合使用Kapranov地图 $|{\psi }_{ñ}|：{\stackrel{〜}{\mathrm{中号}}}_{0，ñ}\to {\mathbb{P}}^{ñ-3}$ 和健忘的地图 ${\pi }_{\mathrm{一世}}：{\stackrel{〜}{\mathrm{中号}}}_{0，\mathrm{一世}}\to {\stackrel{〜}{\mathrm{中号}}}_{0，\mathrm{一世}-\mathrm{1个}}$。我们根据高度的某些泊车函数，为该嵌入的多度给出了一个明确的组合公式。$ñ-3$。我们使用这种组合解释来表明嵌入的总程度（被认为是其圆锥的投影${\mathbb{一种}}^{\mathrm{2个}}\times {\mathbb{一种}}^3\cdots \times {\mathbb{一种}}^{ñ-\mathrm{2个}}$）等于 $（\mathrm{2个}（ñ-3）-\mathrm{1个}）！！=（\mathrm{2个}ñ-7）（\mathrm{2个}ñ-9）\cdots （5）（3）（\mathrm{1个}）$。结果，我们也获得了对奇数双阶乘的新组合解释。