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Amenability of semigroups and the Ore condition for semigroup rings
Semigroup Forum ( IF 0.7 ) Pub Date : 2021-03-09 , DOI: 10.1007/s00233-021-10173-2
V. S. Guba

It is known that if a cancellative monoid M is left amenable then the monoid ring K[M] satisfies the Ore condition, that is, there exist nontrivial common right multiples for the elements of this ring. Donnelly (Semigroup Forum 81:389–392, 2010) shows that a partial converse to this statement is true. Namely, if the monoid \({\mathbb {Z}}^{+}[M]\) of all elements of \({\mathbb {Z}}[M]\) with positive coefficients has nonzero common right multiples, then M is left amenable. He asks whether the converse is true for this particular statement. We show that the converse is false even for the case of groups. If M is a free metabelian group, then M is amenable but the Ore condition fails for \({\mathbb {Z}}^{+}[M]\). Besides, we study the case of the monoid M of positive elements of R. Thompson’s group F. The amenability problem for F is a famous open question. It is equivalent to left amenability of the monoid M. We show that for this case the monoid \({\mathbb {Z}}^{+}[M]\) does not satisfy the Ore condition. That is, even if F is amenable, this cannot be shown using the above sufficient condition.



中文翻译:

半群的适应性和半群环的矿石条件

众所周知,如果使一个可分解的单半体M服从,则该半体半环K [ M ]满足Ore条件,也就是说,该环的元素存在非平凡的公倍数。Donnelly(Semigroup论坛81:389–392,2010)表明,与此说法有部分相反的说法是正确的。也就是说,如果系数为正的\({\ mathbb {Z}} [M] \)的所有元素的等分体\({\ mathbb {Z}} ^ {+} [M] \)具有非零的公共右倍数,那么M就顺服了。他询问相反的说法是否适用于此特定声明。我们证明,即使对于群体而言,反之亦然。如果M是一个自由的metabelian组,则M是可以满足的,但是\({\ mathbb {Z}} ^ {+} [M] \)的矿石条件失败。此外,我们研究了汤普森群F的正元素的等式M的情况。F的顺应性问题是一个著名的开放问题。它等效于类半体M的左适应性。我们证明,在这种情况下,单面体\({\ mathbb {Z}} ^ {+} [M] \)不满足Ore条件。即,即使F是合适的,也不能使用上述充分条件来表示。

更新日期:2021-03-09
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