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h1 ≠ h1 for Anderson t-motives
Journal of Number Theory ( IF 0.6 ) Pub Date : 2021-03-02 , DOI: 10.1016/j.jnt.2021.01.020
A. Grishkov , D. Logachev

Let M be an Anderson t-motive of dimension n and rank r. Associated are two Fq[T]-modules H1(M), H1(M) of dimensions h1(M), h1(M)r - analogs of H1(A,Z), H1(A,Z) for an abelian variety A. There is a theorem (Anderson): h1(M)=rh1(M)=r; in this case M is called uniformizable. It is natural to expect that always h1(M)=h1(M). Nevertheless, we explicitly construct a counterexample. Further, we answer a question of D. Goss: is it possible that two Anderson t-motives that differ only by a nilpotent operator N are of different uniformizability type, i.e. one of them is uniformizable and other not? We give an explicit example that this is possible. Finally, explicit formulas for calculation of h1(M), h1(M) obtained in the present paper will be used in future for systematic calculation of h1, h1 of all Anderson t-motives. Moreover, the first step of this calculation (for a class of t-motives) is already made in a forthcoming paper of the authors.



中文翻译:

h 1  ≠  h 1对于安德森t动机

M为维度n和等级r的安德森t动机。关联的是两个Fq[Ť]-模块 H1个中号H1个中号 尺寸 H1个中号H1个中号[R -类似物 H1个一个žH1个一个ž用于阿贝尔各种。有一个定理(安德森):H1个中号=[RH1个中号=[R; 在这种情况下,M被称为可均匀化的。很自然地希望总是H1个中号=H1个中号。但是,我们明确构造了一个反例。进一步,我们回答D.戈斯的问题:两个仅由幂等算子N区别的安德森t动机是否可能具有不同的均匀性类型,即其中一个是可均匀化的而其他不是?我们给出一个明确的例子,证明这是可能的。最后,用于计算的显式公式H1个中号H1个中号 本文中获得的结果将在将来用于系统地计算 H1个H1个所有安德森(Anderson)的动机。此外,该计算的第一步(针对一类t动机)已经在即将发表的作者论文中进行了。

更新日期:2021-03-16
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