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Fractional Hardy-Sobolev L1-embedding per capacity-duality
Applied and Computational Harmonic Analysis ( IF 2.6 ) Pub Date : 2020-10-14 , DOI: 10.1016/j.acha.2020.10.001
Liguang Liu , Jie Xiao

This paper explores essence of the fractional (0<s<1) Hardy-Sobolev L1-embeddinguLnns+suL1+suL1for alluIs(CcH1) via both capacity and duality based on the Riesz potential operator Is and the fractional differential couple ±s. Naturally, we discover that fIs([H˚s,1]) if and only if there exists g=(g1,...,gn)(L)n such that f=Rg=j=1nRjgj in the John-Nirenberg space BMO where R=(R1,...,Rn) is the vector-valued Riesz transform - this equivalence characterizes R(L)n in the Fefferman-Stein decomposition: BMO=L+R(L)n and indicates that Is([H˚s,1]) is a solution to the Bourgain-Brezis problem under n2: “What are the function spaces X,W1,nXBMO, such that every FX has a decomposition F=j=1nRjYj where YjL?”.



中文翻译:

每个容量对数的分数次Hardy-Sobolev L 1嵌入

本文探讨了分数(0<s<1个)哈迪-索伯列夫 大号1个-嵌入ü大号ññ-s+sü大号1个+-sü大号1个对所有人ü一世sCCH1个 通过容量和对偶性基于Riesz势算子 一世s 和分数微分对 ±s。自然地,我们发现F一世s[H˚-s1个] 当且仅当存在时 G=G1个Gñ大号ñ 这样 F=[RG=Ĵ=1个ñ[RĴGĴ 在约翰·尼伦伯格空间BMO中 [R=[R1个[Rñ 是向量值的Riesz变换-这种等效性表征 [R大号ñ 在Fefferman-Stein分解中: BMO=大号+[R大号ñ 并指出 一世s[H˚-s1个] 是Bourgain-Brezis问题的解决方案 ñ2:“函数空间是什么 Xw ^1个ñXBMO,这样每个 FX 有分解 F=Ĵ=1个ñ[RĴÿĴ 哪里 ÿĴ大号?”。

更新日期:2020-10-30
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