The phase diagrams between thymol and racemic ibuprofen, on the one hand, and between l-menthol and this same ibuprofen, on the other hand, were reviewed and corrected using thermal analysis and thermodynamic approach. The Tammann diagrams constructed from thermal analysis data coupled with the thermodynamic assessments allowed to conclude that the two systems present a eutectic behavior with complete immiscibility in the solid state between the components. For l-menthol–ibuprofen system, this is in contradiction with what it was previously mentioned. Indeed, no eutectic reaction was observed on the l-menthol rich side. This result was previously observed for samples melted before being cooled. Indeed, it happens that one of the two components does not recrystallize once cooled down, preventing at this time from observing the eutectic reaction. In the present case, racemic ibuprofen does not regularly recrystallize once melted, as previously reported for other systems involving this component. In the present study, the samples were prepared and homogenized in a solid state without passing through a pre-melting. Owing to thermodynamic assessment and Gibbs energy calculations, one can conclude that repulsive interactions or attractive interactions take place in the liquid state depending on the system. A packing coefficient is introduced to assess the similarity of the molecules, allowing to discuss the possible formation of solid solution within both systems.

一方面，通过热分析和热力学方法，对百里酚与外消旋布洛芬之间，以及1-薄荷醇与同样的布洛芬之间的相图进行了审查和校正。由热分析数据和热力学评估构成的塔曼图可以得出以下结论：这两个系统呈现出共晶行为，且组件之间的固态完全不相溶。对于1-薄荷醇-布洛芬系统，这与前面提到的相矛盾。事实上，观察到在没有共晶反应升-薄荷醇丰富的一面。先前在冷却之前将样品熔化会观察到该结果。实际上，碰巧两种成分之一一旦冷却就不会重结晶，这时就无法观察到共晶反应。在本例中，外消旋布洛芬一旦熔化就不会规则地重结晶，如先前报道的涉及该组分的其他系统那样。在本研究中，样品未经固态预混即制备成固态。由于热力学评估和吉布斯能量计算，可以得出结论，取决于系统，在液体状态下会发生排斥性相互作用或吸引性相互作用。引入堆积系数以评估分子的相似性，