We say that a triangle T tiles a polygon A, if A can be dissected into finitely many nonoverlapping triangles similar to T. We are concerned with the question whether the triangle of angles $\pi /N,\pi /N$, $(N-2)\pi /N$ tiles the regular N-gon.

It is easy to see that if $N=3,4$ or 6, then the answer is affirmative. We show the same in the cases $N=5,8,10$ and 12.

中文翻译：

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常规的拼接Ñ与角三角形边形π / Ñ，π / Ñ（，Ñ  - 2）π / Ñ为Ñ  = 5,8,10和12

我们说一个三角形牛逼瓷砖的多边形一个，如果一个可以被分成有限多个不重叠的三角形相似牛逼。我们关心的是角度三角形$\pi /ñ，\pi /ñ$， $（ñ-2）\pi /ñ$平铺常规N -gon。

很容易看出 $ñ=3，4$或6，则答案是肯定的。我们在情况下也显示相同$ñ=5，8，10$ 和12。