Abstract

Reformatsky reagent prepared from methyl 1-bromocyclohexanecarboxylate reacted with N,N′-(1,4-phenylene)bis(1-arylmethanimines) to produce 2,2′-(1,4-phenylene)bis[3-aryl-2-azaspiro[3.5]nonan-1-ones] as a result of successive nucleophilic additions to the C=N double bonds of the substrate and intramolecular cyclization of the corresponding intermediates. The stepwise reaction mechanism was proved by the isolation of 2-[4-(arylmethylideneamino)phenyl]-3-aryl-2-azaspiro[3.5]nonan-1-ones in the reactions with equimolar amounts of the Schiff base and Reformatsky reagent.

中文翻译：

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1-溴环己烷甲酸甲酯与N，N'-（1,4-亚苯基）双（1-芳基甲亚胺）的Reformatsky反应

摘要

由1-溴环己烷甲酸甲酯与N，N '-（1,4-亚苯基）双（1-芳基甲亚胺）反应制得的Reformatsky试剂可生成2,2'-（1,4-亚苯基）双[3-芳基-2- azaspiro [3.5] nonan-1-ones的结果，是连续向底物的C = N双键进行亲核加成以及相应中间体的分子内环化作用。通过在与等摩尔量的席夫碱和Reformatsky试剂的反应中分离2- [4-（芳基亚甲基氨基）苯基] -3-芳基-2-氮杂螺[3.5]壬基-1-酮来证明逐步反应机理。