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Superhalogens in fluoride diruthenium Ru 2 F n ( n = 1–10): density functional theory
The European Physical Journal D ( IF 1.5 ) Pub Date : 2020-06-09 , DOI: 10.1140/epjd/e2020-100578-7
Xuefeng Wang , Jun Yan , Wenqian Chen , Xuanyan Zou , Xiaohong Chen

Abstract

The structures of the lowest and a few higher isomers for Ru2Fn (n = 1–10) clusters are obtained based on functional B3P86 with 6–311 + g(d) for fluorine and LANL2DZ for ruthenium. The results show that Ru2Fn (n = 5–10) clusters investigated represent superhalongens characterized by the vertical electron affinity energies (VEA) significantly exceeding 3.8 eV. The VEA values estimated for the Ru2F5, Ru2F6, Ru2F7, Ru2F8, Ru2F9, and Ru2F10 systems are predicted to be 3.8 eV, 4.5 eV, 5.7 eV, 6.0 eV, 6.1 eV, and 6.8 eV. The stabilities of the lowest isomers for Ru2Fn (n = 5–10) and the chemical bonds between the two metal atoms are analyzed. The energy gap, vibration frequency, vertical electron affinity energy, vertical ionization energy and frontier molecular orbitals of these Ru2Fn clusters are also calculated. The spin polarization of Ru2Fn clusters originate mainly from Ru 4d orbitals, which determines the magnetism of the systems.

Graphical abstract



中文翻译:

氟化钌Ru 2 F n(n = 1-10)中的超卤素:密度泛函理论

摘要

Ru 2 F nn  = 1-10)团簇的最低异构体和少数较高异构体的结构是基于功能性B3P86获得的,其中氟为6-311 + g(d),钌为LANL2DZ。结果表明,所研究的Ru 2 F nn  = 5-10)团簇代表超卤代烃,其特征在于垂直电子亲和能(VEA)大大超过3.8 eV。Ru 2 F 5,Ru 2 F 6,Ru 2 F 7,Ru 2 F 8,Ru 2 F 9的VEA估计值以及Ru 2 F 10系统预计为3.8 eV,4.5 eV,5.7 eV,6.0 eV,6.1 eV和6.8 eV。分析了Ru 2 F nn  = 5-10)的最低异构体的稳定性以及两个金属原子之间的化学键。还计算了这些Ru 2 F n团簇的能隙,振动频率,垂直电子亲和能,垂直电离能和前沿分子轨道。Ru 2 F n团簇的自旋极化主要来自Ru 4 d轨道,它决定了系统的磁性。

图形概要

更新日期:2020-06-09
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