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Planar graphs without 4- and 6-cycles are (7 : 2)-colorable
Journal of Combinatorial Optimization ( IF 0.9 ) Pub Date : 2020-04-06 , DOI: 10.1007/s10878-020-00571-7
Haitao Wu , Yaojun Chen , Xiaolan Hu

Let \(G=(V(G),E(G))\) be a graph and st integers with \(s\le t\). If we can assign an s-subset \(\phi (v)\) of the set \(\{1, 2,\ldots ,t\}\) to each vertex v of V(G) such that \(\phi (u)\cap \phi (v)=\emptyset \) for every edge \(uv\in E(G)\), then G is called (t : s)-colorable, and such an assignment \(\phi \) is called a (t : s)-coloring of G. Let \(C_n\) denote a cycle of length n. In this paper, we show that every planar graph without \(C_4\) and \(C_6\) is (7 : 2)-colorable and thus has fractional chromatic number at most 7/2.

中文翻译:

没有4和6循环的平面图是(7:2)可着色的

\(G =(V(G),E(G))\)为图,s,  t整数为\(s \ le t \)。如果我们可以将集合\(\ {1,2,\ ldots,t \} \)s-子\(\ phi(v)\)分配给VG)的每个顶点v,使得\(\ phi(u)\ cap \ phi(v)= \ emptyset \)每个边\(uv \ in E(G)\),则G称为(t  :  s)可着色,并且这样的赋值\(\ phi \)称为G的(t  :  s)着色。令\(C_n \)表示长度为n的循环。在本文中,我们表明每个没有\(C_4 \)\(C_6 \)的平面图都是(7:2)可着色的,因此分数色数最多为7/2。
更新日期:2020-04-06
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