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On the Algorithmic Complexity of Roman $$\{2\}$${2} -Domination (Italian Domination)
Iranian Journal of Science and Technology, Transactions A: Science ( IF 1.4 ) Pub Date : 2020-05-14 , DOI: 10.1007/s40995-020-00875-7
Abolfazl Poureidi , Nader Jafari Rad

A Roman \(\{2\}\)-dominating function (R2DF) \(f:V\longrightarrow \{0,1,2\}\) of a graph \(G=(V, E)\) has the property that for every vertex \(v\in V\) with \(f(v)=0\) either there is a vertex \(u\in N(v)\) with \(f(u)=2\) or there are two vertices \(x,y\in N(v)\) with \(f(x)=f(y)=1\). The weight of f is the sum \(f(V)=\sum _{v\in V}f (v)\). The minimum weight of an R2DF on G is the Roman \(\{2\}\)-domination number of G. In this paper, we first show that the associated decision problem for Roman \(\{2\}\)-domination is NP-complete even when restricted to planar graphs. Then, we give a linear algorithm that computes the Roman \(\{2\}\)-domination number of a given unicyclic graph.

中文翻译:

关于罗马$$ \ {2 \} $$ {2}-支配(意大利支配)的算法复杂性

\(G =(V,E)\)的罗马\(\ {2 \} \)主导函数(R2DF)\(f:V \ longrightarrow \ {0,1,2 \} \)具有对于每个具有\(f(v)= 0 \)的顶点\(v \ in V \)都有一个顶点\(u \ in N(v)\)具有\(f(u)= 2 \)或两个顶点\(x,y \ in N(v)\)中的\(f(x)= f(y)= 1 \)f的权重是和\(f(V)= \ sum _ {v \ in V} f(v)\)。一个R2DF对最小重量ģ是罗马\(\ {2 \} \) -domination的数目ģ。在本文中,我们首先证明了即使限制在平面图上,罗马\(\ {2 \} \)统治的相关决策问题也是NP完全的。然后,我们给出一个线性算法,用于计算给定单环图的罗马\(\ {2 \} \)-支配数。
更新日期:2020-05-14
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