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A search game on a hypergraph with booby traps
Theoretical Computer Science ( IF 0.9 ) Pub Date : 2020-03-24 , DOI: 10.1016/j.tcs.2020.03.011
Thomas Lidbetter , Kyle Y. Lin

A set of n boxes, located on the vertices of a hypergraph G, contain known but different rewards. A Searcher opens all the boxes in some hyperedge of G with the objective of collecting the maximum possible total reward. Some of the boxes, however, are booby trapped. If the Searcher opens a booby trapped box, the search ends and she loses all her collected rewards. We assume the number k of booby traps is known, and we model the problem as a zero-sum game between the maximizing Searcher and a minimizing Hider, where the Hider chooses k boxes to booby trap and the Searcher opens all the boxes in some hyperedge. The payoff is the total reward collected by the Searcher. This model could reflect a military operation in which a drone gathers intelligence from guarded locations, and a booby trapped box being opened corresponds to the drone being destroyed or incapacitated. It could also model a machine scheduling problem, in which rewards are obtained from successfully processing jobs but the machine may crash. We solve the game when G is a 1-uniform hypergraph (the hyperedges are all singletons), so the Searcher can open just 1 box. When G is the complete hypergraph (containing all possible hyperedges), we solve the game in a few cases: (1) same reward in each box, (2) k=1, and (3) n=4 and k=2. The solutions to these few cases indicate that a general simple, closed form solution to the game appears unlikely.



中文翻译:

带有诱杀装置的超图上的搜索游戏

位于超图G的顶点上的一组n个框包含已知但不同的奖励。甲搜索器将打开的一些超边所有框ģ与物镜收集的最大可能的总奖励。但是,有些盒子被诱杀了。如果搜索者打开一个诱杀诱饵盒,搜索将结束,并且她将失去所有收集到的奖励。我们假定知道k个诱杀装置陷阱,并且将问题建模为最大化搜索器和最小化Hider之间的零和博弈,其中Hider选择k到诱杀装置,搜索器会打开某些超边中的所有框。收益是搜索者收集的总奖励。该模型可以反映出一种军事行动,其中无人机从守卫的地方收集情报,而被诱捕的诱杀箱被打开,相当于无人机被摧毁或失去能力。它还可以对机器调度问题进行建模,从成功处理作业中获得奖励,但是机器可能会崩溃。当G是1一致的超图(超边都是单例)时,我们解决游戏,因此搜索器只能打开1个框。当G是完整的超图(包含所有可能的超边)时,我们在以下几种情况下求解游戏:(1)每个框中的奖励相同,(2)ķ=1个和(3) ñ=4ķ=2。针对这几种情况的解决方案表明,针对游戏的通用简单,封闭形式的解决方案似乎不太可能。

更新日期:2020-03-24
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