Hydrothermal reactions of MoO₃ and TeO₂ in acidic conditions resulted three new molybdenum tellurites, MoTeO₅ (1), β-MoTe₂O₇ (2), and MoTe₄O₁₁·KCl (3). Within the structures of three compounds, all Mo(VI) atoms adopt distorted MoO₆ octahedra in a 2 + 2+2 mode with two short, two normal, and two long Mo–O bonds, while Te(IV) atoms are coordinated by three, four and five oxygen atoms and result TeO₃ trigonal pyramid, TeO₄ seesaw, and TeO₅ square pyramid polyhedra with Te–O bond distance cut off at 2.5 Å. Compound 1 adopts a one-dimensional chain structure in which Mo₂O₁₀ dimers, formed by edge-sharing two MoO₆ octahedra, are connected by TeO₃ polyhedra in a corner-sharing mode. Compound 2 also exhibits a one-dimensional chain structure in which TeO₃ and TeO₅ polyhedra are joined together by corner-sharing and results a new [Te₄O₁₀]^4- chain. MoO₆ octahedra are incorporated in the tellurite chain by corner-sharing two TeO₅ and two TeO₃ polyhdedra and edge-sharing another TeO₅. Compound 3 adopts a two-dimensional sheet structure. Within the structure, a new hexagon patterned [Te₄O₉]^2- chain is formed by corner-sharing TeO₄ and TeO₃ polyhedra. These Te chains are connected by MoO₆ polyhedra and extend in yz plane. Crystallographic data: compound 1, monoclinic, space group P2₁/c, a = 4.7106 (3) Å, b = 13.5827 (11) Å, c = 6.0962 (5) Å, β = 93.898 (3)°, V = 389.15 (5) ų, Z = 4; compound 2, orthorhombic, space group Pna2₁, a = 17.5632 (5) Å, b = 4.9107 (2) Å, c = 12.9518 (4) Å, V = 1117.06 (7) ų, Z = 8; compound 3, orthorhombic, space group Pbcm, a = 6.0017 (3) Å, b = 11.6302 (6) Å, c = 16.6773 (5) Å, V = 1164.09 (10) ų, Z = 4.

MoO ₃和TeO ₂在酸性条件下的水热反应产生了三种新的碲化钼，MoTeO ₅（1），β- MoTe ₂ O ₇（2）和MoTe ₄ O ₁₁ ·KCl（3）。在这三种化合物的结构中，所有Mo（VI）原子均以2 + 2 + 2模式采用扭曲的MoO ₆八面体，具有两个短，两个法线和两个长Mo-O键，而Te（IV）原子通过三个，四个和五个氧原子，生成TeO ₃三角金字塔，TeO ₄跷跷板和TeO ₅Te–O键距的方形金字塔多面体截止为2.5Å。化合物1采用一维链结构，其中通过边缘共享两个MoO ₆八面体而形成的Mo ₂ O ₁₀二聚体通过TeO ₃多面体以角共享方式连接。化合物2还表现出一维链结构，其中TeO ₃和TeO ₅多面体通过角共享而连接在一起，并产生新的[Te ₄ O ₁₀ ] ^4-链。通过将两个TeO ₅和两个TeO ₃进行边角共享，将MoO ₆八面体结合到碲酸盐链中多面体并共享另一个TeO ₅。化合物3采用二维片状结构。在该结构内，通过角共享TeO ₄和TeO ₃多面体形成了新的六边形构图的[Te ₄ O ₉ ] ^2-链。这些Te链通过MoO ₆多面体连接并在yz平面上延伸。晶体学数据：化合物1，单斜晶，空间群P 2 ₁ / c，a = 4.7106（3）Å，b = 13.5827（11）Å，c = 6.0962（5）Å，β= 93.898（3）°，V = 389.15（5）³，Z = 4; 化合物2，正交，空间群P na2 ₁中，a = 17.5632（5）A，B = 4.9107（2）埃，c = 12.9518（4），V = 1117.06（7）³，Z = 8; 化合物3，斜方晶系，空间群P BCM中，a = 6.0017（3）A，B = 11.6302（6）A，C = 16.6773（5），V = 1164.09（10）一种³，Z = 4。