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A 1-point poly-quadrature domain of order 1 not biholomorphic to a complete circular domain
Analysis and Mathematical Physics ( IF 1.4 ) Pub Date : 2018-11-02 , DOI: 10.1007/s13324-018-0263-3
Pranav Haridas , Jaikrishnan Janardhanan

It is known that if \(f: D_1 \rightarrow D_2\) is a polynomial biholomorphism with polynomial inverse and constant Jacobian then \(D_1\) is a 1-point poly-quadrature domain (the Bergman span contains all holomorphic polynomials) of order 1 whenever \(D_2\) is a complete circular domain. Bell conjectured that all 1-point poly-quadrature domains arise in this manner. In this note, we construct a 1-point poly-quadrature domain of order 1 that is not biholomorphic to any complete circular domain.

中文翻译:

1阶1点多正交域,不是完整圆域的全同构

众所周知,如果\(f:D_1 \ rightarrow D_2 \)是具有多项式逆和常数Jacobian的多项式双全纯,则\(D_1 \)是一个1点多正交域(Bergman跨度包含所有全纯多项式)每当\(D_2 \)是一个完整的循环域时,顺序为1 。贝尔推测所有1点多正交域都以这种方式出现。在本说明中,我们构建了一个1点的1点多正交域,该域对任何完整的圆形域都不是全纯的。
更新日期:2018-11-02
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