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The repetition threshold for binary rich words
arXiv - CS - Formal Languages and Automata Theory Pub Date : 2019-08-08 , DOI: arxiv-1908.03169
James D. Currie and Lucas Mol and Narad Rampersad

A word of length $n$ is rich if it contains $n$ nonempty palindromic factors. An infinite word is rich if all of its finite factors are rich. Baranwal and Shallit produced an infinite binary rich word with critical exponent $2+\sqrt{2}/2$ ($\approx 2.707$) and conjectured that this was the least possible critical exponent for infinite binary rich words (i.e., that the repetition threshold for binary rich words is $2+\sqrt{2}/2$). In this article, we give a structure theorem for infinite binary rich words that avoid $14/5$-powers (i.e., repetitions with exponent at least 2.8). As a consequence, we deduce that the repetition threshold for binary rich words is $2+\sqrt{2}/2$, as conjectured by Baranwal and Shallit. This resolves an open problem of Vesti for the binary alphabet; the problem remains open for larger alphabets.

中文翻译:

二进制丰富词的重复阈值

如果长度为 $n$ 的单词包含 $n$ 非空回文因子,则它是丰富的。如果一个无限词的所有有限因素都是丰富的,那么它就是丰富的。Baranwal 和 Shallit 产生了一个具有临界指数 $2+\sqrt{2}/2$ ($\approx 2.707$) 的无限富二元词,并推测这是无限富二元词的最小临界指数(即重复二进制丰富词的阈值是 $2+\sqrt{2}/2$)。在本文中,我们给出了避免$14/5$-powers(即指数至少为2.8 的重复)的无限二元富词的结构定理。因此,我们推断出二进制丰富词的重复阈值为 $2+\sqrt{2}/2$,正如 Baranwal 和 Shallit 所推测的那样。这解决了二进制字母表 Vesti 的一个开放问题;对于更大的字母,这个问题仍然存在。
更新日期:2020-08-25
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