The amide in Cr[N(SiMe₃)₂]₂(THF)₂ is displaced by equimolar [K(18-crown-6)][naphthalene] to form the dimetal sandwich Cr₂(naphthalene)₂⁻ as a radical anion paired with [K(18-crown-6)]⁺. Two Cr atoms in the sandwich do not form any multiple Cr/Cr bonds, and instead each interacts with one naphthalene in an η⁶ fashion and with the second naphthalene in an η⁴ connectivity mode. The naphthalene C/C distances show the effect of back donation from two chromium atoms to a greater extent than simply by 1 electron ring reduction, in comparison to the naphthalene radical anion. The SOMO of the product was established by variable temperature EPR spectroscopy, and the atom ratios and elemental purity were supported by XPS. The possible generality of the displacement of N(SiMe₃)₂⁻ from a low valent metal is discussed.

中文翻译：

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通往双金属夹心复合物的新途径，包括自由基阴离子†

[N（森以Cr酰胺₃）₂ ] ₂（THF）₂，通过等摩尔[K（18-冠-6）]移位[萘]，以形成双金属夹层的Cr ₂（萘）₂ ^-作为自由基阴离子与[K（18-crown-6）] ⁺配对。在夹心两个Cr原子不形成任何倍数的Cr / Cr的键，并且与一个萘代替每个相互作用以η ⁶的方式，用在η第二萘⁴连接模式。与萘自由基阴离子相比，萘的C / C距离显示出两个铬原子的回馈作用比仅通过1个电子环还原所产生的作用更大。通过可变温度EPR光谱法确定了产品的SOMO，XPS支持了原子比和元素纯度。的N（森位移的可能一般性₃）₂ ^-从低价金属进行了讨论。