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Cyclic Platina(borasiloxane)s and Platina(siloxane)s and Their Chemical Properties
Organometallics ( IF 2.8 ) Pub Date : 2017-12-26 00:00:00 , DOI: 10.1021/acs.organomet.7b00690
Hiroki Noda 1 , Kimiya Tanaka 1 , Makoto Tanabe 1 , Kohtaro Osakada 1
Affiliation  

[Pt(SiHPh2)2(dmpe)] (dmpe = 1,2-bis(dimethylphosphino)ethane) reacts with arylboronic acids to produce six-membered platinacycles [tiebar above startPt(SiPh2-O-BAr-O-tiebar above endSiPh2)(dmpe)] (Ar = C6H4-4-COMe (1a), C6H4-4-CF3 (1b)). X-ray crystallography of 1a revealed the structure having a planar six-membered ring, composed of Pt, O, B, and Si atoms. Reaction of H2O with [Pt(SiHPh2)2(dmpe)] formed a four-membered cyclic complex, [tiebar above startPt(SiPh2-O-Stiebar above endiPh2)(dmpe)] (2), which was observed in the initial reaction mixture of 4-acetylphenylboronic acid with [Pt(SiHPh2)2(dmpe)]. Exposure of solutions of [Pt(SiHPh2)2(dmpe)] and of [Pt(SiHAr2)2(PMe3)2] (Ar = Ph, C6H4-4-Me) to air resulted in the formation of the cyclic platina(siloxane)s, [tiebar above startPt(O-SiPh2-O-SiPh2tiebar above end-O)(dmpe)] (3) and [tiebar above startPt(O-SiAr2-O-SiAr2-tiebar above endO)(PMe3)2] (4: Ar = Ph; 5: Ar = C6H4-4-Me), respectively. The six-membered platina(borasiloxane) 1a reacts with H2GePh2 and with CF3CO2H to release the cyclic borasiloxanes as the products. The former reaction affords [Pt(GeHPh2)2(dmpe)], while the latter produces [Pt(OCOCF3)2(dmpe)] as the Pt-containing products. A similar reaction of HCl with platina(siloxane) 4 gives a disiloxanediol via cleavage of the Pt–O bonds. Complex 4 reacts with H2SiPh2 to form a triplatinum complex, [{Pt(PMe3)}3(μ-SiPh2)3] (15), which is obtained under milder conditions than the previously reported reaction starting from [Pt(SiHPh2)2(PMe3)2].

中文翻译:

环状Platina(硼硅氧烷)和Platina(硅氧烷)及其化学性质

[Pt(SiHPh 22(dmpe)](dmpe = 1,2-双(二甲基膦基)乙烷)与芳基硼酸反应生成六元上方的拉杆铂环化合物[ Pt(SiPh 2 -O-BAr-O- 末端上方的拉杆SiPh 2)( dmpe)](Ar = C 6 H 4 -4-COMe(1a),C 6 H 4 -4-CF 31b))。1a的X射线晶体学分析显示该结构具有一个平面的六元环,该环由Pt,O,B和Si原子组成。H 2 O与[Pt(SiHPh 22(dmpe)]的反应形成四元环状络合物,[ 上方的拉杆Pt(SiPh2 -OS 末端上方的拉杆IPH 2)(DMPE)](2),这是在4-乙酰基苯基硼酸与初始反应混合物观察到的Pt(SiHPh 22(DMPE)]。[Pt(SiHPh 22(dmpe)]和[Pt(SiHAr 22(PMe 32 ](Ar = Ph,C 6 H 4 -4-Me)的溶液暴露在空气中导致形成环状粗铂的(硅氧烷),[上方的拉杆铂(O-SIPH 2 -O-SIPH 2末端上方的拉杆 -O)(DMPE)](3)和[上方的拉杆铂(O-SIAR 2 -O-SIAR 2 -末端上方的拉杆O)(PMe 32 ](4:Ar = Ph; 5:Ar = C 6 H 4 -4-Me)。六元铂(硼硅氧烷)1a与H 2 GePh 2和CF 3 CO 2 H反应,释放出环状硼硅氧烷作为产物。前者反应提供[Pt(GeHPh 22(dmpe)],而后者产生[Pt(OCOCF 32(dmpe)]为含Pt产物。HCl与铂(硅氧烷)4的类似反应通过Pt–O键的裂解得到二硅氧烷二醇。复杂的4分发生反应用H 2 SIPH 2以形成triplatinum络合物,[{的Pt(PME 3)} 3(μ-SIPH 23 ](15),其比以前报道的反应更温和的条件下得到由[PT开始( SiHPh 22(PMe 32 ]。
更新日期:2017-12-27
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