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BY 4.0 license Open Access Published by De Gruyter July 29, 2021

A variant of Clark’s theorem and its applications for nonsmooth functionals without the global symmetric condition

  • Chen Huang EMAIL logo

Abstract

We give a new non-smooth Clark’s theorem without the global symmetric condition. The theorem can be applied to generalized quasi-linear elliptic equations with small continous perturbations. Our results improve the abstract results about a semi-linear elliptic equation in Kajikiya [10] and Li-Liu [11].

MSC 2010: 35J20; 35J62; 35B45

1 Introduction

The Clark’s theorem is a important result in critical point theory (see [4, 8]). Using this theorem for the even coercive functional, the existence of a sequence of negative critical values tending to 0 is obtained. Specifically, in [8], Heinz obtained a variant of the Clark theorem as follows:

Clark Theorem (see [21]). Let X be a Banach space and assume JC1(X) satisfies, J(0) = 0, the (P-S) conditions, is bounded from below and even. For any positive integer k, there exists a k-dimensional subspace X k of X and βk > 0 such that

supXkSβkJ<0,hereSβ={uX:u=β},

then there exists a sequence of negative critical values for J tending to 0.

This Clark’s theorem was improved by Kajikiya in [9] and Liu-Wang in [18], under the same conditions as in the above Clark’s theorem, they showed the critical points of J also tend to 0 in X. We remark that Liu-Wang also studied the existence of periodic solutions for sub-linear Hamiltonian systems and showed a new version of the Clark’s theorem for non-smooth functionals. Very recently, in [3] Chen-Liu-Wang showed a version of the Clark’s theorem without the Palais-Smale conditions ((P-S) conditions). And then they studied the existence of infinitely many solutions for a degenerate quasi-linear elliptic operator and a second-order Hamiltonian system via their abstract theory.

However, all those versions of Clark’s theorem references to above rely on the symmetric condition about the Euler-Lagrange functional. In [10], Kajikiya established the existence of infinitely many critical points about C1 functional without the global symmetric condition. As applications, they obtained the existence of infinitely many solutions of the sub-linear elliptic equation with a small perturbation. We note that since the

perturbation term only satisfies continuity, the Euler-Lagrange functional corresponding to the sub-linear elliptic equation may not be even.

But for some quasi-linear elliptic problems with continuous perturbations, here the problems do not have a C1 variational formulation and do not satisfy the global symmetric condition. For these reasons, both the classical Clark’s Theorem in [8] and the abstract result in [10] cannot be applied directly. In this situation, we need develop a new non-smooth variational method based on the Clark’s theorem.

In order to state the new variant of Clark’s theorem, we firstly give the following assumption:

Condition (I). Let X be an infinite dimensional Banach space and E be dense subspace of X. For any ε ∈ [0, 1], let Iε be a continuous functional defined on X which is E-differentiable. Iε satisfies (I1)− (I5) below.

(I1): For uX, Iε(u) is bounded from below;

(I2): For uX, |Iε(u) − I0(u)| ≤ ψ(ε), where ψC([0, 1], ℝ) and ψ(0) = 0;

(I3): Iε(u) satisfies the (P-S) conditions uniformly on ε;

(I4): I0(u) is odd on u;

(I5): For any uX \ {0} there exists a unique t(u) > 0 such that I0(tu) < 0 if 0 < |t| < t(u) and I0(tu) ≥ 0 if |t| ≥ t(u).

In order to explain some concepts in Condition (I), we recall some definitions as follows:

Definition 1.1

A continuous functional J is said to be E-differentiable if

(1) for all uX and φE the derivative of J in the direction φ at u exists and will be denoted by DEJ(u), φ:

DEJ(u),φ=limt0+1t(J(u+tφ)J(u)).

(2) The map (u, φ) → DEJ(u), φ satisfies:

  1. DEJ(u), φ is linear in φE,

  2. DEJ(u), φ is continuous in u, that is DEJ(un), φDEJ(u), φ as unu in X.

Definition 1.2

The slope of an E-differentiable functional J at u denoted by |DEJ(u)| is an extended number in [0,∞]:

|DEJ(u)|=sup{DEJ(u),φ:φE,φ=1}.

A point uX is said to be a critical point of J at the level c if |DEJ(u)| = 0 and J(u) = c.

Definition 1.3

Iε(u) is said to satisfy (P-S) conditions uniformly on ε if a sequence (εn , un) ∈ [0, 1X satisfies that

supnN|Iεn(un)|<and|DEIεn(un)|convergestozero,

then (εn , un) has a convergent subsequence.

We now introduce the variant of Clark’s theorem.

Theorem 1.1

Assume that Condition (I) holds. Denote

Sk:={xRk+1:|x|=1},Ak:={αC(Sk,X):αisodd},dk:=infαAkmaxxSkI0(α(x)).

Let k ∈ N \ {0} satisfying dk < dk+1. Then there exist two constants εk+1, ck+1 such that 0 < εk+1 ≤ 1, dk+1ck+1 < −ψ(ε) for ε ∈ [0, εk+1] and for any ε ∈ [0, εk+1], Iε has a critical value in the interval [dk+1ψ(ε), ck+1 + ψ(ε)].

From the above abstract theorem, we have the following corollary.

Corollary 1.1

Assume the condition (I) holds. Then, for any k ∈ N, there exists an εk > 0 such that when 0 ≤ εεk, functional Iε has at least k distinct critical points with negative critical values.

Secondly, we give an another direct proof about Corollary 1.1 in Section 3. Our method is based on the approach developed by Degiovanni-Lancelotti [6]. By this approach, Li-Liu [11] considered a similar perturbation for semilinear elliptic equation in a bounded domain. Since our problems do not have a C1 variational formulation, the method in [11] cannot be applied directly.

Finally, as an application of Theorem 1.1 and Corollary 1.1,we consider the following quasi-linear problem

(1.1) i,j=1NDj(aij(x,u)Diu)+12i,j=1NDsaij(x,u)DiuDju+V(x)u=f(x,u)+εK(x)g(u),xRN,uW1,2(RN),

where N3,Dsaij(x,u)=uaij(x,u),Diu=xiu(x)andDju=xju(x). Denoted F(x,u)by0uf(x,s)ds. For given a > 0, let f (x, u) ∈ C(ℝN × [−a, a]) and satisfy (f1)− (f4) below

(f1): f (x, −u) = −f (x, u) for x ∈ ℝN and |u| ≤ a;

(f2): uf (x, u) − 2F(x, u) < 0when 0 < |u| < a and x ∈ ℝN;

(f3): |f (x, u)| ≤ C|u|r−1 for x ∈ ℝN and |u| ≤ a, where r ∈ [1, 2);

(f4):limu0(minxRNu2F(x,u))=.

Besides, aij(x, u) satisfies

(a): aijC1(ℝN × [−a, a], ℝ), aij is even, aij = aji, for all x ∈ ℝN and |s| ≤ a, Dsaij(x, s)s ≥ 0 and there exist C0, C1 such that C0|ξ|2aijξiξjC1|ξ|2.

And V, KC(ℝN , ℝ) satisfy:

(V): V(x)−1Lr/(2−r)(ℝN) and there exists a constant V0 such that

0 < V 0 V ( x ) , for all x R N ;

(K): K(x) ∈ L1(ℝN) ∩ L(ℝN).

Quasi-linear elliptic equation of the form (1.1) contains the quasi-linear Schrödinger equation

(1.2) Δu12Δ(u2)u+V(x)u=f(x,u)+εK(x)g(u),xRN,uW1,2(RN),

which corresponds to the special case aij(x, t) = (1 + 2t2)δij. The problem (1.2) arose in several models of physical phenomena, such as superfluid films in plasma physics (see e.g. [1, 2, 19]). And it has received considerable attention in mathematical analysis in the last twenty years (see [5, 12, 20, 22, 23]).

Since the variational functional of the quasi-linear problem (1.1) is merely continuous. Even though ε = 0, limited work has been done in the general form of the quasi-linear problem (1.1). In [13], a least energy sign-changing solution of (1.1) with ε = 0 is obtained via the Nehari manifold method. Multiple solutions for (1.1) with ε = 0 was first proved in [16], where a 4-Laplacian perturbation term is added to (1.1) so that the associated functionals are well-defined on W01,4(Ω). Then in [15], they obtained multiplicity of sign-changing solutions for general form of the quasi-linear problem (1.1) with ε = 0. This idea is further developed in [17], where treated the critical exponent case giving new existence results. The previous mentioned four results yield only with the power range f (x, u) = |u|s−2u (4 < s ≤ 2 · 2*). The case 1 < s < 2 is investigated in [18], by using the variants of Clark’s theorem, the quasi-linear problem (1.1) with ε = 0 has a sequence of solutions with L-norms tending to zero. For 2 < s < 4, less results are known, by using the perturbation approach and the invariant sets approach, in [7] Jing-Liu-Wang showed the problem (1.1) with ε = 0 has at least six solutions.

When ε ≠0, under our assumptions on g, the Euler-Lagrange functional corresponding to (1.1)may be not even with respect to u. In Section 4, for |ε| small enough, implying Theorem 1.1, we prove that the generalized quasi-linear elliptic problem with small perturbations (1.1) has infinitely many solutions.

Next, we give our second main result.

Theorem 1.2

Let g(u) be continuous on [−a, a]. Assume that conditions (a), (V), (K) and (f1)-(f4) hold. Then, for any k ∈ N and any b > 0, there exists an ε0(k, b) > 0such that when |ε| ≤ ε0(k, b) the problem (1.1) possesses at least k distinct solutions whose L-norms are less than b.

Remark 1.1

We do not need any growth condition on the nonlinear term f at infinity. Thus there exist some supercritical growth examples satisfying our conditions (f1)− (f4):

  1. f (x, u) = |u|r−1sgn u with r ∈ (1, 2);

  2. f (x, u) = |u|r−1sgn u + |u|i−1sgn u, where 1 < r < 2 , i 2 := 2 N N 2 .

Remark 1.2

Since our theorem does not need any growth or odd condition on the perturbation term g. The Euler-Lagrange functional Iε(u) may not satisfy symmetrical condition. By applying our abstract results, for |ε| small enough, Iε(u) still possesses infinite many critical points.

This paper is organized as follows. In Section 2, we give the proofs of the abstract result Theorem 1.1 and Corollary 1.1. Then we give the another direct proof about Corollary 1.1 in Section 3. As an application of Theorem 1.1, we prove Theorem 1.2 in Sections 4.

In what follows, C denotes positive generic constants.

2 Proof of Theorem 1.1

In this section, we shall prove Theorem 1.1. To this end, we use the following topological lemma, which is an analogue of a result of [10]. Throughout this section, X is an infinite dimensional Banach space and E be dense subspace of X. For any ε ∈ [0, 1], functionals Iε are an E-differentiable functional defined on X and satisfies (I1)− (I5).

Definition 2.1

Let M be a compact subset of X such that 0 ∉M. Denote

  1. M := {ru : r ∈ ℝ, uM};

  2. O := {uX : I0(u) < 0}.

Lemma 2.1

[Topological Lemma] (1) There exists vX such that

v=1andvRM.

(2) Let v be mentioned in Lemma 2.1-(1), there exists a δ0 > 0 such that

tu+(1t)δvOforuM,0t1and0<δ<δ0.

Proof. Notice that condition (I5) means that

O := { u X : I 0 ( u ) < 0 } = { t u : u X { 0 } , 0 < | t | < t ( u ) } ,

which plays a key role in the proof of this lemma. The details in the proof see also [10].

Recall the definitions in Section 1, as follows:

Sk:={xRk+1:|x|=1},Ak:={αC(Sk,X):αis odd},

and

(2.1) dk:=infαAkmaxxSkI0(α(x)).

Using these definitions and the condition (I5), we have the following lemma.

Lemma 2.2

For any k ∈ N, there exists an αk ∈ Ak such that

maxxSkI0(αk(x))<0.

Proof. Let k be a fixed positive integer. For any αAk, by the condition (I5), there exists t(α) such that

I0(t(α)2α)<0.

Then we can take αk=t(α)2α, which satisfies

αk(x)AkandmaxxSkI0(αk(x))<0.

For any k ∈ N, it follows from Lemma 2.2 and the definition of d k that

dkmaxxSkI0(αk(x))<0anddkdk+1.

Next we suppose that there exists a positive integer k such that d k < dk+1 < 0. Define

S + k + 1 := { ( x 1 , , x k + 2 ) : i = 1 k + 2 x i 2 = 1 , x k + 2 0 } , S k := { ( x 1 , , x k + 2 ) : i = 1 k + 2 x i 2 = 1 , x k + 2 = 0 } , H k + 1 := { h C ( S + k + 1 , X ) : h satisfies ( H 1 ) , ( H 2 ) }

(1) h(−x) = −h(x) for xSk.

(2) I0(h(x)) < dk + r for xSk, where the constant r > 0 small enough such that dk + r < dk+1.

Using the above definitions and Lemma 2.1, we show the next fundamental lemma holds. We use the same method as in Kajikiya [10]. For the completeness of the article, we give a detailed proof as follows.

Lemma 2.3

There exists an fk+1 ∈ Ak+1 ∩ℌk+1 such that

maxxSk+1I0(fk+1(x))<0.

Proof. Let d k and r > 0 be defined in (2). From the definition of d k, we can choose an α ∈ Ak satisfying

(2.2) I 0 ( α ( x ) ) < d k + r < 0 for x S k .

Then take M = α(Sk). It follows from (2.2) that M is compact and 0 ∉M. From Lemma 2.1-(2), there exist vX and δ0 > 0 such that

(2.3) tα(x)+(1t)δvOforxSk,0t1and0<δ<δ0.

This means

I0(tα(x)+(1t)δ02v)<0forxSk,0t1.

Next, we denote

x = ( x 1 , , x k + 1 , x k + 2 ) = ( x , x k + 2 ) , x = ( x 1 , , x k + 1 ) , and | x | = i = 1 k + 1 x i 2 1 / 2 .

Then for xS+k+1, we take

f k + 1 ( x ) = | x | α ( x / | x | ) + δ 0 2 ( 1 | x | ) v , if x 0 , δ 0 2 v , if x = 0.

We only need extend the continuous function fk+1(x) onto Sk+1 as an odd mapping f˜k+1(x).Thenf˜k+1Ak+1 k+1 and (2.3) imply that

I0(f˜k+1(x))=I0(fk+1(x))<0,forxS+k+1.

Lemma 2.4

Each d k is a critical value of I0(u) and

dkdk+1<0forkN,limkdk=0.

Before completing the proof of Lemma 2.4, we need the following non-smooth deformation lemma and a notion of genus (see [14, 21]):

Lemma 2.5 (The First Deformation Lemma). [14] Assume J is an E-differentiable functional defined on X and satisfies the (P-S) conditions. For some c ∈ ℝ, let N be a neighborhood of Kc = {uX : J(u) = c, |DEJ(u)| = 0}. Then there exists a deformation map σ : [0, 1] × XX and δ > δ > 0 such that

  1. If J(u) ≤ cδ, then σ(t, u) = u.

  2. If J(u) ≤ c + δ and uN, then J(σ(1, u)) ≤ cδ.

  3. If J(·) is even functional, then σ(t, ·) is odd mapping.

  4. If c is a regular value of J with J(u) ≤ c + δ, then J(σ(1, u)) ≤ cδ.

Definition 2.2

Denote Γ = {AX \ {0} : A is closed, −A = A}. Let AΓ, define a genus γ(A) of A by

γ ( A ) = min { n N : t h e r e e x i s t s a n o d d , c o n t i n u o u s ϕ : A R n { 0 } } ,

If such a minimum does not exist, then we define γ(A) = +∞. Moreover, set γ(∅) = 0. For all k ∈ N, let Γk = {AΓ : γ(A) ≥ k}. We define

ek=infAΓksupuAI0(u).

Remark 2.1

Due to the Borsuk-Ulam theorem, we have γ(Sk) = k +1. Then from the property of genus, for any α ∈ Ak we have γ(α(Sk))≥ k + 1. Besides, since dk < 0, we can suppose 0 ∉ α(Sk). Thus, we deduce AkΓk and then ekdk < 0.

With the help of lemma 2.5, and using the standardmethod as in Rabinowitz’s argument [21] (see Proposition 9.33), we show the following lemma holds.

Lemma 2.6

For all k ∈ N, ek is a critical value of I0(u) and ek → 0 as k →∞.

Proof. Under the condition (I1), we know that

ek>.

Remark 2.1 means ekdk < 0. Since Γk+1Γk, it follows that ekek+1. Then from the above facts, we have

limkek:=e0.

In contradiction to Lemma 2.6, we suppose that

(2.4) e<0.

Next we use the following notation:

K:={uX:DEI0(u)=0,I0(u)e}.

By (P-S) conditions on I0, we have K is compact. It is clear that K is symmetric. Due to (2.4), we have 0 ∉ K.

Then by the properties of genus, there exists a δ > 0 small enough such that

γ(Nδ(K))=γ(K):=i<+,

where Nδ (K) = {uX : dist(u, K) < δ}.

By Lemma 2.5 with c = e, there exists δ > 0 such that

(2.5) I0(σ(1,u))eδ,ifI0(u)e+δanduNδ(K).

Now we fix an integer j ∈ N such that

(2.6) e δ < e j .

By the definition of ei+j, there exists PΓi+j such that

(2.7) sup u P I 0 ( u ) < e i + j + δ .

Let Q = P N δ ( K ) ¯ , then from (2.5) and (2.7), we have

(2.8) I0(σ(1,u))eδforuQ.

Since γ(σ(1,Q))γ(Q)γ(P)γ(Nδ(K))j, we have

σ(1,Q)Γj.

From (2.6), (2.8) and the above fact, we get

e δ < e j sup u Q I 0 ( σ ( 1 , u ) ) e δ .

This is a contradiction.

The proof of Lemma 2.4

. From the definition of d k, we know that for any ϵ > 0, there exists an αk ∈ Ak such that

sup x S k I 0 ( α k ( x ) ) < d k + ϵ .

Here we fix ϵ = δ which is mentioned in Lemma 2.5. Assume to the contrary that the conclusions are false. d k is a regular value. Using Lemma 2.5 with c = dk, there exists σ : [0, 1] × XX satisfying

(2.9) sup x S k I 0 ( σ ( 1 , α k ( x ) ) ) < d k δ .

On the other hand, it is straightforward to show that σ(1, αk) ∈ Ak. Then by the definition of d k, it implies

supxSkI0(σ(1,αk(x)))dk,

which contradicts (2.9). Hence d k is a critical value of I0.

Next we shall prove that d k → 0 as k → ∞. Due to ekd k < 0, it is enough to show the convergence of ek to zero. This fact follows from Lemma 2.6. The proof is complete.

Now, we are ready to prove the variant of Clark’s theorem.

The proof of Theorem 1.1

Fixed a positive integer k, such that

d k < d k + 1 < 0 and d k + r < d k + 1 , for some r > 0

From Lemma 2.3 and I0(u) is even on u, we have

ck+1:=maxS+k+1I0(fk+1(x))=maxSk+1I0(fk+1(x))<0.

Choose εk+1 ∈ (0, 1] so small that

d k + r + 2 ψ ( ε ) < d k + 1 and c k + 1 + ψ ( ε ) < 0 for ε [ 0 , ε k + 1 ] .

For all ε ∈ [0, εk+1], define

bk+1(ε):=infhHk+1maxS+k+1Iε(h(x)).

On one hand, from condition (I1), it implies

(2.10) bk+1(ε)maxS+k+1I0(fk+1(x))+ψ(ε)=ck+1+ψ(ε)<0.

On the other hand, for any h ∈ ℌk+1 fixed, denote the odd extension of honSk+1byh, then hAk+1.

Since I0(u) is even, it holds that

maxS+k+1I0(h(x))=maxSk+1I0(h(x)).

Then

maxS+k+1Iε(h(x))maxS+k+1I0(h(x))ψ(ε)=maxSk+1I0(h(x))ψ(ε)dk+1ψ(ε).

Taking the infimum on h ∈ ℌk+1 in the above inequality, we have

(2.11) b k + 1 ( ε ) d k + 1 ψ ( ε ) > d k + r + ψ ( ε ) .

Then, from (2.10) and (2.11), it implies

dk+1ψ(ε)bk+1(ε)ck+1+ψ(ε).

Next we shall prove bk+1(ε) is critical value of Iε. Assume to the contrary that the conclusions are false. bk+1(ε) is a regular value. Then by Lemma 2.5 with c=bk+1(ε)andcδ=dk+r+ψ(ε), we have an δ(0,δ) and σ : [0, 1] × XX satisfying the conditions below:

  1. If Iε(u) ≤ bk+1(ε) + δ, then Iε(σ(1, u)) ≤ bk+1(ε) − δ.

  2. If Iε(u) ≤ dk + r + ψ(ε), then σ(1, u) = u.

By the definition of bk+1(ε), there exists an h0 ∈ ℌk+1 such that

max S + k + 1 I ε ( h 0 ( x ) ) < b k + 1 ( ε ) + δ .

By the deformation property (i), we have

(2.12) max S + k + 1 I ε ( σ ( 1 , h 0 ( x ) ) ) < b k + 1 ( ε ) δ .

Since h0 ∈ ℌk+1, we get

I ε ( h 0 ( x ) ) I 0 ( h 0 ( x ) ) + ψ ( ε ) < d k + r + ψ ( ε ) for x S k .

From this, we have

σ(1,h0(x))=h0(x)forxSk.

Thus σ(1, h0(x)) satisfies (1) and (2) and then

σ(1,h0(x))Hk+1.

Then, by the definition of b k+1(ε), we obtain

maxS+k+1Iε(σ(1,h0(x)))bk+1(ε),

which contradicts (2.12).

The proof of Corollary 1.1

From Theorem 1.1, there exist sequences {εk+1}, {dk+1} and {bk+1(ε)} such that bk+1(ε) is a critical value of Iε for ε ∈ [0, εk+1] and

(2.13) dk+1ψ(ε)bk+1(ε)ck+1+ψ(ε)<0.

For any δ > 0 and k ∈ N fixed. Let n(i) (i ∈ {1, 2, · · · , k}) be a increasing positive integers sequence, such that

δ < d n ( 1 ) and d n ( i ) c n ( i ) < d n ( i + 1 ) for i { 1 , 2 , , k } .

Then for all i ∈ {1, 2, · · · , k}, there exists εk > 0 small enough such that

(2.14) δ < d n ( 1 ) ψ ( ε ) and c n ( i ) + ψ ( ε ) < d n ( i + 1 ) ψ ( ε ) on ε [ 0 , ε 0 ] .

Combining (2.13) and (2.14), for all ε ∈ [0, εk], we have

δ < b n ( 1 ) ( ε ) < b n ( 2 ) ( ε ) < < b n ( k ) ( ε ) < 0 ,

which means Iε has at least k distinct critical values.

3 The another proof of Corollary 1.1

In this section, we shall give the another proof of Corollary 1.1. To this end, let us recall some notions and facts from Degiovanni-Lancelotti (see [6]). And set Ib = {uX : I(u) ≤ b}.

Definition 3.1

Areal number c is said to be an essential value of I, if for every ε > 0there exist a, b ∈ (cε, c+ε) with a < b such that the pair (Ib, Ia) is not trivial.

Definition 3.2

Let a, b ∈ ℝ∪{−∞, +∞} with ab. The pair (Ib, Ia) is said to be trivial, if for any neighborhood [α, α′′] of a and [β, β′′] of b, there exist two closed subsets A and B such that IαAIα′′, IβBIβ′′ and such that A is a strong deformation retract of B.

Let I be a merely continuous functional in X. The next lemma shows the main property of essential values.

Lemma 3.1

[see Theorem 2.6 in [6]] Let c be an essential value of I. Then for every ε > 0 there exists δ > 0 such that every JC(X, ℝ) with sup |J(u) − I(u)| < δ admits an essential value in (cε, c + ε). uX

In what follows, let I be a E-differentiable functional defined on X, then by the following lemma, we show the relationship between essential values and critical values of I.

Lemma 3.2

Let functional I be E-differentiable functional defined on X and c be an essential value of I. If (P-S) conditions hold for I, then c is a critical value of I.

Proof. By contradiction, let us assume that c is not a critical value of I. By (P-S) conditions of I, there exist positive constants ε and d such that

| D E I ( u ) | d > 0 , for all u { u : c ε < I ( u ) < c + ε } .

Then let a, b ∈ (cε, c + ε) with a < b. By Lemma 2.5, there exists a deformation map σ : [0, 1] × XX such that

σ(0,u)=u,I(σ(t,u))I(u),ifuIb,thenσ(1,u)Ia,and ifuIa,thenσ(t,u)=u.

This means Ia is a strong deformation retract of Ib, so that the pair (Ib, Ia) is trivial, which is a contradiction since c is an essential value of I.

The idea of the proof of Corollary 1.1 is taken from [11]. But our abstract result extends Theorem 1.2 in [11] by relaxing the C1 assumption of I. Moreover, our abstract result is powerful in application such as quasi-linear elliptic problems (see Section 4).

The proof of Corollary 1.1

Set S = {uX : ‖u = 1} and O = {tu : 0 < t < t(u), uS}, where for uS, t(u) is mentioned in condition (I5). From the above definitions, we first show O is contractible, which will be used in the sequel. Define G = {t(u)u/2 : uS}. Consider g : SG as g(u) = t(u)u/2. Then the inverse of g is given by g−1 : GS, g−1(u) = u/‖u and both g and g−1 are continuous. It implies G is homeomorphic to S. On the other hand, G is a strong deformation retract of O. Thus O is contractible since S is contractible.

Next, for k ∈ N, let Sk−1 be the unit sphere in ℝk and define

Hk={hC(Sk1,O):his odd}

and

pk=infhHkmaxxSk1I0(h(x)).

It is easy to see p1p2 ≤ · · · ≤ pk. For any k ∈ N, by Lemma 3.1 and 3.2, there exists εk > 0 such that if 0 ≤ εεk then

pkmaxxSk1I0(gk(x))<0.

Recall the definition of ek in Definition 2.2. By {h(Sk−1) : hH k}⊂ γk, it implies that pkek. From Lemma 2.6, we see that ek → 0as k →∞. So pk → 0as k →∞.

Finally, we set E = {c < 0 : c is an essential value of I0}. It suffices to prove E ≠ ∅ and sup E = 0. By contradiction, there exists k ∈ N such that p k < pk+1 and [pk, 0) ∩ E = ∅. Then there exist constants α, a, α′′ such that

p k < α < a < α < p k + 1 .

By the definition of p k, we can choose hH k satisfying

maxxSk1I0(h(x))<α.

Let S + k = { x : x = ( x , x k + 1 ) , x R k , x k + 1 0 , | x | = 1 } . From O is contractible, it implies that h can extend to hC(S+k,O). Take β=max{I0(h(x)):xS+k}. Since hC(S+k,O), we know β < 0. Then there exist constants b and β such that

β < b < β < 0.

Due to [pk, 0) ∩ E = ∅, the pair (Ib0 , Ia0) is trivial. This means that we can choose two closed subsets A and B of X satisfying

I0αAI0α′′,I0βBI0β′′

and there exists a deformation map σ : [0, 1] × BB such that

σ(0,)=id,σ(1,B))A.

Then we consider h′′(x) = σ(1, h(x)) which satisfies

I0(h′′(S+k))I0α′′andh′′|Sk1is odd.

Denote the odd extension of h′′ on Sk by h*, which satisfies I0(h(Sk))I0α′′. However this contradicts the definition of p k+1, i.e.

p k + 1 max x S k I 0 ( h ( x ) ) α < p k + 1 .

Consequently, there exists {ck}⊂ E such that

c 1 < c 2 < c 3 < < c k < 0 , and c k 0 as k .

For any k ∈ N, by Lemma 3.1 and 3.2, there exists εk > 0 such that if |ε| ≤ εk then Iε has at least k distinct critical points with negative critical values.

4 Proof of Theorem 1.2

In this section, we shall prove Theorem 1.2. For this purpose, we firstly make some modifies. Motivated by the similar modifies in [10, 18], we make use of the following approach: From condition (f4), decreasing a if necessary, we may assume

F(x,u)>0,for0<|u|<a,xRN.

For fixed a > 0. Let ηC0(R,[0,1]) be a cut-off even function such that

η ( t ) = 1 for | t | a / 2 ; η ( t ) > 0 for | t | < a ; η ( t ) = 0 for | t | a ; η ( t ) [ 4 a , 0 ] for a 2 t a .

Using this cut-off function η, we consider the following modified functions:

f ~ ( x , u ) := u ( η ( u ) F ( x , u ) ) , g ~ ( u ) := η ( u ) g ( u ) , F ~ ( x , u ) := 0 u f ~ ( x , s ) d s = η ( u ) F ( x , u ) , a ~ i j ( x , u ) := η ( u ) a i j ( x , u ) + ( 1 η ( u ) ) C 1 δ i j ,

where C1 > 0 is a positive constant mentioned in condition (a).

Next, we give some properties forf˜,g˜anda˜ij.

Lemma 4.1

f˜(x,u)andg˜(u) are continuous functions defined onN × R and satisfy the conditions below

(f1):f˜(x,u)=f˜(x,u) for (x, u) ∈ ℝN × ℝ;

(f2):uf˜(x,u)2F˜(x,u)<0 when 0 < |u| < a and x ∈ ℝN;

(f3):f˜(x,u)=g˜(u)=F˜(x,u)=0 when |u| ≥ a and x ∈ ℝN;

(f4):|f˜(x,u)|C|u|r1for(x,u)RN×R;

(f5):limu0(minxRNu2F˜(x,u))=.

Proof. From the definition off˜(x,u)andg˜(u), it is easy to show that (f1),(f3),(f4)and(f5) hold. To obtain (f2) a little manipulation is needed. For 0 < u < a and x ∈ ℝN, from the definition of η, we consider

u ( u 2 F ~ ( x , u ) ) = η ( u ) u 2 F ( x , u ) + η ( u ) u ( u 2 F ( x , u ) ) = η ( u ) u 2 F ( x , u ) + η ( u ) u 3 ( u f ( x , u ) 2 F ( x , u ) ) < 0.

On the other hand, u(u2F˜(x,u)) can also be denoted by

u(u2F˜(x,u))=u3(uf˜(x,u)2F˜(x,u)).

Combing the above two equations and the fact that uf˜(x,u)2F˜(x,u) is evenon u,we see thatf˜(x,u) satisfies condition (f2).

Lemma 4.2

a˜ij(x,u) satisfies

(a0):a˜ijC1(RN×R,R),a˜ij is even, a˜ij=a˜ji and there exist two constants C0 and C1 such that

C0|ξ|2a˜ijξiξjC1|ξ|2;

(a1): there exists some C > 0, such that

|a˜ij(x,u)|+|Ds(a˜ij(x,u))|CforuR,xRN;
(a2):i,j=1NDs(a˜ij(x,u))uξiξj0foruR,xRN.

Proof. It is clear that a˜ij satisfies (a′0) and (a1). We now verify (a2). Observe the relation,

i , j = 1 N D s ( a ~ i j ( x , u ) ) u ξ i ξ j = i , j = 1 N η ( u ) u a i j ( x , u ) ξ i ξ j + η ( u ) D s ( a i j ( x , u ) ) u ξ i ξ j C 1 η ( u ) u δ i j ξ i ξ j η ( u ) u i , j = 1 N a i j ( x , u ) ξ i ξ j C 1 δ i j ξ i ξ j .

Using condition (a) and the definition of η, we get

η(u)ui,j=1Naij(x,u)ξiξjC1δijξiξj0.

We set X := {W1,2(ℝN) : ℝN V(x)u2dx < ∞} in which the norm is given by

uX:=RN|Du|2+V(x)u2dx1/2,

and E := XL(ℝN). For uX, we consider the following modified functional corresponding to (1.1),

I ε ( u ) := 1 2 R N i , j = 1 N a ~ i j ( x , u ) D i u D j u d x + V ( x ) u 2 d x R N F ~ ( x , u ) d x ε R N K ( x ) G ~ ( u ) d x .

Now by Lemma 4.1, 4.2, Iε is well defined in X. And it is easy to say functionals Iε are E-differentiable in the directions φE.

Next, we verify the (P-S) conditions for functional Iε.

Lemma 4.3

For ε ∈ [0, 1], Iε satisfies (P-S) conditions uniformly on ε.

Proof. For any fixed uX and ε ∈ [0, 1], we have

R N | F ~ ( x , u ) | d x C R N | u | r d x C R N ( V ( x ) 1 ) r / ( 2 r ) d x ( 2 r ) / 2 R N V ( x ) u 2 d x r / 2 C u X r ,

and

ε R N K ( x ) G ~ ( u ) d x = | ε | | u | a K ( x ) | G ~ ( u ) | d x + | ε | | u | > a K ( x ) | G ~ ( u ) | d x = | ε | | u | a K ( x ) | G ~ ( u ) | d x | ε | C R N K ( x ) d x | ε | C .

Thus,

(4.1) Iε(u)C02uX2CuXr|ε|C,uX,

and then Iε(u) is coercive and bounded below. Let (εn , un) ∈ [0, 1] × X be any sequence such that

Iεn(un)cand|DEIεn(un)|0.

Then {un} and {εn} are bounded. Therefore, there exists a subsequence of {εn} converges to ε and a subsequence of {un} converges to u weakly in X and a.e. on ℝN. Next, we shall show this convergence becomes a strong one.

Step 1. u is critical point of Iε.

Take T > a, and define

u T = T , if u T , u , if T < u < T , T , if u T .

Choose φE, φ ≥ 0 and ψn=φexp(HunT) where H > 0 large enough such that Ha˜ij+12Dsa˜ij is negatively definite.

Obviously, ψn can be seen as a test function in DEIε(un), ψn → 0, that is

o(1)=RNi,j=1Na˜ij(x,un)DiunDjψndx+12RNi,j=1NDsa˜ij(x,un)DiunDjunψndx+RNV(x)unψndxRNf˜(x,un)ψndxεRNK(x)g˜(un)ψndx=RNi,j=1Na˜ij(x,un)DiunDjφexp(HunT)dx+RNi,j=1NHa˜ij(x,un)+12Dsa˜ij(x,un)DiunDjunφexp(HunT)dx+RNV(x)unφexp(HunT)dxRNf˜(x,un)φexp(HunT)dxεRNK(x)g˜(un)φexp(HunT)dxRNi,j=1Na˜ij(x,u)DiuDjφexp(HuT)dx+RNi,j=1NHa˜ij(x,u)+12Dsa˜ij(x,u)DiuDjuφexp(HuT)dx+RNV(x)uφexp(HuT)dxRNf˜(x,u)φexp(HuT)dxεRNK(x)g˜(u)φexp(HuT)dx+o(1)=RNi,j=1Na˜ij(x,u)DiuDj(φexp(HuT))dx+12RNi,j=1NDsa˜ij(x,u)DiuDjuφexp(HuT)dx+RNV(x)uφexp(HuT)dxRNf˜(x,u)φexp(HuT)dxεRNK(x)g˜(u)φexp(HuT)dx+o(1),

where we used the Fatou’s Lemma and the lower semi-continuity. Thus, for all φE, φ ≥ 0, we have

(4.2) 0RNi,j=1Na˜ij(x,u)DiuDj(φexp(HuT))dx+12RNi,j=1NDsa˜ij(x,u)DiuDjuφexp(HuT)dx+RNV(x)uφexp(HuT)dxRNf˜(x,u)φexp(HuT)dxεRNK(x)g˜(u)φexp(HuT)dx.

We can choose φ = ϕ exp(HuT) in (4.2) for ϕE and ϕ ≥ 0 we obtain

0RNi,j=1Na˜ij(x,u)DiuDjϕdx+12RNi,j=1NDsa˜ij(x,u)DiuDjuϕdx+RNV(x)uϕdxRNf˜(x,u)ϕdxεRNK(x)g˜(u)ϕdx.

Similarly, by choosing ψ=φexp(HunT), we can get an opposite inequality. Hence, u is a critical point of Iε.

Step 2.We shall show the facts that

RN|f˜(x,un)f˜(x,u)||unu|dx=o(1)andRNK(x)|g˜(un)g˜(u)||unu|dx=o(1).

From {un} converges to u weakly in X and a.e. on ℝN, we know

unustronglyLlocr(RN),with1r<2NN2.

For any R > 0, by the Young inequality and the Hölder inequality, we have

R N | f ~ ( x , u n ) f ~ ( x , u ) | | u n u | d x C R N B R ( 0 ) | u n | r 1 + | u | r 1 ( | u n | + | u | ) d x + C B R ( 0 ) | u n | r 1 + | u | r 1 | u n u | d x C R N B R ( 0 ) | u n | r + | u | r d x + C B R ( 0 ) | u n | r 1 + | u | r 1 | u n u | d x C V ( x ) 1 L r / ( 2 r ) ( R N B R ( 0 ) ) r / 2 V ( x ) u n 2 L 1 ( R N B R ( 0 ) ) r / 2 + V ( x ) u 2 L 1 ( R N B R ( 0 ) ) r / 2 + C u n L r ( B R ( 0 ) ) r 1 + u L r ( B R ( 0 ) ) r 1 u n u L r ( B R ( 0 ) ) C V ( x ) 1 L r / ( 2 r ) ( R N B R ( 0 ) ) r / 2 + C u n u L r ( B R ( 0 ) ) ,

which implies

limnRN|f˜(x,un)f˜(x,u)||unu|dx=0.

Recall that for |u| ≥ a it implies $g(u) = 0. From this and Lebesgue Dominated Convergence Theorem, we have

limnRNK(x)|g˜(un)g˜(u)||unu|dx=0.

Step 3. unu strongly in X.

Due to unTXC with C independent of T and n, we get

|DEIε(un),unT|C|DEIε(un)|.

Taking T → +∞, we obtain that

|DEIε(un),un|C|DEIε(un)|=o(1).

Similarly, we have |DEIε(u), u| = 0. From the definition of $aij and condition (a2), we obtain

a˜ij(x,u)+12Ds(a˜ij(x,u))uξiξjC|ξ|2.

Then

o ( 1 ) = D E I ε ( u n ) , u n D E I ε ( u ) , u R N i , j = 1 N a ~ i j ( x , u n ) + 1 2 D s ( a ~ i j ( x , u n ) ) u n D i ( u n u ) D j ( u n u ) d x + R N V ( x ) ( u n u ) 2 d x R N | f ~ ( x , u n ) f ~ ( x , u ) | | u n u | d x ε R N K ( x ) | g ~ ( u n ) g ~ ( u ) | | u n u | d x C u n u X 2 + o ( 1 ) ,

which implies that unuX20asn.

Lemma 4.4

For any uX \ {0}, I0(u) satisfies condition (I5).

Proof. For any uX \ {0} fixed. For t > 0, we consider

P ( t ) := C 0 2 R N | D u | 2 d x + 1 2 R N V ( x ) u 2 d x t 2 R N F ~ ( x , t u ) d x ,

and

Q(t)=12RNi,j=1Na˜ij(x,tu)DiuDjudxC0RN|Du|2dx.

Then observe the relation,

I0(tu)=t2(P(t)+Q(t)).

Define J(t) := P(t) + Q(t). By condition (f2)and(a2), we have

P(t)=t3RNtuf˜(x,tu)2F˜(x,tu)dx>0fort>0,

and

Q(t)=12RNi,j=1NDsa˜ij(x,tu)uDiuDjudx>0fort>0.

Thus, J(t) > 0 for t > 0.

Take ϵ > 0 small enough such that

μ(Dϵ)>0andDϵ:={xRN:ϵ<|u(x)|<1/ϵ},

where μ denotes the Lebesgue measure of ℝN.

Due to $F(x, u) ≥ 0, we can estimate the function J(t) as follows:

J ( t ) 1 2 R N i , j = 1 N a ~ i j ( x , t u ) D i u D j u d x + R N V ( x ) u 2 d x t 2 D ϵ F ~ ( x , t u ) d x 1 2 max { 1 , C 1 } u X 2 ϵ 2 μ ( D ϵ ) inf x D ϵ ( ( t u ( x ) ) 2 F ~ ( x , t u ) ) .

By condition (f4) in Lemma 4.1, it implies that limt0+J(t)=. Hence, J(t) < 0 for t > 0 small enough.

On the other hand, for t > 0 large, by 1 ≤ r < 2 we have

J ( t ) 1 2 R N i , j = 1 N a ~ i j ( x , t u ) D i u D j u d x + R N V ( x ) u 2 d x t 2 C R N | t u | r d x 1 2 min { 1 , C 0 } u X 2 t r 2 u X r > 0.

Accordingly, for fixed uX \ {0}, J(t) has a unique zero t(u) such that

J ( t ) < 0 , for 0 < t < t ( u ) , J ( t ) 0 , t ( u ) t .

Thus the above result holds for I0(tu).

Before proving the multiplicity of the critical points for Iε, by the Moser’s iteration (see Lemma 3.7 in [7]) and condition (f2), we give some priori estimates.

Lemma 4.5

There exist positive constants μ and C* such that if |u)| = 0 with |ε| ≤ 1, thenu‖≤ DEIε(L∞(N) CuXμ.

Proof. Notice that from conditions (VW), (K) and (f), for uX, we have 3

(4.3) |f˜(x,u)|C|u|r1andK(x)|g˜(u)|Cfor someC>0.

Let uX be a critical point of Iε. Using the equation, for any ψXL(ℝN), we obtain

(4.4) RNi,j=1Na˜ij(x,u)DiuDjψdx+12RNi,j=1NDsa˜ij(x,u)DiuDjuψdx+RNV(x)uψdx=RNf˜(x,u)ψdx+εRNK(x)g˜(u)ψdx

Choosing ψ = |uT|ηuT in (4.4), where η > 0 (will be fixed by some constants) and uT is defined in Lemma 4.3, we obtain

(4.5) |u|Ti,j=1Na˜ij(x,u)DiuDju(η+1)|uT|ηdx+12RNi,j=1NDsa˜ij(x,u)DiuDju|uT|ηuTdx+RNV(x)u|uT|ηuTdx=RNf˜(x,u)|uT|ηuTdx+εRNK(x)g˜(u)|uT|ηuTdx

Combining the second, third term in the left side of the above equation is nonnegative and (4.3), we obtain

C0(η+2)2RN|D|uT|η2+1|2CRN|u|η+r+CRN|u|η+1.

Without loss of generality, for fixed uX, we have the following estimate

(4.6) 1(η+2)2RN|D|uT|η2+1|2CRN|u|η+r.

Since we can assume RN|u|η+rRN|u|η+1,the caseRN|u|η+r<RN|u|η+1 is similarly treated by the following arguments.

On the other hand, using the Sobolev inequality, we deduce

(4.7) S(η+2)2uT(η+2)N/(N2)η+21(η+2)2RN|D|uT|η2+1|2CRN|u|η+r,

where we used that S=inf{RN|Dv|2dx:RN|v|2dx=1}. From the Fatou’s lemma, sending T → ∞in (4.7), it implies that

(4.8) u(η+2)N/(N2)C˜(η+2)2η+2uη+r(η+r)/(η+2).

Let us define ηk=(ηk1+2)NN2r,wherek=1,2,...andη0=2r. It is easy to see that ηk → +∞as k → +∞.

We may assume$> 1, then for i < j, it follows that

(C˜(ηi+2))(ηj+r)/(ηj+2)C˜(ηi+2).

By Moser’s iteration method we have

uηk+1+rexpi=0k2ln(C˜(ηi+2))ηi+2u2μk,

where μk=i=0kηi+rηi+2. Letting k → ∞, we obtain that

uexpi=02ln(C˜(ηi+2))ηi+2u2μ,

where μ=i=0ηi+rηi+2with0<μ<1andexpi=02ln(C˜(ηi+2))ηi+2 is a positive constant. This ends the proof.

Lemma 4.6

For any b > 0, there exists a δ(b) > 0 such that if |ε| ≤ δ(b), |DEIε(u)| = 0 and |Iε(u)| ≤ δ(b), thenuXb.

Proof. Suppose on the contrary that there exist two sequences {un}⊂ X and {εn} such that εn → 0, Iεn (un)→ 0 as n →∞, |DEIεn (un)| = 0, and ‖unXb0 > 0, where b0 is independent of n. Obviously, we can see {un} as the (P-S) sequence of I0. Then from Lemma 4.3, we obtain that a subsequence of {un} which converges to u0 in X, which satisfies

D E I 0 ( u 0 ) , u 0 = R N i , j = 1 N a ~ i j ( x , u 0 ) D i u 0 D j u 0 d x + 1 2 R N i , j = 1 N D s a ~ i j ( x , u 0 ) u 0 D i u 0 D j u 0 d x + R N V ( x ) ( u 0 ) 2 d x R N f ~ ( x , u 0 ) u 0 d x = 0

and

I 0 ( u 0 ) = 1 2 R N i , j = 1 N a ~ i j ( x , u 0 ) D i u 0 D j u 0 + V ( x ) u 0 2 d x R N F ~ ( x , u 0 ) d x = 0.

From the above two equations, it follows that

I 0 ( u 0 ) 1 2 D E I 0 ( u 0 ) , u 0 = 1 4 R N i , j = 1 N D s a ~ i j ( x , u 0 ) u 0 D i u 0 D j u 0 d x + R N 1 2 f ~ ( x , u 0 ) u 0 F ~ ( x , u 0 ) d x = 0.

Since u0X, conditions (a2) and (f2) imply that u0 ≡ 0.

On the other hand, from ‖unXb0 > 0 and unu0 in X, we have ‖u0Xb0 > 0, which contradicts the fact that u0 ≡ 0. The proof is complete.

From the above two lemmas, it is straightforward to show the following corollary.

Corollary 4.1

If u is critical point of Iε(u) with |ε|δ(a2C)and|Iε(u)|δ(a2C),thenuL(RN)a2, this means u is a critical of the original problem (1.1).

Now, we are ready to prove the second main result.

The proof of Theorem 1.2

Without loss of generality, we assume ε > 0. Because the case ε < 0 is same studied by replacing g˜(u)byg˜(u).

Next we are ready to verify that Iε(u) satisfies conditions (I1)− (I5) in Theorem 1.1. To verify condition (I1), by (4.1), we have

infε[0,1],uXIε(u)>.

Condition (I2) follows from

|Iε(u)I0(u)||ε|RN|K(x)||G˜(u)|dx|ε|C:=ψ(ε),

where C is a constant independent of u and ε. Conditions (I3) and (I5) follow from Lemma 4.3 and 4.4 respectively. Thus Iε(u) satisfies all the conditions in Theorem 1.1. Then by the proof of Corollary 1.1, for any δ > 0, we have k distinct critical values of Iε satisfying

δ < b n ( 1 ) ( ε ) < b n ( 2 ) ( ε ) < < b n ( k ) ( ε ) < 0.

Finally, due to the arbitrariness of δ, take 0<δ<δ(a2C), by Corollary 4.1, the original problem (1.1) has at least k solutions whose L-norms are less a2.

Acknowledgements

The author expresses his sincere thanks to professor Zhi-Qiang Wang and Chao Ji for valuable suggestions. This work is supported by Postdoctoral Science Foundation of China (2020M682065).

  1. Conflict of interest: Authors state no conflict of interest.

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Received: 2020-12-29
Accepted: 2021-06-13
Published Online: 2021-07-29

© 2021 Chen Huang, published by De Gruyter

This work is licensed under the Creative Commons Attribution 4.0 International License.

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