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BY 4.0 license Open Access Published by De Gruyter June 30, 2021

Variation inequalities for rough singular integrals and their commutators on Morrey spaces and Besov spaces

  • Xiao Zhang , Feng Liu EMAIL logo and Huiyun Zhang

Abstract

This paper is devoted to investigating the boundedness, continuity and compactness for variation operators of singular integrals and their commutators on Morrey spaces and Besov spaces. More precisely, we establish the boundedness for the variation operators of singular integrals with rough kernels ΩLq(Sn−1) (q > 1) and their commutators on Morrey spaces as well as the compactness for the above commutators on Lebesgue spaces and Morrey spaces. In addition, we present a criterion on the boundedness and continuity for a class of variation operators of singular integrals and their commutators on Besov spaces. As applications, we obtain the boundedness and continuity for the variation operators of Hilbert transform, Hermit Riesz transform, Riesz transforms and rough singular integrals as well as their commutators on Besov spaces.

MSC 2010: Primary 42B20; 42B25

1 Introduction

An active topic of current research is the investigation on the variational inequalities for various operators. The first work was due to Lépingle [21] in 1976 when he established the variational inequality for general martingales (see [31] for a simple proof). Lépingle’s result was later used by Bourgain [2] to establish similar variational estimates for the ergodic averages. Since then, Bourgain’s work has inaugurated a new research direction in ergodic theory and harmonic analysis. We can consult [2, 16, 17] for the ergodic averages, [24, 25] for the differential operators, [3, 13] for the Hilbert transform, [8, 13] for the Riesz transforms, [4, 5, 9, 18] for the singular integrals with rough kernels,[6, 24, 25, 35, 36] for the Calderón-Zygmund singular integrals and their commutators as well as [26, 27] for the discrete singular integral operators. Recently, Liu and Cui [22] established the boundedness and compactness for variation operators of Calderón-Zygmund singular integrals and their commutators on weighted Morrey spaces and Sobolev spaces. Based on this, we are interested in two types of results:

  1. Boundedness and compactness properties for variation operators of singular integrals with rough kernels and their commutators on Morrey spaces.

  2. Boundedness and continuity properties for variation operators of Calderón-Zygmund singular integrals and their commutators on Besov spaces.

These contents are the main motivations of this work. It should be pointed out that this is the first work focusing on the boundedness and compactness for variation operators of singular integrals with rough kernels and their commutators on Morrey spaces as well as the boundedness and continuity of variation operators of Calderón-Zygmund singular integrals and their commutators on Besov spaces.

1.1 Background

Let 𝓣 = {Tϵ}ϵ>0 be a family of bounded operators satisfying

limϵ0Tϵf(x)=Tf(x)

almost everywhere for a certain class of functions f. For ρ > 2, the ρ-variation operator of 𝓣 is defined by

Vρ(T)(f)(x)=sup{ϵi}0(i=1|Tϵif(x)Tϵi+1f(x)|ρ)1/ρ,

where the supremum runs over all sequences {ϵi} of positive numbers decreasing to zero.

Let K(⋅, ⋅) be a kernel defined on ℝn × ℝn ∖ {(x, x) : x ∈ ℝn}, we consider the following operator of Calderón-Zygmund type

TK(f)(x)=RnK(x,y)f(y)dy,forallxsuppf. (1.1)

Formally, the operator TK can be rewritten as

TK(f)(x)=limϵ0+TK,ϵ(f)(x),

where TK,ϵ is the truncated singular integral operator, i.e.

TK,ϵ(f)(x)=|xy|>ϵK(x,y)f(y)dy.

The commutator of TK with a suitable function b is defined as

TK,b(f)(x):=[b,TK](f)(x)=Rn(b(x)b(y))K(x,y)f(y)dy=limϵ0+TK,b,ϵ(f)(x),

where

TK,b,ϵ(f)(x):=|xy|>ϵ(b(x)b(y))K(x,y)f(y)dy.

Denote TK,b1 = TK,b. The iterated commutator TK,bm with m ≥ 2 is defined by

TK,bm(f)(x):=[b,TK,bm1](f)(x)=Rn(b(x)b(y))mK(x,y)f(y)dy=limϵ0+TK,b,ϵm(f)(x), (1.2)

where

TK,b,ϵm(f)(x):=|xy|>ϵ(b(x)b(y))mK(x,y)f(y)dy.

The variation operators of Calderón-Zygmund singular integrals and their commutators can be defined as follows:

Definition 1.1

(Variation operators for singular integrals and their commutators). Let 𝓣K = {TK,ϵ}ϵ>0 and TK,bm={TK,b,ϵm}ϵ>0 with m ≥ 1. For ρ > 2, the ρ-variation operator of 𝓣K is defined by

Vρ(TK)(f)(x):=supεi0(i=1|εi+1<|xy|εiK(x,y)f(y)dy|ρ)1/ρ. (1.3)

Analogously, the ρ-variation operator of TK,bm can be given as

Vρ(TK,bm)(f)(x):=supεi0(i=1|εi+1<|xy|εi(b(x)b(y))mK(x,y)f(y)dy|ρ)1/ρ, (1.4)

where the above sup is taken over all sequences {εi} decreasing to zero. Clearly, Vρ(TK,bm) = 𝓥ρ (𝓣K) for m = 0. For convenience, we set Vρ(TK,bm) = 𝓥ρ (𝓣K,b) for m = 1.

The operators defined in (1.1) and (1.2) have some classical models, which are listed as follows:

  • When n = 1 and K(x,y)=1xy, then TK (resp., TK,bm ) is the (resp., the m-th order commutator of) Hilbert transform. We denote 𝓣K = 𝓗 and TK,bm=Hbm for m ≥ 1.

  • When n = 1 and K(x, y) = ℜ±(x, y), where ℜ±(x, y) is a Hermit Riesz kernel whose expressions can be found in [32], then TK (resp., TK,bm ) is (resp., the m-th order commutator of) Hermit Riesz transform. We denote 𝓣K = 𝓡± and TK,bm=R±,bm for m ≥ 1.

  • When n ≥ 2 and K(x, y) = Rj(x, y), where Rj(x,y):=Γ(n+12)πn+12xjyj|xy|n+1 for 1 ≤ jn, then TK (resp., TK,bm ) is (resp., the m-th order commutator of) Riesz transform. We denote 𝓣K = 𝓡j and TK,bm=Rj,bm for m ≥ 1.

  • When n ≥ 2 and K(x, y) = Ω(xy)|xy|n, where ΩL1(Sn−1) is homogeneous of zero and satisfies

    Sn1Ω(θ)dσ(θ)=0. (1.5)

    Then TK (resp., TK,bm ) is just the usual (resp., the m-th order commutator of) singular integral operator with rough kernel Ω. We denote 𝓣K = 𝓣Ω and TK,bm=TΩ,bm for m ≥ 1.

  • When TK is bounded on L2(ℝn) and the kernel K is a standard Calderón-Zygmund kernel, which satisfies the size condition

    |K(x,y)|A|xy|n,forxy; (1.6)

    and the regularity conditions for some δ > 0

    |K(x,y)K(z,y)|A|xz|δ|xy|n+δ,for|xy|>2|xz|; (1.7)
    |K(y,x)K(y,z)|A|xz|δ|xy|n+δ,for|xy|>2|xz|. (1.8)

Then TK (resp., TK,bm ) is the (resp., the m-th order commutator of) standard Calderón-Zygmund singular integral operator on ℝn.

Throughout this paper, we always assume that ρ > 2 since the ρ-variation in the case ρ ≤ 2 is often not bounded (see [1, 2]). Let us attribute the developments of the variation operators for singular integrals to two stages.

Stage 1 (n = 1). The variation operators for singular integrals were first studied by Campbell et al. [3] who showed that 𝓥ρ(𝓗) is of type (p, p) for 1 < p < ∞ and of weak type (1, 1). The above result was later extended to weighted version in [8, 13]. Same conclusions hold for 𝓥ρ(𝓡±) (see [8, Theorem A]). A general result was given by Liu and Wu [23] who proved that 𝓥ρ(𝓣K) is bounded on Lp(w) for 1 < p < ∞ and wAp(ℝ), provided that n = 1 and 𝓥ρ(𝓣K) is of type (p0, p0) for some p0 ∈ (1, ∞) and K satisfies the conditions (1.6)-(1.8).

Stage 2 (n ≥ 1). In 2002, Campbell et al. [4] first established the Lp(ℝn) (1 < p < ∞) bounds for 𝓥ρ(𝓣Ω), provided that ΩL log+ L(Sn−1). This result was essentially improved by Ding et al. [9] to the case ΩH1(Sn−1) since L log+ L(Sn−1) ⊊ H1(Sn−1), which is a proper inclusion. The weighted result for 𝓥ρ(𝓣Ω) was first considered by Ma et al. [25] who proved that 𝓥ρ (𝓣Ω) is bounded on Lp(w) for 1 < p < ∞ and wAp(ℝn), provided that Ω ∈ Lipα(Sn−1) for α > 0. Later on, the above result was improved by Chen et al. [5] to the case ΩLq(Sn−1) for some q > 1. In [13], Gillespie and Torrea studied the variation operators for Riesz transforms and showed that 𝓥ρ(𝓡j) is bounded on Lp(∣xα) for 1 < p < ∞ and −1 < α < p − 1. Recently, Zhang and Wu [35] extended the above result to general Ap weight. Particularly, Ma et al. [25] proved that 𝓥ρ(𝓣K) is bounded on Lp(w) for all 1 < p < ∞ and wAp(ℝn) if K satisfies (1.6)-(1.8) and the following priori estimate:

Vρ(TK)(f)Lp0(Rn)n,p0fLp0(Rn), (1.9)

for some p0 ∈ (1, ∞).

The variation operator for the commutators was first studied by Liu and Wu [23] who showed that Vρ(TK,bm) is bounded on Lp(w) for 1 < p < ∞ and wAp(ℝ), provided that m ≥ 1, b ∈ BMO(ℝ) and K satisfies (1.6)-(1.9). As applications, they obtained the Lp(w) bounds for Vρ(Hbm) and Vρ(R±,bm) for 1 < p < ∞ and wAp(ℝ) if b ∈ BMO(ℝ). Recently, Liu and Cui [22] extended the above results to the general case n ≥ 1. For the commutator of rough singular integral, Chen et al. [6] proved that Vρ(TΩ,bm) is bounded on Lp(w) for 1 < p < ∞ if ΩLq(Sn−1) for some q > 1 satisfying (1.5), m = 1, b ∈ BMO(ℝ) and one of the following conditions holds: (a) q′ ≤ p < ∞, p ≠ 1 and wAp/q(ℝn); (b) 1 < pq, p ≠ ∞ and w1p1 Ap′/q(ℝn). Actually, applying the above result, the method in the proof of [6, Theorem 1.1] and induction arguments as in getting [11, Theorem 1], one can conclude that Vρ(TΩ,bm) is bounded on Lp(w) for 1 < p < ∞ if ΩLq(Sn−1) for some q > 1 satisfying (1.5), m ≥ 1, b ∈ BMO(ℝ) and one of the following conditions holds: (a) q′ ≤ p < ∞, p ≠ 1 and wAp/q(ℝn); (b) 1 < pq, p ≠ ∞ and w1p1 Ap′/q(ℝn). These conclusions together with the main result of [5] imply the following result.

Theorem A

Let m ∈ 𝓝, ρ > 2, b ∈ BMO(ℝn) and ΩLq(Sn−1) for some q > 1 satisfying (1.5). Then, for 1 < p < ∞, we have

Vρ(TΩ,bm)(f)Lp(Rn)n,ρ,p,mbBMO(Rn)mfLp(Rn),fLp(Rn).

Recently, Guo et al. [14] first studied the compactness for 𝓥ρ(𝓣K,b) on Lp(w). They proved that 𝓥ρ(𝓣K,b) is a compact operator on Lp(w) for 1 < p < ∞ and wAp(ℝn), provided that b ∈ CMO(ℝn) and K satisfies (1.6)-(1.9). Here CMO(ℝn) is the closure of Cc (ℝn) in the BMO(ℝn) topology, which coincides with the space of functions of vanishing mean oscillation. Very recently, Liu and Cui [22] showed that Vρ(TK,bm) is a compact operator on Lp(w) for 1 < p < ∞ and wAp(ℝn), provided that m ≥ 1, b ∈ CMO(ℝn) and K satisfies (1.6)-(1.9).

1.2 Boundedness and compactness on Morrey spaces

As a natural extension of the classical Lebesgue spaces, the Morrey spaces play key roles in partial differential equations and harmonic analysis. Let us recall one definition.

Definition 1.2

(Weighed Morrey spaces) ([19]). Let 1 ≤ p < ∞ and 0 ≤ β < 1. For a weight w defined on ℝn, the weighted Morrey space Mp,β(w) is defined by

Mp,β(w):={fLlocp(w):fMp,β(w)<},

where

fMp,β(w):=supBballsinRn(1w(B)βB|f(x)|pw(x)dx)1/p,

where the supremum is taken over all balls in ℝn. Particularly, the Mp,β(w) is just the classical weighted Lebesgue space Lp(w) when β = 0.

When w ≡ 1, Mp,β(w) reduces to the classical Morrey space Mp,β(ℝn), which was first introduced by Morrey [28] to study the local behavior of solutions to second order elliptic partial differential equations. The weighted Morrey spaces Mp,β(w) were originally introduced by Komori and Shirai [19] who established the bounds for the Hardy-Littlewood maximal operator, fractional integral operator and the Calderón-Zygmund singular integral operator on Mp,β(w). Later on, more and more scholars have devoted to investigating the boundedness of various operators on Mp,β(ℝn) (cf. e.g. [12], [29], [30]).

The boundedness of variation operators of singular integrals and their commutators on Morrey spaces was first studied by Zhang and Wu [36] who proved that 𝓥ρ(𝓣K) is bounded on Mp, β}(w) for 0 < β < 1, 1 < p < ∞ and wAp(ℝn), provided that n = 1 and K satisfies (1.6)-(1.9). Very recently, Liu and Cui [22] studied the boundedness and compactness for variation operators of Calderón-Zygmund singular integrals and their commutators on weighted Morrey spaces. To be more precise, they showed that Vρ(TK,bm) is bounded on Mp,β(w) for 0 < β < 1, 1 < p < ∞ and wAp(ℝn), provided that m ∈ 𝓝, b ∈ BMO(ℝn) and K satisfies (1.6)-(1.9). They also proved that Vρ(TK,bm) is a compact operator on Mp,β(w) for 0 < β < 1, 1 < p < ∞ and wAp(ℝn), provided that m ≥ 1, b ∈ CMO(ℝn) and K satisfies (1.6)-(1.9).

Particularly, Liu and Cui [22] obtained the following result.

Theorem B

([22]). Let Ω ∈ Lipα(Sn−1) for some α > 0 and Ω satisfy (1.5). Let ρ > 2, 1 < p < ∞ and 0 ≤ β < 1. Then

  1. If m ∈ 𝓝 and b ∈ BMO(ℝn), then

    Vρ(TΩ,bm)(f)Mp,β(Rn)CbBMO(Rn)mfMp,β(Rn),fMp,β(Rn).
  2. If m ≥ 1 and b ∈ CMO(ℝn), then Vρ(TΩ,bm) is a compact operator on Mp,β(ℝn).

It is well known that

Lipα(Sn1)Lq(Sn1),α>0,1<q. (1.10)

Note that the above inclusion relationship is proper.

Based on Theorem B and (1.10), a natural question is the following

Question 1.3

Does Theorem B hold under the condition that ΩLq(Sn−1) for some q > 1?

This is one of the main motivations of this work. In this paper, we shall establish the following results.

Theorem 1.1

Let m ∈ 𝓝, ρ > 2, 0 ≤ β < 1 and 1 < p < ∞. Assume that b ∈ BMO(ℝn) and ΩLq(Sn−1) for some q > 1 satisfying (1.5). Then

Vρ(TΩ,bm)(f)Mp,β(Rn)n,p,β,mbBMO(Rn)mfMp,β(Rn),fMp,β(Rn).

Theorem 1.2

Let m ≥ 1, ρ > 2, 1 < p < ∞ and 0 ≤ β < 1. Let ΩLq (Sn−1) for some q > 1 and satisfy (1.5). For r ≥ 1, define

F(r):=01wr(δ)δ(1+|logδ|)dδ<. (1.11)

Here wr(δ) denotes the integral modulus of continuity of order r of Ω defined by

wr(δ):=supρ<δ(Sn1|Ω(ρx)Ω(x)|rdσ(x))1/r

and ρ is a rotation inn and ∥ρ∥: = supx′∈Sn−1ρ x′ − x′∣. Assume that b ∈ CMO(ℝn) and F(1) < ∞, then the operator Vρ(TΩ,bm) is a compact operator on Mp,β(ℝn).

Remark 1.1

  1. The condition (1.11) was firstly introduced by Chen et al. [7] who proved TΩ,b is a compact operator on Mp,β(ℝn) for 1 < p < ∞ and 0 < β < 1, provided that Ω satisfies (1.5) and ΩLq(Sn−1) for some q > 1/(1 − β) satisfying F(q) < ∞. Note that F(r1) ≤ CF(r2) for some C > 0 if r2r1 ≥ 1.

  2. The condition (1.11) is strictly weaker than the condition Ω ∈ Lipα(Sn−1) with some α > 0. Thus, Theorems 1.1 and 1.2 essentially improve the conclusions of Theorem B.

  3. When β = 0, Theorems 1.1 and 1.2 imply the boundedness and compactness of Vρ(TΩ,bm) on the Lebesgue spaces Lp(ℝn).

  4. Theorem 1.1 for the case 0 < β < 1 is new, even in the special case m = 0.

  5. Theorem 1.2 is new, even in the special case β = 0 and m = 1.

Based on the above, some driving questions are the following

Question 1.5

Do the conclusions in Theorems 1.1 and 1.2 hold under the condition that ΩL log+ L(Sn−1) or ΩH1(Sn−1) or Ω ∈ 𝓕α(Sn−1) for some α > 0?

1.3 Boundedness and continuity on Besov spaces

The second motivation of this work is to investigate the boundedness and continuity for variation operators of singular integrals and their commutators. For s ∈ ℝ and 0 < p, q ≤ ∞ (p ≠ ∞), we denote by B˙sp,q (ℝn) (resp., Bsp,q (ℝn)) the homogeneous (resp., inhomogeneous) Besov spaces. It is well known that

fBsp,q(Rn)fB˙sp,q(Rn)+fLp(Rn),fors>0,1<p,q<, (1.12)

In [23], Liu and Wu established the following criterion on the boundedness and continuity of a class of sublinear operators on Besov spaces.

Proposition 1.3

([23]). Let T be a sublinear operator. Assume that T : Lp(ℝn) → Lp(ℝn) for some p ∈ (1, ∞). If T satisfies

|Δζ(Tf)(x)||T(Δζ(f))(x)| (1.13)

for any x, ζ ∈ ℝn. Here Δζ(f) is the difference of f for an arbitrary function f defined onn and ζ ∈ ℜn, i.e., Δζ(f)(x) = fζ(x)−f(x) and fζ(x) = f(x + ζ). Then T is bounded on B˙sp,q (ℝn) for 0 < s < 1 and 1 < q < ∞. Specially, if T also satisfies the following

|TfTg||T(fg)| (1.14)

for arbitrary functions f, g defined onn. Then T is continuous from Bsp,q (ℝn) to B˙sp,q (ℝn) for 0 < s < 1 and 1 < q < ∞.

Note that the operator 𝓥ρ(𝓣K) is sublinearity and commutes with translations, i.e. 𝓥ρ(𝓣K)(f)(x + h) = 𝓥ρ(𝓣K)(fh)(x) when K(x, y) = K(xy). One can easily check that 𝓥ρ(𝓣K) satisfies (1.13) and (1.14). Applying Proposition 1.3, we have the following result.

Proposition 1.4

Let ρ > 2 and 𝓥ρ(𝓣K) be given as in (1.3). Assume that K(x, y) = K(xy) and 𝓥ρ(𝓣K) is bounded on Lp(ℝn) for some p ∈ (1, ∞). Then 𝓥ρ(𝓣K) is bounded and continuous on Bsp,q (ℝn) for 0 < s < 1 and 1 < q < ∞.

As applications of Proposition 1.4, the following results are valid.

Corollary 1.5

Let ρ > 2 and 𝓥ρ(𝓣K) be given as in (1.3). Assume that K(x, y) = K(xy) and K satisfies the conditions (1.6)-(1.9). Then 𝓥ρ(𝓣K) is bounded and continuous on Bsp,q (ℝn) for 0 < s < 1, 1 < p < ∞ and 1 < q < ∞.

Corollary 1.6

Let ρ > 2 and one of the following conditions hold:

  1. n = 1 and 𝓣 = 𝓗;

  2. n = 1 and 𝓣 = 𝓡±;

  3. n ≥ 2, 𝓣 = 𝓡j, 1 ≤ jn;

  4. n ≥ 2 and 𝓣 = 𝓣Ω, where ΩH1(Sn−1) or Ω ∈ ⋂α > 2 𝓕α(Sn−1). Here 𝓕α(Sn−1) for α > 0 denotes the set of all integrable functions over Sn−1 which satisfy

    supξSn1Sn1|Ω(y)|(log+1|ξy|)αdσ(y)<.

    Then the operator 𝓥ρ(𝓣) is bounded and continuous on Bsp,q (ℝn) for 0 < s < 1, 1 < p < ∞ and 1 < q < ∞.

Remark 1.6

  1. It should be pointed out that Corollary 1.5 follows from Theorem 1 in [25] and Proposition 1.4.

  2. The corresponding results in Corollary 1.6 for the cases (i)-(iii) follow from the known bounds for the corresponding operators and Proposition 1.4. It was shown in [9] (see Theorem 1.2 and Corollary 1.6 in [9]) that 𝓥ρ(𝓣Ω) is bounded on Lp(ℝn) for all p ∈ (1, ∞) under the condition that ΩH1(Sn−1) or Ω ∈ ⋂α > 2 𝓕α(Sn−1). This together with Proposition 1.4 yields the conclusion of Corollary 1.6 for case (iv).

  3. We remark that the space 𝓕α(Sn−1) was introduced by Grafakos and Stefanov [15] in the study of Lp boundedness of singular integral operator with rough kernels. Clearly,$\bigcupq > 1 Lq(Sn−1) ⊊ 𝓕α(Sn−1) for any α > 0. Moreover, the examples in [15] show that

    α>1Fα(Sn1)H1(Sn1)α>1Fα(Sn1).

It should be pointed out that the operator Vρ(TK,bm) does not satisfy the condition (1.13), even in the special case m = 1 and K(x, y) = K(xy), which makes that Proposition 1.3 does not apply for Vρ(TK,bm) Therefore, it is natural to ask the following

Question 1.7

Is the operator Vρ(TK,bm) bounded and continuous on Bsp,q (ℝn) for some 0 < s < 1 and 1 < p, q < ∞ when m ≥ 1?

In this paper we shall present a positive answer to this question, which is another one of main motivations. Before presenting the rest of main results, let us introduce the following definition.

Definition 1.8

(Lipschitz space). The homogeneous Lipschitz space Λ̇(ℝn) is given by

Λ˙(Rn):={f:RnCcontinuous:fΛ˙(Rn)<},

where

fΛ˙(Rn):=supxRnsuphRn{0}|f(x+h)f(x)||h|<.

The inhomogeneous Lipschitz space Λ(ℝn) is defined by

Λ(Rn):={f:RnCcontinuous:fΛ(Rn):=fL(Rn)+fΛ˙(Rn)<}.

The rest of main results can be formulated as follows:

Proposition 1.7

Let ρ > 2, m ≥ 1 and Vρ(TK,bm) be given as in (1.4). Assume that bΛ(ℝn), K(x, y) = K(xy) and 𝓥ρ(𝓣K) is bounded on Lp(ℝn) for some p ∈ (1, ∞). Then Vρ(TK,bm) is bounded and continuous on Bsp,q (ℝn) for 0 < s < 1 and 1 < q < ∞. Particularly,

Vρ(TK,bm)(f)Bsp,q(Rn)CbΛ(Rn)mfBsp,q(Rn),fBsp,q(Rn). (1.15)

As some applications of Proposition 1.7, we obtain

Corollary 1.8

Let ρ > 2, m ≥ 1 and Vρ(TK,bm) be given as in (1.4). Assume that bΛ(ℝn), K(x, y) = K(xy) and K satisfies the conditions (1.6)-(1.9). Then Vρ(TK,bm) is bounded and continuous on Bsp,q (ℝn) for 0 < s < 1, 1 < p < ∞ and 1 < q < ∞. Particularly,

Vρ(TK,bm)(f)Bsp,q(Rn)CbΛ(Rn)mfBsp,q(Rn),fBsp,q(Rn).

Corollary 1.9

Let m ≥ 1, ρ > 2, bΛ(ℝn) and one of the following conditions hold:

  1. n = 1 and T=Hbm;

  2. n = 1 and T=R±,bm;

  3. T=Rj,bm, 1 ≤ jn;

  4. T=TΩ,bm, where ΩH1(Sn−1) or Ω ∈ ⋂α > 2 𝓕α(Sn−1).

Then the operator 𝓥ρ(𝓣) is bounded and continuous on Bsp,q (ℝn) for 0 < s < 1, 1 < p < ∞ and 1 < q < ∞. Moreover,

Vρ(T)(f)Bsp,q(Rn)CbΛ(Rn)mfBsp,q(Rn),fBsp,q(Rn).

Remark 1.9

  1. The corresponding results in Corollary 1.9 for the cases (i)-(iii) follow from the known bounds for the corresponding operators and Proposition 1.7. It was shown in [9] (see Theorem 1.2 and Corollary 1.6 in [9]) that 𝓥ρ(𝓣Ω) is bounded on Lp(ℝn) for all p ∈ (1, ∞) under the condition that ΩH1(Sn−1) or Ω ∈ ⋂α > 2 𝓕α(Sn−1). This together with Proposition 1.7 yields the conclusions of Corollary 1.9 for case (iv).

Some interesting questions can be formulated as follows:

Question 1.10

Do the corresponding results in Propositions 1.4 and 1.7 and Corollaries 1.5 and 1.8 hold when K(x, y) ≠ K(xy)?

1.4 Outline of this paper and some notations

The rest of this paper is organized as follows. Section 2 is devoted to presenting the proof of Theorem 1.1. The proof of Theorem 1.2 will be given in Section 3. Finally, we shall prove Proposition 1.7 in Section 4. We would like to remark that the proofs of Theorems 1.1 and 1.2 are motivated by the methods from [7]. The proof of Proposition 1.7 is based on some known arguments from [22, 23]. However, some new techniques are needed to be explored.

Throughout this paper, for any p ∈ (1, ∞), we let p′ denote the dual exponent to p defined as 1/p+1/p′ = 1. For x ∈ ℝn and r > 0, we denote by B(x, r) the open ball centered at x with radius r. For t > 0 and B := B(x, r) with x ∈ ℝn and r > 0, we denote tB = B(x, tr). We end this section by presenting an useful inequality:

(i=1|εi+1<f(x,y)εiF(x,y)dy|ρ)1/ρRn|F(x,y)|dy, (1.16)

for all x ∈ ℝn, any arbitrary functions F and f defined on ℝn × ℝn, where ρ > 1 and {εi} is an increasing or decreasing sequence of positive numbers.

2 Proof of Theorem 1.1

In this section we shall prove Theorem 1.1. At first, let us introduce some notations and lemmas, which are the main ingredients of our proof. For ΩL1(Sn−1), the maximal operator with rough kernel Ω is defined by

MΩf(x)=supr>01rn|y|r|Ω(y)f(xy)|dy.

The following lemma was proved by Chen et al. [7].

Lemma 2.1

([7]). Let 0 < β < 1 and ΩLq(Sn−1) for some q > 1 satisfying (1.5). Then for 1 < p < ∞, there exists an ϵ > 0 such that for any k ∈ 𝓝 and fMp,β(ℝn),

B(t,r)|MΩfk(x)|pdxp,β,n2kϵrnβfMp,β(Rn)p,

where B := B(t, r) is an arbitrary fixed ball and fk = 2k+1B∖2kB.

Motivated by the idea in the proof of Theorem 1.8 in [7], we have the following result.

Proposition 2.2

Let 0 < β < 1, m ∈ 𝓝, b ∈ BMO(ℝn) and ΩLq(Sn−1) for some q > 1 satisfying (1.5). Let Tb be a linear or sublinear operator satisfying

|Tbf(x)|C1Rn|Ω(xy)||xy|n|(b(x)b(y))mf(y)|dy, (2.1)

where C1 > 0. If there exist p ∈ (1, ∞) and C2 > 0 such that Tb satisfies

TbfLp(Rn)C2bBMO(Rn)mfLp(Rn),fLp(Rn). (2.2)

Then we have

TbfMp,β(Rn)m,n,p,β,Ω,C1,C2bBMO(Rn)mfMp,β(Rn),fMp,β(Rn). (2.3)

Proof

Proposition 2.2 for the case m = 0 was proved by Chen et al. in [7] (see Theorem 1.8 in [7]). We shall prove the case m ≥ 1 by adopting the method as in the proof of Theorem 1.8 in [7]. Let B = B(x0, r), where x0 ∈ ℝn and r > 0. To prove (2.3), it suffices to show that

(1|B|βB|Tbf(x)|pdx)1/pm,n,p,β,Ω,C1,C2CbBMO(Rn)mfMp,β(Rn), (2.4)

where C > 0 is independent of x0, r and b.

Decompose f as f = 2B + (2B)c. By Minkowski’s inequality and the sublinearity of Tb, one gets

(1|B|βB|Tbf(x)|pdx)1/p(1|B|βB|Tb(fχ2B)(x)|pdx)1/p+(1|B|βB|Tb(fχ(2B)c)(x)|pdx)1/p=:I1+I2. (2.5)

From the assumption (2.2) we see that

I1C2bBMO(Rn)m(1|B|β2B|f(x)|pdx)1/p2nβ/pC2bBMO(Rn)m(1|2B|β2B|f(x)|pdx)1/p2nβ/pC2bBMO(Rn)mfMp,β(Rn). (2.6)

Next we estimate I2. Fix xB. We get from (2.1) that

Tb(fχ(2B)c)(x)C1(2B)c|Ω(xz)||xz|n|b(x)b(z)|m|f(z)|dz=C1k=12k+1B2kB|Ω(xz)||xz|n|b(x)b(z)|m|f(z)|dz. (2.7)

Fix k ≥ 1. Note that

2k+2r(2k+1+1)r|zx0|+|xx0||xz||zx0||xx0|(2k1)r2k1r, (2.8)

when z ∈ 2k+1B ∖ 2kB. By (2.8), we have

2k+1B2kB|Ω(xz)||xz|n|b(x)b(z)|m|f(z)|dz(2k1r)n2k+1B2kB|Ω(xz)||b(x)b(z)|m|f(z)|dzn,m(1|2k+1B|2k+1B2kB|Ω(xz)||b(z)b2k+1B|m|f(z)|dz+|b(x)b2k+1B|m1|2k+1B|2k+1B2kB|Ω(xz)||f(z)|dz)n,m:(Jk,1(x)+Jk,2(x)). (2.9)

Let fk = 2k+1B∖2kB and s ∈ (1, min{p, q}). By Hölder’s inequality and the well-known property for ∥bBMO(ℝn), one has

Jk,1(x)(1|2k+1B|2k+1B2kB(|Ω(xz)||fk(z)|)sdz)1/s×(1|2k+1B|2k+1B2kB|b(z)b2k+1B|msdz)1/sm,n,sbBMO(Rn)m×(1|2k+1B|2k+1B2kB(|Ω(xz)||fk(z)|)sdz)1/s. (2.10)

On the other hand, by (2.8) and a change of variable, we have

(1|2k+1B|2k+1B2kB(|Ω(xz)||fk(z)|)sdz)1/s(1|2k+1B|2k1r|xz|2k+2r(|Ω(xz)||fk(z)|)sdz)1/sn(1(2k+1r)n2k1r|z|2k+2r(|Ω(z)||fk(xz)|)sdz)1/sn,s(MΩs(fk)s)1/s(x). (2.11)

In light of (2.10) and (2.11) we would have

Jk,1(x)m,n,sbBMO(Rn)m(MΩs(fk)s)1/s(x). (2.12)

Note that ΩsLq/s(Sn−1) and q/s > 1. By Lemma 2.1 and (2.12), there exists a constant ϵ1 > 0 independent of B such that

(1|B|βB|Jk,1(x)|pdx)1/pm,n,sbBMO(Rn)m(1|B|βB(MΩs(fk)s)p/s(x)dx)1/pm,n,sbBMO(Rn)m(1|B|β2kϵ1rnβfsMp/s,β(Rn)p/s)1/pm,n,sbBMO(Rn)m2kϵ1/pfsMp/s,β(Rn)1/sm,n,s,p,βbBMO(Rn)m2kϵ1/pfMp,β(Rn), (2.13)

where in the last of inequality (2.13) we have used the fact that fsMp/s,β(Rn)1/s=fMp,β(Rn) and p/s > 1. Then we get from (2.13) that

k=1(1|B|βB|Jk,1(x)|pdx)1/pm,n,s,p,βbBMO(Rn)mk=12kϵ1/pfMp,β(Rn)m,n,s,p,βbBMO(Rn)mfMp,β(Rn). (2.14)

It remains to estimate Jk,2(x). Let us consider two cases:

  1. In this case we have that ΩLp′}(Sn−1). By Hölder’s inequality, a change of variable and (2.8), we get

    2k+1B2kB|Ω(xz)||f(z)|dz(2k+1B2kB|f(z)|pdz)1/p(2k+1B2kB|Ω(xz)|pdz)1/p(2k+1B|f(z)|pdz)1/p(2k1r|xz|2k+2r|Ω(xz)|pdz)1/p|2k+1B|β/pfMp,β(Rn)(2k1r|z|2k+2r|Ω(z)|pdz)1/p|2k+1B|β/pfMp,β(Rn)(2k1r2k+2rtn1dtSn1|Ω(θ)|pdσ(θ))1/pn,pΩLp(Sn1)|2k+1B|β/p+1/pfMp,β(Rn).

    It follows that

    Jk,2(x)n,pΩLp(Sn1)|2k+1B|(β1)/pfMp,β(Rn)|b(x)b2k+1B|m.

    Then we have

    (1|B|βB|Jk,2(x)|pdx)1/pn,p,Ω|2k+1B|(β1)/pfMp,β(Rn)(1|B|βB|b(x)b2k+1B|mpdx)1/p. (2.15)

    By the property of ∥bBMO(ℝn), we have

    B|b(x)b2k+1B|mpdx2mp1(B|b(x)bB|mpdx+|bBb2k+1B|mp|B|)m,p,n(bBMO(Rn)mp|B|+(k+1)mpbBMO(Rn)mp|B|)m,p,nkmpbBMO(Rn)mp|B|. (2.16)

    Combining (2.16) with (2.15) implies that

    (1|B|βB|Jk,2(x)|pdx)1/pm,n,p|2k+1B|(β1)/pfMp,β(Rn)|B|(1β)/pkmbBMO(Rn)mm,n,pkm2(k+1)n(1β)/pbBMO(Rn)mfMp,β(Rn). (2.17)

    Note that β ∈ (0, 1). From (2.17) we see that

    k=1(1|B|βB|Jk,2(x)|pdx)1/pm,n,pk=1km2(k+1)n(1β)/pfMp,β(Rn)bBMO(Rn)mm,n,p,βbBMO(Rn)mfMp,β(Rn). (2.18)
  2. We can choose u > 1 and s ∈ (1/q, 1) such that 1/(pu)+1/q < 1 and 1/(pu)+1/(qs) = 1. It is clear that pu′ > qs. By Hölder’s inequality, one has

    1|2k+1B|2k+1B2kB|Ω(xz)||f(z)|dz=1|2k+1B|2k+1B2kB|Ω(xz)||fk(z)|1/u|f(z)|1/udz(1|2k+1B|2k+1B2kB|Ω(xz)|qs|fk(z)|qs/udz)1/(qs)×(1|2k+1B|2k+1B2kB|f(z)|pdz)1/(pu)|2k+1B|(β1)/(pu)fMp,β(Rn)1/u×(1|2k+1B|2k+1B2kB|Ω(xz)|qs|fk(z)|qs/udz)1/(qs). (2.19)

    By the arguments similar to those used to derive (2.11), one gets

    (1|2k+1B|2k+1B2kB|Ω(xz)|qs|fk(z)|qs/udz)1/(qs)n,s,q,u(MΩsq(fk)qs/u)1/(qs)(x).

    Then we get from (2.19) that

    Jk,2(x)n,s,q,u|2k+1B|(β1)/(pu)fMp,β(Rn)1/u×|b(x)b2k+1B|m(MΩsq(fk)sq/u)1/(qs)(x). (2.20)

    Note that ΩqsL1/s(Sn−1) and pu′/(qs) > 1. By Hölder’s inequality with exponents u and u′, Lemma 2.1 and (2.20), there exists a constant ϵ2 > 0 independent of B and k such that

    (B|Jk,2(x)|pdx)1/pn,s,q,u|2k+1B|(β1)/(pu)fMp,β(Rn)1/u×(B|b(x)b2k+1B|mp(MΩsq(fk)sq/u)p/(qs)(x)dx)1/pn,s,q,u|2k+1B|(β1)/(pu)fMp,β(Rn)1/u(B|b(x)b2k+1B|mpudx)1/(pu)×(B(MΩsq(fk)sq/u)pu/(qs)(x)dx)1/(pu)n,s,q,u|2k+1B|(β1)/(pu)fMp,β(Rn)1/u(B|b(x)b2k+1B|mpudx)1/(pu)×(2kϵ2rnβfsq/uMpu/(qs),β(Rn)pu/(qs))1/(pu)n,s,q,u|2k+1B|(β1)/(pu)fMp,β(Rn)1/u2kϵ2/(pu)|B|β/(pu)fsq/uMpu/(qs),β(Rn)1/(qs)×(B|b(x)b2k+1B|mpudx)1/(pu).

    Note that

    fsq/uMpu/(qs),β(Rn)1/(qs)=fMp,β(Rn)1/u.

    By the arguments similar to those used in getting (2.16), we have

    B|b(x)b2k+1B|mpudxm,p,ukmpubBMO(Rn)mpu|B|.

    Therefore, we have

    (1|B|βB|Jk,2(x)|pdx)1/pm,n,s,p,q,u|2k+1B|(β1)/(pu)|B|β/pfMp,β(Rn)2kϵ2/(pu)×|B|β/(pu)kmbBMO(Rn)m|B|1/(pu)m,n,s,p,q,ufMp,β(Rn)bBMO(Rn)m2kϵ2/(pu)km2(k+1)n(1β)/(pu).

    It follows that

    k=1(1|B|βB|Jk,2(x)|pdx)1/pm,n,s,p,q,uk=12kϵ2/(pu)km2(k+1)n(1β)/(pu)bBMO(Rn)mfMp,β(Rn)m,n,s,p,q,ubBMO(Rn)mfMp,β(Rn), (2.21)

    since β ∈ [0, 1).

    Hence, by (2.7), (2.9), (2.14), (2.18), (2.21) and Minkowski’s inequality, we get

    I2n,m,C1k=1(1|B|βB|Jk,1(x)|pdx)1/p+k=1(1|B|βB|Jk,2(x)|pdx)1/p)m,n,s,p,q,β,C1bBMO(Rn)mfMp,β(Rn). (2.22)

    Then (2.4) follows from (2.5), (2.6) and (2.22). This completes the proof of Proposition 2.2.□

    We now proceed with the proof of Theorem 1.1.

Proof

Proof of Theorem 1.1. By (1.16) and the definition of Vρ(TΩ,bm) , it is not difficult to see that Vρ(TΩ,bm) satisfies (2.1). Applying Proposition 2.2 and Theorem A, we can get the desired conclusions of Theorem 1.1.□

3 Proof of Theorem 1.2

3.1 Preliminaries

To prove Theorem 1.2, we need the following characterization that a subset in Mp,β(ℝn) is a strongly pre-compact set.

Proposition 3.1

Let 1 < p < ∞ and 0 ≤ β < 1. Then a subset 𝔉 of Mp,β(ℝn) is strongly pre-compact set in Mp,β(w) if 𝔉 satisfies the following conditions:

  1. 𝔉 is bounded, i.e.

    supfFfMp,β(Rn)<.
  2. 𝔉 uniformly vanishes as infinity, i.e.

    limN+fχENMp,β(Rn)=0,uniformlyforallfF,

    where EN = {x ∈ ℝn; ∣x∣ > N}.

  3. 𝔉 is uniformly translation continuous, i.e.

    limr0suphB(0,r)f(+h)f()Mp,β(Rn)=0,uniformlyforallfF.

Remark 3.1

When β = 0, Proposition 3.1 is just the classical Fréchet-Kolmogorov theorem. When β ∈ (0, 1), Proposition 3.1 was proved by Chen. et al in [7].

The following result follows from [10].

Lemma 3.2

([10]). Let 0 ≤ β < n and ΩL1(Sn−1) satisfying (1.5). Then for R > 0, there exists a constant C > 0 independent of R such that for x ∈ ℝn withx∣ < R/2,

R<|y|<2R|Ω(yx)|yx|nβΩ(y)|y|nβ|dyCRβ(|x|R+|x|/(2R)|x|/Rw(δ)δdδ).

Here w(δ) is given as in Theorem 1.2.

3.2 Proof of Theorem 1.2

We divide the proof of Theorem 1.2 into four steps:

  1. We shall adopt the truncated techniques followed from [20] to prove Theorem 1.2. Let φC([0, ∞)) satisfy that 0 ≤ φ ≤ 1, φ(t) ≡ 1 if t ∈ [0, 1] and φ(t) ≡ 0 if t ∈ [2, ∞). For any η > 0, we define the function Ωη by

    Ωη(z)=Ω(z)(1φ(2η|z|)). (3.1)

    It is clear that ΩηLq(Sn−1) and Ωη satisfies (1.5). In what follows, let us fix b ∈ CMO(ℝn), 1 < p < ∞ and 0 ≤ β < 1. We shall prove that there exists a constant C > 0 independent of η such that

    Vρ(T Ωη,bm)(f)Vρ(TΩ,bm)(f)M p , β( Rn)CηfM p , β( Rn),fMp,β(Rn). (3.2)

    By (1.16), we have

    |Vρ(TΩη,bm)(f)(x)Vρ(TΩ,bm)(f)(x)|supϵi0(i=1|ϵi+1<|xz|ϵi(Ωη(xz)|xz|nΩ(xz)|xz|n)×(b(x)b(z))mf(z)dz|ρ)1/ρRn|Ωη(xz)|xz|nΩ(xz)|xz|n||(b(x)b(z))mf(z)|dz=Rn|(b(x)b(z))mf(z)||Ω(xz)||xz|nφ(2η|xz|)dz(|b(x)|+bL(Rn))m1bL(Rn)|xz|η|Ω(xz)f(z)||xz|n1dz. (3.3)

    Note that

    |xz|η|Ω(xz)f(z)||xz|n1dz=|z|η|Ω(z)f(xz)||z|n1dzk=02(k+1)η|z|2kη|Ω(z)f(xz)||z|n1dzk=02kη1(2(k+1)η)n|z|2kη|Ω(z)f(xz)|dynηMΩf(x).

    This together with (3.3) leads to

    |Vρ(TΩη,bm)(f)(x)Vρ(TΩ,bm)(f)(x)|n(|b(x)|+bL(Rn))m1ηMΩf(x). (3.4)

    Note that

    MΩf(x) Rn|Ω(xy)||xy |n|f(y)|dy.

    Combining this with the Lp(ℝn) bounds for MΩ with 1 < p < ∞ and Proposition 2.2 yields that

    MΩfMp,β(Rn)n,p,β,Ω,bfMp,β(Rn),fMp,β(Rn). (3.5)

    Combining (3.5) with (3.4) leads to (3.2).

    By (3.2) and [34, p. 278, Theorem (iii)], to prove the compactness for Vρ(TΩ,bm) , it suffices to prove the compactness for Vρ(TΩη,bm) when η > 0 is small enough. For β > 0, let

    F:={ Vρ( T Ω η , bm)(f):f M p , β ( R n )1}.

    To prove the compactness for Vρ(TΩη,bm) , it is enough to show that the set 𝓕 satisfies the conditions (i)-(iii) of Proposition 3.1 when η > 0 is small enough.

  2. A verification for condition (i) of Proposition 3.1. Let η ∈ (0, 1). By Theorem 1.1, (3.4) and (3.5), we have

    Vρ(TΩη,bm)(f)Mp,β(Rn)Vρ(TΩη,bm)(f)Vρ(TΩ,bm)(f)Mp,β(Rn)+Vρ(TΩ,bm)(f)Mp,β(Rn)CfMp,β(Rn)C,

    when ∥fMp,β(ℝn) ≤ 1. This yields that 𝓕 satisfies condition (i) of Proposition 3.1.

  3. A verification for condition (ii) of Proposition 3.1. Assume that b C0 (ℝn) and is supported in a ball B = B(0, r). Fix fMp,β(ℝn) with ∥fMp,β(ℝn) ≤ 1 and EN := {x ∈ ℝn:∣x∣ > N} with N ≥ max{nr, 1}. Note that b(x) = 0 when xEN since Nnr. By (1.16) and a change of variable, we have

    Vρ(TΩη,bm)(f)(x)Rn|(b(x)b(z))mf(z)||Ωη(xz)||xz|ndznbL(Rn)m|xz|r|Ω(z)||z|n|f(xz)|dz, (3.6)

    when xEN.

    For a fixed ball = (x0, t). We consider two cases:

    1. (q < p). By Hölder’s inequality and (3.6), we have

      Vρ(TΩη,bm)(f)(x)n,m,b,r(|xz|r|Ω(z)|q|z|qn|f(xz)|qdz)1/q.

      By Minkowski’s inequality, we have

      (1|B~|βB~|Vρ(TΩη,bm)(f)(x)χEN(x)|pdx)1/pn,m,b,r|B~|β/p(B~EN(|xz|r|Ω(z)|q|z|qn|f(xz)|qdz)p/qdx)1/pn,m,b,r(|z|(N1)r|Ω(z)|q|z|qn(1|B~|βB~EN|f(xz)|pdx)q/pdz)1/qn,m,b,rfMp,β(Rn)(|z|(N1)r|Ω(z)|q|z|qndz)1/qn,m,b,r,Ω,q((q1)n)1/qfMp,β(Rn)((N1)r)(q1)n/q. (3.7)
    2. (qp). By Hölder’s inequality and (3.6), we get

      Vρ(TΩη,bm)(f)(x)n,m,b,r(|xz|r|Ω(z)|p|z|pn|f(xz)|pdz)1/p.

      Then by Fubini’s theorem, we get

      (1|B~|βB~|Vρ(TΩ,bm)(f)(x)χEN(x)|pdx)1/pn,m,b,r|B~|β/p(B~EN|xz|r|Ω(z)|p|z|pn|f(xz)|pdzdx)1/pn,m,b,r(|z|(N1)r|Ω(z)|p|z|pn1|B~|βB~EN|f(xz)|pdxdz)1/pn,m,b,rfMp,β(Rn)(|z|(N1)r|Ω(z)|p|z|pndz)1/pn,m,b,r,pΩLq(Sn1)fMp,β(Rn)((N1)r)(p1)n/p. (3.8)

      Combining (3.8) with (3.7) implies that 𝓕 satisfies condition (ii) of Proposition 3.1.

  4. A verification for condition (iii) of Proposition 3.1. We want to show that

    lim|h|0Vρ(TΩη,bm)(f)(+h)Vρ(TΩη,bm)(f)()Mp,β(Rn)=0 (3.9)

    for a fixed η ∈ (0, 1).

    In what follows, we set |h| < η8 and η ∈ (0, 1). By the definition of Vρ(TΩ,bm), we have

    |Vρ(TΩη,bm)(f)(x+h)Vρ(TΩη,bm)(f)(x)|supεi0(i=1|εi+1<|x+hy|εi(b(x+h)b(y))mΩη(x+hy)|x+hy|nf(y)dyεi+1<|xy|εi(b(x)b(y))mΩη(xy)|xy|nf(y)dy|ρ)1/ρsupεi0(i=1|εi+1<|xy|εi((b(x+h)b(y))m(b(x)b(y))m)×Ωη(xy)|xy|nf(y)dy|ρ)1/ρ+supεi0(i=1|εi+1<|xy|εi(b(x+h)b(y))m×(Ωη(x+hy)|x+hy|nΩη(xy)|xy|n)f(y)dy|ρ)1/ρ+supεi0(i=1|Rn(b(x+h)b(y))mΩη(x+hy)|x+hy|nf(y)×(χεi+1<|x+hy|εi(y)χεi+1<|xy|εi(y))dy|ρ)1/ρ=:I1f(x)+I2f(x)+I3f(x). (3.10)

    For I1f(x). Note that

    (b(x+h)b(y))m(b(x)b(y))m=j=0m1cmj(b(x+h)b(x))mj(b(x)b(y))j

    and

    (b(x)b(y))j=μ=0jcjμb(x)jμ(1)μb(y)μ,0jm1,

    where cNr=N!r!(Nr)! for any r, N ∈ 𝓝 with rN. Therefore, we have

    I1f(x)j=0m1cmjbL(Rn)mj|h|mjμ=0jcjμ|b(x)|jμ×supεi0(i=1|εi+1<|xy|εiΩη(xy)|xy|nb(y)μf(y)dy|ρ)1/ρ. (3.11)

    For a decreasing sequence {εi}i≥1 of positive numbers converging to 0, we set N({εi}): = max{i ≥ 1 : εiη}. Note that Ωη(xy) = 0 when |xy| ≤ η2 and Ωη(xy) = Ω(xy) when |xy| ≥ η. By (1.16), we have that, for 0 ≤ jm – 1 and 0 ≤ μj,

    (i=1|εi+1<|xy|εiΩη(xy)|xy|nbμ(y)f(y)dy|ρ)1/ρ(i=1N({εi})1|εi+1<|xy|εiΩ(xy)|xy|nbμ(y)f(y)dy|ρ)1/ρ+(i=N({εi})|εi+1<|xy|εiΩη(xy)|xy|nχη2<|xy|η(y)bμ(y)f(y)dy|ρ)1/ρ)Vρ(TΩ)(bμf)(x)+bL(Rn)μη2<|xy|η|Ω(xy)||xy|n|f(y)|dyVρ(TΩ)(bμf)(x)+2nωnbL(Rn)μMΩf(x). >

    This together with (3.11) yields that

    I1f(x)m,n,b|h|j=0m|b(x)|j(μ=0m1Vρ(TΩ)(bμf)(x)+MΩf(x)). (3.12)

    By Theorem 1.1 and Minkowski’s inequality, we get from (3.5) and (3.12) that

    I1fMp,β(Rn)m,n,b|h|(μ=0m1Vρ(TΩ)(bμf)Mp,β(Rn)+MΩfMp,β(Rn))m,n,b,p,β|h|. (3.13)

    For I2f(x). Let |h| < η8 e–1/η, then we have Ωη(x + hy) = Ωη(xy) = 0 when |xy| ≤ η4 . Moreover, |xy| > 2|h| when |xy| > η4 . We get by (1.16) and a change of variables that

    I2f(x)supεi0(i=1|ϵi+1<|xy|ϵi(b(x+h)b(y))m×(Ωη(x+hy)|x+hy|nΩη(xy)|xy|n)f(y)χ|xy|>η4(y)dy|ρ)1/ρRn|Ωη(x+hy)|x+hy|nΩη(xy)|xy|n|×|(b(x+h)b(y))mf(y)|χ|xy|>η4(y)dy(|b(x+h)|+bL(Rn))m|z|>η4|Ωη(z+h)|z+h|nΩη(z)|z|n||f(z)|dz. (3.14)

    Fix a ball B = B(x0, r). By Minkowski’s inequality, one has

    (1|B|βB|I2f(x)|pdx)1/p2mbL(Rn)m|B|β/p×(B(|z|>η4|Ωη(z+h)|z+h|nΩη(z)|z|n||f(xz)|dz)pdx)1/pm,b|B|β/p|z|>η4(B|f(xz)|pdx)1/p|Ωη(z+h)|z+h|nΩη(z)|z|n|dzm,bfMp,β(Rn)|z|>η4|Ωη(z+h)|z+h|nΩη(z)|z|n|dz. (3.15)

    Invoking Lemma 3.2, we obtain

    |z|>η4|Ωη(z+h)|z+h|nΩη(z)|z|n|dzk=02k2η<|z|2k1η|Ωη(z+h)|z+h|nΩη(z)|z|n|dzCk=0(|h|2k2η+|h|/(2k1η)|h|/(2k2η)w(δ)δdδ)Ce1/η+Ck=011+k+η1|h|/(2k1η)|h|/(2k2η)w(δ)δ(1+|logδ|)dδCe1/η+Cη01w(δ)δ(1+|logδ|)dδCη(1+F(1)).

    This together with (3.15) implies that

    I2fMp,β(Rn)Cη(1+F(1))fMp,β(Rn). (3.16)

    Finally, we estimate I3f. Let 1 < s < min{p, q}. Note that

    χεi+1<|x+hy|εi(y)χεi+1<|xy|εi(y)0

    if and only if at least one of the following statements holds:

    1. εi+1 < |x + hy| ≤ εi, |xy| ≤ εi+1;

    2. εi+1 < |x + hy| ≤ εi, |xy| > εi;

    3. εi+1 < |xy| ≤ εi, |x + hy| ≤ εi+1;

    4. εi+1 < |xy| ≤ εi, |x + hy| > εi.

    In case (a) we have that |x + hy| ≤ |xy|+|h| ≤ εi+1 + |h|; In case (b) we have that |xy| ≤ |xy + h| + |h| ≤ εi + |h|; In case (c) we have that |xy| ≤ |xy + h| + |h| ≤ εi+1 + |h|; In case (d) we have that |x + hy| ≤ |xy| + |h| ≤ εi + |h|. Then we have

    |RnΩη(x+hy)|x+hy|n(b(x+h)b(y))mf(y)×(χεi+1<|x+hy|εi(y)χεi+1<|xy|εi(y))dy|(|b(x+h)|+bL(Rn))m(|x+hy|η2|Ωη(x+hy)||x+hy|n|f(y)|×χεi+1<|x+hy|εi(y)χεi+1<|x+hy|εi+1+|h|(y)dy+|x+hy|η2|Ωη(x+hy)||x+hy|n|f(y)|×χεi+1<|x+hy|εi(y)χεi<|xy|εi+|h|(y)dy+|x+hy|η2|Ωη(x+hy)||x+hy|n|f(y)|×χεi+1<|xy|εi(y)χεi+1<|xy|εi+1+|h|(y)dy+|x+hy|η2|Ωη(x+hy)||x+hy|n|f(y)|×χεi+1<|xy|εi(y)χεi<|x+hy|εi+|h|(y)dy)=:(|b(x+h)|+bL(Rn))mj=14I3,jf(x). (3.17)

    We now estimate I3,if, respectively.

    For I3,1f. In case (a) we have that |xy| ≥ |x + hy| – |h| ≥ η2 η8 > η4 > 2|h| and |x + hy| ≥ |xy| – |h| ≥ 12 |xy| when |x + hy| > η2 . By Hölder’s inequality, we obtain

    I3,1f(x)(|x+hy|η2|Ωη(x+hy)f(y)|s|x+hy|nsχεi+1<|x+hy|εi(y)dy)1/s×(Rnχεi+1<|x+hy|εi+1+|h|(y)dy)1/sn,s(|x+hy|η2|Ωη(x+hy)f(y)|s|x+hy|nsχεi+1<|x+hy|εi(y)dy)1/s×((εi+1+|h|)nεi+1n)1/sn,s(|x+hy|η2|Ωη(x+hy)f(y)|s|x+hy|nsχεi+1<|x+hy|εi(y)dy)1/s×((εi+1+|h|)n1|h|)1/s.

    Note that εi+1 + |h| ≤ 54 |x + hy| and |x + hy| ≥ 12 |xy| when |x + hy| > η2 . Then we have

    I3,1f(x)n,s|h|1/s×(|xy|η4|Ωη(x+hy)f(y)|s|xy|n+s1χεi+1<|x+hy|εi(y)dy)1/s. (3.18)

    For I3,2f. In case (b) we have that |xy| ≥ εi ≥ |x + hy| ≥ η2 > 4|h| and |x + hy| ≥ |xy| – |h| ≥ |xy|2 when |x + hy| > η2 . By the arguments similar to those used to derive (3.18),

    I3,2f(x)n,s|h|1/s×(|xy|η4|Ωη(x+hy)f(y)|s|xy|n+s1χεi+1<|x+hy|εi(y)dy)1/s. (3.19)

    For I3,3f. In case (c) we have that |xy| > εi+1 ≥ |x + hy| ≥ η2 > 4|h| and |x + hy| ≥ |xy| – |h| ≥ |xy|2 when |x + hy| > η2 . The arguments similar to (3.18) will give that

    I3,3f(x)n,s|h|1/s×(|xy|η4|Ωη(x+hy)f(y)|s|xy|n+s1χεi+1<|xy|εi(y)dy)1/s. (3.20)

    For I3,4f. In case (d) we have that εi ≥ |xy| ≥ |x + hy| – |h| ≥ η2 η8 η4 > 2|h| and |x + hy| ≥ |xy| – |h| ≥ |xy|2 when |x + hy| > η2 . Similar arguments to those in getting (3.18) may give that

    I3,4f(x)n,s|h|1/s(|xy|η4|Ωη(x+hy)f(y)|s|xy|n+s1χεi+1<|xy|εi(y)dy)1/s. (3.21)

    By (3.17)-(3.21), (1.16) and a change of variable, we have

    I3f(x)n,s|h|1/s(|b(x+h)|+bL(Rn))m×(supεi0i=1(|xy|η4|Ωη(x+hy)f(y)|s|xy|n+s1×χεi+1<|x+hy|εi(y)dy)ρ/s)1/ρ+supεi0(i=1(|xy|η4|Ωη(x+hy)f(y)|s|xy|n+s1×χεi+1<|xy|εi(y)dy)ρ/s)1/ρ)n,s(|b(x+h)|+bL(Rn))m|h|1/s×(|xy|η4|Ωη(x+hy)f(y)|s|xy|n+s1dy)1/sn,s(|b(x+h)|+bL(Rn))m|h|1/s×(|y|η4|Ωη(y+h)f(xy)|s|y|n+s1dy)1/s. (3.22)

    Fix a ball B. By (3.22) and Minkownski’s inequality, one gets

    (1|B|βB|I3f(x)|pdx)1/pn,sbL(Rn)m|h|1/s|B|β/p×(B((|y|η4|Ωη(y+h)f(xy)|s|y|n+s1dy)p/sdx)1/pm,n,b,s|h|1/s(|y|η4(1|B|βB|f(xy)|pdx)s/p|Ωη(y+h)|s|y|n+s1dy)1/sm,n,b,s|h|1/sfMp,β(Rn)(|y|η4|Ωη(y+h)|s|y|n+s1dy)1/s. (3.23)

    Note that |y| ≥ |y + h| – |h| ≥ 38 |y + h| when |h| ≤ η8 and |y + h| ≥ η2 . By a change of variable and Hölder’s inequality, we have

    |y|η4|Ωη(y+h)|s|y|n+s1dyn,s|y+h|η2|Ωη(y+h)|s|y+h|n+s1dyn,s|z|η2|Ω(z)|s|z|n+s1dyn,sη/2rsdrSn1|Ω(θ)|sdσ(θ)n,sη1sΩLs(Sn1)sn,sΩLq(Sn1)sη1s.

    This together with (3.23) leads to

    I3fMp,β(Rn)m,n,b,sΩLq(Sn1)|h|1/sfMp,β(Rn)η1/sm,n,b,s(|h|η)1/s. (3.24)

    It follows from (3.10), (3.13), (3.16) and (3.24) that

    Vρ(TΩη,bm)(f)(+h)Vρ(TΩη,bm)(f)()Mp,β(Rn)m,n,b,s,p,q,β|h|+(|h|η)1/s.

    This yields (3.9) and finishes the proof of Theorem 1.2.□

4 Proof of Proposition 1.7

This section is devoted to proving Proposition 1.7. The proof will be divided into two parts:

  1. Proof of the boundedness part. It was proved by Yabuta [33] that if 0 < s < 1, 1 ≤ p < ∞ and 1 ≤ q ≤ ∞, then

    fB˙sp,q(Rn)(kZ2ksq(RnRn|Δ2kζf(x)|pdxdζ)q/p)1/q. (4.1)

    It was shown in [22] (see [22, (5.16)]) that

    |Δh((Vρ(TK,bm)(f))(x)|l=0mcml|bhml(x)|Vρ(TK)(bhlΔhf)(x)+l=1mcml=0lcl|Δhb(x)|μ=0mlcmlμ×|bmlμ(x)|Vρ(TK)(bμ(Δhb)lf)(x)=:G(f)(h,x) (4.2)

    for any x, h ∈ ℝn. By (4.1), (4.2), Minkowski’s inequality and the property of b, we have

    Vρ(TK,bm)(f)B˙sp,q(Rn)C(kZ2ksq(RnRn|Δ2kζ(Vρ(TK,bm)(f))(x)|pdxdζ)q/p)1/qC(kZ2ksq(RnRn|G(f)(2kζ,x)|pdxdζ)q/p)1/qCbL(Rn)m(kZ2ksq(RnRn(Vρ(TK)(Δ2kζf)(x))pdxdζ)q/p)1/q+CbL(Rn)m1×((kZ2ksq(RnRn(Vρ(TK)(Δ2kζbf)(x))pdxdζ)q/p)1/q+(kZ2ksq(RnRn|Δ2kζb(x)Vρ(TK)(f)(x)|pdxdζ)q/p)1/q). (4.3)

    Note that 0 < s < 1. By the Lp bounds for 𝓥ρ(𝓣K) and (4.1), we have

    (kZ2ksq(RnRn(Vρ(TK)(Δ2kζf)(x))pdxdζ)q/p)1/qC(kZ2ksq(RnRn|Δ2kζf)(x)|pdxdζ)q/p)1/qCfB˙sp,q(Rn). (4.4)

    By the Lp bounds for 𝓥ρ(𝓣K), (4.1) and the property of b, we get

    (kZ2ksq(RnRn(Vρ(TK)(Δ2kζbf)(x))pdxdζ)q/p)1/qC(kZ2ksq(RnRn|Δ2kζb(x)f(x)|pdxdζ)q/p)1/qCfLp(Rn)(bΛ˙(Rn)qk=12kq(1s)+bL(Rn)qk=02ksq)1/qCbΛ(Rn)fLp(Rn). (4.5)
    (kZ2ksq(RnRn|Δ2kζb(x)Vρ(TK)(f)(x)|pdxdζ)q/p)1/qC(kZ2ksq(bΛ˙(Rn)q2kqχ[1,)(k)+bL(Rn)qχ(,0](k))×(RnRn|f(x)|pdxdζ)q/p)1/qCbΛ(Rn)fLp(Rn)(k=12kq(1s)+k=02ksq)1/qCbΛ(Rn)fLp(Rn). (4.6)

    It follows from (4.3)-(4.6) and (1.12) that

    Vρ(TK,bm)(f)B˙sp,q(Rn)CbΛ(Rn)mfBsp,q(Rn). (4.7)

    On the other hand, it was shown in [22] (see [22, (5.11)]) that

    Vρ(TK,bm)(f)Lp(Rn)CbL(Rn)mfLp(Rn). (4.8)

    Then we get from (4.7), (4.8) and (1.12) that

    Vρ(TK,bm)(f)Bsp,q(Rn)CbΛ(Rn)mfBsp,q(Rn).

    This proves the boundedness part.

  2. Proof of the continuity part. Let 0 < s < 1, 1 < q < ∞ and fjf in Bsp,q (ℝn) as j → ∞. From (1.12) we see that fjf in B˙sp,q (ℝn) and in Lp(ℝn) as j → ∞. By the sublinearity of 𝓥ρ( TK,bm ) and (4.8), we have that 𝓥ρ( TK,bm )(fj) → 𝓥ρ( TK,bm )(f) in Lp(ℝn) as j → ∞. Hence, to get the continuity of 𝓥ρ( TK,bm ), it is enough to conclude that

    Vρ(TK,bm)(fj)Vρ(TK,bm)(f)inB˙sp,q(Rn)asj. (4.9)

    Next we shall prove (4.9) by contradiction. Without loss of generality we may assume that there exists c > 0 such that

    Vρ(TK,bm)(fj)Vρ(TK,bm)(f)B˙sp,q(Rn)>c

    for every j. Note that

    (RnRn|Δ2kζ(Vρ(TK,bm)(fj)Vρ(TK,bm)(f))(x)|pdxdζ)1/p2|Rn|1/pVρ(TK,bm)(fj)Vρ(TK,bm)(f)Lp(Rn).

    This yields that

    (RnRn|Δ2kζ(Vρ(TK,bm)(fj)Vρ(TK,bm)(f))(x)|pdxdζ)1/p0asj. (4.10)

    On the other hand, by (4.2) and the sublinearity of 𝓥ρ(𝓣K), we have that

    |Δ2kζ(Vρ(TK,bm)(fj)Vρ(TK,bm)(f))(x)||Δ2kζ(Vρ(TK,bm)(fj))(x)|+|Δ2kζ(Vρ(TK,bm)(f))(x)|G(fj)(2kζ,x)+G(f)(2kζ,x)G(fjf)(2kζ,x)+2G(2kζ,x). (4.11)

    By (4.3)-(4.6), we get

    (kZ2ksq(RnRn(G(f)(2kζ,x))pdxdζ)q/p)1/qCbΛ(Rn)mfBsp,q(Rn). (4.12)

    It follows that

    (kZ2ksq(RnRn(G(fjf)(2kζ,x))pdxdζ)q/p)1/qCbΛ(Rn)mfjfBsp,q(Rn)0asj.

    Thus, one can extract a subsequence such that

    j=1(kZ2ksq(RnRn(G(fjf)(2kζ,x))pdxdζ)q/p)1/q<. (4.13)

    For (k, ζ, x) ∈ ℤ × ℜn × ℝn, we set

    Γ(k,ζ,x):=j=1G(fjf)(2kζ,x)+2G(2kζ,x).

    By (4.11), we have

    |Δ2kζ(Vρ(TK,bm)(fj)Vρ(TK,bm)(f))(x)|Γ(k,ζ,x), (4.14)

    for (k, ζ, x) ∈ ℤ × ℜn × ℝn. By (4.12), (4.13) and Minkowski’s inequality, we get

    (kZ2ksq(RnRn(Γ(k,ζ,x))pdxdζ)q/p)1/q<. (4.15)

    It follows from (4.10), (4.14), (4.15) and the dominated convergence theorem that

    (kZ2ksq(RnRn|Δ2kζ(Vρ(TK,bm)(fj)Vρ(TK,bm)(f))(x)|pdxdζ)q/p)1/q0asj,

    which together with (4.1) leads to

    Vρ(TK,bm)(fj)Vρ(TK,bm)(f)B˙sp,q(Rn)0asj.

    This is a contradiction and completes the proof of Proposition 1.7.

Acknowledgement

The authors want to express their sincere thanks to the referees for their valuable remarks and suggestions, which made this paper more readable.

This work was supported partly by NNSF of China (Grant No. 11701333).

  1. Conflict of interest: Authors state no conflict of interest.

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Received: 2021-01-03
Accepted: 2021-04-21
Published Online: 2021-06-30

© 2021 X. Zhang et al., published by De Gruyter

This work is licensed under the Creative Commons Attribution 4.0 International License.

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