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Supercongruences concerning truncated hypergeometric series

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Abstract

Let \(n\ge 3\) be an integer and p be a prime with \(p\equiv 1\pmod {n}\). In this paper, we show that

$$\begin{aligned} {}_nF_{n-1}\bigg [\begin{array}{llll} \frac{n-1}{n}&{}\frac{n-1}{n}&{}\ldots &{}\frac{n-1}{n}\\ &{}1&{}\ldots &{}1\end{array}\bigg | \, 1\bigg ]_{p-1}\equiv -\Gamma _p\bigg (\frac{1}{n}\bigg )^n\pmod {p^3}, \end{aligned}$$

where the truncated hypergeometric series

$$\begin{aligned} {}_nF_{n-1}\bigg [\begin{array}{llll} x_1&{}x_2&{}\ldots &{}x_n\\ &{}y_1&{}\cdots &{}y_{n-1}\end{array}\bigg | \, z\bigg ]_m=\sum _{k=0}^{m}\frac{z^k}{k!}\prod _{j=0}^{k-1}\frac{(x_1+j)\cdots (x_{n}+j)}{(y_1+j)\cdots (y_{n-1}+j)} \end{aligned}$$

and \(\Gamma _p\) denotes the p-adic Gamma function. This confirms a conjecture of Deines et al. (Hypergeometric Series, Truncated Hypergeometric Series, and Gaussian Hypergeometric Functions, Directions in Number Theory, vol. 3, pp. 125–159. Assoc.WomenMath. Ser., Springer, New York, 2016). Furthermore, under the same assumptions, we also prove that

$$\begin{aligned} p^n\cdot {}_{n+1}F_{n}\bigg [\begin{matrix} 1&{}1&{}\ldots &{}1\\ &{}\frac{n+1}{n}&{}\ldots &{}\frac{n+1}{n}\end{matrix}\bigg | \, 1\bigg ]_{p-1} \equiv -\Gamma _p\left( \frac{1}{n}\right) ^n\pmod {p^3}, \end{aligned}$$

which solves another conjecture in [5].

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Acknowledgements

We are grateful to the anonymous referee for his/her very helpful comments on our paper.

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Correspondence to Hao Pan.

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Chen Wang is supported by the National Natural Science Foundation of China (Grant No. 11971222). Hao Pan is supported by the National Natural Science Foundation of China (Grant No. 12071208). Hao Pan is the corresponding author.

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Wang, C., Pan, H. Supercongruences concerning truncated hypergeometric series. Math. Z. 300, 161–177 (2022). https://doi.org/10.1007/s00209-021-02772-0

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