The linear stability of a blowup solution is equivalent to the well-posedness of linearized equations in \(\mathbb{R}^{3}\). For any \((t,x)\in (0,T^{*})\times \mathbb{R}^{3}\), we recall the perturbation equations
$$ \textstyle\begin{cases} n_{t}+(\textbf{v}+\overline{\textbf{u}})\cdot \nabla n=\triangle n- \chi \nabla \cdot (n\nabla c)+\sigma n-\mu n^{2}, \\ c_{t}+(\textbf{v}+\overline{\textbf{u}})\cdot \nabla c=\triangle c-c+n, \\ \textbf{v}_{t}+\textbf{v}\cdot \nabla \overline{\textbf{u}}+ \overline{\textbf{u}}\cdot \nabla \textbf{v}+\textbf{v}\cdot \nabla \textbf{v}=\nabla \overline{P}+\nu \triangle \textbf{v}+n\nabla \Phi , \\ \nabla \cdot \textbf{v}=0, \end{cases} $$
(2.1)
with initial data
$$ \textstyle\begin{cases} n(0,x)=n_{0}(x),& x\in \mathbb{R}^{3}, \\ c(0,x)=c_{0}(x),& x\in \mathbb{R}^{3}, \\ \textbf{v}(0,x)=\textbf{v}_{0}(x),& x\in \mathbb{R}^{3}, \end{cases} $$
(2.2)
and the boundary condition
$$ \textstyle\begin{cases} \lim_{|x|\rightarrow +\infty }n(t,x)=0, \\ \lim_{|x|\rightarrow +\infty }c(t,x)=0, \\ \lim_{|x|\rightarrow +\infty }\textbf{v}(t,x)=0, \end{cases} $$
(2.3)
where \((t,x)\in (0,T^{*})\times \mathbb{R}^{3}\), the pressure P̅ satisfies
$$ \begin{aligned} \overline{P}(t,x)=&{-}\triangle ^{-1} \Biggl(\sum_{k=1}^{3}\biggl( \frac{\partial v_{k} }{\partial x_{k}}\biggr)^{2}+2k\bigl(T^{*}-t \bigr)^{2a}\biggl(\frac{\partial v_{2}}{\partial x_{1}}-\frac{\partial v_{1}}{\partial x_{2}}\biggr) +2 \frac{\partial v_{1} }{\partial x_{2}}\frac{\partial v_{2}}{\partial x_{1}} \\ &{} +2\frac{\partial v_{1}}{\partial x_{3}}\frac{\partial v_{3} }{\partial x_{1}}+2\frac{\partial v_{2}}{\partial x_{3}} \frac{\partial v_{3} }{\partial x_{2}} -\nabla \cdot (n\nabla \Phi ) \Biggr), \end{aligned} $$
and we have
$$ \nabla \overline{\textbf{u}}=\begin{pmatrix} \frac{a}{T^{*}-t}&-k(T^{*}-t)^{2a}&0 \\ k(T^{*}-t)^{2a}&\frac{a}{T^{*}-t}&0 \\ 0&0&-\frac{2a}{T^{*}-t} \end{pmatrix}. $$
Let \(R\in (0,1)\) be a fixed constant. We define
$$ \mathcal{B}_{R}:= \bigl\{ \bigl(n(t,x),c(t,x), \textbf{v}(t,x) \bigr)^{T}: \Vert n \Vert _{\mathcal{C}_{1}^{s+\frac{11}{2}}}+ \Vert c \Vert _{\mathcal{C}_{1}^{s+\frac{11 }{2}}}+ \Vert \textbf{v} \Vert _{\mathcal{C}_{1}^{s+\frac{11}{2}}} \leq R< 1 \bigr\} $$
(2.4)
with a constant \(s>0\).
Assume that fixed functions \((n(t,x),c(t,x),\textbf{v}(t,x) )^{T}\in \mathcal{B}_{R}\). We linearize the nonlinear equations (2.1) around fixed functions \((n(t,x),c(t,x),\textbf{v}(t,x) )^{T}\) to get the linearized equations on the unknown variables \((\Gamma (t,x),\Lambda (t,x),\textbf{h}(t,x) )^{T}\) with an external force \((f_{1}(t,x),f_{2}(t,x),\textbf{g}(t,x) )^{T}\) as follows:
$$ \textstyle\begin{cases} \Gamma _{t}-\triangle \Gamma +(2\mu n-\sigma )\Gamma +(\textbf{v}+ \overline{\textbf{u}})\cdot \nabla \Gamma +\textbf{h}\cdot \nabla n\\ \quad {} +\chi \nabla \cdot [\Gamma \nabla c+n\nabla \Lambda ]=f_{1}(t,x), \\ \Lambda _{t}-\triangle \Lambda +\Lambda +(\textbf{v}+ \overline{\textbf{u}})\cdot \nabla \Lambda +\textbf{h}\cdot \nabla c- \Gamma =f_{2}(t,x), \\ \textbf{h}_{t}-\nu \triangle \textbf{h}+\textbf{h}\cdot \nabla ( \overline{\textbf{u}}+\textbf{v})+(\overline{\textbf{u}}+\textbf{v}) \cdot \nabla \textbf{h} -(\mathcal{F}_{\textbf{v}}\nabla \overline{P}) \textbf{h}\\ \quad {}-(\mathcal{F}_{n}\nabla \overline{P})\Gamma -\Gamma \nabla \Phi =\textbf{g}(t,x), \\ \nabla \cdot \textbf{h}=0,\quad \forall (t,x)\in (0,T^{*})\times \Omega _{t}, \end{cases} $$
(2.5)
where \(\mathcal{F}_{\textbf{v}}\) denotes the Fréchet derivative on v and \(\textbf{h}(t,x)= (h_{1}(t,x),h_{2}(t,x),h_{3}(t,x) )^{T}\).
In order to get some suitable prior estimates, we rewrite the linearized equations (2.5) as a coupled system,
$$\begin{aligned}& \Gamma _{t}-\triangle \Gamma +(2\mu n-\sigma ) \Gamma +(\textbf{v}+ \overline{\textbf{u}})\cdot \nabla \Gamma +\textbf{h}\cdot \nabla n+ \chi \nabla \cdot [\Gamma \nabla c+n\nabla \Lambda ]=f_{1}(t,x), \end{aligned}$$
(2.6)
$$\begin{aligned}& \Lambda _{t}-\triangle \Lambda +\Lambda +( \textbf{v}+ \overline{\textbf{u}})\cdot \nabla \Lambda +\textbf{h}\cdot \nabla c- \Gamma =f_{2}(t,x), \end{aligned}$$
(2.7)
$$\begin{aligned}& \begin{aligned} &\partial _{t}h_{1}- \nu \triangle h_{1}+\frac{a}{T^{*}-t}h_{1}+k \bigl(T^{*}-t\bigr)^{2a}h_{2}+ \biggl( \frac{ax_{1}}{T^{*}-t}+kx_{2}\bigl(T^{*}-t \bigr)^{2a} \biggr)\partial _{x_{1}}h_{1} \\ &\quad{} + \biggl(\frac{ax_{2}}{T^{*}-t}+kx_{1}\bigl(T^{*}-t \bigr)^{2a} \biggr)\partial _{x_{2}}h_{1}- \frac{2ax_{3} }{T^{*}-t}\partial _{x_{3}}h_{1}+h_{1} \partial _{x_{1}}w_{1}+w_{1} \partial _{x_{1}}h_{1} \\ &\quad{} +h_{2}\partial _{x_{2}}w_{1}+w_{2} \partial _{x_{2}}h_{1}+h_{3} \partial _{x_{3}}w_{1}+w_{3}\partial _{x_{3}}h_{1}-\Gamma \partial _{x_{1}} \Phi = \partial _{x_{1}}f(t,x)+g_{1}(t,x), \end{aligned} \end{aligned}$$
(2.8)
$$\begin{aligned}& \begin{aligned}& \partial _{t}h_{2}- \nu \triangle h_{2}-k\bigl(T^{*}-t\bigr)^{2a}h_{1}+ \frac{a}{T^{*}-t}h_{2}+ \biggl(\frac{ax_{1}}{T^{*}-t}+kx_{2} \bigl(T^{*}-t\bigr)^{2a} \biggr)\partial _{x_{1}}h_{2} \\ &\quad {}+ \biggl(\frac{ax_{2}}{T^{*}-t}-kx_{1}\bigl(T^{*}-t \bigr)^{2a} \biggr)\partial _{x_{2}}h_{2}- \frac{2ax_{3} }{T^{*}-t}\partial _{x_{3}}h_{2}+h_{1} \partial _{x_{1}}w_{2}+w_{1} \partial _{x_{1}}h_{2} \\ &\quad {}+h_{2}\partial _{x_{2}}w_{2}+w_{2} \partial _{x_{2}}h_{2}+h_{3} \partial _{x_{3}}w_{2}+w_{3}\partial _{x_{3}}h_{2}- \Gamma \partial _{x_{2}} \Phi =\partial _{x_{2}}f(t,x)+g_{2}(t,x), \end{aligned} \end{aligned}$$
(2.9)
$$\begin{aligned}& \begin{aligned} &\partial _{t}h_{3}- \nu \triangle h_{3}-\frac{a}{T^{*}-t}h_{3}+ \biggl( \frac{ax_{1} }{T^{*}-t}+kx_{2}\bigl(T^{*}-t \bigr)^{2a} \biggr)\partial _{x_{1}}h_{3} \\ &\quad{} + \biggl(\frac{ax_{2}}{T^{*}-t}-kx_{1}\bigl(T^{*}-t \bigr)^{2a} \biggr)\partial _{x_{2}}h_{3}- \frac{2ax_{3} }{T^{*}-t}\partial _{x_{3}}h_{3}+h_{1} \partial _{x_{1}}w_{3}+w_{1} \partial _{x_{1}}h_{3} \\ &\quad{} +h_{2}\partial _{x_{2}}w_{3}+w_{2} \partial _{x_{2}}h_{3}+h_{3} \partial _{x_{3}}w_{3}+w_{3}\partial _{x_{3}}h_{3}- \Gamma \partial _{x_{3}} \Phi =\partial _{x_{3}}f(t,x)+g_{3}(t,x), \end{aligned} \end{aligned}$$
(2.10)
with the incompressibility condition
$$ \nabla \cdot \textbf{h}=0, $$
where
$$\begin{aligned} f(t,x) =&-2\triangle ^{-1} \Biggl[\sum_{i=1}^{3} \bigl(\partial _{x_{i}}w_{i} \partial _{x_{i}}h_{i}- \partial _{x_{i}}(\Gamma \partial _{x_{i}} \Phi ) \bigr)+k \bigl(T^{*}-t\bigr)^{2a}(\partial _{x_{1}}h_{2}- \partial _{x_{2}}h_{1}) \\ &{}+ \partial _{x_{2}}h_{1} \partial _{x_{1}}w_{2} +\partial _{x_{1}}h_{2}\partial _{x_{2}}w_{1}+ \partial _{x_{3}}w_{1} \partial _{x_{1}}h_{3}+ \partial _{x_{3}}h_{1}\partial _{x_{1}}w_{3} \\ &{}+ \partial _{x_{3}}w_{2}\partial _{x_{2}}h_{3}+ \partial _{x_{3}}h_{2} \partial _{x_{2}}w_{3} \Biggr]. \end{aligned}$$
(2.11)
We introduce the similarity coordinates
$$ \begin{aligned} &\tau =-\ln \bigl(T^{*}-t \bigr)+\ln T^{*}, \\ &y=\frac{x}{\sqrt{T^{*}-t}}, \end{aligned} $$
(2.12)
where one can see the blowup time \(T^{*}>0\) has been transformed into +∞ in the similarity coordinates (2.12). So the local existence of linearized coupled system (2.6)–(2.10) with the incompressibility condition in some Sobolev space is equivalent to the global existence of linearized coupled system (2.13)–(2.17) in a related Sobolev space. This means the key point is to get the decay in time of solutions for system (2.13)–(2.17).
The linearized coupled system (2.6)–(2.10) under these coordinates is transformed into
$$\begin{aligned} &\partial _{\tau }\Gamma - \triangle _{y}\Gamma -\frac{y}{2}\cdot \nabla _{y}\Gamma +T^{*}e^{-\tau }(2\mu n-\sigma ) \Gamma +ay_{1} \partial _{y_{1}}\Gamma +ay_{2} \partial _{y_{2}}\Gamma -2ay_{3} \partial _{y_{3}} \Gamma \\ &\qquad{} +k\bigl(T^{*}\bigr)^{2a+1}e^{-(2a+1)\tau } (y_{2}\partial _{y_{1}} \Gamma +y_{1}\partial _{y_{2}}\Gamma )+\bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1 }{2}\tau } \textbf{h}\cdot \nabla _{y} n+\chi \sum_{i=1}^{3} \partial _{y_{i}}(\Gamma \partial _{y_{i}}c) \\ &\qquad{} +\chi \nabla _{y}\cdot (n\nabla _{y}\Lambda )=T^{*}e^{-\tau }f_{1}\bigl(T^{*} \bigl(1-e^{- \tau }\bigr),\bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau }y \bigr), \end{aligned}$$
(2.13)
$$\begin{aligned} &\partial _{\tau }\Lambda - \triangle _{y}\Lambda -\frac{y}{2}\cdot \nabla _{y}\Lambda +T^{*}e^{-\tau }\Lambda +ay_{1}\partial _{y_{1}} \Lambda +ay_{2} \partial _{y_{2}}\Lambda -2ay_{3}\partial _{y_{3}} \Lambda \\ &\qquad{} +k\bigl(T^{*}\bigr)^{2a+1}e^{-(2a+1)\tau } (y_{2}\partial _{y_{1}} \Lambda +y_{1}\partial _{y_{2}}\Lambda ) +\bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1 }{2}\tau } \Biggl(\sum_{i=1}^{2}h_{i} \partial _{y_{i}}c_{i}-\Gamma \Biggr) \\ &\quad =T^{*}e^{-\tau }f_{2} \bigl(T^{*}\bigl(1-e^{-\tau }\bigr),\bigl(T^{*} \bigr)^{\frac{1}{2}}e^{-\frac{1 }{2}\tau }y\bigr), \end{aligned}$$
(2.14)
$$\begin{aligned} &\partial _{\tau }h_{1}- \nu \triangle _{y}h_{1} -\frac{y}{2}\cdot \nabla _{y}h_{1}+ah_{1}+a\partial _{y_{1}}h_{1}+ay_{2}\partial _{y_{2}}h_{1}-2ay_{3} \partial _{y_{3}}h_{1} \\ &\qquad {}+k\bigl(T^{*}\bigr)^{2a+1}e^{-(2a+1)\tau } (h_{2}+y_{2}\partial _{y_{1}}h_{1}+y_{1} \partial _{y_{2}}h_{1} )-\bigl(T^{*} \bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau } \Gamma \partial _{y_{1}}\Phi \\ &\qquad{} +\bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau }\sum _{i=1}^{3} (h_{i} \partial _{y_{i}}w_{1}+w_{i}\partial _{y_{i}}h_{1} ) \\ &\quad =\bigl(T^{*}\bigr)^{\frac{1}{2}}\partial _{y_{1}} \overline{f}+T^{*}e^{-\tau }g_{1} \bigl(T^{*}\bigl(1-e^{- \tau }\bigr),\bigl(T^{*} \bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau }y\bigr), \end{aligned}$$
(2.15)
$$\begin{aligned} &\partial _{\tau }h_{2}- \nu \triangle _{y}h_{2}-\frac{y}{2}\cdot \nabla _{y}h_{2}+ah_{2}+ay_{1} \partial _{y_{1}}h_{2}+ay_{2}\partial _{y_{2}}h_{2}-2ay_{3} \partial _{y_{3}}h_{2} \\ &\qquad{} +k\bigl(T^{*}\bigr)^{2a+1}e^{-(2a+1)\tau } (-h_{1}+y_{2}\partial _{y_{1}}h_{2}-y_{1} \partial _{y_{2}}h_{2} )-\bigl(T^{*} \bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau } \Gamma \partial _{y_{2}}\Phi \\ &\qquad{} +\bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau }\sum _{i=1}^{3} (h_{i} \partial _{y_{i}}w_{2}+w_{i}\partial _{y_{i}}h_{2} ) \\ &\quad =\bigl(T^{*}\bigr)^{\frac{1}{2}}\partial _{y_{2}} \overline{f}+T^{*}e^{-\tau }g_{2} \bigl(T^{*}\bigl(1-e^{- \tau }\bigr),\bigl(T^{*} \bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau }y\bigr), \end{aligned}$$
(2.16)
$$\begin{aligned} &\partial _{\tau }h_{3}- \nu \triangle _{y}h_{3}-\frac{y}{2}\cdot \nabla _{y}h_{3}-h_{3}+ay_{1} \partial _{y_{1}}h_{3}+ay_{2}\partial _{y_{2}}h_{3}-2ay_{3} \partial _{y_{3}}h_{3} \\ &\qquad{} +k\bigl(T^{*}\bigr)^{2a+1}e^{-(2a+1)\tau } (y_{2}\partial _{y_{1}}h_{3}-y_{1} \partial _{y_{2}}h_{3} )-\bigl(T^{*} \bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau } \Gamma \partial _{y_{3}}\Phi \\ &\qquad{} +\bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau }\sum _{i=1}^{3} (h_{i} \partial _{y_{i}}w_{3}+w_{i}\partial _{y_{i}}h_{3} ) \\ &\quad =\bigl(T^{*}\bigr)^{\frac{1}{2}}\partial _{y_{3}} \overline{f}+T^{*}e^{-\tau }g_{3} \bigl(T^{*}\bigl(1-e^{- \tau }\bigr),\bigl(T^{*} \bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau }y\bigr), \end{aligned}$$
(2.17)
with the incompressibility condition
$$ \nabla _{y}\cdot \textbf{h}=0, $$
where
$$\begin{aligned} \overline{f} =&-2\triangle _{y}^{-1} \Biggl[\sum_{i=1}^{3} \bigl(\partial _{y_{i}}w_{i} \partial _{y_{i}}h_{i}- \partial _{y_{i}}(\Gamma \partial _{y_{i}} \Phi ) \bigr)+k \bigl(T^{*}\bigr)^{2a}e^{-2a\tau }(\partial _{y_{1}}h_{2}-\partial _{y_{2}}h_{1}) \\ &{} +\partial _{y_{2}}h_{1}\partial _{y_{1}}w_{2}+\partial _{y_{1}}h_{2} \partial _{y_{2}}w_{1}+\partial _{y_{3}}w_{1} \partial _{y_{1}}h_{3}+ \partial _{y_{3}}h_{1} \partial _{y_{1}}w_{3} \\ &{} +\partial _{y_{3}}w_{2} \partial _{y_{2}}h_{3}+\partial _{y_{3}}h_{2} \partial _{y_{2}}w_{3} \Biggr]. \end{aligned}$$
(2.18)
We supplement the linearized system (2.13)–(2.17) with the initial data
$$ \textstyle\begin{cases} \Gamma (0,y)=\Gamma _{0}(y)\in H^{s}(\mathbb{R}^{3}), \\ \Lambda (0,y)=\Lambda _{0}(y)\in H^{s}(\mathbb{R}^{3}), \\ \textbf{h}(0,y)=\textbf{h}_{0}(y)\in H^{s}(\mathbb{R}^{3}), \end{cases} $$
(2.19)
and the boundary condition
$$ \textstyle\begin{cases} \lim_{|y|\rightarrow \infty }\Gamma (\tau ,y)=0, \\ \lim_{|y|\rightarrow \infty }\Lambda (\tau ,y)=0, \\ \lim_{|y|\rightarrow \infty }\textbf{h}(\tau ,y)=0. \end{cases} $$
(2.20)
We first derive prior estimates of the linearized coupled system (2.13)–(2.17) with the initial data (2.19) and condition (2.20).
Lemma 2.1
Let \(s>0\), \(0< a\ll \frac{1}{8}\) and \(T^{*}\in (0,1)\) be constants. Assume that \(\|\Phi \|_{\mathbb{H}^{s+3}(\mathbb{R}^{3})}\lesssim R\ll 1\), \(f_{i}\in \mathbb{C}^{1}((0,+\infty ),\mathbb{H}^{s}(\mathbb{R}^{3}))\) \((i=1,2)\), \(\textbf{g}\in \mathbb{C}^{1}((0,+\infty ),H^{s}(\mathbb{R}^{3}))\) and \((n,c,\textbf{v} )^{T}\in \mathcal{B}_{R}\). Then, for any \(\tau >0\), the solution \((\Gamma ,\Lambda ,\textbf{h} )^{T}\) of linearized coupled system (2.13)–(2.17) with the initial data (2.19) and condition (2.20) satisfies
$$\begin{aligned} \int _{\mathbb{R}^{3}}\bigl( \vert \Gamma \vert ^{2}+ \vert \Lambda \vert ^{2}+ \vert \textbf{h} \vert ^{2}\bigr)\,dy \lesssim& e^{-C\tau } \biggl( \int _{\mathbb{R}^{3}}\bigl( \vert \Gamma _{0} \vert ^{2}+ \vert \Lambda _{0} \vert ^{2}+ \vert \textbf{h}_{0} \vert ^{2}\bigr)\,dy\\ &{}+ \int _{0}^{+\infty } \int _{ \mathbb{R}^{3}} \bigl( \vert f_{1} \vert ^{2}+ \vert f_{2} \vert ^{2}+ \vert \textbf{g} \vert ^{2}\bigr)\,dy\,d\tau \biggr), \end{aligned}$$
where C is a positive constant.
Proof
Multiplying both sides of (2.13)–(2.17) by Γ, Λ, \(h_{1}\), \(h_{2}\) and \(h_{3}\), respectively, then integrating by parts (using the boundary condition (2.20)), we have
$$\begin{aligned}& \begin{aligned}[b] &\frac{1}{2} \frac{d}{d\tau } \Vert \Gamma \Vert _{\mathbb{L}^{2}}^{2}+ \Vert \nabla _{y} \Gamma \Vert ^{2}_{\mathbb{L}^{2}}+ \biggl(\frac{3}{4}-T^{*}e^{-\tau }\sigma \biggr) \Vert \Gamma \Vert ^{2}_{\mathbb{L}^{2}} +2\mu T^{*}e^{-\tau } \int _{\mathbb{R}^{3}}n \Gamma ^{2}\,dy \\ &\qquad{} +\chi \sum_{i=1}^{3} \int _{\mathbb{R}^{3}} \bigl(\Gamma \partial _{y_{i}}c\partial _{y_{i}}\Gamma +n\partial _{y_{i}}^{2} \Lambda \bigr)\,dy +\bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau } \int _{ \mathbb{R}^{3}}(\textbf{h}\cdot \nabla _{y} n)\Gamma \,dy \\ &\quad =T^{*}e^{-\tau } \int _{\mathbb{R}^{3}}\Gamma f_{1}\,dy, \end{aligned} \end{aligned}$$
(2.21)
$$\begin{aligned}& \begin{aligned}[b] &\frac{1}{2} \frac{d}{d\tau } \Vert \Lambda \Vert _{\mathbb{L}^{2}}^{2}+ \Vert \nabla _{y} \Lambda \Vert ^{2}_{\mathbb{L}^{2}}+ \biggl(\frac{3}{4}+T^{*}e^{-\tau }\biggr) \Vert \Lambda \Vert ^{2}_{\mathbb{L}^{2}} \\ &\qquad {}+\bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau } \int _{\mathbb{R}^{3}} \Biggl(\sum_{i=1}^{2}h_{i} \partial _{y_{i}}c_{i}-\Gamma \Biggr)\Lambda \,dy =T^{*}e^{-\tau } \int _{\mathbb{R}^{3}}\Lambda f_{2}\,dy, \end{aligned} \end{aligned}$$
(2.22)
$$\begin{aligned}& \frac{1}{2} \frac{d}{d\tau } \Vert h_{1} \Vert _{\mathbb{L}^{2}}^{2}+ \nu \sum_{i,j=1}^{3} \Vert \partial _{y_{i}} h_{j} \Vert ^{2}_{\mathbb{L}^{2}}+ \biggl(a+\frac{3}{4}\biggr) \Vert h_{1} \Vert ^{2}_{\mathbb{L}^{2}}+k\bigl(T^{*}\bigr)^{2a+1}e^{-2(a+1)\tau } \int _{\mathbb{R}^{3}}h_{1}h_{2}\,dy \\& \qquad{} +\bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau }\sum _{i=1}^{3} \int _{\mathbb{R}^{3}}h_{1} (h_{i}\partial _{y_{i}}w_{1}+w_{i} \partial _{y_{i}}h_{1} )\,dy \\& \qquad{} -\bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau } \int _{\mathbb{R}^{3}} \Gamma \partial _{y_{1}}\Phi h_{1}\,dy=\bigl(T^{*}\bigr)^{\frac{1}{2}} \int _{ \mathbb{R}^{3}}h_{1}\partial _{y_{1}} \overline{f}\,dy+ \int _{\mathbb{R}^{3}}h_{1}g_{1}\,dy, \end{aligned}$$
(2.23)
$$\begin{aligned}& \frac{1}{2} \frac{d}{d\tau } \Vert h_{2} \Vert _{\mathbb{L}^{2}}^{2}+ \nu \sum_{i,j=1}^{3} \Vert \partial _{y_{i}} h_{j} \Vert ^{2}_{\mathbb{L}^{2}}+ \biggl(a+\frac{3}{4}\biggr) \Vert h_{2} \Vert ^{2}_{\mathbb{L}^{2}}-k\bigl(T^{*}\bigr)^{2a+1}e^{-2(a+1)\tau } \int _{\mathbb{R}^{3}}h_{1}h_{2}\,dy \\& \qquad{} +\bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau }\sum _{i=1}^{3} \int _{\mathbb{R}^{3}}h_{2} (h_{i}\partial _{y_{i}}w_{2}+w_{i} \partial _{y_{i}}h_{2} )\,dy \\& \qquad{} -\bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau } \int _{\mathbb{R}^{3}} \Gamma \partial _{y_{2}}\Phi h_{2}\,dy=\bigl(T^{*}\bigr)^{\frac{1}{2}} \int _{ \mathbb{R}^{3}}h_{2}\partial _{y_{2}} \overline{f}\,dy+ \int _{\mathbb{R}^{3}}h_{2}g_{2}\,dy, \end{aligned}$$
(2.24)
and
$$ \begin{aligned}[b] &\frac{1}{2} \frac{d}{d\tau } \Vert h_{3} \Vert _{\mathbb{L}^{2}}^{2}+ \nu \sum_{i,j=1}^{3} \Vert \partial _{y_{i}} h_{j} \Vert ^{2}_{\mathbb{L}^{2}}+ \biggl(\frac{3}{4}-2a\biggr) \Vert h_{3} \Vert ^{2}_{\mathbb{L}^{2}}\\ &\qquad{}+\bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau } \sum_{i=1}^{3} \int _{\mathbb{R}^{3}}h_{3} (h_{i}\partial _{y_{i}}w_{3}+w_{i} \partial _{y_{i}}h_{3} )\,dy \\ &\qquad{} -\bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau } \int _{\mathbb{R}^{3}} \Gamma \partial _{y_{3}}\Phi h_{3}\,dy=\bigl(T^{*}\bigr)^{\frac{1}{2}} \int _{ \mathbb{R}^{3}}h_{3}\partial _{y_{3}} \overline{f}\,dy+ \int _{\mathbb{R}^{3}}h_{3}g_{3}\,dy. \end{aligned} $$
(2.25)
Summing up (2.21)–(2.25), then
$$\begin{aligned}& \frac{1}{2}\sum _{i=1}^{3}\frac{d}{d\tau } \bigl( \Vert h_{i} \Vert _{\mathbb{L}^{2}}^{2}+ \Vert \Gamma \Vert _{\mathbb{L}^{2}}^{2}+ \Vert \Lambda \Vert _{\mathbb{L}^{2}}^{2} \bigr)+ \Vert \nabla _{y}\Gamma \Vert ^{2}_{\mathbb{L}^{2}}+ \Vert \nabla _{y}\Lambda \Vert ^{2}_{ \mathbb{L}^{2}} +3\nu \sum _{i,j=1}^{3} \Vert \partial _{y_{i}} h_{j} \Vert ^{2}_{ \mathbb{L}^{2}} \\& \qquad{} +\biggl(\frac{3}{4}-T^{*}e^{-\tau }\sigma \biggr) \Vert \Gamma \Vert ^{2}_{\mathbb{L}^{2}}+\biggl( \frac{3 }{4}+T^{*}e^{-\tau }\biggr) \Vert \Lambda \Vert ^{2}_{\mathbb{L}^{2}}+\biggl(a+\frac{3}{4}\biggr) \bigl( \Vert h_{1} \Vert ^{2}_{\mathbb{L}^{2}}+ \Vert h_{2} \Vert ^{2}_{\mathbb{L}^{2}}\bigr) \\& \qquad{}+\biggl( \frac{3 }{4}-2a\biggr) \Vert h_{3} \Vert ^{2}_{\mathbb{L}^{2}} +2\mu T^{*}e^{-\tau } \int _{\mathbb{R}^{3}}n\Gamma ^{2}\,dy-\chi \sum _{i=1}^{3} \int _{\mathbb{R}^{3}} \bigl(\Gamma \partial _{y_{i}}c \partial _{y_{i}}\Gamma +n\partial _{y_{i}}^{2}\Lambda \bigr)\,dy \\& \qquad{} +\bigl(T^{*}\bigr)^{\frac{1 }{2}}e^{-\frac{1}{2}\tau } \int _{\mathbb{R}^{3}}(\textbf{h}\cdot \nabla _{y} n)\Gamma \,dy +\bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau } \int _{\mathbb{R}^{3}} \Biggl(\sum_{i=1}^{3}h_{i} \partial _{y_{i}}c_{i}-\Gamma \Biggr)\Lambda \,dy \\& \qquad{}- \bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau }\sum _{i=1}^{3} \int _{\mathbb{R}^{3}} \Gamma \partial _{y_{i}}\Phi h_{i}\,dy +\bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau }\sum _{i=1}^{3} \int _{ \mathbb{R}^{3}}h_{1} (h_{i}\partial _{y_{i}}w_{1}+w_{i}\partial _{y_{i}}h_{1} )\,dy \\& \qquad{} +\bigl(T^{*} \bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau }\sum_{i=1}^{3} \int _{ \mathbb{R}^{3}}h_{2} (h_{i}\partial _{y_{i}}w_{2}+w_{i}\partial _{y_{i}}h_{2} )\,dy \\& \qquad{} +\bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau }\sum _{i=1}^{3} \int _{ \mathbb{R}^{3}}h_{3} (h_{i}\partial _{y_{i}}w_{3}+w_{i}\partial _{y_{i}}h_{3} )\,dy \\& \quad =\bigl(T^{*}\bigr)^{\frac{1}{2}}\sum _{i=1}^{3} \int _{\mathbb{R}^{3}}h_{i} \partial _{y_{i}} \overline{f}\,dy+T^{*}e^{-\tau } \int _{\mathbb{R}^{3}}\Biggl( \Gamma f_{1}+\Lambda f_{2}+\sum_{i=1}^{3}h_{i}g_{i} \Biggr)\,dy,\quad \forall \tau >0. \end{aligned}$$
(2.26)
We now estimate each coupled nonlinear term in (2.26). Note that \((n,c,\textbf{v} )^{T}\in \mathcal{B}_{R}\) and \(H^{\frac{5}{2}}(\mathbb{R}^{3})\subset L^{\infty }(\mathbb{R}^{3})\). We use Young’s inequality to derive
$$ \begin{aligned} & \biggl\vert 2\mu T^{*}e^{-\tau } \int _{\mathbb{R}^{3}}n\Gamma ^{2}\,dy \biggr\vert \lesssim C_{R} \Vert \Gamma \Vert _{\mathbb{L}^{2}}^{2}, \\ & \Biggl\vert \sum_{i=1}^{3} \int _{\mathbb{R}^{3}} \bigl(\Gamma \partial _{y_{i}}c \partial _{y_{i}}\Gamma +n\partial _{y_{i}}^{2}\Lambda \bigr)\,dy \Biggr\vert \lesssim C_{R} \Biggl( \Vert \Gamma \Vert _{\mathbb{L}^{2}}^{2}+\sum_{i=1}^{3} \bigl( \Vert \partial _{y_{i}}\Gamma \Vert _{\mathbb{L}^{2}}^{2}+ \Vert \partial _{y_{i}} \Lambda \Vert _{\mathbb{L}^{2}}^{2} \bigr) \Biggr), \\ & \biggl\vert \bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau } \int _{\mathbb{R}^{3}}( \textbf{h}\cdot \nabla _{y} n)\Gamma \,dy \biggr\vert \lesssim C_{R} \Biggl( \Vert \Gamma \Vert _{\mathbb{L}^{2}}^{2}+\sum_{i=1}^{3} \Vert h_{i} \Vert _{\mathbb{L}^{2}}^{2} \Biggr), \\ & \Biggl\vert \bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau } \int _{\mathbb{R}^{3}} \Biggl( \sum_{i=1}^{3}h_{i} \partial _{y_{i}}d_{i}-\Gamma \Biggr)\Lambda \,dy \Biggr\vert \\ &\quad \lesssim \frac{(T^{*})^{\frac{1}{2}}}{2}e^{-\frac{1}{2}\tau } \bigl(2 \Vert \Lambda \Vert _{\mathbb{L}^{2}}^{2}+ \Vert \Gamma \Vert _{\mathbb{L}^{2}}^{2} \bigr)+C_{R} \sum _{i=1}^{3} \Vert h_{i} \Vert _{\mathbb{L}^{2}}^{2}, \\ & \Biggl\vert \bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau } \sum_{i=1}^{3} \int _{ \mathbb{R}^{3}}\Gamma \partial _{y_{i}}\Phi h_{i}\,dy \Biggr\vert \lesssim C_{R} \Biggl( \Vert \Gamma \Vert _{\mathbb{L}^{2}}^{2}+\sum _{i=1}^{3} \Vert h_{i} \Vert _{ \mathbb{L}^{2}}^{2} \Biggr), \end{aligned} $$
(2.27)
and
$$ \begin{aligned} & \Biggl\vert \sum _{i=1}^{3} \int _{\mathbb{R}^{3}}h_{1} (h_{i}\partial _{x_{i}}w_{1}+w_{i} \partial _{y_{i}}h_{1} )\,dy \Biggr\vert \lesssim C_{R} \sum_{i=1}^{3} \bigl( \Vert h_{i} \Vert ^{2}_{\mathbb{L}^{2}}+ \Vert \partial _{y_{i}}h_{1} \Vert _{\mathbb{L}^{2}} \bigr), \\ & \Biggl\vert \sum_{i=1}^{3} \int _{\mathbb{R}^{3}}h_{2} (h_{i}\partial _{y_{i}}w_{2}+w_{i} \partial _{y_{i}}h_{2} )\,dy \Biggr\vert \lesssim C_{R} \sum_{i=1}^{3} \bigl( \Vert h_{i} \Vert ^{2}_{\mathbb{L}^{2}}+ \Vert \partial _{y_{i}}h_{2} \Vert _{\mathbb{L}^{2}} \bigr), \\ & \Biggl\vert \sum_{i=1}^{3} \int _{\mathbb{R}^{3}}h_{3} (h_{i}\partial _{y_{i}}w_{3}+w_{i} \partial _{y_{i}}h_{3} )\,dy \Biggr\vert \lesssim C_{R} \sum_{i=1}^{3} \bigl( \Vert h_{i} \Vert ^{2}_{\mathbb{L}^{2}}+ \Vert \partial _{y_{i}}h_{3} \Vert _{\mathbb{L}^{2}} \bigr), \end{aligned} $$
(2.28)
where \(C_{R}\), \(C_{a,R}\), \(C_{\kappa ,R}\) are three positive constants depending on R, a, R and κ, R, respectively.
On the other hand, by (2.18) and the standard Calderon–Zygmund theory, i.e. for the Riesz operator \(\mathcal{R}\), we have \(\|\mathcal{R}w\|_{\mathbb{L}^{p}}\leq \|w\|_{\mathbb{L}^{p}}\) with \(1< p<\infty \), we also use Young’s inequality to get
$$ \Biggl\vert \sum_{i=1}^{3} \int _{\Omega }h_{i}\partial _{y_{i}} \overline{f}\,dy \Biggr\vert \lesssim C_{R}\sum _{i,j=1}^{3} \bigl( \Vert \Gamma \Vert _{\mathbb{L}^{2}}^{2}+ \Vert h_{i} \Vert _{\mathbb{L}^{2}}^{2}+ \Vert \partial _{y_{i}}h_{j} \Vert _{\mathbb{L}^{2}}^{2} \bigr) $$
(2.29)
and
$$ \begin{aligned}[b] &\Biggl\vert T^{*}e^{-\tau } \int _{\Omega }\Biggl(\Gamma f_{1}+\Lambda f_{2}+\sum_{i=1}^{3}h_{i}g_{i} \Biggr)\,dy \Biggr\vert \\ &\quad \leq T^{*}e^{-\tau } \Biggl[b\bigl( \Vert \Gamma \Vert _{\mathbb{L}^{2}}^{2}+ \Vert \Lambda \Vert _{\mathbb{L}^{2}}^{2}\bigr)+b^{-1}\bigl( \Vert f_{1} \Vert _{\mathbb{L}^{2}}^{2}+ \Vert f_{2} \Vert _{\mathbb{L}^{2}}^{2}\bigr) \\ &\qquad {}+\sum_{i=1}^{3} \bigl(b \Vert h_{i} \Vert ^{2}_{\mathbb{L}^{2}}+b^{-1} \Vert g_{i} \Vert ^{2}_{\mathbb{L}^{2}} \bigr) \Biggr], \end{aligned} $$
(2.30)
where the positive constant \(b<1\).
Thus by (2.27)–(2.30), it follows from (2.26) that
$$\begin{aligned} &\frac{1}{2}\sum _{i=1}^{3}\frac{d}{d\tau } \Vert h_{i} \Vert _{\mathbb{L}^{2}}^{2}+(1-C_{R}) \Vert \nabla _{y}\Gamma \Vert ^{2}_{\mathbb{L}^{2}}+(1-C_{R}) \Vert \nabla _{y} \Lambda \Vert ^{2}_{\mathbb{L}^{2}}+(3 \nu -C_{R})\sum_{i,j=1}^{3} \Vert \partial _{y_{i}} h_{j} \Vert ^{2}_{\mathbb{L}^{2}} \\ &\qquad{} + \biggl(\frac{3}{4}-T^{*}e^{-\tau }(b+ \sigma )-\frac{(T^{*})^{\frac{1}{2}} }{2}e^{-\frac{1}{2}\tau }-C_{R} \biggr) \Vert \Gamma \Vert ^{2}_{\mathbb{L}^{2}} \\ &\qquad {}+ \biggl(\frac{3}{4}+T^{*}e^{-\tau }(1-b)- \bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1 }{2}\tau }-C_{R} \biggr) \Vert \Lambda \Vert ^{2}_{\mathbb{L}^{2}} \\ &\qquad{} + \biggl(a+\frac{3}{4}-T^{*}e^{-\tau }b-C_{R} \biggr) \bigl( \Vert h_{1} \Vert ^{2}_{ \mathbb{L}^{2}}+ \Vert h_{2} \Vert ^{2}_{\mathbb{L}^{2}}\bigr) + \biggl(\frac{3}{4}-2a-T^{*}e^{- \tau }b-C_{R} \biggr) \Vert h_{3} \Vert ^{2}_{\mathbb{L}^{2}} \\ &\quad \lesssim b^{-1} \Biggl( \Vert f_{1} \Vert _{\mathbb{L}^{2}}^{2}+ \Vert f_{2} \Vert _{ \mathbb{L}^{2}}^{2}+\sum_{i=1}^{3} \Vert g_{i} \Vert ^{2}_{\mathbb{L}^{2}} \Biggr), \end{aligned}$$
(2.31)
where \(C_{R}\) is a positive constant depending on R, which can be very small if constants R is small.
There exists a sufficiently small positive constant \(b\in (0,1)\) such that
$$ \begin{aligned} &1-C_{R}>0,\qquad 1-C_{R}>0, \quad 3\nu -C_{R}>0, \\ &\frac{3}{4}-T^{*}e^{-\tau }(b+\sigma )- \frac{(T^{*})^{\frac{1}{2}}}{2}e^{-\frac{1 }{2}\tau }-C_{R}>0,\\ &\frac{3}{4}+T^{*}e^{-\tau }(1-b)- \bigl(T^{*}\bigr)^{\frac{1 }{2}}e^{-\frac{1}{2}\tau }-C_{R}>0, \\ &a+\frac{3}{4}-T^{*}e^{-\tau }b-C_{R}>0, \qquad \frac{3}{4}-2a-T^{*}e^{- \tau }b-C_{R}>0. \end{aligned} $$
Hence, applying Gronwall’s inequality to (2.31), there exists a positive constant C such that
$$ \begin{aligned} \Vert \Gamma \Vert _{\mathbb{L}^{2}}^{2}+ \Vert \Gamma \Vert _{\mathbb{L}^{2}}^{2}+\sum _{i=1}^{3} \Vert h_{i} \Vert _{\mathbb{L}^{2}}^{2}\lesssim{}& e^{-C\tau } \int _{\mathbb{R}^{3}} \Biggl(\Gamma ^{2}_{0} + \Lambda ^{2}_{0}+\sum_{i=1}^{3}h_{0i}^{2} \Biggr)\,dy \\ &{} + e^{-C\tau } \int _{0}^{+\infty } \int _{\mathbb{R}^{3}} \Biggl(f_{1}^{2}+f^{2}_{2}+ \sum_{i=1}^{3}g_{i}^{2}d \tau \Biggr)\,dy,\quad \forall \tau >0. \end{aligned} $$
□
In what follows, we plan to carry out higher order derivative estimates to the solutions of linearized system (2.8)–(2.10). For a fixed constant \(s>0\), applying \(\nabla ^{s}=\partial _{y_{i}}^{s}\) to both sides of (2.22)–(2.10), we obtain
$$\begin{aligned} &\partial _{\tau }\nabla ^{s}_{y}\Gamma -\triangle _{y}\nabla ^{s}_{y} \Gamma -\frac{y}{2}\cdot \nabla ^{s+1}_{y}\Gamma + \biggl(T^{*}e^{-\tau }(2 \mu n-\sigma )-\frac{s}{2} \biggr)\nabla ^{s}_{y} \Gamma +ay_{1}\partial _{y_{1}} \nabla ^{s}_{y} \Gamma +ay_{2}\partial _{y_{2}}\nabla _{y}^{s} \Gamma \\ &\qquad{} -2ay_{3}\partial _{y_{3}}\nabla _{y}^{s} \Gamma +k\bigl(T^{*}\bigr)^{2a+1}e^{-(2a+1) \tau } \bigl(2s \nabla _{y}^{s}\Gamma +y_{2}\partial _{y_{1}}\nabla _{y}^{s} \Gamma +y_{1}\partial _{y_{2}}\nabla _{y}^{s} \Gamma \bigr) \\ &\qquad{} +\bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau }\nabla _{y}^{s}( \textbf{h}\cdot \nabla _{y} n) + \chi \sum_{i=1}^{3}\partial _{y_{i}} \nabla ^{s}_{y}(\Gamma \partial _{y_{i}}c)+\chi \nabla _{y}^{s} \bigl( \nabla _{y}\cdot (n\nabla _{y}\Lambda ) \bigr) \\ &\quad =T^{*}e^{-\tau } \nabla ^{s}_{y}f_{1}, \end{aligned}$$
(2.32)
$$\begin{aligned} &\partial _{\tau }\nabla _{y}^{s}\Lambda -\triangle _{y}\nabla _{y}^{s} \Lambda -\frac{y}{2}\cdot \nabla _{y}^{s+1}\Lambda +\biggl(T^{*}e^{-\tau }- \frac{s }{2}\biggr)\nabla _{y}^{s}\Lambda +ay_{1}\partial _{y_{1}}\nabla _{y}^{s} \Lambda +ay_{2}\partial _{y_{2}}\nabla _{y}^{s} \Lambda \\ &\qquad{} -2ay_{3} \partial _{y_{3}}\nabla _{y}^{s} \Lambda +k\bigl(T^{*}\bigr)^{2a+1}e^{-(2a+1)\tau } \bigl(2s\nabla _{y}^{s}\Lambda +y_{2} \partial _{y_{1}}\nabla _{y}^{s}\Lambda +y_{1}\partial _{y_{2}} \nabla _{y}^{s} \Lambda \bigr) \\ &\qquad{}+\bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau } \Biggl(\sum_{i=1}^{2}\nabla _{y}^{s}(h_{i}\partial _{y_{i}}c_{i})- \Gamma \Biggr) =T^{*}e^{-\tau }\nabla _{y}^{s}f_{2}, \end{aligned}$$
(2.33)
$$\begin{aligned} &\partial _{\tau }\nabla _{y}^{s}h_{1}-\nu \triangle _{y}\nabla _{y}^{s}h_{1}- \frac{y }{2}\cdot \partial _{y}\nabla _{y}^{s}h_{1}+ \biggl(a-\frac{s}{2}\biggr)\nabla _{y}^{s}h_{1}+ay_{1} \partial _{y_{1}}\nabla _{y}^{s}h_{1}+ay_{2} \partial _{y_{2}}\nabla _{y}^{s}h_{1} \\ &\qquad{}-2ay_{3} \partial _{y_{3}}\nabla _{y}^{s}h_{1} +k\bigl(T^{*}\bigr)^{2a+1}e^{-(2a+1)\tau } \bigl( \nabla _{y}^{s}h_{2}+2s \nabla _{y}^{s}h_{1}+y_{2}\partial _{y_{1}}\nabla _{y}^{s}h_{1}+y_{1} \partial _{y_{2}}\nabla _{y}^{s}h_{1} \bigr) \\ &\qquad{}-\bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1 }{2}\tau }\nabla _{y}^{s}(\Gamma \partial _{y_{1}}\Phi ) +\bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau }\sum _{i=1}^{3} \bigl( \nabla _{y}^{s}h_{i}\partial _{y_{i}}w_{1}+w_{i} \partial _{y_{i}} \nabla _{y}^{s}h_{1} \bigr) =\tilde{g}_{1}, \end{aligned}$$
(2.34)
$$\begin{aligned} &\partial _{\tau }\nabla ^{s}_{y}h_{2}-\nu \triangle _{y}\nabla ^{s}_{y}h_{2}- \frac{y }{2}\cdot \partial _{y}\nabla ^{s}_{y}h_{2}+ \biggl(a-\frac{s}{2}\biggr)\nabla ^{s}_{y}h_{2}+ay_{1} \partial _{y_{1}}\nabla ^{s}_{y}h_{2}+ay_{2} \partial _{y_{2}}\nabla ^{s}_{y}h_{2} \\ &\qquad{} -2ay_{3}\partial _{y_{3}}\nabla ^{s}_{y}h_{2}+k \bigl(T^{*}\bigr)^{2a+1}e^{-(2a+1) \tau } \bigl(-\nabla ^{s}_{y}h_{1}+y_{2}\partial _{y_{1}}\nabla ^{s}_{y}h_{2}-y_{1} \partial _{y_{2}}\nabla ^{s}_{y}h_{2} \bigr) \\ &\qquad{} -\bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1 }{2}\tau }\nabla _{y}^{s}(\Gamma \partial _{y_{2}}\Phi )+\bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau }\sum _{i=1}^{3} \bigl( \nabla ^{s}_{y}h_{i}\partial _{y_{i}}w_{2}+w_{i} \partial _{y_{i}} \nabla ^{s}_{y}h_{2} \bigr)=\tilde{g}_{2}, \end{aligned}$$
(2.35)
$$\begin{aligned} &\partial _{\tau }\nabla ^{s}_{y}h_{3}-\nu \triangle _{y}\nabla ^{s}_{y}h_{3}- \frac{y }{2}\cdot \partial _{y}\nabla ^{s}_{y}h_{3}- \biggl(2a+\frac{s}{2}\biggr) \nabla ^{s}_{y}h_{3}+ay_{1} \partial _{y_{1}}\nabla ^{s}_{y}h_{3}+ay_{2} \partial _{y_{2}}\nabla ^{s}_{y}h_{3} \\ &\qquad{}-2ay_{3} \partial _{y_{3}}\nabla ^{s}_{y}h_{3} +k\bigl(T^{*}\bigr)^{2a+1}e^{-(2a+1)\tau } \bigl(y_{2}\partial _{y_{1}} \nabla ^{s}_{y}h_{3}-y_{1} \partial _{y_{2}}\nabla ^{s}_{y}h_{3} \bigr) \\ &\qquad{} +\bigl(T^{*}\bigr)^{\frac{1 }{2}}e^{-\frac{1}{2}\tau }\sum _{i=1}^{3} \bigl(\nabla ^{s}_{y}h_{i} \partial _{y_{i}}w_{3}+w_{i} \partial _{y_{i}}\nabla ^{s}_{y}h_{3} \bigr)-\bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau }\nabla _{y}^{s}(\Gamma \partial _{y_{3}}\Phi )= \tilde{g}_{3}, \end{aligned}$$
(2.36)
where
$$\begin{aligned}& \begin{aligned}[b] \tilde{g}_{1}:={}& \bigl(T^{*}\bigr)^{\frac{1}{2}}\partial _{y_{1}}\nabla _{y}^{s} \overline{f}+T^{*}e^{-\tau } \nabla _{y}^{s}g_{1} \\ &{} -\bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau }\sum _{j=1}^{3}\sum _{i_{1}+i_{2}=s,~0 \leq i_{2}\leq s-1} \bigl(\nabla ^{i_{2}}_{y}h_{j} \partial _{y_{j}} \nabla ^{i_{1}}_{y}w_{1}+ \nabla ^{i_{1}}_{y}w_{j}\partial _{y_{j}} \nabla _{y}^{i_{2}}h_{1} \bigr), \end{aligned} \end{aligned}$$
(2.37)
$$\begin{aligned}& \begin{aligned}[b] \tilde{g}_{2}:={}& \bigl(T^{*}\bigr)^{\frac{1}{2}}\partial _{y_{2}}\nabla ^{s}_{y} \overline{f}+T^{*}e^{-\tau } \nabla ^{s}_{y}g_{2} \\ &{} -\bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau }\sum _{j=1}^{3}\sum _{i_{1}+i_{2}=s,~0 \leq i_{2}\leq s-1} \bigl(\nabla ^{i_{2}}_{y}h_{j} \partial _{y_{j}} \nabla ^{i_{1}}_{y}w_{2}+ \nabla ^{i_{1}}_{y}w_{j}\partial _{y_{j}} \nabla ^{i_{2}}_{y}h_{2} \bigr), \end{aligned} \end{aligned}$$
(2.38)
$$\begin{aligned}& \begin{aligned}[b] \tilde{g}_{3}:={}& \bigl(T^{*}\bigr)^{\frac{1}{2}}\partial _{y_{3}}\nabla ^{s}_{y} \overline{f}+T^{*}e^{-\tau } \nabla ^{s}_{y}g_{3} \\ &{} - \bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau }\sum _{j=1}^{3}\sum _{i_{1}+i_{2}=s,~0 \leq i_{2}\leq s-1} \bigl(\nabla ^{i_{2}}_{y}h_{j} \partial _{y_{j}} \nabla ^{i_{1}}_{y}w_{3}+ \nabla ^{i_{1}}_{y}w_{j}\partial _{y_{j}} \nabla ^{i_{2}}_{y}h_{3} \bigr). \end{aligned} \end{aligned}$$
(2.39)
We now have the following higher order derivatives estimates.
Lemma 2.2
Let \(0< a\ll \frac{1}{8}\) and \(0< s<\frac{3}{2}-5a\) be constants. Assume that \(\|\Phi \|_{\mathbb{H}^{s+3}(\mathbb{R}^{3})}\lesssim R\ll 1\), \(f_{i}\in \mathbb{C}^{1}((0,+\infty ),\mathbb{H}^{s}(\mathbb{R}^{3}))\) \((i=1,2)\), \(\textbf{g}\in \mathbb{C}^{1}((0,+\infty ),H^{s}(\mathbb{R}^{3}))\) and \((n,c,\textbf{v} )^{T}\in \mathcal{B}_{R}\). Then, for any \(\tau >0\), the solution \((\Gamma ,\Lambda ,\textbf{h} )^{T}\) of the linearized coupled system (2.13)–(2.17) with the initial data (2.19) and condition (2.20) satisfies
$$ \begin{aligned} & \int _{\mathbb{R}^{3}} \Biggl( \bigl\vert \nabla _{y}^{s} \Gamma \bigr\vert ^{2}+ \bigl\vert \nabla _{y}^{s} \Lambda \bigr\vert ^{2}+\sum_{i=1}^{3} \bigl\vert \nabla _{y}^{s}h_{i} \bigr\vert ^{2} \Biggr)\,dy \\ &\quad \lesssim e^{-C_{R,T^{*}}\tau } \int _{\mathbb{R}^{3}} \Biggl( \bigl\vert \nabla _{y}^{s} \Gamma _{0} \bigr\vert ^{2}+ \bigl\vert \nabla _{y}^{s}\Lambda _{0} \bigr\vert ^{2}+\sum_{i=1}^{3} \bigl\vert \nabla _{y}^{s}h_{0i} \bigr\vert ^{2} \Biggr)\,dy \\ &\qquad{} +e^{-C_{R,T^{*}}\tau } \int _{0}^{+\infty } \Biggl( \bigl\Vert \nabla _{y}^{s}f_{1} \bigr\Vert _{\mathbb{L}^{2}}^{2}+ \bigl\Vert \nabla _{y}^{s}f_{2} \bigr\Vert _{\mathbb{L}^{2}}^{2}+ \sum _{i=1}^{3} \bigl\Vert \nabla _{y}^{s}g_{i} \bigr\Vert ^{2}_{\mathbb{L}^{2}} \Biggr)d \tau , \quad \forall \tau >0, \end{aligned} $$
where \(C_{R,T^{*}}\) is a positive constant depending on constants R, \(T^{*}\).
Proof
Taking the inner product of both sides of (2.32)–(2.36) by \(\nabla _{y}^{s}\Gamma \), \(\nabla _{y}^{s}\Lambda \), \(\nabla _{y}^{s}h_{1}\), \(\nabla _{y}^{s}h_{2}\) and \(\nabla _{y}^{s}h_{3}\), respectively, then integrating by parts, we have
$$\begin{aligned} &\frac{1}{2} \frac{d}{d\tau } \bigl\Vert \nabla _{y}^{s}\Gamma \bigr\Vert _{\mathbb{L}^{2}}^{2}+ \bigl\Vert \nabla _{y}^{s+1}\Gamma \bigr\Vert ^{2}_{\mathbb{L}^{2}}+ \biggl(\frac{3}{4}-\frac{s }{2}-T^{*}e^{-\tau } \sigma ++2s\kappa \bigl(T^{*}\bigr)^{2a+1}e^{-(2a+1)\tau } \biggr) \bigl\Vert \nabla _{y}^{s}\Gamma \bigr\Vert ^{2}_{\mathbb{L}^{2}} \\ &\qquad{} +2\mu T^{*}e^{-\tau } \int _{\mathbb{R}^{3}}n \vert \nabla _{y}\Gamma \vert ^{2}\,dy +\bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau } \int _{\mathbb{R}^{3}}\nabla _{y}^{s}( \textbf{h}\cdot \nabla _{y} n)\cdot \nabla _{y}^{s} \Gamma \,dy \\ &\qquad{} +\chi \sum_{i=1}^{3} \int _{\mathbb{R}^{3}}\partial _{y_{i}}\nabla ^{s}_{y}( \Gamma \partial _{y_{i}}c)\cdot \nabla _{y}^{s}\Gamma \,dy+\chi \int _{\mathbb{R}^{3}}\nabla _{y}^{s} \bigl( \nabla _{y} \cdot (n\nabla _{y}\Lambda ) \bigr)\cdot \nabla _{y}^{s}\Gamma \,dy \\ &\quad =T^{*}e^{- \tau } \int _{\mathbb{R}^{3}}\nabla ^{s}_{y}f_{1} \cdot \nabla _{y}^{s} \Gamma \,dy, \end{aligned}$$
(2.40)
$$\begin{aligned} &\frac{1}{2} \frac{d}{d\tau } \bigl\Vert \nabla _{y}^{s}\Lambda \bigr\Vert _{\mathbb{L}^{2}}^{2}+ \bigl\Vert \nabla _{y}^{s+1}\Lambda \bigr\Vert ^{2}_{\mathbb{L}^{2}}+ \biggl(\frac{3}{4}-\frac{s }{2}+T^{*}e^{-\tau }+2s \kappa \bigl(T^{*}\bigr)^{2a+1}e^{-(2a+1)\tau } \biggr) \bigl\Vert \nabla _{y}^{s}\Lambda \bigr\Vert ^{2}_{\mathbb{L}^{2}} \\ &\qquad{} +\bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau } \int _{\mathbb{R}^{3}} \Biggl(\sum_{i=1}^{2} \nabla _{y}^{s}(h_{i}\partial _{y_{i}}d_{i})- \nabla _{y}^{s} \Gamma \Biggr)\cdot \nabla _{y}^{s}\Lambda \,dy \\ &\quad =T^{*}e^{- \tau } \int _{\mathbb{R}^{3}}\nabla _{y}^{s}f_{2} \cdot \nabla _{y}^{s} \Lambda \,dy, \end{aligned}$$
(2.41)
$$\begin{aligned} &\frac{1}{2} \frac{d}{d\tau } \bigl\Vert \nabla _{y}^{s}h_{1} \bigr\Vert _{\mathbb{L}^{2}}^{2}+ \nu \sum _{i,j=1}^{3} \bigl\Vert \partial _{y_{i}} \nabla _{y}^{s}h_{j} \bigr\Vert ^{2}_{ \mathbb{L}^{2}}+\biggl(a+\frac{3}{4}- \frac{s}{2}\biggr) \bigl\Vert \nabla _{y}^{s}h_{1} \bigr\Vert ^{2}_{ \mathbb{L}^{2}} \\ &\qquad{} +k\bigl(T^{*} \bigr)^{2a+1}e^{-(2a+1)\tau } \int _{\mathbb{R}^{3}} \nabla _{y}^{s}h_{1} \cdot \nabla _{y}^{s}h_{2}\,dy \\ &\qquad{} +\bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau }\sum _{i=1}^{3} \int _{ \mathbb{R}^{3}}\nabla _{y}^{s}h_{1} \cdot \bigl(\nabla _{y}^{s}h_{i} \partial _{y_{i}}w_{1}+w_{i}\partial _{y_{i}} \nabla _{y}^{s}h_{1} \bigr)\,dy \\ &\qquad{} - \bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau } \int _{\mathbb{R}^{3}} \nabla _{y}^{s}h_{1} \cdot \nabla _{y}^{s}(\Gamma \partial _{y_{1}} \Phi )\,dy \\ &\quad = \int _{\mathbb{R}^{3}}\nabla _{y}^{s}h_{1} \cdot \tilde{g}_{1}\,dy, \end{aligned}$$
(2.42)
$$\begin{aligned} &\frac{1}{2} \frac{d}{d\tau } \bigl\Vert \nabla _{y}^{s}h_{2} \bigr\Vert _{\mathbb{L}^{2}}^{2}+ \nu \sum _{i,j=1}^{3} \bigl\Vert \partial _{y_{i}} \nabla _{y}^{s}h_{j} \bigr\Vert ^{2}_{ \mathbb{L}^{2}}+\biggl(a+\frac{3}{4}- \frac{s}{2}\biggr) \bigl\Vert \nabla _{y}^{s}h_{2} \bigr\Vert ^{2}_{ \mathbb{L}^{2}} \\ &\qquad{} -k\bigl(T^{*} \bigr)^{2a+1}e^{-(2a+1)\tau } \int _{\Omega }\nabla _{y}^{s}h_{1} \cdot \nabla _{y}^{s}h_{2}\,dy \\ &\qquad +\bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau }\sum _{i=1}^{3} \int _{\Omega }\nabla _{y}^{s}h_{2} \cdot \bigl(\nabla _{y}^{s}h_{i} \partial _{y_{i}}w_{2}+w_{i}\partial _{y_{i}} \nabla _{y}^{s}h_{2} \bigr)\,dy \\ &\qquad{} - \bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau } \int _{\Omega }\nabla _{y}^{s}h_{2} \cdot \nabla _{y}^{s}(\Gamma \partial _{y_{2}} \Phi )\,dy \\ &\quad = \int _{\Omega }\nabla _{y}^{s}h_{2} \cdot \tilde{g}_{2}\,dy, \end{aligned}$$
(2.43)
and
$$ \begin{aligned}[b] &\frac{1}{2} \frac{d}{d\tau } \bigl\Vert \nabla _{y}^{s}h_{3} \bigr\Vert _{\mathbb{L}^{2}}^{2}+ \nu \sum _{i,j=1}^{3} \bigl\Vert \partial _{y_{i}} \nabla _{y}^{s}h_{j} \bigr\Vert ^{2}_{ \mathbb{L}^{2}}+\biggl(\frac{3}{4}-2a- \frac{s}{2}\biggr) \bigl\Vert \nabla _{y}^{s}h_{3} \bigr\Vert ^{2}_{ \mathbb{L}^{2}} \\ &\qquad{} +\bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau }\sum _{i=1}^{3} \int _{ \Omega }\nabla _{y}^{s}h_{3} \cdot \bigl(\nabla _{y}^{s}h_{i}\partial _{y_{i}}w_{3}+w_{i} \partial _{y_{i}} \nabla _{y}^{s}h_{3} \bigr)\,dy \\ &\qquad{} - \bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1 }{2}\tau } \int _{\Omega }\nabla _{y}^{s}h_{3} \cdot \nabla _{y}^{s}( \Gamma \partial _{y_{3}} \Phi )\,dy = \int _{\Omega }\nabla _{y}^{s}h_{3} \cdot \tilde{g}_{3}\,dy. \end{aligned} $$
(2.44)
Summing up (2.42)–(2.44), we have
$$\begin{aligned} &\frac{1}{2}\sum _{i=1}^{3}\frac{d}{d\tau } \bigl( \bigl\Vert \nabla _{y}^{s}\Gamma \bigr\Vert _{\mathbb{L}^{2}}^{2}+ \bigl\Vert \nabla _{y}^{s} \Lambda \bigr\Vert ^{2}_{\mathbb{L}^{2}}+ \bigl\Vert \nabla _{y}^{s}h_{i} \bigr\Vert _{\mathbb{L}^{2}}^{2} \bigr) + \bigl\Vert \nabla _{y}^{s+1} \Gamma \bigr\Vert ^{2}_{\mathbb{L}^{2}}+ \bigl\Vert \nabla _{y}^{s+1}\Lambda \bigr\Vert ^{2}_{ \mathbb{L}^{2}} \\ &\qquad{} +3\nu \sum_{i,j=1}^{3} \bigl\Vert \partial _{y_{i}} \nabla _{y}^{s}h_{j} \bigr\Vert ^{2}_{\mathbb{L}^{2}} + \biggl(\frac{3}{4}-\frac{s}{2}-T^{*}e^{-\tau } \sigma +2s\kappa \bigl(T^{*}\bigr)^{2a+1}e^{-(2a+1) \tau } \biggr) \bigl\Vert \nabla _{y}^{s}\Gamma \bigr\Vert ^{2}_{\mathbb{L}^{2}} \\ &\qquad{}+2\mu T^{*}e^{- \tau } \int _{\mathbb{R}^{3}}n \vert \nabla _{y}\Gamma \vert ^{2}\,dy \\ &\qquad{}+ \biggl(\frac{3}{4}-\frac{s}{2}+T^{*}e^{-\tau }+2s \kappa \bigl(T^{*}\bigr)^{2a+1}e^{-(2a+1) \tau } \biggr) \bigl\Vert \nabla _{y}^{s}\Lambda \bigr\Vert ^{2}_{\mathbb{L}^{2}} \\ &\qquad{} +\biggl(a+\frac{3 }{4}- \frac{s}{2}\biggr) \bigl( \bigl\Vert \nabla _{y}^{s}h_{1} \bigr\Vert ^{2}_{\mathbb{L}^{2}}+ \bigl\Vert \nabla _{y}^{s}h_{2} \bigr\Vert ^{2}_{\mathbb{L}^{2}} \bigr) +\biggl(\frac{3}{4}-2a-\frac{s}{2}\biggr) \bigl\Vert \nabla _{y}^{s}h_{3} \bigr\Vert ^{2}_{ \mathbb{L}^{2}} \\ &\qquad{} +\bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau } \int _{ \mathbb{R}^{3}}\nabla _{y}^{s}(\textbf{h} \cdot \nabla _{y} n)\cdot \nabla _{y}^{s} \Gamma \,dy+\chi \sum_{i=1}^{3} \int _{\mathbb{R}^{3}} \partial _{y_{i}}\nabla ^{s}_{y}(\Gamma \partial _{y_{i}}c)\cdot \nabla _{y}^{s}\Gamma \,dy \\ &\qquad{}+\chi \int _{\mathbb{R}^{3}}\nabla _{y}^{s} \bigl( \nabla _{y} \cdot (n\nabla _{y}\Lambda ) \bigr)\cdot \nabla _{y}^{s}\Gamma \,dy \\ &\qquad{}+\bigl(T^{*} \bigr)^{\frac{1 }{2}}e^{-\frac{1}{2}\tau } \int _{\mathbb{R}^{3}} \Biggl(\sum_{i=1}^{2} \nabla _{y}^{s}(h_{i}\partial _{y_{i}}d_{i})-\nabla _{y}^{s} \Gamma \Biggr)\cdot \nabla _{y}^{s}\Lambda \,dy \\ &\qquad{} +\bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau }\sum _{i=1}^{3} \int _{ \mathbb{R}^{3}} \bigl[\nabla _{y}^{s}h_{1} \cdot \bigl(\nabla _{y}^{s}h_{i} \partial _{y_{i}}w_{1}+w_{i}\partial _{y_{i}} \nabla _{y}^{s}h_{1} \bigr) \\ &\qquad{}+\nabla _{y}^{s}h_{2}\cdot \bigl(\nabla _{y}^{s}h_{i}\partial _{y_{i}}w_{2}+w_{i} \partial _{y_{i}}\nabla _{y}^{s}h_{2} \bigr) +\nabla _{y}^{s}h_{3}\cdot \bigl( \nabla _{y}^{s}h_{i}\partial _{y_{i}}w_{3}+w_{i} \partial _{y_{i}} \nabla _{y}^{s}h_{3} \bigr)\,dy \bigr] \\ &\qquad{}- \bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1 }{2}\tau }\sum _{i=1}^{3} \int _{\mathbb{R}^{3}}\nabla _{y}^{s}h_{i} \cdot \nabla _{y}^{s}(\Gamma \partial _{y_{i}} \Phi )\,dy \\ &\quad =T^{*}e^{-\tau } \int _{\mathbb{R}^{3}} \bigl(\nabla ^{s}_{y}f_{1} \cdot \nabla _{y}^{s}\Gamma +\nabla ^{s}_{y}f_{2} \cdot \nabla _{y}^{s} \Lambda \bigr) \,dy+\sum _{i=1}^{3} \int _{\mathbb{R}^{3}} \bigl(\nabla _{y}^{s}h_{i} \cdot \tilde{g}_{i} \bigr)\,dy. \end{aligned}$$
(2.45)
We now estimate each nonlinear term in (2.45). On the one hand, note that \((n,c,\textbf{v} )^{T}\in \mathcal{B}_{R}\). We employ Young’s inequality, \(H^{\frac{5}{2}}(\mathbb{R}^{3})\subset L^{\infty }(\mathbb{R}^{3})\) and integrating by parts to derive
$$ \begin{aligned} & \biggl\vert 2\mu T^{*}e^{-\tau } \int _{\mathbb{R}^{3}}n|\nabla _{y}\Gamma| ^{2}\,dy \biggr|\lesssim C_{R} \Vert \nabla _{y} \Gamma \Vert ^{2}_{\mathbb{L}^{2}}, \\ &\biggl|\bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau } \int _{\mathbb{R}^{3}} \nabla _{y}^{s}( \textbf{h}\cdot \nabla _{y} n)\cdot \nabla _{y}^{s} \Gamma \,dy\biggr|\\ &\quad \lesssim C_{R} \Biggl( \bigl\Vert \nabla _{y}^{s}\Gamma \bigr\Vert _{ \mathbb{L}^{2}}^{2}+ \sum_{i=1}^{3}\bigl( \Vert h_{i} \Vert _{\mathbb{L}^{2}}^{2}+ \bigl\Vert \nabla _{y}^{s}h_{i} \bigr\Vert _{\mathbb{L}^{2}}^{2}\bigr) \Biggr), \\ &\biggl|\chi \sum_{i=1}^{3} \int _{\mathbb{R}^{3}}\partial _{y_{i}} \nabla ^{s}_{y}(\Gamma \partial _{y_{i}}c)\cdot \nabla _{y}^{s} \Gamma \,dy\biggr|\lesssim C_{R} \bigl( \bigl\Vert \nabla _{y}^{s+1}\Gamma \bigr\Vert _{ \mathbb{L}^{2}}^{2}+ \bigl\Vert \nabla _{y}^{s} \Gamma \bigr\Vert _{\mathbb{L}^{2}}^{2} \bigr), \\ &\biggl|\chi \int _{\mathbb{R}^{3}}\nabla _{y}^{s} \bigl( \nabla _{y}\cdot (n \nabla _{y}\Lambda ) \bigr)\cdot \nabla _{y}^{s}\Gamma \,dy\biggr|\\ &\quad \lesssim C_{R} \bigl( \bigl\Vert \nabla _{y}^{s+1}\Gamma \bigr\Vert _{\mathbb{L}^{2}}^{2}+ \bigl\Vert \nabla _{y}^{s+1} \Lambda \bigr\Vert _{\mathbb{L}^{2}}^{2}+ \bigl\Vert \nabla _{y}^{s}\Gamma \bigr\Vert _{\mathbb{L}^{2}}^{2}+ \bigl\Vert \nabla _{y}^{s}\Lambda \bigr\Vert _{\mathbb{L}^{2}}^{2} \bigr), \\ &\Biggl|\bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau } \int _{\mathbb{R}^{3}} \Biggl( \sum_{i=1}^{2} \nabla _{y}^{s}(h_{i}\partial _{y_{i}}d_{i})-\nabla _{y}^{s} \Gamma \Biggr)\cdot \nabla _{y}^{s}\Lambda \,dy\Biggr| \\ &\quad \lesssim \frac{(T^{*})^{\frac{1 }{2}}}{2}e^{-\frac{1}{2}\tau } \bigl(2 \bigl\Vert \nabla _{y}^{s}\Lambda \bigr\Vert _{ \mathbb{L}^{2}}^{2}+ \bigl\Vert \nabla _{y}^{s}\Gamma \bigr\Vert _{\mathbb{L}^{2}}^{2} \bigr) +C_{R}\sum_{i=1}^{2} \bigl( \Vert h_{i} \Vert _{\mathbb{L}^{2}}^{2}+ \bigl\Vert \nabla _{y}^{s}h_{i} \bigr\Vert _{\mathbb{L}^{2}}^{2}\bigr), \end{aligned} $$
(2.46)
and
$$\begin{aligned} & \Biggl\vert \sum _{i=1}^{3} \int _{\mathbb{R}^{3}}\nabla _{y}^{s}h_{1} \cdot \bigl(\nabla _{y}^{s}h_{i}\partial _{y_{i}}w_{1}+w_{i}\partial _{y_{i}} \nabla _{y}^{s}h_{1} \bigr)\,dy \Biggr\vert \\ &\quad \lesssim \Biggl(\sum_{k=1}^{3} \bigl( \Vert \partial _{y_{i}}w_{1} \Vert _{ \mathbb{L}^{\infty }}+ \Vert w_{i} \Vert _{\mathbb{L}^{\infty }}\bigr) \Biggr)\sum_{i=1}^{3} \int _{\mathbb{R}^{3}}\bigl( \bigl\vert \nabla _{y}^{s}h_{i} \bigr\vert ^{2}+ \bigl\vert \partial _{y_{i}} \nabla _{y}^{s}h_{1} \bigr\vert ^{2} \bigr)\,dy \\ &\quad \lesssim C_{R}\sum_{i=1}^{3} \int _{\mathbb{R}^{3}}\bigl( \bigl\vert \nabla _{y}^{s}h_{i} \bigr\vert ^{2}+ \bigl\vert \partial _{y_{i}}\nabla _{y}^{s}h_{1} \bigr\vert ^{2} \bigr)\,dy, \end{aligned}$$
(2.47)
$$\begin{aligned} & \Biggl\vert \sum _{i=1}^{3} \int _{\mathbb{R}^{3}}\nabla _{y}^{s}h_{2} \cdot \bigl(\nabla _{y}^{s}h_{i}\partial _{y_{i}}w_{2}+w_{i}\partial _{y_{i}} \nabla _{y}^{s}h_{2} \bigr)\,dy \Biggr\vert \\ &\quad \lesssim \Biggl(\sum_{i=1}^{3} \bigl( \Vert \partial _{y_{i}}w_{2} \Vert _{ \mathbb{L}^{\infty }}+ \Vert w_{i} \Vert _{\mathbb{L}^{\infty }}\bigr) \Biggr)\sum_{i=1}^{3} \int _{\mathbb{R}^{3}}\bigl( \bigl\vert \nabla ^{s}_{y}h_{i} \bigr\vert ^{2}+ \bigl\vert \partial _{y_{i}} \nabla ^{s}_{y}h_{2} \bigr\vert ^{2} \bigr)\,dy \\ &\quad \lesssim C_{R}\sum_{k=1}^{3} \int _{\mathbb{R}^{3}}\bigl( \bigl\vert \nabla ^{s}_{y}h_{i} \bigr\vert ^{2}+ \bigl\vert \partial _{y_{i}}\nabla ^{s}_{y}h_{2} \bigr\vert ^{2} \bigr)\,dy, \end{aligned}$$
(2.48)
$$\begin{aligned} & \Biggl\vert \sum _{i=1}^{3} \int _{\mathbb{R}^{3}}\nabla _{y}^{s}h_{3} \cdot \bigl(\nabla _{y}^{s}h_{i}\partial _{y_{i}}w_{3}+w_{i}\partial _{y_{i}} \nabla _{y}^{s}h_{3} \bigr)\,dy \Biggr\vert \\ &\quad \lesssim \Biggl(\sum_{i=1}^{3} \bigl( \Vert \partial _{y_{i}}w_{3} \Vert _{ \mathbb{L}^{\infty }}+ \Vert w_{i} \Vert _{\mathbb{L}^{\infty }}\bigr) \Biggr) \\ &\qquad {}\times\sum_{i=1}^{3} \int _{\mathbb{R}^{3}}\bigl( \bigl\vert \nabla _{y}^{s}h_{i} \bigr\vert ^{2}+ \bigl\vert \partial _{y_{i}} \nabla _{y}^{s}h_{3} \bigr\vert ^{2} \bigr)\,dy \\ &\quad \lesssim C_{R}\sum_{i=1}^{3} \int _{\mathbb{R}^{3}}\bigl( \bigl\vert \nabla _{y}^{s}h_{i} \bigr\vert ^{2}+ \bigl\vert \partial _{y_{i}}\nabla _{y}^{s}h_{3} \bigr\vert ^{2} \bigr)\,dy, \end{aligned}$$
(2.49)
$$\begin{aligned} &\Biggl\vert \bigl(T^{*} \bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau }\sum_{i=1}^{3} \int _{ \mathbb{R}^{3}}\nabla _{y}^{s}h_{i} \cdot \nabla _{y}^{s}(\Gamma \partial _{y_{i}} \Phi )\,dy \Biggr\vert \\ &\quad \lesssim C_{R} \Biggl( \bigl\Vert \nabla _{y}^{s} \Gamma \bigr\Vert _{\mathbb{L}^{2}}^{2}+ \sum_{i=1}^{3} \bigl\Vert \nabla _{y}^{s}h_{i} \bigr\Vert _{\mathbb{L}^{2}}^{2} \Biggr), \end{aligned}$$
(2.50)
where the \(C_{R}\) are a positive constants depending on R, which are small constants as R is small.
On the other hand, by (2.18), we know the highest order derivatives on \(h_{i}\) of \(\partial _{y_{1}}\nabla _{y}^{s}\overline{f}\) is s. So we can use the standard Calderon–Zygmund theory, Young’s inequality and integrating by parts to derive
$$ \Biggl\vert \sum_{i=1}^{3} \int _{\mathbb{R}^{3}}\nabla _{y}^{s}h_{i} \cdot \partial _{y_{i}}\nabla _{y}^{s} \overline{f}\,dy \Biggr\vert \lesssim C_{R} \Biggl(\sum _{i=1}^{3} \bigl\Vert \nabla ^{s}_{y}h_{i} \bigr\Vert ^{2}_{\mathbb{L}^{2}}+ \bigl\Vert \nabla _{y}^{s} \Gamma \bigr\Vert _{\mathbb{L}^{2}}^{2} \Biggr), $$
(2.51)
furthermore, by (2.37)–(2.39), we have
$$ \begin{aligned} & \biggl\vert T^{*}e^{-\tau } \int _{\mathbb{R}^{3}} \bigl(\nabla ^{s}_{y}f_{1} \cdot \nabla _{y}^{s}\Gamma +\nabla ^{s}_{y}f_{2} \cdot \nabla _{y}^{s} \Lambda \bigr) \biggr\vert \\ &\quad \lesssim \frac{1}{2} \Biggl(\sum_{i=1}^{2} \bigl\Vert \nabla _{y}^{s}f_{i} \bigr\Vert _{\mathbb{L}^{2}}^{2}+ \bigl\Vert \nabla _{y}^{s}\Gamma \bigr\Vert _{\mathbb{L}^{2}}^{2}+ \bigl\Vert \nabla _{y}^{s}\Lambda \bigr\Vert _{\mathbb{L}^{2}}^{2} \Biggr), \\ & \Biggl\vert \sum_{i=1}^{3} \int _{\mathbb{R}^{3}} \bigl(\nabla _{y}^{s}h_{i} \cdot \tilde{g}_{i} \bigr)\,dy \Biggr\vert \\ &\quad \lesssim \biggl(C_{R,T^{*}}+\frac{1}{2}\biggr)\sum _{i=1}^{3} \bigl( \bigl\Vert \nabla ^{s}_{y}h_{i} \bigr\Vert ^{2}_{\mathbb{L}^{2}}+ \bigl\Vert \nabla _{y}^{s} \Gamma \bigr\Vert _{\mathbb{L}^{2}}^{2} \bigr) +4\sum _{i=1}^{3} \bigl\Vert \nabla _{y}^{s}g_{i} \bigr\Vert _{\mathbb{L}^{2}}^{2}, \end{aligned} $$
(2.52)
where \(C_{R,T^{*}}\) is a positive constant depending on R, \(T^{*}\), which is a small constant as R small.
Hence we can apply estimates (2.46)–(2.52) to (2.45), then
$$\begin{aligned} &\frac{1}{2}\sum _{i=1}^{3}\frac{d}{d\tau } \bigl( \bigl\Vert \nabla _{y}^{s}\Gamma \bigr\Vert _{\mathbb{L}^{2}}^{2}+ \bigl\Vert \nabla _{y}^{s} \Lambda \bigr\Vert _{\mathbb{L}^{2}}^{2}+ \bigl\Vert \nabla _{y}^{s}h_{i} \bigr\Vert _{\mathbb{L}^{2}}^{2} \bigr) \\ &\qquad {} +(1-C_{R}) \bigl\Vert \nabla _{y}^{s+1} \Gamma \bigr\Vert ^{2}_{\mathbb{L}^{2}}+(1-C_{R}) \bigl\Vert \nabla _{y}^{s+1}\Lambda \bigr\Vert ^{2}_{ \mathbb{L}^{2}}+(3\nu -C_{R})\sum_{i,j=1}^{3} \bigl\Vert \partial _{y_{i}} \nabla _{y}^{s}h_{j} \bigr\Vert ^{2}_{\mathbb{L}^{2}} \\ &\qquad{} + \biggl(\frac{3}{4}- \frac{s}{2}-T^{*}e^{-\tau }(b+ \sigma )- \frac{(T^{*})^{\frac{1}{2}}}{2}e^{-\frac{1}{2}\tau }-C_{R} \biggr) \Vert \Gamma \Vert ^{2}_{\mathbb{L}^{2}} \\ &\qquad{} + \biggl(\frac{3}{4}-\frac{s}{2}+T^{*}e^{-\tau }(1-b)- \bigl(T^{*}\bigr)^{\frac{1 }{2}}e^{-\frac{1}{2}\tau }-C_{R} \biggr) \Vert \Lambda \Vert ^{2}_{\mathbb{L}^{2}} \\ &\qquad{} + \biggl(a+\frac{3}{4}-\frac{s}{2}-T^{*}e^{-\tau }b-C_{R} \biggr) \bigl( \bigl\Vert \nabla _{y}^{s}h_{1} \bigr\Vert ^{2}_{\mathbb{L}^{2}}+ \bigl\Vert \nabla _{y}^{s}h_{2} \bigr\Vert ^{2}_{ \mathbb{L}^{2}} \bigr) \\ &\qquad{} + \biggl(\frac{3}{4}- \frac{s}{2}-2a-T^{*}e^{-\tau }b-C_{R} \biggr) \bigl\Vert \nabla _{y}^{s}h_{3} \bigr\Vert ^{2}_{\mathbb{L}^{2}} \\ &\quad \lesssim \frac{1}{2} \bigl( \Vert f_{1} \Vert _{\mathbb{L}^{2}}^{2}+ \Vert f_{2} \Vert _{ \mathbb{L}^{2}}^{2} \bigr)+4\sum_{i=1}^{3} \bigl\Vert \nabla _{y}^{s}g_{i} \bigr\Vert ^{2}_{ \mathbb{L}^{2}}. \end{aligned}$$
(2.53)
Since \(0< a\ll \frac{1}{8}\) and \(0< s<\frac{3}{2}-5a\) are constants, there exists a sufficient small positive constant R such that
$$ \begin{aligned} &1-C_{R}>0,\qquad 1-C_{R}>0, \qquad 3\nu -C_{R}>0, \\ &\frac{3}{4}-\frac{s}{2}-T^{*}e^{-\tau }(b+ \sigma )-\frac{(T^{*})^{\frac{1}{2}} }{2}e^{-\frac{1}{2}\tau }-C_{R}>0, \\ &\frac{3}{4}-\frac{s}{2}+T^{*}e^{-\tau }(1-b)- \bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1 }{2}\tau }-C_{R}>0, \\ &a+\frac{3}{4}-\frac{s}{2}-T^{*}e^{-\tau }b-C_{R}>0, \\ &\frac{3}{4}-\frac{s}{2}-2a-T^{*}e^{-\tau }b-C_{R}>0. \end{aligned} $$
Hence, applying Gronwall’s inequality to (2.53), there exists a positive constant \(C_{R,T^{*}}\) depending on R and \(T^{*}\) such that
$$ \begin{aligned} &\sum_{i=1}^{3} \bigl( \bigl\Vert \nabla _{y}^{s}\Gamma \bigr\Vert _{\mathbb{L}^{2}}^{2}+ \bigl\Vert \nabla _{y}^{s} \Lambda \bigr\Vert _{\mathbb{L}^{2}}^{2}+ \bigl\Vert \nabla _{y}^{s}h_{i} \bigr\Vert _{\mathbb{L}^{2}}^{2} \bigr)\\ &\quad \lesssim e^{-C_{R,T^{*}}\tau } \sum _{i=1}^{3} \bigl( \bigl\Vert \nabla _{y}^{s}\Gamma _{0} \bigr\Vert _{\mathbb{L}^{2}}^{2}+ \bigl\Vert \nabla _{y}^{s} \Lambda _{0} \bigr\Vert _{\mathbb{L}^{2}}^{2}+ \bigl\Vert \nabla _{y}^{s}h_{0i} \bigr\Vert _{ \mathbb{L}^{2}}^{2} \bigr) \\ &\qquad{} +e^{-C_{R,T^{*}}\tau } \int _{0}^{+\infty } \Biggl( \Vert f_{1} \Vert _{ \mathbb{L}^{2}}^{2}+ \Vert f_{2} \Vert _{\mathbb{L}^{2}}^{2}+\sum _{i=1}^{3} \bigl\Vert \nabla _{y}^{s}g_{i} \bigr\Vert ^{2}_{\mathbb{L}^{2}} \Biggr)d\tau ,\quad \forall \tau >0. \end{aligned} $$
□
Furthermore, we have the following result.
Lemma 2.3
Let \(0< a\ll \frac{1}{8}\) and \(0< s<\frac{3}{2}-5a\) be constants. Assume that \(\|\Phi \|_{\mathbb{H}^{s+5}(\mathbb{R}^{3})}\lesssim R\ll 1\), \(f_{i}\in \mathbb{C}^{1}((0,+\infty ),\mathbb{H}^{s}(\mathbb{R}^{3}))\) \((i=1,2)\), \(\textbf{g}\in \mathbb{C}^{1}((0,+\infty ),H^{s}(\mathbb{R}^{3}))\) and \((n,c,\textbf{v} )^{T}\in \mathcal{B}_{R}\). Then, for any \(\tau >0\), the solution \((\Gamma ,\Lambda ,\textbf{h} )^{T}\) of the linearized coupled system (2.13)–(2.17) with the initial data (2.19) and condition (2.20) satisfies
$$ \begin{aligned} & \int _{\mathbb{R}^{3}} \Biggl( \bigl\vert \nabla _{y}^{s} \partial _{\tau }\Gamma \bigr\vert ^{2}+ \bigl\vert \nabla _{y}^{s}\partial _{\tau }\Lambda \bigr\vert ^{2}+\sum_{i=1}^{3} \bigl\vert \nabla _{y}^{s} \partial _{\tau }h_{i} \bigr\vert ^{2} \Biggr)\,dy \\ &\quad \lesssim e^{-C_{a,R,\kappa ,\nu ,\mu ,\delta }\tau } \int _{ \mathbb{R}^{3}} \Biggl( \bigl\vert \nabla _{y}^{s} \partial _{\tau }\Gamma _{0} \bigr\vert ^{2}+ \bigl\vert \nabla _{y}^{s}\partial _{\tau } \Lambda _{0} \bigr\vert ^{2}+\sum _{i=1}^{3} \bigl\vert \nabla _{y}^{s}\partial _{\tau }h_{0i} \bigr\vert ^{2} \Biggr)\,dy \\ &\qquad{} +e^{-C_{a,R,\kappa ,\nu ,\mu ,\delta }\tau } \int _{0}^{+ \infty } \Biggl( \bigl\Vert \nabla _{y}^{s}\partial _{\tau }f_{1} \bigr\Vert _{\mathbb{L}^{2}}^{2}+ \bigl\Vert \nabla _{y}^{s}\partial _{\tau }f_{2} \bigr\Vert _{\mathbb{L}^{2}}^{2}+\sum_{i=1}^{3} \bigl\Vert \nabla _{y}^{s}\partial _{\tau }g_{i} \bigr\Vert ^{2}_{\mathbb{L}^{2}} \Biggr)d \tau , \quad \forall \tau >0, \end{aligned} $$
where \(C_{a,R,\kappa ,\nu ,\mu ,\delta }\) is a positive constant depending on the constants a, R, κ, ν, μ, δ.
Proof
Similar to getting the estimate in Lemma 2.2, we apply the operator \(\partial _{\tau }\nabla _{y}^{s}\) to both sides of (2.8)–(2.10), then using a similar process to the proof of Lemma 2.2, we can obtain this result. □
Proposition 2.1
Let \(0< a\ll \frac{1}{8}\) and \(0< s<\frac{3}{2}-5a\) be constants. Assume that \(\|\Phi \|_{\mathbb{H}^{s+5}(\mathbb{R}^{3})}\lesssim R\ll 1\), \(f_{i}\in \mathbb{C}^{1}((0,+\infty ),\mathbb{H}^{s}(\mathbb{R}^{3}))\) \((i=1,2)\), \(\textbf{g}\in \mathbb{C}^{1}((0,+\infty ),H^{s}(\mathbb{R}^{3}))\) and \((n,c,\textbf{v} )^{T}\in \mathcal{B}_{R}\). Then, for any \(\tau >0\), the linearized coupled system (2.13)–(2.17) with the initial data (2.19) and condition (2.20) admits a solution
$$ \begin{aligned} &\Gamma \in \mathcal{C}_{0}^{s}:= \bigcap_{i= 0}^{1}\mathbb{C}^{i} \bigl((0,+ \infty );\mathbb{H}^{s-i}\bigr), \\ &\Lambda \in \mathcal{C}_{0}^{s}:=\bigcap _{i= 0}^{1}\mathbb{C}^{i}\bigl((0,+ \infty );\mathbb{H}^{s-i}\bigr), \\ &\textbf{h}\in \overline{\mathcal{C}}_{0}^{s}:=\bigcap _{i= 0}^{1} \mathbb{C}^{i} \bigl((0,+\infty );H^{s-i}\bigr). \end{aligned} $$
Moreover,
$$\begin{aligned}& \Vert \Gamma \Vert _{\mathcal{C}_{0}^{s}}^{2}+ \Vert \Lambda \Vert _{\mathcal{C}^{s}_{0}}^{2}+ \Vert \textbf{h} \Vert ^{2}_{\overline{\mathcal{C}}_{0}^{s}} \lesssim \Vert \Gamma _{0} \Vert _{\mathcal{C}_{0}^{s}}^{2}+ \Vert \Lambda _{0} \Vert _{\mathcal{C}_{0}}^{2}+ \Vert \textbf{h}_{0} \Vert ^{2}_{\overline{\mathcal{C}}_{0}^{s}}+ \Vert f_{1} \Vert ^{2}_{ \mathcal{C}_{0}^{s}}+ \Vert f_{2} \Vert ^{2}_{\mathcal{C}_{0}^{s}} + \Vert \textbf{g} \Vert ^{2}_{ \overline{\mathcal{C}}_{0}^{s}}, \\& \quad \forall \tau >0. \end{aligned}$$
(2.54)
Proof
Let \(\mathbb{P}\) be the Leray projector onto the space of divergence free functions. We apply the Leray projector to system (2.5), we have
$$ \textstyle\begin{cases} \Gamma _{t}-\triangle \Gamma +(2\mu n-\sigma )\Gamma +(\textbf{v}+ \overline{\textbf{u}})\cdot \nabla \Gamma +\textbf{h}\cdot \nabla n+ \chi \nabla \cdot [\Gamma \nabla c+n\nabla \Lambda ]=f_{1}(t,x), \\ \Lambda _{t}-\triangle \Lambda +\Lambda +(\textbf{v}+ \overline{\textbf{u}})\cdot \nabla \Lambda +\textbf{h}\cdot \nabla c- \Gamma =f_{2}(t,x), \\ \textbf{h}_{t}-\nu \mathbb{P}\triangle \textbf{h}+\mathbb{P} ( \textbf{h}\cdot \nabla (\overline{\textbf{u}}+\textbf{v})+( \overline{\textbf{u}}+\textbf{v})\cdot \nabla \textbf{h} -\Gamma \nabla \Phi )=\mathbb{P}\textbf{g}(t,x). \end{cases} $$
(2.55)
In the similarity coordinates (2.12), we can rewrite the linear system (2.55) as
$$ \partial _{\tau }U+ (\mathcal{A}+\mathcal{N} )U=T^{*}e^{-\tau }F, $$
where \(U:= (\Gamma ,\Lambda ,h_{1},h_{2},h_{3} )^{T}\), \(\mathcal{N}(U):= (\mathbb{M}_{1},\mathbb{M}_{2},\mathbb{N}_{1}, \mathbb{N}_{2},\mathbb{N}_{3} )^{T}\), \(F:= (f_{1},f_{2},\mathbb{P}g_{1},\mathbb{P}g_{2},\mathbb{P}g_{3} )^{T}\) and the matrix operator is given by
$$ \mathcal{A}:=\begin{pmatrix} -\mu \triangle _{y}&0&0&0&0 \\ 0&-\delta \triangle _{y}&0&0&0 \\ 0&0&-\nu \mathbb{P}\triangle _{y}&0&0 \\ 0&0&0&-\nu \mathbb{P}\triangle _{y}&0 \\ 0&0&0&0&-\nu \mathbb{P}\triangle _{y} \end{pmatrix}_{5\times 5}, $$
and
$$\begin{aligned}& \begin{aligned} \mathbb{M}_{1}(\Gamma ,\Lambda , \textbf{h}):={}&{-}\triangle _{y}\Gamma -\frac{y }{2}\cdot \nabla _{y}\Gamma +T^{*}e^{-\tau }(2\mu n-\sigma ) \Gamma +ay_{1}\partial _{y_{1}}\Gamma +ay_{2} \partial _{y_{2}}\Gamma \\ &{}-2ay_{3} \partial _{y_{3}} \Gamma +k\bigl(T^{*}\bigr)^{2a+1}e^{-(2a+1)\tau } (y_{2}\partial _{y_{1}} \Gamma +y_{1}\partial _{y_{2}}\Gamma )\\ &{}+\bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1 }{2}\tau } \textbf{h}\cdot \nabla _{y} n+\chi \sum_{i=1}^{3} \partial _{y_{i}}(\Gamma \partial _{y_{i}}c) +\chi \nabla _{y}\cdot (n\nabla _{y}\Lambda ), \end{aligned} \\& \begin{aligned} \mathbb{M}_{2}(\Gamma ,\Lambda ,\textbf{h}):={}&{-}\frac{y}{2} \cdot \nabla _{y} \Lambda +T^{*}e^{-\tau }\Lambda +ay_{1}\partial _{y_{1}}\Lambda +ay_{2} \partial _{y_{2}}\Lambda -2ay_{3}\partial _{y_{3}} \Lambda \\ &{} +k\bigl(T^{*}\bigr)^{2a+1}e^{-(2a+1)\tau } (y_{2}\partial _{y_{1}} \Lambda +y_{1}\partial _{y_{2}}\Lambda ) +\bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1 }{2}\tau } \Biggl(\sum_{i=1}^{2}h_{i} \partial _{y_{i}}c_{i}-\Gamma \Biggr), \end{aligned} \\& \begin{aligned} \mathbb{N}_{1}(\Gamma ,\Lambda , \textbf{h}):={}&{-}\frac{y}{2}\cdot \nabla _{y}h_{1}+ah_{1}+ay_{1} \partial _{y_{1}}h_{1}+ay_{2}\partial _{y_{2}}h_{1}-2ay_{3}\partial _{y_{3}}h_{1} \\ &{} +k\bigl(T^{*}\bigr)^{2a+1}e^{-(2a+1)\tau } (h_{2}+y_{2}\partial _{y_{1}}h_{1}+y_{1} \partial _{y_{2}}h_{1} )-\bigl(T^{*} \bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau } \Gamma \partial _{y_{1}}\Phi \\ &{} +\bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau }\sum _{i=1}^{3} (h_{i} \partial _{y_{i}}w_{1}+w_{i}\partial _{y_{i}}h_{1} ), \end{aligned} \\& \begin{aligned} \mathbb{N}_{2}(\Gamma ,\Lambda ,\textbf{h}):={}&{-}\frac{y}{2} \cdot \nabla _{y}h_{2}+ah_{2}+ay_{1} \partial _{y_{1}}h_{2}+ay_{2}\partial _{y_{2}}h_{2}-2ay_{3}\partial _{y_{3}}h_{2} \\ &{} +k\bigl(T^{*}\bigr)^{2a+1}e^{-(2a+1)\tau } (-h_{1}+y_{2}\partial _{y_{1}}h_{2}-y_{1} \partial _{y_{2}}h_{2} )-\bigl(T^{*} \bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau } \Gamma \partial _{y_{2}}\Phi \\ &{} +\bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau }\sum _{i=1}^{3} (h_{i} \partial _{y_{i}}w_{2}+w_{i}\partial _{y_{i}}h_{2} ), \end{aligned} \\& \begin{aligned} \mathbb{N}_{3}(\Gamma ,\Lambda ,\textbf{h}):={}&{-}\frac{y}{2} \cdot \nabla _{y}h_{3}-ah_{3}+ay_{1} \partial _{y_{1}}h_{3}+ay_{2}\partial _{y_{2}}h_{3}-2ay_{3}\partial _{y_{3}}h_{3} \\ &{} +k\bigl(T^{*}\bigr)^{2a+1}e^{-(2a+1)\tau } (y_{2}\partial _{y_{1}}h_{3}-y_{1} \partial _{y_{2}}h_{3} )-\bigl(T^{*} \bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau } \Gamma \partial _{y_{3}}\Phi \\ &{} +\bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1}{2}\tau }\sum _{i=1}^{3} (h_{i} \partial _{y_{i}}w_{3}+w_{i}\partial _{y_{i}}h_{3} ). \end{aligned} \end{aligned}$$
Obviously, there is no singular coefficient in the linear operator \(\mathcal{A}+\mathcal{N}\) by noticing (2.55). We follow the idea of [38] to show the linear operator \(\mathcal{A}+\mathcal{N}\) generate a strongly continuous semigroup \(e^{(\mathcal{A}+\mathcal{N})\tau }\) in Sobolev space \(\mathbb{H}^{s}(\mathbb{R}^{3})\times \mathbb{H}^{s}(\mathbb{R}^{3}) \times H^{s}(\mathbb{R}^{3})\). To see this, by the same process as getting (2.53), for the constants \(0< a\ll \frac{1}{8}\) and \(0< s<\frac{3}{2}-5a\), we can obtain
$$ \begin{aligned}[b] & \int _{\Omega }\nabla ^{s}_{y}U\cdot \nabla ^{s}_{y} \bigl((\mathcal{A}+ \mathcal{N})U \bigr)\,dy \\ &\quad \lesssim - \biggl(\frac{3}{4}-\frac{s}{2}-T^{*}e^{-\tau }(b+ \sigma )-\frac{(T^{*})^{\frac{1 }{2}}}{2}e^{-\frac{1}{2}\tau }-C_{R} \biggr) \Vert \Gamma \Vert ^{2}_{ \mathbb{L}^{2}} \\ &\qquad{} - \biggl(\frac{3}{4}-\frac{s}{2}+T^{*}e^{-\tau }(1-b)- \bigl(T^{*}\bigr)^{\frac{1 }{2}}e^{-\frac{1}{2}\tau }-C_{R} \biggr) \Vert \Lambda \Vert ^{2}_{\mathbb{L}^{2}} \\ &\qquad{} - \biggl(a+\frac{3}{4}-\frac{s}{2}-T^{*}e^{-\tau }b-C_{R} \biggr) \bigl( \bigl\Vert \nabla _{y}^{s}h_{1} \bigr\Vert ^{2}_{\mathbb{L}^{2}}+ \bigl\Vert \nabla _{y}^{s}h_{2} \bigr\Vert ^{2}_{\mathbb{L}^{2}} \bigr) \\ &\qquad{} - \biggl(\frac{3}{4}-\frac{s}{2}-2a-T^{*}e^{-\tau }b-C_{R} \biggr) \bigl\Vert \nabla _{y}^{s}h_{3} \bigr\Vert ^{2}_{\mathbb{L}^{2}} \end{aligned} $$
(2.56)
and
$$ \begin{aligned} &\frac{3}{4}-\frac{s}{2}-T^{*}e^{-\tau }(b+ \sigma )-\frac{(T^{*})^{\frac{1}{2}} }{2}e^{-\frac{1}{2}\tau }-C_{R}>0, \\ &\frac{3}{4}-\frac{s}{2}+T^{*}e^{-\tau }(1-b)- \bigl(T^{*}\bigr)^{\frac{1}{2}}e^{-\frac{1 }{2}\tau }-C_{R}>0, \\ &a+\frac{3}{4}-\frac{s}{2}-T^{*}e^{-\tau }b-C_{R}>0, \\ &\frac{3}{4}-\frac{s}{2}-2a-T^{*}e^{-\tau }b-C_{R}>0. \end{aligned} $$
Hence by (2.56), we get
$$ \int _{\Omega }\nabla ^{s}_{y}U\cdot \nabla ^{s}_{y} \bigl((\mathcal{A}+ \mathcal{N})U \bigr)\,dy\leq 0. $$
Hence the linear operator \(\mathcal{A}+\mathcal{N}\) is a linear dissipative operator in \(\mathbb{H}^{s}(\mathbb{R}^{3})\times \mathbb{H}^{s}(\mathbb{R}^{3}) \times H^{s}(\mathbb{R}^{3})\). Moreover, if we set
$$ (\mathcal{A}+\mathcal{N})U=0, $$
then, by (2.56), we know the linear operator \(\mathcal{A}+\mathcal{N}\) is injective. Furthermore, we can verify that this linear operator is surjective by using the standard theory of elliptic-type equations of the general order. Thus the linear operator \(\mathcal{A}+\mathcal{N}\) can generate a strongly continuous semigroup \(e^{(\mathcal{A}+\mathcal{N})\tau }\) in Sobolev space \(\mathbb{H}^{s}(\mathbb{R}^{3})\times \mathbb{H}^{s}(\mathbb{R}^{3}) \times H^{s}(\mathbb{R}^{3})\) by the Lumer–Phillips theorem [23]. Therefore, the linear system (2.55) admits a solution
$$ \begin{aligned} &\Gamma \in \mathcal{C}_{0}^{s}:= \bigcap_{i= 0}^{1}\mathbb{C}^{i} \bigl((0,+ \infty );\mathbb{H}^{s-i}\bigr), \\ &\Lambda \in \mathcal{C}_{0}^{s}:=\bigcap _{i= 0}^{1}\mathbb{C}^{i}\bigl((0,+ \infty );\mathbb{H}^{s-i}\bigr), \\ &\textbf{h}\in \overline{\mathcal{C}}_{0}^{s}:=\bigcap _{i= 0}^{1} \mathbb{C}^{i} \bigl((0,+\infty );H^{s-i}\bigr). \end{aligned} $$
Furthermore, it follows from Lemmas 2.2–2.3 that (2.54) holds. □
Recalling the self-similarity coordinates (2.12), the original coordinate can be expressed by the self-similarity coordinates as follows:
$$ t=T\bigl(1-e^{-\tau }\bigr),\qquad x=y\sqrt{T^{*}-t}, $$
so we can directly use Proposition 2.1 to get the following result.
Proposition 2.2
Let \(0< a\ll \frac{1}{8}\) and \(0< s<\frac{3}{2}-5a\) be constants. Assume that \(\|\Phi \|_{\mathbb{H}^{s+5}(\mathbb{R}^{3})}\lesssim R\ll 1\), \(f_{i}\in \mathbb{C}^{1}((0,T^{*}),\mathbb{H}^{s}(\mathbb{R}^{3}))\) \((i=1,2)\), \(\textbf{g}\in \mathbb{C}^{1}((0,T^{*}),H^{s}(\mathbb{R}^{3}))\) and \((n,c,\textbf{v} )^{T}\in \mathcal{B}_{R}\). Then the linearized coupled system (2.5) with the initial data (2.2) and condition (2.3) admits a local solution
$$ \begin{aligned} &\Gamma \in \mathcal{C}_{0}^{s}:= \bigcap_{i= 0}^{1}\mathbb{C}^{i} \bigl(\bigl(0,T^{*}\bigr); \mathbb{H}^{s-i}\bigl( \mathbb{R}^{3}\bigr)\bigr), \\ &\Lambda \in \mathcal{C}_{0}^{s}:=\bigcap _{i= 0}^{1}\mathbb{C}^{i}\bigl( \bigl(0,T^{*}\bigr); \mathbb{H}^{s-i}\bigl( \mathbb{R}^{3}\bigr)\bigr), \\ &\textbf{h}\in \overline{\mathcal{C}}_{0}^{s}:=\bigcap _{i= 0}^{1} \mathbb{C}^{i} \bigl(\bigl(0,T^{*}\bigr);H^{s-i}\bigl( \mathbb{R}^{3}\bigr)\bigr). \end{aligned} $$
Moreover,
$$\begin{aligned}& \Vert \Gamma \Vert _{\mathcal{C}_{0}^{s}}^{2}+ \Vert \Lambda \Vert _{\mathcal{C}^{s}_{0}}^{2}+ \Vert \textbf{h} \Vert ^{2}_{\overline{\mathcal{C}}_{0}^{s}} \lesssim \Vert \Gamma _{0} \Vert _{\mathcal{C}_{0}^{s}}^{2}+ \Vert \Lambda _{0} \Vert _{\mathcal{C}_{0}}^{2}+ \Vert \textbf{h}_{0} \Vert ^{2}_{\overline{\mathcal{C}}_{0}^{s}}+ \Vert f_{1} \Vert ^{2}_{ \mathcal{C}_{0}^{s}}+ \Vert f_{2} \Vert ^{2}_{\mathcal{C}_{0}^{s}} + \Vert \textbf{g} \Vert ^{2}_{ \overline{\mathcal{C}}_{0}^{s}}, \\& \quad \forall t\in \bigl(0,T^{*}\bigr). \end{aligned}$$