Elsevier

Journal of Number Theory

Volume 231, February 2022, Pages 48-79
Journal of Number Theory

General Section
Modular equations for congruence subgroups of genus zero (II)

https://doi.org/10.1016/j.jnt.2020.10.016Get rights and content

Abstract

We present a result that the modular equation of a Hauptmodul for a certain congruence subgroup ΓH(N,t) of genus zero satisfies Kronecker's congruence relation. This generalizes the author's previous result about Γ1(m)Γ0(mN). Furthermore we show that the similar result holds for a certain congruence subgroup Γ of genus zero with [Γ:ΓH(N,t)]=2. Finally we prove a conjecture of Lee and Park, asserting that the modular equation of the continued fraction of order six satisfies a certain form of Kronecker's congruence relation.

Introduction

It is well known that the modular equation Φn(x,y) of the elliptic modular function j(τ) for the full modular group SL2(Z) satisfies the so-called Kronecker's congruence relationΦp(x,y)(xpy)(xyp)(modpZ[x,y]) for any prime p (see [8, §2 in Chapter 5] or [6, Theorem 11.18]). After this classical result, Chen and Yui [2, Theorem 2.6], Cais and Conrad [1, Section 6], Cho, Koo, and Park [4], [5], and Cho [3, Theorem 2.1] showed that modular equations of other Hauptmoduln also satisfy certain forms of Kronecker's congruence relation. For more details, see the introduction in the author's article [3]. Instead, it is worth noting that every Kronecker's congruence relation that appeared in the articles above was of the form(xpy)(xyp) or(xpy)((x+a)(yp+b)+c) modulo pZ[x,y].

Recently, Lee and Park [10] gave a systematic way to compute modular equations of the continued fraction X(τ) of order six and raised an interesting conjecture (see [10, Remark 3.10]) that its modular equation satisfies Kronecker's congruence relation of the formFp(x,y){(xpy)(xyp)(modpZ[x,y])if p±1(mod12)(xpy)(x+yp)(modpZ[x,y])if p±5(mod12). For explicit computations of Fp(x,y), see [12, Section 2] and [10, Table 1]. Observe that a new form (xpy)(x+yp) of Kronecker's congruence relation has conjecturally appeared. Naturally, this observation motivated the author to deal with their conjecture.

Section snippets

Modular equations for ΓH(N,t) and ΓH(N,t)αΓH(N,t)

Throughout the remainder of this article, let N and t be positive integers with t|N, and H a subgroup of (Z/NZ)×, andΓH(N,t)={(abcd)SL2(Z)|a¯H,b0(modt),c0(modN)}, where x¯ denotes the reduction of xZ modulo N. Without loss of generality, we may assume that IΓH(N,t), i.e. 1H. For notational convenience, we simply denote ΓH(N,t) by ΓH. For any nN, letMnΓH={(abcd)M2(Z)|(a,b,c,d)=1,adbc=n,a¯H,b0(modt),c0(modN)}. Given an integer aZ with (a,N)=1, we fix σaSL2(Z) such thatσa(a100a)

Proofs of main theorems

We begin by introducing some elementary identities.

Lemma 3.1

(1) If d|n, then we havei)0k<n(k,d)=11=φ(d)nd,ii)0k<n(k,d)=1(ζnk)={1ifd=11ifd>1. (2) For any n,N, we havei)d|n(n/d,)=1φ(d)=npprimep|(,n)(11p),ii)a|n(a,)=10b<n/a(b,a,n/a)=11=npprimep|n,p(1+1p). (3) For any nN, we havei)0k<n(k,n)=1(1ζnk)={0if n=1pif n=prwithp a prime and rN1otherwise,ii)0k<n(k,n)=1(1+ζnk)={2if n=10if n=2pif n2=prwithp a prime and rN1otherwise.

Proof

The identities (1) and (2) are proven in [3, Lemma 3.1] and

Acknowledgments

The author would like to express his sincere thanks to the anonymous referee for his or her careful reading and valuable comments on the manuscript, especially for giving a much shorter and simpler proof of Lemma 3.1 (3) ii) than the author's original proof. Some other proofs also became clearer and simpler thanks to the referee.

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Cited by (0)

The author was supported by the National Research Foundation of Korea (NRF-2018R1A2B6001645) and the Dongguk University Research Fund of 2019.

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