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BY 4.0 license Open Access Published by De Gruyter December 8, 2020

The concentration-compactness principles for Ws,p(·,·)(ℝN) and application

  • Ky Ho and Yun-Ho Kim EMAIL logo

Abstract

We obtain a critical imbedding and then, concentration-compactness principles for fractional Sobolev spaces with variable exponents. As an application of these results, we obtain the existence of many solutions for a class of critical nonlocal problems with variable exponents, which is even new for constant exponent case.

MSC 2010: 35B33; 35D30; 35J20; 35R11; 46E35; 49J35

1 Introduction

Nonlocal equations have been modeled for various problems in real fields, for instance, phase transitions, thin obstacle problem, soft thin films, crystal dislocation, stratified materials, anomalous diffusion, semipermeable membranes and flame propagation, material science, ultra-relativistic limits of quantum mechanics, multiple scattering, minimal surfaces, water waves, etc. After the seminal papers by Caffarelli et al. [1, 2, 3], problems involving fractional P-Laplacian have been intensively studied. On the other hand, various other real fields such as electrorheological fluids and image processing, etc. require partial differential equations with variable exponents (see e.g., [4, 5]). Natural solution spaces for those problems are Sobolev spaces with fractional order or variable exponents, which were comprehensively investigated in [6] and [7].

Recently, many authors have been studied the fractional Sobolev spaces with variable exponents and the corresponding nonlocal equations with variable exponents (see e.g., [11, 9, 8, 10]). To the authors’ best knowledge, though most properties of the classical fractional Sobolev spaces have been extended to the fractional Sobolev spaces with variable exponents, there have no results for the critical Sobolev type imbedding for these spaces. Consequently, there have no results on nonlocal equations with variable critical growth because the critical Sobolev type imbedding is essential in the study of such critical equations. The critical problem was initially studied in the seminal paper by Brezis-Nirenberg [12], which treated for Laplace equations. Since then there have been extensions of [12] in many directions. Elliptic equations involving critical growth are delicate due to the lack of compactness arising in connection with the variational approach. For such problems, the concentration-compactness principles (the CCPs, for short) introduced by P.L. Lions [13, 14] and its variant at infinity [16, 15, 17] have played a decisive role in showing a minimizing sequence or a Palais-Smale sequence is precompact. By using these CCPs or extending them to the Sobolev spaces with fractional order or variable exponents, many authors have been successful to deal with critical problems involving p-Laplacian or p(.)-Laplacian or fractional p-Laplacian, see e.g., [18, 25, 21, 22, 20, 19, 23, 24, 26, 27] and references therein.

As we mentioned above, there have no results for the critical Sobolev type imbedding for the fractional Sobolev spaces with variable exponents. Although the usual critical Sobolev immersion theorem holds in the fractional order or variable exponents setting, we do not know this assertion even in fractional Sobolev spaces with variable exponents defined in bounded domain; see [11, 9, 8, 10]. Because of this, our first aim of the present paper is to obtain a critical imbedding from fractional Sobolev spaces with variable exponents into Lebesgue spaces with variable exponents. We provide sufficient conditions on the variable exponents such as the log-Hölder type continuity condition to obtain such critical imbedding (Theorem 3.3). Thanks to this critical Sobolev imbedding, inspired by [14, 21, 22, 19, 27], we then establish two Lions type concentration-compactness principles for fractional Sobolev spaces with variable exponents, which are our second aim (Theorems 4.1 and 4.2). As an application of these results, we will obtain the existence of many solutions for the following nonlocal problem with variable exponents

(1.1) L u ( x ) + | u | p ( x , x ) 2 u = f ( x , u ) + λ | u | q ( x ) 2 u  in  R N ,

where the operator 𝓛 is defined as

(1.2) L u ( x ) = 2 lim ε 0 y R N : | y x | ε | u ( x ) u ( y ) | p ( x , y ) 2 ( u ( x ) u ( y ) ) | x y | N + s p ( x , y ) d y , x R N ,

where s ( 0 , 1 ) , p C ( R N × R N ) is symmetric i.e., p(x,y)=p(y,x) for all (x,y)N×N such that 1 < p := inf ( x , y ) R N × R N p ( x , y ) p + := sup ( x , y ) R N × R N p ( y , x ) < N s ; q C R N satisfies p ( x , x ) < q ( x ) p s ( x ) := N p ( x , x ) N s p ( x , x ) for all xN ; 𝜆 is a positive real parameter; and f : R N × R R is a Carathéodory function of local p+ -superlinear and to be specified later.

The main feature of our final consequence in the present paper is to establish the multiplicity result for problem (1.1) under the critical growth condition x R N : q ( x ) = p s ( x ) ϕ , originally introduced in [21] for the p(·)-Laplacian case, and some conditions on f different from the related works [18, 28, 29] (Theorem 5.1). As far as we are aware, there are no existence results about the critical problems in this situation even in the case of constant exponents.

The rest of our paper is organized as follows. In Section 2, we briefly review some properties of the Sobolev spaces with fractional order or variable exponents. In Section 3, we establish a critical Sobolev type imbedding for the fractional Sobolev spaces with variable exponents, which is a key to our arguments. In Section 4 we establish Lions type concentration-compactness principles for fractional Sobolev spaces with variable exponents. In Section 5, we show the existence of many solutions for a superlinear nonlocal problem with variable exponents using genus theory. In Appendix, we give an auxiliary result, which is used to prove our CCPs.

2 Variable exponent Lebesgue spaces and fractional Sobolev spaces

In this section, we briefly review the Lebesgue spaces with variable exponents and the classical fractional Sobolev spaces.

Let Ω be a Lipschitz domain in ℝN Denote

C + ( Ω ¯ ) = h C ( Ω ¯ ) : 1 < inf x Ω ¯ h ( x ) sup x Ω ¯ h ( x ) < ,

and for h C + ( Ω ¯ ) , denote

h + = sup x Ω ¯ h ( x )  and  h = inf x Ω ¯ h ( x ) .

For p C + ( Ω ¯ ) and a σ-finite, complete measure 𝜇 in Ω, define the variable exponent Lebesgue space L μ p ( ) ( Ω ) as

L μ p ( ) ( Ω ) := u : Ω R  is  μ  measurable,  Ω | u ( x ) | p ( x ) d μ <

endowed with the Luxemburg norm

u L μ p ( ) ( Ω ) := inf λ > 0 : Ω u ( x ) λ p ( x ) d μ 1 .

When 𝜇 is the Lebesgue measure, we write d x , L p ( ) ( Ω ) and | | u | | L p ( ) ( Ω ) instead of 𝜇, d μ , L μ p ( ) ( Ω ) and u L μ p ( ) ( Ω ) , respectively. Set L + p ( ) ( Ω ) := u L p ( ) ( Ω ) : u > 0  a.e. in  Ω and for a Lebesgue measurable and positive a.e. function w : Ω R , set L p ( ) ( w , Ω ) := L μ p ( ) ( Ω ) with d μ = w ( x ) d x . Some basic properties of L μ p ( ) ( Ω ) are listed in the next three propositions.

Proposition 2.1

([7, Corollary 3.3.4]). Let α , β C + ( Ω ¯ ) such that α ( x ) β ( x ) for all x Ω ¯ . Then, we have

| | u | | L μ α ( ) ( Ω ) 2 [ 1 + μ ( Ω ) ] | | u | | L μ β ( ) ( Ω ) , u L μ α ( ) ( Ω ) L μ β ( ) ( Ω ) .

Proposition 2.2

([30]). Define the modular ρ : L μ p ( ) ( Ω ) R as

ρ ( u ) := Ω | u | p ( x ) d μ , u L p ( ) ( Ω )

Then, we have the following relations between the norm and modular.

  1. For u L μ p ( ) ( Ω ) { 0 } , λ = u L μ p ( ) ( Ω ) if and only if ρ ( u λ ) = 1.

  2. ρ ( u ) > 1 ( = 1 ; < 1 ) if and only if u L μ p ( ) ( Ω ) > 1 ( = 1 ; < 1 ) , respectively.

  3. If u L μ p ( ) ( Ω ) > 1 , then u L μ p ( ) ( Ω ) p ρ ( u ) u L μ p ( ) ( Ω ) p + .

  4. If u L μ p ( ) ( Ω ) < 1 , then u L μ p ( ) ( Ω ) p ρ ( u ) u L μ p ( ) ( Ω ) p + .

Proposition 2.3

([30, 31]). The space L p ( ) ( Ω ) is a separable, uniformly convex Banach space, and its dual space is L p ( ) ( Ω ) where 1 / p ( x ) + 1 / p ( x ) = 1 . For any u L p ( ) ( Ω ) and v L p ( ) ( Ω ) , we have

Ω u v d x 2 u L p ( ) ( Ω ) v L p ( ) ( Ω ) .

Let s ∈ (0,1) and p(1,) be constants. Define the fractional Sobolev space Ws,p(Ω) as

W s , p ( Ω ) := u L p ( Ω ) : Ω Ω | u ( x ) u ( y ) | p | x y | N + s p d x d y <

endowed with norm

u s , p , Ω := Ω | u ( x ) | p d x + Ω Ω | u ( x ) u ( y ) | p | x y | N + s p d x d y 1 / p .

We recall the following crucial imbeddings.

Proposition 2.4

([6]). Let s ∈ (0,1) and p(1,) be such that sp<N. It holds that

  1. W s , p ( Ω ) ↪↪ L q ( Ω ) if Ω is bounded and 1q<NpNsp=:ps ;

  2. W s , p ( Ω ) L q ( Ω ) if p q p s .

3 The Sobolev spaces W s , p ( , ) ( Ω )

In this section, we recall the fractional Sobolev spaces with variable exponents that was first introduced in [11], and was then refined in [10]. Furthermore, we will obtain a critical Sobolev type imbedding on these spaces.

Let Ω be a bounded Lipschitz domain in ℝN or Ω = ℝN Throughout this article, we assume that

s ∈ (0,1); p C ( Ω ¯ × Ω ¯ ) is uniformly continuous and symmetric such that

1 < p := inf ( x , y ) Ω ¯ × Ω ¯ p ( x , y ) p + := sup ( x , y ) Ω ¯ × Ω ¯ p ( x , y ) < N s .

In the following, for brevity, we write p (x) instead of p (x, x) and with this notation, p C + ( Ω ¯ ) . Define

W s , p ( , ) ( Ω ) := u L p ( ) ( Ω ) : Ω Ω | u ( x ) u ( y ) | p ( x , y ) | x y | N + s p ( x , y ) d x d y < +

endowed with the norm

u s , p , Ω := inf λ > 0 : M Ω u λ < 1 ,

where M Ω ( u ) := Ω u p ( x ) d x + Ω Ω | u ( x ) u ( y ) | p ( x , y ) | x y | N + s p ( x , y ) d x d y . Then, W s , p ( , ) ( Ω ) is a separable reflexive Banach space (see [11, 9, 8]). On W s , p ( , ) ( Ω ) , we also make use of the following norm

| u | s , p , Ω := | | u | | L p ( ) ( Ω ) + [ u ] s , p , Ω ,

where

[ u ] s , p , Ω := inf λ > 0 : Ω Ω | u ( x ) u ( y ) | p ( x , y ) λ p ( x , y ) | x y | N + s p ( x , y ) d x d y < 1 .

Note that s , p , Ω and | | s , p , Ω are equivalent norms on W s , p ( , ) ( Ω ) with the relation

(3.1) 1 2 u s , p , Ω | u | s , p , Ω 2 u s , p , Ω , u W s , p ( , ) ( Ω ) .

In what follows, when Ω is understood, we just write s,p , | | s , p and [ ] s , p instead of s,p,Ω , ||s,p,Ω and []s,p,Ω , respectively. We also denote the ball in ℝN centered at z with radius ε by B ε ( z ) and denote the Lebesgue measure of a set EN by |E| . For brevity, we write Bε and Bεc instead of Bε(0) and N\Bε(0) , respectively.

Proposition 3.1

([10]) On W s , p ( , ) ( Ω ) it holds that

  1. for u W s , p ( , ) ( Ω ) { 0 } , λ =∥ u s , p if and only if M Ω ( u λ ) = 1 ;

  2. M Ω ( u ) > 1 ( = 1 ; < 1 ) if and only if u s , p > 1 ( = 1 ; < 1 ) , respectively;

  3. if u s , p 1 , then u s , p p M Ω ( u ) ≤∥ u s , p p + ;

  4. if us,p<1 , then u s , p p + M Ω ( u ) ≤∥ u s , p p .

Theorem 3.2

(Subcrtitical imbeddings, [10]) It holds that

  1. W s , p ( , ) ( Ω ) ↪↪ L r ( ) ( Ω ) , if Ω is a bounded Lipschitz domain and r C + ( Ω ¯ ) such that r ( x ) < N p ( x ) N s p ( x ) =: p s ( x ) for all x Ω ¯ ;

  2. W s , p ( , ) ( R N ) L r ( ) ( R N ) for any uniformly continuous function rC+(N) satisfying p(x)r(x) for all xN and inf x R N ( p s ( x ) r ( x ) ) > 0 ;

  3. W s , p ( , ) ( R N ) ↪↪ L loc r ( ) ( R N ) for any rC+(N) satisfying r(x)<ps(x) for all xN.

The next critical imbedding is our first main result.

Theorem 3.3

(Critical imbedding) Let Ω be a bounded Lipschitz domain inN or Ω = ℝN. Let ( P 1 ) hold. Furthermore, let the variable exponent P satisfy the following log-Hölder type continuity condition

(3.2)infε>0sup(x,y)Ω×Ω0<|xy|<1/2|p(x,y)pΩx,ε×Ωy,ε|log1|xy|<,

where Ωz,ε:=Bε(z)Ω for zΩ and ε>0 , and pΩx,ε×Ωy,ε:=inf(x,y)Ωx,ε×Ωy,εp(x,y). Let q:Ω¯ be a function satisfying

( Q 1 ) q C + ( Ω ¯ ) such that for any xΩ , there exists ε=ε(x)>0 such that the following locally critical growth condition holds:

(3.3) sup y Ω x , ε q ( y ) N inf ( y , z ) Ω x , ε × Ω x , ε p ( y , z ) N s inf ( y , z ) Ω x , ε × Ω x , ε p ( y , z ) .

In addition, when Ω = ℝN, q is uniformly continuous and p(x)<q(x) for all x ∈ ℝN.

Then, it holds that

(3.4) W s , p ( , ) ( Ω ) L q ( ) ( Ω ) .

Proof

By the closed graph theorem, to prove (3.4) it suffices to show that W s , p ( , ) ( Ω ) L q ( ) ( Ω ) . Let u W s , p ( , ) ( Ω ) { 0 } be arbitrary and fixed. We will show that u L q ( ) ( Ω ) , namely,

(3.5) Ω | u | q ( x ) d x < .

To this end, we first note that by (3.2), there exists constant ε0(0,1) such that

(3.6) sup ( x , y ) Ω × Ω 0 < | x y | < 1 / 2 p ( x , y ) p Ω x , ε 0 × Ω y , ε 0 log 1 | x y | < C .

Here and in the remainder of the proof, C denotes a positive constant independent of u and may vary from line to line. We consider the following two cases.

Case 1: Ω is a bounded Lipschitz domain.

We cover Ω̅ by { B ε i ( x i ) } i = 1 m with xiΩ and εi(0,ε0) such that Ω i := B ε i ( x i ) Ω being Lipschitz domains and the locally critical growth condition (3.3) being satisfied for all i{1,,m} . Fix i{1,,m} and denote p i := inf ( y , z ) Ω i × Ω i p ( y , z ) and q i := sup x Ω i q ( x ) . By (3.3) and the choice of εi , we have

q i N p i N s p i =: p s , i .

From this and Proposition 2.4, we have

Ω i | u | q i d x C Ω i | u | p i d x + Ω i Ω i | u ( x ) u ( y ) | p i | x y | N + s p i d x d y q i p i ,

and hence,

(3.7) Ω i | u | q ( x ) d x Ω i C Ω i + Ω i | u | p ( x ) d x + Ω i Ω i | u ( x ) u ( y ) | p i | x y | N + s p i d x d y q i p i .

On the other hand, we have

(3.8)ΩiΩi|u(x)u(y)|p(x,y)|xy|N+sp(x,y)dxdy=ΩiΩi|u(x)u(y)||xy|2sp(x,y)1|xy|Nspi1|xy|p(x,y)pisdxdy.

Note that by (3.6), we have

(3.9) | x y | s p ( x , y ) p i = e s p ( x , y ) p i log | x y | C , x , y Ω , x y .

Thus, (3.8) yields

ΩiΩi|u(x)u(y)|p(x,y)|xy|N+sp(x,y)dxdyCΩiΩi|u(x)u(y)||xy|2sp(x,y)1|xy|NspidxdyCΩiΩi|u(x)u(y)||xy|2spi11|xy|Nspidxdy

Hence,

(3.10)ΩiΩi|u(x)u(y)|p(x,y)|xy|N+sp(x,y)dxdyCΩiΩi|u(x)u(y)|pi|xy|N+spidxdyCΩiΩi1|xy|Nspidxdy.

We have

(3.11) Ω i Ω i 1 | x y | N s p i d x d y Ω d y B 2 d z | z | N s p i = | Ω | N B 1 2 s p i s p i .

From (3.7), (3.10) and (3.11), we obtain

Ωi|u|q(x)dxC1+Ωi|u|p(x)dx+ΩiΩi|u(x)u(y)|p(x,y)|xy|N+sp(x,y)dxdyqipiC1+Ω|u|p(x)dx+ΩΩ|u(x)u(y)|p(x,y)|xy|N+sp(x,y)dxdyg+p.

Summing up for i=1,,m , we arrive at

Ω | u | q ( x ) d x C 1 + Ω | u | p ( x ) d x + Ω Ω | u ( x ) u ( y ) | p ( x , y ) | x y | N + s p ( x , y ) d x d y q + p < ,

and so (3.5) is claimed.

Case 2: Ω = R N .

Decompose R N by cubes { Q i } i N with sides of length ε(0,1) and parallel to coordinates axes. By the locally critical growth condition (3.3) and the uniform continuity of q we can choose ε>0 sufficiently small such that

(3.12) p i p i + q i q i N p i N s p i =: p s , i , i N ,

where

p i := inf ( y , z ) Q i × Q i p ( y , z ) , p i + := sup ( y , z ) Q i × Q i p ( y , z ) , q i := inf x Q i q ( x ) , and q i := sup x Q i q ( x ) .

Set v=uus,p . Thus, vs,p=1 and hence, MN(v)=1 in view of Proposition 3.1. This yields MQi(v)1 for all i є ℕ and hence,

(3.13) v s , p , Q i 1 , i N .

We claim that

(3.14) | | v | | L q ( ) ( Q i ) C v s , p , Q i , i N .

Here and in the remainder of the proof, C is a positive constant independent of v and i. In order to prove (3.14), we first prove that

(3.15) | | v | | s , p i , Q i C | | v | | s , p , Q i , i N .

Indeed, let i є ℕ and consider the measure 𝜇 on R N × R N such that

d μ ( x , y ) = d x d y | x y | N s p i .

As in (3.11) we have

(3.16) μ Q i × Q i Q i N B 1 2 s p i s p i < N B 1 2 s p + s p , i N .

Set λ := [ v ] s , p , Q i and F ( x , y ) := | v ( x ) v ( y ) | x y | 2 s . Invoking Proposition 3.1 and (3.9) we estimate

1=QiQi|v(x)v(y)|p(x,y)λp(x,y)|xy|N+sp(x,y)dxdy=QiQi|v(x)v(y)p(x,y)|λ|xy2s1|xy|sp(x,y)pidxdy|xy|Nspi(C+1)1Qi×QiF(x,y)λp(x,y)dμ(x,y)Qi×Qi(C+1)p(x,y)piF(x,y)λp(x,y)dμ(x,y)=Qi×QiF(x,y)(C+1)1piλp(x,y)dμ(x,y).

Thus,

F L μ p ( , ) ( Q i × Q i ) ( C + 1 ) 1 p i λ = ( C + 1 ) 1 p i [ v ] s , p , Q i .

Meanwhile, invoking Proposition 2.1 we have

F L μ p i ( Q i × Q i ) 2 ( 1 + μ ( Q i × Q i ) ) F L μ p ( , ) ( Q i × Q i ) .

Combining the last two inequalities and (3.16) we obtain

(3.17) F L μ p i ( Q i × Q i ) C [ v ] s , p , Q i .

Noting

F L μ p i Q i × Q i = Q i Q i | v ( x ) v ( y ) | | x y | 2 s p i d x d y | x y | N s p i 1 p i = Q i Q i | v ( x ) v ( y ) | p i | x y | N + s p i d x d y 1 p i = [ v ] s , p i , Q i ,

we deduce from (3.17) that

(3.18) [ v ] s , p i , Q i C [ v ] s , p , Q i .

Combining (3.18) with the following estimate:

v L p i Q i 2 1 + Q i v L p ( ) Q i 4 v L p ( ) Q i

(see Proposition 2.1) and the relation (3.1), we obtain (3.15).

As in [10, Proof of Theorem 3.5], we can obtain an extension v ~ W s , p i R N with compact support in ℝN such that v ~ = v on Qi, and

v ~ L p s , i ( R N ) C v s , p i , Q i .

This and (3.12) yield

(3.19) v L q i Q i C v s , p i , Q i .

Note that by Proposition 2.1 again,

(3.20) v L q ( ) Q i 2 1 + Q i v L q i Q i 4 v L q i Q i .

From (3.15), (3.19), and (3.20) we obtain (3.14). Now, for each i N ,  if  v L q ( ) Q i 1 , then by (3.13), (3.14) and Proposition 3.1 we have

Q i | v | q ( x ) d x v L q ( ) Q i q i C v s , p , Q i q i C Q i | v | p ( x ) d x + Q i Q i | v ( x ) v ( y ) | p ( x , y ) | x y | N + s p ( x , y ) d x d y q i p i + C Q i | v | p ( x ) d x + Q i Q i | v ( x ) v ( y ) | p ( x , y ) | x y | N + s p ( x , y ) d x d y .

Similarly, if v L q ( ) Q i 1 , , then

Q i | v | q ( x ) d x v L q ( ) Q i q ¯ i C v s , p , Q i q ¯ i C Q i | v | p ( x ) d x + Q i Q i | v ( x ) v ( y ) | p ( x , y ) | x y | N + s p ( x , y ) d x d y q ¯ i p i + C Q i | v | p ( x ) d x + Q i Q i | v ( x ) v ( y ) | p ( x , y ) | x y | N + s p ( x , y ) d x d y .

So in any case,

Q i | v | q ( x ) d x C Q i | v | p ( x ) d x + Q i Q i | v ( x ) v ( y ) | p ( x , y ) | x y | N + s p ( x , y ) d x d y .

Summing up for i N , , we obtain

R N | v | q ( x ) d x C R N | v | p ( x ) d x + R N R N | v ( x ) v ( y ) | p ( x , y ) | x y | N + sp ( x , y ) d x d y ,

which implies (3.5) with Ω = ℝN The proof is complete.

We conclude this section with a compact imbedding from W S , p ( , ) R N into the weighted Lebesgue spaces with variable exponents.

Theorem 3.4

Assume that (𝒫1), (Q1), and the log-Hölder continuity condition (3.2) hold. Let W L + q ( ) q ( ) r ( ) R N for some r C + R N such that inf x R N [ q ( x ) r ( x ) ] > 0 . Then, it holds that

W S , p ( , ) R N ↪↪ L r ( ) w , R N .

A proof of Theorem 3.4 can be obtained in a similar fashion to that of [27, Lemma 4.1] and we omit it.

4 The concentration-compactness principles for W s , p ( , ) ( R N )

In this section we establish two Lions type concentration-compactness principles for the spaces W s , p ( , ) ( R N ) .

4.1 Statements of the concentration-compactness principles

Let 𝛭(ℝN) be the space of all signed finite Radon measures on ℝN endowed with the total variation norm. Note that we may identify 𝛭(ℝN) with the dual of C 0 R N , , the completion of all continuous functions u : R N R whose support is compact relative to the supremum norm (see, e.g., [32, Section 1.3.3]).

In the rest of this paper, we always assume that the variable exponents p and q satisfy the following assumptions.

(𝒫2) p:N×N is uniformly continuous and symmetric such that

1 < p := inf ( x , y ) R N × R N p ( x , y ) sup ( x , y ) R N × R N p ( x , y ) =: p ¯ < N s ;

there exists ε0(0,12) such that p(x,y)=p¯ for all x,yN satisfying |xy|<ε0 and supyNp(x,y)=p¯ for all xN; and |{xN:p(x)=/p¯}|<, where p*(x):=infyNp(x,y) for xN .

(𝓠2) q:N is uniformly continuous such that p(x)q(x)p¯s:=Np¯Nsp¯ for all xN and C := { x R N : q ( x ) = p ¯ s .

It is clear that if p satisfies (𝒫2 ), then p(x,x)=p¯ for all xN and p satisfies (𝒫1) and (3.2). Hence, by Theorem 3.3, we have

(4.1) W s , p ( , ) R N L p ¯ s R N .

On the other hand, by (𝒫2) we have that for any uLp¯(N) ,

R N | u ( x ) | p ( x ) d x = { p ( x ) = p ¯ } | u ( x ) | p ( x ) d x + { p ( x ) p ¯ } | u ( x ) | p ( x ) d x p ( x ) = p ¯ | u ( x ) | p ¯ d x + { p ( x ) p ¯ } 1 + | u ( x ) | p ¯ d x = χ R N : p ( x ) p ¯ + R N | u ( x ) | p ¯ d x < .

Hence, L p ¯ ( R N ) L p ( ) ( R N ) . From this and (4.1) we obtain

(4.2) W s , p ( , ) R N L t ( ) R N

for any tC(N) satisfying p(x)t(x)p¯s for all xN. In particular, (𝓠2) yields

(4.3) S q := inf u W s , p ( , ) R N { 0 } u s , p u L q ( ) R N > 0.

Our main results in this sections are the following CCPs for W s , p ( , ) ( R N ) .

Theorem 4.1

Assume that (𝒫2) and (𝓠2) hold. Let {un} be a bounded sequence in W s , p ( , ) ( R N ) such that

(4.4) u n u in W s , p ( , ) ( R N ) ,
(4.5) u n p ¯ + R N u n ( x ) u n ( y ) p ( x , y ) | x y | N + s p ( x , y ) d y μ in M R N ,
(4.6)|un|q(x)νinM(N).

Then, there exist sets { μ i } i I ( 0 , ) , { ν i } i I ( 0 , ) and { x i } i I C , where I is an at most countable index set, such that

(4.7) μ | u | p ¯ + R N | u ( x ) u ( y ) | p ( x , y ) | x y | N + s p ( x , y ) d y + i I μ i δ x i ,
(4.8) ν = | u | q ( x ) + i I ν i δ x i ,
(4.9) S q v i 1 p ¯ s μ i 1 p ¯ , i I .

For possible loss of mass at infinity, we have the following.

Theorem 4.2

Assume that (𝒫2) and (𝓠2) hold. Let {un} be a sequence in W s , p ( , ) ( R N ) as in Theorem 4.1. Set

(4.10) v := lim R lim sup n B R c u n q ( x ) d x ,
(4.11) μ := lim R lim sup n B R c u n p ¯ + R N u n ( x ) u n ( y ) p ( x , y ) | x y | N + s p ( x , y ) d y d x .

Then

(4.12) lim sup n R N u n q ( x ) d x = v R N + v ,
(4.13) lim sup n R N u n p ¯ + R N u n ( x ) u n ( y ) p ( x , y ) | x y | N + s p ( x , y ) d y d x = μ R N + μ .

Assume in addition that

) There exist lim|x|,|y|p(x,y)=p¯ and lim|x|q(x)=q for p̅ given by (𝒫2) and some q ( 1 , ) .

Then

(4.14) S q ν 1 q μ 1 p ¯ .

The following example provides a nonconstant exponent p that fulfills the conditions in Theorems 4.1 and 4.2.

Example 4.3

Let p(x,y)=p¯ξ(|xy|)φ(x,y) , where ξ C ( R ) such that 0 ξ ( t ) 1 for all t R , ξ ( t ) = 0 for t ε 0 and ξ ( t ) = 1 for t 1 ; φ C c ( R N × R N ) , φ ( x , y ) = φ ( y , x ) and 0 φ ( x , y ) < p ¯ 1 for all ( x , y ) R N × R N . Here ε0 and are as in (𝒫2).

4.2 Auxiliary lemmas and proofs of the concentration-compactness principles

The following auxiliary lemmas are useful to prove Theorems 4.1 and 4.2.

Lemma 4.4

Let x 0 R N be fixed and let ψ C ( R N ) be such that 0 ψ 1 , ψ 1 on B1, supp ( ψ ) B 2 and | | ψ | | 2 . For ρ > 0 , define ψ ρ ( x ) := ψ ( x x 0 ρ ) for x ∈ ℝN. Let (𝒫2 ) hold and let {un} be as in Theorem 4.1. Then, we have

(4.15)lim supρ0+lim supnRNRNun(x)p(x,y)ψρ(x)ψρ(y)p(x,y)|xy|N+sp(x,y)dy dx=0.

Lemma 4.5

Let ϕ C ( R N ) be such that 0 ϕ 1 , ϕ 0 on B1, ϕ 1 on R N B 2 , and | | ϕ | | 2. For R > 0 , define ϕ R ( x ) := ϕ ( x R ) for x ∈ ℝN Let (𝒫2 ) hold and let {un} be as in Theorem 4.1. Then, we have

(4.16) lim R lim sup n R N R N u n ( x ) p ( x , y ) ϕ R ( x ) ϕ R ( y ) p ( x , y ) | x y | N + sp ( x , y ) d y d x = 0.

Proof of Lemma 4.4. Set

J ( n , ρ ) = R N R N u n ( x ) p ( x , y ) ψ ρ ( x ) ψ ρ ( y ) p ( x , y ) | x y | N + s p ( x , y ) d y d x .

Let K > 4 be arbitrary and fixed and let ρ ( 0 , ε 0 2 K ) . Clearly,

R N × R N = ( R N B 2 ρ ( x 0 ) ) × ( R N B 2 ρ ( x 0 ) ) B K ρ ( x 0 ) × R N ( R N B K ρ ( x 0 ) ) × B 2 ρ ( x 0 ) .

From this and the fact that | ψ ρ ( x ) ψ ρ ( y ) | = 0 on ( R N B 2 ρ ( x 0 ) ) × ( R N B 2 ρ ( x 0 ) ) , we have

(4.17) J ( n , ρ ) = B K ρ x 0 R N u n ( x ) p ( x , y ) ψ ρ ( x ) ψ ρ ( y ) p ( x , y ) | x y | N + s p ( x , y ) d y d x + R N B K ρ x 0 B 2 ρ x 0 u n ( x ) p ( x , y ) ψ ρ ( x ) ψ ρ ( y ) p ( x , y ) | x y | N + s p ( x , y ) d y d x =: J 1 ( n , ρ ) + J 2 ( n , ρ ) .

We first estimate J 1 ( n , ρ ) . Decompose

(4.18) J 1 ( n , ρ ) = B K ρ x 0 { | x y | ρ } u n ( x ) p ( x , y ) ψ ρ ( x ) ψ ρ ( y ) p ( x , y ) | x y | N + s p ( x , y ) d y d x + B K ρ x 0 ρ < | x y | < ε 0 u n ( x ) p ( x , y ) ψ ρ ( x ) ψ ρ ( y ) p ( x , y ) | x y | N + s p ( x , y ) d y d x + B K ρ x 0 | x y | ε 0 u n ( x ) p ( x , y ) ψ ρ ( x ) ψ ρ ( y ) p ( x , y ) | x y | N + s p ( x , y ) d y d x =: i = 1 3 J 1 ( i ) ( n , ρ ) .

By (𝒫2) and the choice of ψρ , we have p(x,y)=p¯ and |ψρ(x)ψρ(y)|2ρ|xy| on {|xy|<ρ} . Thus, we obtain

J 1 ( 1 ) ( n , ρ ) 2 ρ p ¯ B K ρ x 0 u n ( x ) p ¯ { | x y | ρ } | x y | N + ( 1 s ) p ¯ d y d x .

Hence,

(4.19) J 1 ( 1 ) ( n , ρ ) 2 p ¯ N B 1 ( 1 s ) p ¯ ρ s p ¯ B K ρ x 0 u n ( x ) p ¯ d x .

By (4.4), we have that unu in Lp¯(BKρ(x0)) in view of and Theorem 3.2 (iii). From this fact and (4.19) we obtain

(4.20) lim sup n J 1 ( 1 ) ( n , ρ ) 2 p ¯ N B 1 ( 1 s ) p ¯ ρ s p ¯ B K ρ x 0 | u ( x ) | p ¯ d x .

Using the Hölder inequality we have

(4.21) B K ρ x 0 | u ( x ) | p ¯ d x B 1 s p ¯ N K s p ¯ ρ s p ¯ B K ρ x 0 | u ( x ) | p ¯ s d x p ¯ p ¯ s

From (4.20), (4.21) and the fact that uLp¯s(N) (see (4.1)) we arrive at

(4.22) lim sup ρ 0 + lim sup n J 1 ( 1 ) ( n , ρ ) = 0.

On the other hand, from p ( x , y ) = p ¯ and | ψ ρ ( x ) ψ ρ ( y ) | p ( x , y ) 1 on { ρ < | x y | < ε 0 } we have

J 1 ( 2 ) ( n , ρ ) B K ρ x 0 u n ( x ) p ¯ ρ < | x y | < ε 0 | x y | N s p ¯ d y d x .

That is,

(4.23) J 1 ( 2 ) ( n , ρ ) N B 1 s p ¯ B K ρ x 0 u n ( x ) p ¯ ρ s p ¯ ε 0 s p ¯ d x .

Arguing as that obtained (4.20) we deduce from (4.23) that

(4.24) lim sup n J 1 ( 2 ) ( n , ρ ) N B 1 s p ¯ B K ρ x 0 | u ( x ) | p ¯ ρ s p ¯ ε 0 s p ¯ d x .

Then, using (4.21) and the fact that u L p ¯ s ( R N ) again we obtain from (4.24) that

(4.25) lim sup ρ 0 + lim sup n J 1 ( 2 ) ( n , ρ ) = 0.

In order to estimate J 1 ( 3 ) ( n , ρ ) , using the following estimations on { | x y | ε 0 } :

| u n ( x ) | p ( x , y ) 1 + | u n ( x ) | p ¯

and

| ψ ρ ( x ) ψ ρ ( y ) | p ( x , y ) | x y | N + s p ( x , y ) 1 | x y | N + s p ( x , y ) 1 | x y | N + s p + 1 | x y | N + s p ¯ ,

we first estimate

J 1 ( 3 ) ( n , ρ ) B K ρ x 0 1 + u n ( x ) p ¯ | x y | ε 0 1 | x y | N + s p + 1 | x y | N + s p ¯ d y d x 2 N B 1 ε 0 s p ¯ s p B K ρ x 0 1 + u n ( x ) p ¯ d x .

Then, arguing as before we obtain

(4.26) lim sup ρ 0 + lim sup n J 1 ( 3 ) ( n , ρ ) = 0.

Utilizing (4.22), (4.25) and (4.26), we infer from (4.18) that

(4.27) lim sup ρ 0 + lim sup n J 1 ( n , ρ ) = 0.

Next, we estimate J 2 ( n , ρ ) . Note that

(4.28) J 2 ( n , ρ ) t { p , p ¯ } R N B K ρ x 0 B 2 ρ x 0 u n ( x ) t ( x ) ψ ρ ( x ) ψ ρ ( y ) t ( x ) | x y | N + s t ( x ) d y d x =: t p , p ¯ J 2 ( n , ρ , t ) .

Let t { p , p ¯ } . Using the fact that

| x y | | x x 0 | | y x 0 | | x x 0 | 2 ρ 1 2 | x x 0 | , ( x , y ) ( R N B K ρ ( x 0 ) ) × B 2 ρ ( x 0 ) ,

we have

J 2 ( n , ρ , t ) 2 N + s p ¯ R N B K ρ x 0 u n ( x ) t ( x ) x χ 0 N + s t ( x ) B 2 p x 0 d y d x .

That is,

J 2 ( n , ρ , t ) 2 2 N + s p ¯ B 1 R N B K ρ x 0 u n ( x ) t ( x ) x x 0 N + s t ( x ) ρ N d x .

Invoking Proposition 2.3 again and using the boundedness of {un} in L p ¯ s ( R N ) , we deduce from the last inequality that

(4.29) J 2 ( n , ρ , t ) C 1 u n t ( x ) L p ¯ s t ( ) R N B K p x 0 x x 0 N s t ( x ) ρ N p ¯ s L p ¯ s t ( ) R N B K ρ x 0 C 2 max R N B K ρ x 0 X X 0 ( N + s t ( x ) ) p s p s t ( x ) ρ N p ¯ s p ¯ s t ( x ) d x p ¯ s t p ¯ s + , R N B K ρ x 0 x X 0 ( N + st ( x ) ) p s P ¯ S t ( x ) ρ N p s p ¯ s t ( x ) p ¯ s t p ¯ s .

Here and in the remainder of the proof Ci (i є ℕ) is a positive constant independent of n,ρ and K. By changing variable x = x 0 + ρ z we have

(4.30) R N B K ρ x 0 χ χ 0 ( N + s t ( x ) ) p ¯ s p ¯ s t ( x ) ρ N p ¯ s p ¯ s t ( x ) d x = { | z | K } | z | N + s t x 0 + ρ z p ¯ s p ¯ s t x 0 + ρ z ρ N s t x 0 + ρ z p ¯ s p ¯ s t x 0 + ρ z d z .

Note that for any x ∈ ℝN, it holds that N s t ( x ) p ¯ s p ¯ s t ( x ) 0 due to t ( x ) p ¯ and ( N + s t ( x ) ) p ¯ s p ¯ s t ( x ) = N + t ( x ) N + s p ¯ s p ¯ s t ( x ) > N + α , where α := N + p ¯ s p ¯ s 1 > 0 . Plugging this into (4.30) we obtain

R N B K ρ x 0 χ χ 0 ( N + s t ( x ) ) p ¯ s p ¯ s t ( x ) ρ N p s p ¯ s t ( x ) d x { | z | K } | z | N α d z = N B 1 α K α .

Combining this with (4.28) and (4.29) we derive

J 2 ( n , ρ ) C 3 K α p ¯ s p ¯ p ¯ s

for all n ϵ N and all ρ ( 0 , ε 0 2 K ) . Thus,

lim sup ρ 0 + lim sup n J 2 ( n , ρ ) C 3 K α p ¯ p ¯ p s .

Since K > 4 was chosen arbitrarily, the last inequality yields

(4.31) lim sup ρ 0 + lim sup n J 2 ( n , ρ ) = 0.

From (4.17), (4.27), and (4.31), we obtain (4.16) and the proof is complete.

Proof of Lemma 4.5. Let R>2 and decompose

(4.32) R N R N u n ( x ) p ( x , y ) ϕ R ( x ) ϕ R ( y ) p ( x , y ) | x y | N + s p ( x , y ) d y d x = B R c R N u n ( x ) p ( x , y ) ϕ R ( x ) ϕ R ( y ) p ( x , y ) | x y | N + s p ( x , y ) d y d x + B R R N u n ( x ) p ( x , y ) ϕ R ( x ) ϕ R ( y ) p ( x , y ) | x y | N + s p ( x , y ) d y d x =: I 1 ( n , R ) + I 2 ( n , R ) .

First, we estimate I 1 ( n , R ) . By rearranging

I 1 ( n , R ) = B R c R N u n ( x ) ϕ R ( x ) ϕ R ( y ) | x y | s p ( x , y ) 1 | x y | N d y d x ,

we easily get

(4.33) I 1 ( n , R ) B R c R N | u n ( x ) | p ¯ | ϕ R ( x ) ϕ R ( y ) | p ¯ | x y | s p ¯ + | u n ( x ) | p ( x ) | ϕ R ( x ) ϕ R ( y ) | p ( x ) | x y | s p ( x ) d y d x | x y | N = B R c R N | u n ( x ) | p ¯ | ϕ R ( x ) ϕ R ( y ) | p ¯ | x y | N + s p ¯ d y d x + B R c R N | u n ( x ) | p ( x ) | ϕ R ( x ) ϕ R ( y ) | p ( x ) | x y | N + s p ( x ) d y d x =: I 1 ( n , R , p ¯ ) + I 1 ( n , R , p ) .

By (4.2) and the boundedness of {un} in W s , p ( , ) ( R N ) , we can find M>0 such that

(4.34) max t { p ¯ , p } sup n N R N u n ( x ) t ( x ) d x M .

Let t { p ¯ , p } . We have

(4.35) I 1 ( n , R , t ) = B R c R N u n ( x ) t ( x ) ϕ R ( x ) ϕ R ( y ) t ( x ) | x y | N + s t ( x ) d y d x = B R c u n ( x ) t ( x ) { | x y | R } ϕ R ( x ) ϕ R ( y ) t ( x ) | x y | N + st ( x ) d y d x + B R c u n ( x ) t ( x ) { | x y | R } ϕ R ( x ) ϕ R ( y ) t ( x ) | x y | N + st ( x ) d y d x = : I 1 ( 1 ) ( n , R , t ) + I 1 ( 2 ) ( n , R , t ) .

We have

I 1 ( 1 ) ( n , R , t ) B R c u n ( x ) t ( x ) B R c d z | z | N + s t ( x ) d x = N B 1 B R c u n ( x ) t ( x ) s t ( x ) R s t ( x ) d x N B 1 s p R s p B R c u n ( x ) t ( x ) d x .

Combining this with (4.34) gives

(4.36) sup n N I 1 ( 1 ) ( n , R , t ) N B 1 M s p R s p .

On the other hand, using estimation:

(4.37) ϕ R ( x ) ϕ R ( y ) t ( x ) | x y | N + s t ( x ) | x y | N + ( 1 s ) t ( x ) ϕ R t ( x ) | x y | N + ( 1 s ) t ( x ) 2 R t ( x ) , ( x , y ) R N × R N , x y ,

we have

I 1 ( 2 ) ( n , R , t ) B R c u n ( x ) t ( x ) { | x y | R } 2 R t ( x ) | x y | N + ( 1 s ) t ( x ) d y d x = B R c u n ( x ) t ( x ) 2 R t ( x ) N B 1 R ( 1 s ) t ( x ) ( 1 s ) t ( x ) d x 2 p ¯ N B 1 1 s R s p B R c u n ( x ) t ( x ) d x .

Combining this and (4.34) yields

(4.38) sup n N I 1 ( 2 ) ( n , R , t ) 2 p ¯ N B 1 M 1 s R s p .

From (4.33), (4.35), (4.36) and (4.38) we obtain

sup n N I 1 ( n , R ) 2 p ¯ + 1 N B 1 M s ( 1 s ) R s p

and hence,

(4.39) lim R lim sup n I 1 ( n , R ) = 0

Next, we estimate I 2 ( n , R ) . Fix σ ( 0 , 1 / 2 ) and decompose

(4.40) I 2 ( n , R ) = B R B σ R | x y | R 2 u n ( x ) p ( x , y ) ϕ R ( x ) ϕ R ( y ) p ( x , y ) | x y | N + sp ( x , y ) d y d x + B R B σ R | x y | > R 2 u n ( x ) p ( x , y ) ϕ R ( x ) ϕ R ( y ) p ( x , y ) | x y | N + sp ( x , y ) d y d x + B σ R R N u n ( x ) p ( x , y ) ϕ R ( x ) ϕ R ( y ) p ( x , y ) | x y | N + sp ( x , y ) d y d x =: I 2 ( 1 ) ( n , R , σ ) + I 2 ( 2 ) ( n , R , σ ) + I 2 ( 3 ) ( n , R , σ ) .

Note that as in (4.37), we have

ϕ R ( x ) ϕ R ( y ) p ( x , y ) | x y | N + s p ( x , y ) | x y | N | | x y 1 s 2 R p ( x , y ) 2 p ¯ t p ¯ , p R t | x y | N + ( 1 s ) t , ( x , y ) R N × R N , x y .

Thus, for x B R B σ R we have

| x y | R 2 ϕ R ( χ ) ϕ R ( y ) p ( x , y ) | χ y | N + s p ( x , y ) d y 2 p ¯ t p ¯ , p | x y | R 2 R t | χ y | N + ( 1 s ) t d y 2 2 p ¯ N B 1 t p ¯ , p R s t ( 1 s ) t .

From this and (4.34) we obtain

(4.41) I 2 ( 1 ) ( n , R , σ ) B R B σ R u n ( x ) p ¯ + u n ( x ) p ( x ) | x y | R 2 ϕ R ( x ) ϕ R ( y ) p ( x , y ) | x y | N + s p ( x , y ) d y d x 2 1 + 2 p ¯ N B 1 ( 1 s ) p R s p B R B σ R u n ( x ) p ¯ + u n ( x ) p ( x ) d x 2 2 + 2 p ¯ N B 1 M ( 1 s ) p R s p , n N .

Using (4.34) again, we have

(4.42) I 2 ( 2 ) ( n , R , σ ) B R B σ R u n ( x ) p ¯ + u n ( x ) p ( x ) | x y | > R 2 d y | x y | N + s p ( x , y ) d x B R B σ R u n ( x ) p ¯ + u n ( x ) p ( x ) | z | > R 2 d z | z | N + s p d x 2 1 + s p N B 1 M s p R s p , n N .

Finally, to estimate I 2 ( 3 ) ( n , R , σ ) we first note that ϕ R ( x ) ϕ R ( y ) = 0 for all ( x , y ) B σ R × B R and | x y | ( 1 σ ) R for all ( x , y ) B σ R × B R c . Using these facts and invoking (4.34) again, we have

(4.43) I 2 ( 3 ) ( n , R , σ ) = B σ R B R c u n ( x ) p ( x , y ) ϕ R ( x ) ϕ R ( y ) p ( x , y ) | x y | N + s p ( x , y ) d y d x B σ R u n ( x ) p ¯ + u n ( x ) p ( x ) B R c d y | x y | N + s p ( x , y ) d x B σ R u n ( x ) p ¯ + u n ( x ) p ( x ) { | z | ( 1 σ ) R } d z | z | N + s p d x 2 N B 1 ( 1 σ ) s p M s p R s p .

Making use of (4.41)-(4.43), we deduce from (4.40) that

(4.44)limRlimsupnI2(n,R)=0.

Finally, (4.15) follows from (4.32), (4.39) and (4.44). The proof is complete.□

We now prove the first concentration-compactness principle.

Proof of Theorem 4.1. Let vn = un - u. Then,

(4.45)vn0inWs,p(,)(N).

Invoking Theorem 3.2, we deduce from (4.45) that

(4.46)vn0inLlocr()(N)

for any rC+(N) satisfying r(x)<p¯s for all xN . Hence, up to a subsequence we have

(4.47)vn(x)0fora.e.xN.

Using (4.6), (4.45), (4.47) and arguing as in [27], we have

(4.48)|vn|q(x)ν|u|q(x)=:ν¯inM(RN).

Obviously, vnp¯+RNvn(x)vn(y)pp(x,y)|xy|N+sp(x,y)dy is bounded in L1(RN) . So up to a subsequence, we have

(4.49)vnp¯+RNvn(x)vn(y)p(x,y)|xy|N+sp(x,y)dyμ¯ in MRN

for some nonnegative finite Radon measure μ̅ on ℝN. Let ϕCc(RN) and let R > 2 be such that

(4.50)supp(ϕ)BRandd:=dist(BRc,supp(ϕ))1+R2.

By (4.3), we have

(4.51)Sq||ϕvn||Lq()(RN)||ϕvn||s,p.

Set ν¯n:=|vn|q(x), μ¯n:=vn(x)p¯+RNvn(x)vn(y)p(x,y)|xy|N+sp(x,y)dy , and λn:=∥ϕvns,p . Let ε>0 be arbitrary and fixed. Then, there exists C(ε)(2,) such that

(4.52)|a+b|p(x,y)(1+ε)|a|p(x,y)+C(ε)|b|p(x,y),a,bR,x,yRN.

Invoking Proposition 3.1 and (4.52) we have

(4.53)1=RNϕvnλnp¯dx+RNRNϕvn(x)ϕvn(y)p(x,y)λnp(x,y)|xy|N+sp(x,y)dydxRNϕvnλnp¯dx+(1+ε)RNRN|ϕ(x)|p(x,y)vn(x)vn(y)p(x,y)λnp(x,y)|xy|N+sp(x,y)dydx+C(ε)RNRNvn(y)p(x,y)|ϕ(x)ϕ(y)|p(x,y)λnp(x,y)|xy|N+sp(x,y)dydx.

Set

In:=RNRNVn(y)p(x,y)|ϕ(x)ϕ(y)|p(x,y)λnp(x,y)|xy|N+sp(x,y)dydx.

Then, invoking Proposition 3.1 again we deduce from (4.53) that

(4.54)1(1+ε)(||ϕ||p¯+1)min{λnp¯,λnp}1+vns,pp¯+C(ε)In.

By the symmetry of P we also have

In=RNRNvn(x)p(x,y)|ϕ(x)ϕ(y)|p(x,y)λnp(x,y)|xy|N+sp(x,y)dydx.

Thus, by the facts that supp (Φ) ⊂ BR and λnp(x,y)min{λnp¯,λnp} for all x,yRN ,

(4.55)In1minλnp¯,λnpBRcvn(x)p(x)+vn(x)p¯BR|ϕ(x)ϕ(y)|p(x,y)|xy|N+sp(x,y)dydx+BRvn(x)p+(x)+vn(x)p¯BRc|ϕ(x)ϕ(y)|p(x,y)|xy|N+sp(x,y)dydx+BRvn(x)p(x)+vn(x)p¯BR|ϕ(x)ϕ(y)|p(x,y)|xy|N+sp(x,y)dydx.

We estimate each integral in the right-hand side of (4.55) as follows. Arguing as that obtained (4.34) we have

(4.56)maxtp¯,psupnNRNvn(x)t(x)dxC1.

Here and in the rest of the proof, Ci (i є ℕ) denotes a positive constant independent of n and R while Ci (i є ℕ) denotes a positive constant independent of n. Let t{p¯,p} . Using (4.50) and (4.56), we have

(4.57)BRcvn(x)t(x)BR|ϕ(x)ϕ(y)|p(x,y)|xy|N+sp(x,y)dydx=BRcvn(x)t(x)supp(ϕ)|ϕ(y)|p(x,y)|xy|N+sp(x,y)dydx1+ϕp¯BRcvn(x)t(x)supp(ϕ)dyR2N+sp(x,y)dx1+ϕp¯R2N+spBRRNvn(x)t(x)dxC2Rsp.

Before estimating the remaining integrals, we note that by (4.50) again,

(4.58)BRc|ϕ(x)ϕ(y)|p(x,y)|xy|N+sp(x,y)dy=BRc|ϕ(x)|p(x,y)|xy|N+sp(x,y)dy1+ϕp¯{|z|1}dz|z|N+sp=1+ϕp¯N|B1|sp,xBR.

Using (4.58), we have

(4.59)BR|vn(x)|t(x)(BRc|ϕ(x)ϕ(y)|p(x,y)|xy|N+sp(x,y)dy)dxC3BR|vn(x)|t(x)dx.

To estimate the last integral in the right-hand side of (4.55) we notice that for xBR,

Bg|ϕ(χ)ϕ(y)|p(x,y)|xy|N+sp(x,y)dy1+ϕp¯BRdy|xy|N+(s1)p(x,y)1+ϕp¯BR1+1|xy|N+(s1)pdy1+ϕp¯BR+B2Rdz|z|N+(s1)p=1+ϕp¯BR+NB1(2R)(1s)p(1s)p.

This yields

BRvn(x)t(x)BR|ϕ(x)ϕ(y)|p(x,y)|xy|N+sp(x,y)dydxC4(R)BRvn(x)t(x)dx.

Using this, (4.57) and (4.59), we obtain from (4.55) that

(4.60)InC5min{λnp¯,λnp}1Rsp+C6(R)t{p¯,p} BR |vn(x)|t(x)x.

Combining this with (4.56) and the boundedness of {vn} in Ws,p(,)(RN) , we deduce from (4.54) that

1C7(R)min{λnp¯,λnp}

and hence

λnC8(R),nN.

Thus {λn is a bounded sequence in ℝ and hence, up to a subsequence, we may assume that there exists λ* ∈ [0, ∞) such that

(4.61)limnλn=λ.

Suppose that λ* > 0. From (4.53) and (4.60) we obtain

1(1+ε)RNϕ(x)λnp(x)+ϕ(x)λnpvn(x)p¯+RNvn(x)vn(y)p(x,y)|xy|N+sp(x,y)dydx+C5minλnp¯,λnp1Rsp+C6(R)t{p¯,p}BRvn(x)t(x)dx.

Letting n → ∞ in the last inequality, noticing (4.49), (4.61) and limnBR |vn(x)|t(x)dx=0 for t{p¯,p} (see (4.46)), we obtain

1(1+ε)RN ϕλp(x)+ϕλp¯dμ¯+C5min{λp¯,λp}Rsp.

Letting R → ∞ and then letting ε0+ , we deduce from the last inequality that

1RN ϕλp(x)+ϕλp¯dμ¯.

Invoking Proposition 2.2, we easily obtain from the last estimate that

λ21pmax||ϕ||Lμ¯p()(RN),||ϕ||Lμ¯p¯(RN).

From (4.48), (4.51), (4.61) and the last inequality, we arrive at

(4.62)Sq||ϕ||Lν¯q()(RN)21pmax||ϕ||Lμ¯p()(RN),||ϕ||Lμ¯p¯(RN).

If λ* = then by (4.48) and (4.51), we get ||ϕ||Lν¯q()(RN)=0 ; hence, (4.62) also holds. That is, (4.62) holds for any ϕCc(N) and hence, (4.8) follows by invoking Proposition 6.1 and the definition of ν¯ (see (4.48)).

The fact that {xi}iIC can be obtained by an argument similar to that of [27, Theorem 3.3] and we omit the proof. Next, we obtain the relation (4.9). Let i є l and for ρ>0 , define ψρ as in Lemma 4.4 with x0 replaced by xi. Thus ψρC(N) , 0ψρ1 , ψρ1 on Bρ(xi) , supp(ψρ)B2ρ(xi) . Using (4.3) again, we have

Sq||ψρun||Lq()(N)ψρuns,p.

Taking the limit inferior as n → ∞ in the above inequality and using (4.6) we obtain

(4.63)SqψρLvq(.)B2ρxilim infnψρuns,p.

Hence,

(4.64)Sqlimsupρ0+||ψρ||Lνq()(B2ρ(xi))limsupρ0+liminfnψρuns,p.

Invoking Proposition 2.2, we have

(4.65)ψρLνq()(B2ρ(xi))min(B2ρ(xi)|ψρ|q(x)dν)1qi,ρ+,(B2ρ(xi)|ψρ|q(x)dν)1qi,ρminν(Bρ(xi))1qi,ρ+,ν(Bρ(xi))1qi,ρ,

where qi,ρ+:=maxxBρ(xi)¯q(x) , qi,ρ:=minxBρ(xi)¯q(x) . Thus, we obtain a lower bound of the left-hand side of (4.64) as follows:

(4.66)lim supρ0+||ψρ||Lνq()(B2ρ(xi))νi1q(xi)=νi1p¯s

due to the continuity of q and the fact that xiC . To obtain an upper bound of the right-hand side of (4.64), we first prove that there exist ρ0(0,1) and λ0(0,) such that

(4.67)0<Sq2vi1qx1lim infnλn,ρ=:λ,ρλ0 for any ρ0,ρ0,

where λn,ρ:=∥ψρuns,p. Indeed, by the continuity of q and the positiveness of νi, we can choose ρ0(0,1) such that

(4.68)Sqminνi1qi,ρ+,νi1qi,ρ>Sq2νi1q(xi),ρ(0,ρ0)

From (4.63), (4.65) and (4.68), we infer Sq2νi1q(xi)λ*,ρ for all ρ(0,ρ0). On the other hand, by choosing ρ0 smaller if necessary we have

(4.69)limsupnNN|un(y)|p(x,y)|ψρ(x)ψρ(y)|p(x,y)|xy|N+sp(x,y)yx<1,ρ(0,ρ0)

in view of Lemma 4.4. Note that

(4.70)RNψρunp¯dx+RNRNψρun(x)ψρun(y)p(x,y)|xy|N+sp(x,y)dydxRNψρunp¯dx+2p¯1RNRNψρ(x)p(x,y)un(x)un(y)p(x,y)|xy|N+sp(x,y)dydx+2p¯1RNRNun(y)p(x,y)ψρ(x)ψρ(y)p(x,y)|xy|N+sp(x,y)dydx.

Using (4.69), (4.70), the boundedness of {un} in Ws,p(,)(RN) and invoking Proposition 3.1, we can easily show that there exists λ0(0,) such that λn,ρ<λ0 for all n ϵ ℕ and ρ(0,ρ0) . Thus, (4.67) has been proved. Next, let ε>0 be arbitrary and fixed. We have

1=RNψρunλn,ρp¯dx+RNRNψρun(x)ψρun(y)p(x,y)λn,ρp(x,y)|xy|N+sp(x,y)dydx=RNψρunλn,ρp¯dx+2B2pxiRNB2ρxiψρun(x)ψρun(y)p(x,y)λn,ρp(x,y)|xy|N+sp(x,y)dydx+B2ρxiB2pxiψρun(x)ψρun(y)p(x,y)λn,ρp(x,y)|xy|N+sp(x,y)dydx.

Hence, by utilizing (4.52) again we have

1RNψρunλn,ρp¯ dx+2B2pxiRNB2pxjun(x)λn,ρp(x,y)ψρ(x)ψρ(y)p(x,y)|xy|N+sp(x,y)dy dx+(1+ε)B2ρxiB2px1ψρ(x)p(x,y)un(x)un(y)p(x,y)λn,ρp(x,y)|xy|N+sp(x,y)dy dx+C(ε)B2px1B2pxiun(y)λn,ρp(x,y)ψρ(x)ψρ(y)p(x,y)|xy|N+sp(x,y)dy dx.

Combining this with the fact that 0ψρ1 yields

(4.71)1C(ε)minλn,ρp,λn,ρpi,ρRNRNun(x)p(x,y)ψρ(x)ψρ(y)p(x,y)|xy|N+sp(x,y)dydx+1+εminλn,ρp¯,λn,ρpiRNψρ(x)Un(x)dx,

where pi=inf(x,y)B2ρ(xi)×B2ρ(xi)p(x,y) . Here and in what follows, for brevity we denote

(4.72)Un(x):=|un(x)|p¯+RN|un(x)un(y)|p(x,y)|xy|N+sp(x,y)dy,xRN,nN.

Using (4.67), we deduce from (4.71) that

1C(ϵ)min{λ,ρp¯,λ,ρpi}lim supnRNRNun(x)p(x,y)|ψρ(x)ψρ(y)|p(x,y)|xy|N+sp(x,y)dydx+1+ϵmin{λ,ρp¯,λ,ρpi}RNψρdμ,ρ(0,ρ0).

Hence,

minλ,ρp¯,λ,ρptC(ε)lim supnR2Nun(x)p(x,y)ψρ(x)ψρ(y)p(x,y)|xy|N+5p(x,y)dydx+(1+ε)RNψρdμ.

Taking limit superior as ρ0+ in the last inequality and invoking Lemma 4.4, we obtain

λp¯(1+ε)μii.e.,λ(1+ε)1p¯μi1p¯,

where λ*:=limsupρ0+λ*,ρ and μi:=limρ0+μ(B2ρ(xi)) . Combining this with (4.64) and (4.66) together with the fact that ε was chosen arbitrarily we obtain (4.9). Hence, {xi}iI are also atoms of 𝜇.

Finally, to obtain (4.7) we note that for each ϕC0(N) , ϕ0 , the functional

uRNϕ(x)|u(x)|p¯+RN|u(x)u(y)|p(x,y)|xy|N+sp(x,y)dydx

is convex and differentiable on Ws,p(,)(RN) . From this and (4.5) we infer

RNϕ(x)|u(x)|p¯+RN|u(x)u(y)|p(x,y)|xy|N+sp(x,y)dydxlim infnRNϕ(x)un(x)p¯+RNun(x)un(y)p(x,y)|xy|N+sp(x,y)dydx=RNϕdμ.

Thus,

μ|u|p+RN|u(x)u(y)|p(x,y)|xy|N+sp(x,y)dy.

Extracting 𝜇 to its atoms, we get (4.7) and the proof is complete.

We conclude this section by proving Theorem 4.2.

Proof of Theorem 4.2. For each R > 0, define ϕR as in Lemma 4.5. Thus ϕRCc(N) , 0ϕR1 , ϕR0 on BR and ϕR1 on B2Rc , and ||ϕR||2R. In order to obtain (4.13), we decompose

(4.73)RNUn(x)dx=RNϕR(x)Un(x)dx+RN1ϕR(x)Un(x)dx,

where Un is given by (4.72). By (4.11) and the fact that

B2RcUn(x)dxRNϕR(x)Un(x)dxBRcUn(x)dx

for all n ϵ N and R > 0, we obtain

(4.74)μ=limRlim supnRNϕR(x)Un(x)dx.

On the other hand, the fact that 1ϕRCc(RN) gives

(4.75)limnRN1ϕR(x)Un(x)dx=RN1ϕR(x)dμ.

Meanwhile,

limRRNϕR(x)dμ=0

in view of the Lebesgue dominated convergence theorem. From the last two equalities, we obtain

limRlimnRN1ϕR(x)Un(x)dx=μRN.

From this and (4.73)-(4.75) we obtain (4.13).

In order to prove (4.12), we decompose

(4.76)RNun(x)q(x)dx=RNϕRq(x)un(x)q(x)dx+RN1ϕRq(x)un(x)q(x)dx.

From the definition (4.10) of ν and the estimate

B2Rcun(x)q(x)dxRNϕRq(x)un(x)q(x)dxBRcun(x)q(x)dx

for all n ϵ N and R > 0, we deduce

(4.77)v=limRlim supnRNϕRq(x)(x)un(x)q(x)dx.

Arguing as that obtained (4.13) above for which ϕR is replaced with ϕRq(x) , we obtain (4.12).

We conclude the proof by proving (4.14). Without loss of generality we assume ν>0. Let ε(0,1) be arbitrary and fixed. By (ε), we can choose R1 > 1 such that

(4.78)p(x,y)p¯|<εand|q(x)q|<εfor all|x|,|y|>R1.

From (4.3), we have

(4.79)Sq||ϕRun||Lq()(RN)||ϕRun||s,p.

For R > R1, using (4.78) and Proposition 2.2 we have

ϕRunLq()(RN)=ϕRunLq()(BRc)min(BRcϕRq(x)|un|q(x)dx)1q+ϵ,(BRcϕRq(x)|un|q(x)dx)1qϵmin(B2Rc|un|q(x)dx)1q+ϵ,(B2Rc|un|q(x)dx)1qϵ.

Thus,

(4.80)lim infRlim supnϕRunLq()(RN)minν1q+ϵ,ν1qϵ.

Next, we estimate the right-hand side of (4.79). To this end, denote σn,R:=∥ϕRuns,p for brevity. We will show that there exist R2(R1,) and σ(0,) such that

(4.81)0<Sq14v14ω0,R:=limnsupnR<0,RR2,.

Indeed, we first choose ε¯>0 sufficiently small such that

(4.82)min{(ν2)1q+ε¯,(ν2)1qε¯}>(ν4)1q.

Then we can find R¯2>R1 such that

(4.83)ϕRunLq()(RN)min{(BRcϕRq(x)|un|q(x)dx)1q+ϵ¯,(BRcϕRq(x)|un|q(x)dx)1qϵ¯}

for all R>R¯2 . Finally, by (4.77), we can find R2>R¯2 such that

(4.84)lim supnRNϕRq(x)unq(x)dx=lim supnBRcϕRq(x)unq(x)dx>v2

for all R>R¯2 . From (4.83) and (4.84) we get

lim supnϕRunLq()RNminv214+z¯,V21qε¯

and hence, by (4.82),

lim supnϕRunLq()RNV41q

for all R>R2 . This and (4.79) yield Sq(14ν)1qσ,R for all R(R2,) . By a similar argument to that obtained (4.67), invoking Lemma 4.5 and choosing R2 larger if necessary, we can show that there exists σ(0,) such that σ,R<σ for all R(R2,) . Thus, (4.81) has been proved.

We now turn to estimate the right-hand side of (4.79). For each R>R2 given, let nk=nk(R) (k=1,2,) be a sequence such that

(4.85)limkσnk,R=lim supnσn,R=σ,R.

Utilizing Proposition 3.1 and (4.52) again, we have

1=RNϕR(x)unk(x)p¯σnk,Rp¯dx+RNRNϕRunk(x)ϕRunk(y)p(x,y)σnk,Rp(x,y)|xy|N+sp(x,y)dxdy=RNϕR(x)p¯unk(x)p¯σnk,Rp¯dx+2BRcBRϕR(x)p(x,y)unk(x)p(x,y)σnk,Rp(x,y)|xy|N+sp(x,y)dydx+BRcBRcϕRunk(x)ϕRunk(y)p(x,y)σnkp(x,y)|xy|N+sp(x,y)dydxBRcϕR(x)p¯unk(x)p¯σnk,Rp¯dx+2BRcBRunk(x)p(x,y)σnk,Rp(x,y)ϕR(x)ϕR(y)p(x,y)|xy|N+sp(x,y)dydx+C(ε)BRcBRcunk(x)p(x,y)σnk,Rp(x,y)ϕR(x)ϕR(y)p(x,y)|xy|N+sp(x,y)dydx+(1+ε)BRcBRcϕR(y)p(x,y)σnk,Rp(x,y)unk(x)unk(y)p(x,y)|xy|N+sp(x,y)dxdy.

This and the fact that 0ϕR1 yield

1C(ε)minσnk,Rp¯,σnk,RpBRcRNunk(x)p(x,y)ϕR(x)ϕR(y)p(x,y)|xy|N+sp(x,y)dydx+1+εminσnk,Rp¯+ε,σnk,Rp¯εBRcϕR(x)Unk(x)dx.

Taking limit superior as k → ∞ in the last inequality with noticing (4.81) and (4.85) we obtain

(4.86)C(ε)minσ,Rp¯,σ,Rplim supnBRcRNun(x)p(x,y)ϕR(x)ϕR(y)p(x,y)|xy|N+sp(x,y)dydx+1+εminσ,Rp¯+ε,σ,Rp¯εlim supnBRcϕR(x)Un(x)dx.

Now, taking the limit as R → ∞ in (4.86) with taking Lemma 4.5 and (4.74) into account, we deduce

11+εminσp¯+ε,σp¯εμ, i.e., σ(1+ε)1pεmaxμ1p¯+εμ1p¯+ε,

where σ:=lim infRσ,R and hence, 0 < σ* < σ due to (4.81). From this, (4.79) and (4.80) we obtain

Sqminv1q+ε,v1qε(1+ε)1p¯εmaxμ1p+ε¯,μ1μ¯ε.

Since ε was chosen arbitrarily in the last inequality, (4.14) follows. The proof of Theorem 4.2 is complete.□

5 Application

5.1 The existence of solutions

In this section, we investigate the existence and multiplicity of solutions to the following problem

(5.1)Lu+|u|p(x)2u=f(x,u)+λ|u|q(x)2u in RN,uWs,p(,)RN,

where s,p,q satisfy (𝒫2), (𝒬2) and (ε) with p+ < q; the operator 𝓛 is defined as in (1.2); 𝜆 is a positive real parameter; and the nonlinear term f satisfies the following assumptions.

(𝓕1) f:RN×RR is a Carathéodory function such that f is odd with respect to the second variable.

(𝓕2) There exist functions rj,aj with rjC+(RN) , infxRN[q(x)rj(x)]>0, ajL+q()q()rj()(RN)(j=1,,m) , and max1jmrj+>p such that

|f(x,u)|j=1m aj(x)|u|rj(x)1fora.e.xRNand alluR.

(𝓕3) There exist Bε(x0) and aL+q()q()p+(Bε(x0)) such that sup|u|M|F(x,u)|L1Bεx0 for each M > 0, and

lim|u|F(x,u)a(x)|u|p+=uniformly for a.e.xBε(x0),

where F(x,u):=0uf(x,τ)dτ.

(𝓕4) There exist α[p+,q) and gL+1(N) such that

αF(x,u)f(x,u)ug(x)for a.e.xNand allu.

A trivial example for f(x,u) satisfying (F1)(F4) is f(x,u)=a(x)|u|r(x)2u with rC+(N) such that p+<r and infxN[q(x)r(x)]>0, and aLq()q()r()(RN) with a(x)>0 a.e. on some ball BN.

We say that uWs,p(,)(RN) is a (weak) solution of problem (5.1) if

RNRN|u(x)u(y)|p(x,y)2(u(x)u(y))(v(x)v(y))|xy|N+sp(x,y)dxdy+RN|u|p(x)2uvdx=RNf(x,u)vdx+λRN|u|q(x)2uvdx,vWs,p(,)RN.

By Theorems 3.3 and 3.4, this definition is clearly well defined under assumptions (F1)(F2). Our main existence result is stated as follows.

Theorem 5.1

Let (𝒫2), (𝒬2) and (ε) hold with p+<q. If (F1)(F4) are fulfilled, then there exists a sequence {λk}k=1 of positive real numbers with λk+1<λk for all k ϵ ℕ such that for any λ(λk+1,λk), problem (5.1) admits at least k pairs of nontrivial solutions.

5.2 Proof of Theorem 5.1

In order to prove Theorem 5.1, we will make use of the following abstract result for symmetric C1 functionals, which is a variant of Theorem 2.19 in [33] (see also [34, Theorem 10.20]).

Lemma 5.2

([33]) Let E=VX, where E is a real Banach space and V is finite dimensional. Suppose that JC1(E,) is an even functional satisfying J(0)=0 and

(𝓙1) there exist constants ρ,β>0 such that J(u)β for all uBρX;

(𝓙2) there exists a subspace of E with dimV<dimE˜< and {uE˜:J(u)0} is bounded in E;

(𝓙3) for 𝛽 and respectively given in (𝓙1) and (𝓙2), J satisfies the (PS)c condition for any c[0,L] with L:=supuE˜J(u).

Then J possesses at least dimE˜dimV pairs of nontrivial critical points.

Proof

The proof is similar to that of [34, Theorem 10.20] for which we take Em in the proof of [34, Lemma 10.19] as Em=span{e1,,em}, where {ek}k=1dimE~ is a basis of .

To determine solutions to problem (5.1), we will apply Lemma 5.2 for E:=Ws,p(,)(RN) endowed with the norm :=s,p and J=Jλ, where Jλ:E is the energy functional associated with problem (5.1) defined as

(5.2)Jλ(u):=RNRN|u(x)u(y)|p(x,y)p(x,y)|xy|N+sp(x,y)dxdy+RN1p¯|u|p¯dxRNF(x,u)dxλRN1q(x)|u|q(x)dx,uE.

It is clear that under the assumptions (F1)(F2), Jλ is of class C1(E,) and its Fréchet derivative Jλ':EE is given by

(5.3)Jλ(u),v=RNRN|u(x)u(y)|p(x,y)2(u(x)u(y))(v(x)v(y))|xy|N+sp(x,y)dxdy+RN|u|p¯2uvdxRNf(x,u)vdxλRN|u|q(x)2uvdx,u,vE.

Here, E and , denote the dual space of E and the duality pairing between E and E, respectively. Clearly, Jλ is even in E, Jλ(0)=0, and each critical point of Jλ is a solution to problem (5.1). The next lemma will be utilized for verifying (𝓙3).

Lemma 5.3

For any given λ>0, Jλ satisfies the (PS)c condition provided

(5.4)c<1α1qminSq(qh)+,Sq(qh)minλh+,λhg1α,

where h(x):=p¯q(x)p¯ for x ∈ ℝN and Sq is defined as in (4.3).

Proof

Let {un} be a (PS)c sequence for Jλ with c satisfying (5.4). We first claim that {un} is bounded in E. Indeed, by (F4) and invoking Proposition 3.1 we have that for n large,

c+1+unJλun1αJλun,unRNRN1p(x,y)1αun(x)un(y)p(x,y)|xy|N+sp(x,y)dxdy+RN1p¯1α|u|p¯dx+λRN1α1q(x)|un|q(x)x+RN1αf(x,un)unF(x,un)xλ1α1qRN|un|q(x)dx1αg1.

That is,

(5.5)λ1α1qRNunq(x)dxC1+un, for all nN large. .

Here and in the remaining proof, Ci (i є ℕ) denotes a positive constant independent of n. On the other hand, by the relation between modular and norm (see Proposition 3.1) and (𝓕2) we have that for n large,

1p¯unp1Jλun+RNFx,undx+λRN1q(x)unq(x)dxc+1+j=1mRNaj(x)rj(x)unrj(x)dx+λqRNunq(x)dx.

Then, by the Young inequality we easily get

(5.6)unpC21+RN|un|q(x)x.

From (5.5) and (5.6) we obtain

unpC31+un, for all nN large. 

This implies the boundedness of {un} since p>1 and hence,

(5.7)C:=supnNRNRN|un(x)un(y)|p(x,y)|xy|N+sp(x,y)dxdy+RN|un|p¯dx<

in view of Proposition 3.1. Then, invoking Theorems 3.2, 4.1 and 4.2, up to a subsequence, we have

(5.8)un(x)u(x)for a.e.xN,
(5.9)unuinE,
(5.10)Un(x)μU(x)+iIμiδxiinM(RN),
(5.11)|un|q(x)ν=|u|q(x)+iIνiδxiinM(N),
(5.12)Sqνi1p¯sμi1p¯,iI,

where Un(x):=un(x)p¯+RNun(x)un(y)p(x,y)|xy|N+sp(x,y)dy and U(x):=|u(x)|p¯+RN|u(x)u(y)|p(x,y)|xy|N+sp(x,y)dy for n ϵ ℕ and x ∈ ℝN. Moreover, we have

(5.13)limsupnNUn(x)x=μ(N)+μ,
(5.14)lim supnRN|un|q(x)dx=v(RN)+v,
(5.15)Sqν1qμ1p¯.

We will show that I= and ν=0. For this purpose we invoke (F4) to estimate

c=limn[Jλ(un)1αJλ(un),un](1α1q)λlimsupnN|un|q(x)xg1α.

Combining this with (5.14) gives

(5.16)c(1α1q)λ[ν(N)+ν]g1α.

We now suppose on the contrary that I=. Let i є l and for ρ>0, define ψρ as in Lemma 4.4 with x0 replaced by xi. For an arbitrary and fixed 𝜌, it is not difficult to see that {unψρ} is a bounded sequence in E. Hence,

on(1)=Jλ(un),unψρ=RNψρUnxλRNψρ|un|q(x)dxRNf(x,un)unψρx+RNRNun(x)un(y)p(x,y)2un(x)un(y)un(y)ψρ(x)ψρ(y)|xy|N+sp(x,y)dx dy.

This yields

(5.17)|Nψρ(x)μλNψρ(x)ν|limsupn|I1(n,ψρ)|+limsupn|I2(n,ψρ)|,

where

I1(n,ψρ):=Nf(x,un)unψρx

and

I2(n,ψρ):=RNRN|un(x)un(y)|p(x,y)2(un(x)un(y))un(y)(ψρ(x)ψρ(y))|xy|N+sp(x,y)dxdy.

Note that the boundedness of {un} in E implies the boundedness of {un} in Lq()(RN) due to Theorem 3.3. Hence, from (𝓕2) and invoking Propositions 2.2 and 2.3 we have

(5.18)I1n,ψρj=1mRNaj(x)unrj(x)ψρdxj=1m2ajLq()q()rj()(B2ρ(xi))|un|rjLq()rj()(B2ρ(xi))j=1m2ajLq()q()rj()(B2ρ(xi))1+unLq()(RN)rj+C4j=1majLq()q()rj()(B2ρ(xi)),nN.

Here and in the remaining proof, Ci(iN) denotes a positive constant independent of n and ρ From (5.18), we obtain

(5.19)limsupρ0+lim supnI1n,ψρ=0.

In order to estimate I2(n,ψρ), let δ > 0 be arbitrary and fixed. By (5.7) and the Young inequality we have

(5.20)I2n,ψρδRNRNun(x)un(y)p(x,y)|xy|N+sp(x,y)dxdy+C5RNRNun(y)p(x,y)ψρ(x)ψρ(y)p(x,y)|xy|N+sp(x,y)dxdyCδ+C5RNRNun(y)p(x,y)ψρ(x)ψρ(y)p(x,y)|xy|N+sp(x,y)dxdy.

Taking limit superior in (5.20) as n → ∞ then taking limit superior as ρ → 0+ with taking Lemma 4.4 into account, we arrive at

limsupρ0+lim supnI2n,ψρCδ.

Since δ > 0 was chosen arbitrarily we obtain

(5.21)limsupρ0+lim supnI2n,ψρ=0.

Now, by taking limit superior in (5.17) as ρ → 0+ with taking (5.19) and (5.21) into account, we obtain

μi=λνi.

Plugging this into (5.12) we get

μiSq(xi)p¯q(xi)p¯λp¯q(xi)p¯.

This yields

(5.22)λνi=μimin{S(qh)+,S(qh)}min{λh+,λh}.

From (5.22) and (5.16), we obtain

c1α1qλvig1α1α1qminS(qh)+,S(qh)minλh+,λhg1α,

which is a contradiction to (5.4), and hence, I = ∅. Next, we prove that ν=0. Suppose on the contrary that ν>0. Let ϕR be the same as in Lemma 4.5. Using a similar argument to that obtained (5.17), we arrive at

(5.23)lim supnRNϕRUndxλlim supnRNϕRunq(x)dx+lim supnI3n,ϕR+lim supnI4n,ϕR,

and

(5.24)λlim supnRNϕRunq(x)dxlim supnRNϕRUndx+lim supnI3n,ϕR+lim supnI4n,ϕR,

where

I3n,ϕR:=RNfx,ununϕRdx

and

I4n,ϕR:=RNRNun(x)un(y)p(x,y)2un(x)un(y)un(y)ϕR(x)ϕR(y)|xy|N+sp(x,y)dxdy.

We claim that

(5.25)limRlim supn|I3(n,ϕR)|=0

and

(5.26)limRlim supn|I4(n,ϕR)|=0.

Indeed, the equality (5.25) can be obtained in a similar fashion to (5.19). To prove (5.26), we proceed as in (5.20) to get

I4n,ϕRCδ+C5RNRNun(y)p(x,y)ϕR(x)ϕR(y)p(x,y)|xy|N+sp(x,y)dxdy

for each δ > 0 arbitrary and fixed. Taking limit superior in the last estimate as n → ∞ and then taking limit as R → ∞ with taking Lemma 4.5 into account, we obtain

limRlim supn|I4(n,ϕR)|Cδ.

Since δ > 0 in the last inequality can be taken arbitrarily we deduce (5.26). Using (5.25) and (5.26) and letting R → ∞ in (5.23) and (5.24) we obtain

(5.27)μ=λν.

Here we have used (4.74) and the fact that

v=limRlim supnRNunq(x)ϕRdx,

which can be seen by using ϕR in place of ϕRq(x) in (4.76). Combining (5.27) with (5.15) gives

(5.28)λν=μSqp¯qp¯λp¯qp¯.

The fact that q=lim|x|q(x)[q,q+] yields

(qh)qp¯qp¯(qh)+andhp¯qp¯h+.

From this and (5.28) one has

λνmin{S(qh)+,S(qh)}min{λh+,λh}.

Utilizing this estimate we deduce from (5.16) that

c1α1qλνg1α1α1qmin{S(qh)+,S(qh)}min{λh+,λh}g1α,

which is a contradiction to (5.4), and hence; ν=0.

Combining the facts that I = ∅ and ν=0. with (5.11) and (5.14), we obtain

lim supnRNunq(x)dx=RN|u|q(x)dx.

Invoking the Fatou lemma we get from (5.8) that

RN|u|q(x)dxlim infnRNunq(x)dx.

Thus,

limnRNunq(x)dx=RN|u|q(x)dx.

By a Brezis-Lieb type result for the Lebesgue spaces with variable exponents (see e.g., [27, Lemma 3.9]), it follows from the last equality and (5.8) that

R N u n u q ( x ) d x 0 ,  i.e.,  u n u  in  L q ( ) R N .

Consequently, we have R N | u n | q ( x ) 2 u n ( u n u ) d x 0 by invoking Proposition 2.3 and the boundedness of {un} in L q ( ) ( R N ) . Also, we easily obtain R N f x , u n u n u d x 0 by using (𝓕2), (5.9), Proposition 2.3 and Theorem 3.4. We therefore have

R N R N | u n ( x ) u n ( y ) | p ( x , y ) 2 ( u n ( x ) u n ( y ) ) ( ( ( u n u ) ( x ) ( u n u ) ( y ) ) | x y | N + s p ( x , y ) d x d y + R N | u n | p ¯ 2 u n ( u n u ) d x = J λ ( u n ) , u n u + R N f ( x , u n ) ( u n u ) d x + λ R N | u n | q ( x ) 2 u n ( u n u ) d x 0.

Hence, unu in E in view of [9, Lemma 4.2 (i)]. The proof is complete. □

We now conclude this section by proving Theorem 5.1.

Proof of Theorem 5.1. We will show that conditions ( J 1 ) ( J 3 ) of Lemma 5.2 are fulfilled with E := W s , p ( , ) ( R N ) and J = J𝜆. In order to verify (ℐ1), let { e n } n = 1 be a Schauder basis of E and let { e n } n = 1 E be such that for each n ϵ ℕ,

e n ( u ) = α n for u = k = 1 α k e k E .

For each k ϵ ℕ, define

V k := u E : e n ( u ) = 0 , n > k , X k := u E : e n ( u ) = 0 , n k ,

and

(5.29) ξ k := sup u X k u 1 max 1 j m u L r j ( ) ( a j , R N ) .

Then,

E = V k X k , k N .

Since X k + 1 X k (k ϵ ℕ), we have

0 ξ k + 1 ξ k , k N .

Thus, the sequence {ξk} converges to some ξ* as k → ∞. We claim that ξ* = 0. Indeed, for each k ϵ ℕ there exists u k X k such that u k ∥≤ 1 and

(5.30) 0 ξ k max 1 j m u k L r j ( ) ( a j , R N ) + 1 k .

Since {uk} is bounded in E, up to a subsequence we have

(5.31) u k u in E

and hence, by Theorem 3.4,

(5.32) u k u  in  L r j ( ) a j , R N , j { 1 , , m } .

From (5.31) and the definition of Xk we have that for any n ϵ ℕ,

(5.33) e n , u = lim k e n , u k = 0.

This yields u = 0. This fact together with (5.32) and (5.30) infer ξ* = 0. That is, we have just proved that

(5.34) lim k ξ k = 0.

For uXk with u ∥= ρ k > 1 , by (𝓕2) and invoking Proposition 2.2 and Theorem 3.4 we have

(5.35) J λ ( u ) 1 p ¯ u p 1 j = 1 m 1 r j R N a j ( x ) | u | r j ( x ) d x λ q R N | u | q ( x ) d x 1 p ¯ u p 1 p ¯ 1 r j = 1 m u L r j ( ) ( a j , R N ) r + + 1 λ q max u L q ( ) ( R N ) q + , u L q ( ) ( R N q 1 p ¯ u p m r ξ k r + u r + 1 p ¯ + m r max S q q + , S q q q λ u q + ,

where r := min 1 j m r j and r + := max 1 j m r j + . Let ρ k > 0 be such that

m r ξ k r + ρ k r + = 1 2 p ¯ ρ k p i .e ., ρ k = r 2 m p ¯ ξ k r + 1 r + p .

Note that ξk → 0 as k → ∞ by (5.34) and hence, ρk as k → ∞. Thus, we can fix k0 such that

(5.36) ρ k 0 > 1 and 1 2 p ¯ ρ k 0 p 1 p ¯ + m r > 1 4 p ¯ ρ k 0 p .

Then, (5.35) yields

(5.37) J λ ( u ) 1 4 p ¯ ρ k 0 p max S q q + , S q q q ρ k 0 q + λ , u X k 0 B ρ k 0 .

Therefore, by choosing V := Vk0, X :=Xk0 and λ := q ρ k 0 p q + 4 p ¯ max S q q + , S q q , we have that for any λ ∈ (0,λ*),

J λ ( u ) β , u X B ρ

with ρ = ρk0 and β = max S q q + , S q q ρ k 0 q + q λ λ . That is, Jλ verifies (ℐ1) in Lemma 5.2.

Next, we show that Jλ verifies (ℐ2) and (ℐ3) in Lemma 5.2. Let ( y k , φ k ) be the kth eigenpair of the following eigenvalue problem

Δ u = y u  in  B ε x 0 , u = 0  on  B ε x 0 .

Extend φ k ( x ) to ℝN by putting φ k ( x ) = 0 for x R N B ε ( x 0 ) . Clearly, { φ k } E . Define

E k := span φ 1 , , φ k ( k N ) .

Let k ϵ ℕ be arbitrary and fixed. We claim that there exists Rk > 0 independent of 𝜆 such that

(5.38) J λ ( u ) 0 , u E k B R k .

Indeed, since all norms on Ek are equivalent we can find ζ k > 0 such that

(5.39) ζ k u u L p ¯ ( a , B ϵ ( x 0 ) ) , u E k .

Choose θk > 0 such that

(5.40) 1 p θ k ζ k p ¯ < 0.

By (𝓕3), we can choose M k > 0 such that

F ( x , u ) θ k a ( x ) | u | p ¯ for a .e . x B ε ( x 0 ) and all | u | M k .

This infers

(5.41) F ( x , u ) θ k a ( x ) | u | p ¯ sup | u | M k | F ( x , u ) |  for a.e.  x B ε x 0  and all  u R .

From (5.40), (5.41) and invoking Proposition 2.2 again, we have that for uEk with u R k > 1 ,

J λ ( u ) 1 p u p ¯ θ k B ϵ ( x 0 ) a ( x ) | u | p ¯ d x + B ϵ ( x 0 ) sup | t | M k | F ( x , t ) | d x 1 p θ k ζ k p ¯ u p ¯ + B ϵ ( x 0 ) sup | t | M k | F ( x , t ) | d x < 0

provided Rk large enough. Clearly, Rk can be chosen independently of 𝜆. That is, we have just obtained (5.38). Noting J λ ( 0 ) = 0 , we deduce from (5.38) that

sup u E k J λ ( u ) = max u E k u R k J λ ( u ) max u B R k R N R N | u ( x ) u ( y ) | p ( x , y ) p ( x , y ) | x y | N + s p ( x , y ) d x d y + R N 1 p ¯ | u | p ¯ d x R N F ( x , u ) d x =: L k .

It is clear that for all k ϵ ℕ, Lk is independent of 𝜆 and Lk ϵ [0, ∞) due to (𝓕2). Finally, let { λ k } k = 1 ( 0 , λ ) be such that for any k ϵ ℕ,

(5.42) L k 0 + k < 1 a 1 q min S q ( q h ) + , S q ( q h ) min λ k h + , λ k h g 1 α , λ k + 1 < λ k .

Then, for any λ(λk+1,λk) we have

Lk0+k<(1α1q)min{Sq(qh)+,Sq(qh)}min{λh+,λh}g1α

and hence, Jλ satisfies the (PS)c for any c ϵ [0, Lk0+k] in view of Lemma 5.3. Thus, Jλ satisfies (ℐ2) and (ℐ3) with E˜=Ek0+k and L=Lk0+k. So, Jλ admits at least dimE˜dimV=k pairs of nontrivial critical points in view of Lemma 5.2; hence, problem (5.1) has at least k pairs of nontrivial solutions. The proof is complete.

A An auxiliary result

In this appendix, we state a result for the Radon measures on ℝN, which is necessary for proving Theorem 4.1.

Proposition A.1

Let p, q, r ϵ C+(ℝN) such that inf x R N { r ( x ) max { p ( x ) , q ( x ) } } > 0. Let μ ν be two finite and nonnegative Radon measures onN such that

ϕ L v r ( · ) R N C max ϕ L μ p ( · ) R N , ϕ L μ q ( · ) R N , ϕ C c R N ,

for some constant C > 0. Then there exist an at most countable set { x i } i I of distinct point in ℝN and { ν i } i I (0, ∞) such that

ν=iIνiδxi.

In order to prove Proposition 6.1, we will make use of the following result.

Lemma A.2

Let p,q,rC+(N) such that infxN{r(x)max{p(x),q(x)}}>0. Let ν be a finite nonnegative Radon measure onN such that

ϕ L ν r ( ) ( R N ) C max { ϕ L ν p ( ) ( R N ) , ϕ L ν q ( ) ( R N ) } , ϕ C c ( R N ) .

Then v = 0 or there exist { x i } i = 1 n of distinct points in ℝN and { ν i } i = 1 n ( 0 , ) such that ν = i = 1 n ν i δ x i .

The proof of Lemma 6.2 is similar to that of [27, Lemma 3.8] and using this result we can prove Proposition 6.1 via the same method as in [21, Lemma 3.2] and we leave the proofs to the reader.

Acknowledgements

The first author was supported by University of Economics Ho Chi Minh City, Vietnam. The second author was supported by the Basic Science Research Program through the National Research Foundation of Korea (NRF) funded by the Ministry of Education (NRF-2019R1F1A1057775).

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Received: 2020-01-19
Accepted: 2020-10-16
Published Online: 2020-12-08

© 2021 Y.-H. Kim and K. Ho, published by De Gruyter

This work is licensed under the Creative Commons Attribution 4.0 International License.

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