An analogue of Ruzsa's conjecture for polynomials over finite fields
Introduction
Let denote the set of positive integers and let . A strong form of a conjecture by Ruzsa is the following assertion. Suppose that satisfies the following 2 properties:
- (P1)
mod p for every prime p and every ;
- (P2)
.
Theorem 1.1 Hall-Ruzsa, 1971
Suppose that satisfies (P1) and then f is a polynomial.
The best upper bound was obtained in 1996 by Zannier [18] by extending earlier work of Perelli and Zannier [17], [13]: Theorem 1.2 Zannier, 1996 Suppose that satisfies (P1) and then f is a polynomial.
This paper is motivated by our recent work on D-finite series [3] and a review of Ruzsa's conjecture. From now on, let be the finite field of order q and characteristic p, let , and let . We have the usual degree map . A map is called a polynomial map if it is given by values on of an element of . For every , let , , and . Let be the set of irreducible polynomials; the sets , , and are defined similarly. The superscript + is used to denote the subset consisting of all the monic polynomials, for example , , , etc. From the well-known identity [14, pp. 8]: we have for every . In view of the reasoning behind Ruzsa's conjecture, it is natural to ask the following:
Question 1.3 Let satisfy the following 2 properties: for every and ; .
Is it true that f is a polynomial map?
Note that (P3) should be the appropriate analogue of (P1): over the natural numbers, iterating (P1) yields for every and prime p. On the other hand, over , due to the presence of characteristic p, iterating the congruence condition for and is not enough to yield (P3). By the following example that is similar to the one by Hall-Woodall, we have that the upper bound q in (P4) cannot be increased. Fix a total order ≺ on such that whenever . We define inductively. First, we assign arbitrary values of g at the constant polynomials. Let , , and assume that we have defined for every with such that: For every , let with such that mod P. By the Chinese Remainder Theorem, there exists a unique with such that mod P for every . Then we define It is not hard to prove that g satisfies Property (P3) (with g in place of f) and for every , , we have by (1). This latter property implies that g cannot be a polynomial map.
Following Professor Ruzsa's suggestion, we have: Definition 1.4 Property (P3) is called the prime congruence-preserving condition. A map with this property is called a prime congruence-preserving map.
Our main result implies the affirmative answer to Question 1.3; in fact we can replace (P4) by the much weaker condition that is not too small compared to : Theorem 1.5 Let be a prime congruence-preserving map such that Then f is a polynomial map.
There is nothing special about the constant in (2) and one can certainly improve it by optimizing the estimates in the proof. It is much more interesting to know if the function in (2) can be replaced by a larger function (see Section 4). There are significant differences between Ruzsa's conjecture and Question 1.3 despite the apparent similarities at first sight. Indeed none of the key techniques in the papers [13], [18] seem to be applicable in our situation. Obviously, the crucial result used in [18] that the generating series is D-finite has no counterpart here. The proof of the main result of [13] relies on a nontrivial linear recurrence relation of the form . Over the integers, such a relation will allow one to determine for every once one knows . On the other hand, for Question 1.3, while it seems possible to imitate the arguments in [13] to obtain a recurrence relation of the form for with and , such a relation does not seem as helpful: when is large, one cannot use the relation to relate to the values of f at smaller degree polynomials. Finally, the technical trick of using the given congruence condition to obtain the vanishing on from the vanishing on (see [13, pp. 11–12] and [18, pp. 396–397]) does not seem applicable here.
The proof of Theorem 1.5 consists of 2 steps. The first step is to show that the points for belong to an algebraic plane curve over , then it follows that can be bounded above by a linear function in . The second step, which might be of independent interest, treats the more general problem in which f is prime congruence-preserving and there exists a special sequence in such that is bounded above by a linear function in . Both steps rely on the construction of certain auxiliary polynomials; such a construction has played a fundamental role in diophantine approximation, transcendental number theory, and combinatorics. For examples in number theory, the readers are referred to [1], [12] and the references therein. In combinatorics, the method of constructing polynomials vanishing at certain points has recently been called the Polynomial Method and is the subject of the book [9]. This method has produced surprisingly short and elegant solutions of certain combinatorial problems over finite fields [7], [5], [8].
Acknowledgments. We are grateful to Professor Imre Ruzsa for his interest and helpful suggestions. We wish to thank Dr. Carlo Pagano, Professor Umberto Zannier, and the anonymous referee for the useful comments. J. B is partially supported by the NSERC Discovery Grant RGPIN-2016-03632. K. N. is partially supported by the NSERC Discovery Grant RGPIN-2018-03770, a start-up grant at UCalgary, and the CRC tier-2 research stipend 950-231716.
Section snippets
A nontrivial algebraic relation
We start with the following simple lemma: Lemma 2.1 Let and assume that there exists such that the following 3 properties hold: for every and . for every with . for every .
Then g is identically 0.
Proof
Otherwise, assume there is of smallest degree such that . We have . Since for every and since for every monic irreducible polynomial P of degree at most D there is some C such that has
A result under a linear bound
In this section, we consider a related result in which the inequality (2) is replaced by a much stronger linear bound on where is a special sequence in . Moreover, the next theorem together with Corollary 2.3 yield Theorem 1.5.
Theorem 3.1 Let be a prime congruence-preserving map. Assume there exist with (i.e. U is not the p-th power of an element of ) and positive integers and such that for every . Then f is a polynomial map.
For every
A further question
As mentioned in the introduction, it is an interesting problem to strengthen 1.5 by replacing the function in (2) by a larger function. Let which is the degree of the product of all monic irreducible polynomials of degree at most n. It seems reasonable to ask the following: Question 4.1 Suppose is a prime congruence-preserving map and there exists such that for all sufficiently large n, for all of degree n, we have Is it true that f is
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