Appendix
Here, we provide proofs for the \(L^2(\Gamma _\epsilon )\) trace inequality (Lemma 5) and the higher regularity estimate (Lemma 9).
We first recall the following lemma, which will be used throughout “Appendix.”
Lemma 11
(Sobolev inequality) Let \(\varOmega _{\epsilon }=\mathbb {R}^3\backslash \overline{\varSigma _{\epsilon }}\) be as in Sect. 2.1. For any \({\varvec{u}}\in D^{1,2}(\varOmega _{\epsilon })\), we have
$$\begin{aligned} \Vert {\varvec{u}}\Vert _{L^6(\varOmega _{\epsilon })} \le C\Vert \nabla {\varvec{u}}\Vert _{L^2(\varOmega _{\epsilon })}, \end{aligned}$$
(A.1)
where C depends only on \(c_\Gamma \) and \(\kappa _{\max }\).
The proof of \(\epsilon \)-independence of C appears in Appendix A.2.4 of [18].
1.1 Proof of Lemma 5
The proof of the \(L^2(\Gamma _\epsilon )\) trace inequality follows the same outline as the proof of Lemma 4, contained in Appendix A.2.1 of [18]. In particular, using the \(\epsilon \)-independent \(C^2\)-diffeomorphisms \(\psi _j\) (defined in Appendix A.2.1, [18]) which map segments of the curved slender body \(\varSigma _\epsilon \) to a straight cylinder, it suffices to show the \(\sqrt{\epsilon }\left|\log \epsilon \right|\) dependence of the trace constant for a straight cylinder.
Accordingly, let \(\mathcal {D}_\rho \subset \mathbb {R}^2\) denote the open disk of radius \(\rho \) in \(\mathbb {R}^2\), centered at the origin, and, for some \(a<\infty \), define the cylindrical surface \(\Gamma _{\epsilon ,a}=\partial \mathcal {D}_\epsilon \times [-a,a]\) and the cylindrical shell \(\mathcal {C}_{\epsilon ,a}= (\mathcal {D}_1\backslash \overline{\mathcal {D}_\epsilon }) \times [-a,a]\). Consider the function space
$$\begin{aligned} D^{1,2}_\Gamma (\mathcal {C}_{\epsilon ,a})= \big \{ {\varvec{u}}\in D^{1,2}(\mathcal {C}_{\epsilon ,a}) \; : \; {\varvec{u}}\big |_{\partial \mathcal {C}_{\epsilon ,a}\backslash \Gamma _{\epsilon ,a}} = 0 \big \}. \end{aligned}$$
As in the proof of Lemma 4, it suffices to show the \(\sqrt{\epsilon }\left|\log \epsilon \right|\) dependence of the \(L^2(\Gamma _{\epsilon ,a})\) trace constant for functions belonging to \(D^{1,2}_\Gamma (\mathcal {C}_{\epsilon ,a})\).
By estimate (A.4) in [18], any \({\varvec{u}}\in C^1(\mathcal {C}_{\epsilon ,a}) \cap C^0(\overline{\mathcal {C}_{\epsilon ,a}})\cap D^{1,2}_\Gamma (\mathcal {C}_{\epsilon ,a})\) satisfies
$$\begin{aligned} \left|\mathrm{Tr}({\varvec{u}}) \right|^2 \le \left|\log \epsilon \right| \int _\epsilon ^1 \left|\frac{\partial {\varvec{u}}}{\partial \rho } \right|^2 \rho \, {\text {d}}\rho . \end{aligned}$$
Then, noting that the surface element on \(\Gamma _{\epsilon ,a}\) is simply \(\epsilon \), we have
$$\begin{aligned} \left\Vert \mathrm{Tr}({\varvec{u}}) \right\Vert _{L^2(\Gamma _{\epsilon ,a})}^2&= \int _{-a}^a \int _0^{2\pi } \left|\mathrm{Tr}({\varvec{u}}) \right|^2 \epsilon \, {\text {d}}\theta \, {\text {d}}s \\&\le \epsilon \left|\log \epsilon \right| \int _{-a}^a \int _0^{2\pi }\int _\epsilon ^1 \left|\frac{\partial {\varvec{u}}}{\partial \rho } \right|^2 \rho \, {\text {d}}\rho \, {\text {d}}\theta \, {\text {d}}s \le \epsilon \left|\log \epsilon \right|\left\Vert \nabla {\varvec{u}} \right\Vert _{L^2(\mathcal {C}_{\epsilon ,a})}^2. \end{aligned}$$
The same result for \({\varvec{u}}\in D^{1,2}_\Gamma (\mathcal {C}_{\epsilon ,a})\) follows by density.
1.2 Proof of Lemma 9
To determine the \(\epsilon \)-dependence of the constant in (5.3), it suffices to work locally near the slender body surface and show that Lemma 9 holds within an \(\epsilon \)-independent region about the slender body centerline. We define the region
$$\begin{aligned} \mathcal {O} = \big \{{\varvec{x}}\in \varOmega _{\epsilon } \; : \; {\varvec{x}}= {\varvec{X}}(s) + \rho {\varvec{e}}_{\rho }(s,\theta ), \quad \epsilon< \rho <r_{\max } \big \}, \end{aligned}$$
(A.2)
where \(r_{\max }\) is as in Sect. 2.1. Within \(\mathcal {O}\), we can use the orthonormal frame (2.2). We will use the notation \(\partial _s,\partial _\theta ,\partial _\rho \) to denote derivatives \(\partial /\partial s\), \(\partial /\partial \theta \), \(\partial /\partial \rho \) with respect to the variables \(s,\theta ,\rho \), defined with respect to the orthonormal frame. We verify the \(\epsilon \)-dependence in the bound for \(\nabla ^2{\varvec{u}}^{\mathrm{p}}\) and \(\nabla p^{\mathrm{p}}\) in two parts: we first show an \(L^2\) bound for derivatives \(\nabla (\partial _s{\varvec{u}}^{\mathrm{p}})\), \(\nabla (\partial _\theta {\varvec{u}}^{\mathrm{p}})\), \(\partial _s p^{\mathrm{p}}\), and \(\partial _\theta p^{\mathrm{p}}\) in directions tangent to the slender body surface \(\Gamma _\epsilon \), and then use these bounds to estimate the derivatives \(\nabla (\partial _\rho {\varvec{u}}^{\mathrm{p}})\), \(\partial _\rho p^{\mathrm{p}}\) normal to \(\Gamma _\epsilon \).
We begin by estimating the tangential derivatives \(\nabla (\partial _s{\varvec{u}}^{\mathrm{p}})\) and \(\nabla (\partial _\theta {\varvec{u}}^{\mathrm{p}})\). Since the derivatives \(\partial _s\) and \(\partial _\theta \) with respect to the orthonormal frame (2.2) do not commute with the “straight” differential operators \(\nabla \) and \(\mathrm{{div}\,}\), we will need to make use of the following commutator bounds.
Proposition 1
(Commutator estimates) For any function \({\varvec{u}}\in D^{1,2}_0(\mathcal {O})\) and for each of the differential operators \(D=\mathrm{{div}\,},\, \nabla ,\, \mathcal {E}(\cdot )\), the following commutator estimates hold:
$$\begin{aligned} \left\Vert [D,\partial _\theta ]{\varvec{u}} \right\Vert _{L^2(\mathcal {O})}&\le C\left\Vert \nabla {\varvec{u}} \right\Vert _{L^2(\mathcal {O})}, \quad \left\Vert [D,\partial _s]{\varvec{u}} \right\Vert _{L^2(\mathcal {O})} \le C\left\Vert \nabla {\varvec{u}} \right\Vert _{L^2(\mathcal {O})}, \end{aligned}$$
where the constant C depends only on \(c_\Gamma \), \(\kappa _{\max }\), and \(\xi _{\max }\).
Proof
We begin by denoting
$$\begin{aligned} {\varvec{e}}_\theta (s,\theta )&= -\sin \theta {\varvec{e}}_{n_1}(s) + \cos \theta {\varvec{e}}_{n_2}(s),\\ u_\rho&= {\varvec{u}}\cdot {\varvec{e}}_\rho , \; u_\theta ={\varvec{u}}\cdot {\varvec{e}}_\theta , \; u_s = {\varvec{u}}\cdot {\varvec{e}}_t. \end{aligned}$$
Then, with respect to the orthonormal frame (2.2), the divergence and gradient are given by
$$\begin{aligned} \mathrm{{div}\,}{\varvec{u}}&= \frac{1}{1-\rho \widehat{\kappa }} \bigg ( \frac{1}{\rho } \frac{\partial (\rho (1-\rho \widehat{\kappa })u_\rho )}{\partial \rho } + \frac{1}{\rho }\frac{\partial ((1-\rho \widehat{\kappa })u_\theta )}{\partial \theta } + \frac{\partial u_s}{\partial s} \bigg ), \\ \nabla {\varvec{u}}&= {\varvec{e}}_\rho (s,\theta )\frac{\partial {\varvec{u}}}{\partial \rho }^{\mathrm{T}} + {\varvec{e}}_\theta (s,\theta )\frac{1}{\rho }\frac{\partial {\varvec{u}}}{\partial \theta }^{\mathrm{T}} + {\varvec{e}}_t(s)\frac{1}{1-\rho \widehat{\kappa }} \bigg (\frac{\partial {\varvec{u}}}{\partial s} -\kappa _3 \frac{\partial {\varvec{u}}}{\partial \theta } \bigg )^{\mathrm{T}}, \end{aligned}$$
where
$$\begin{aligned} \widehat{\kappa }(s,\theta ) = \kappa _1(s)\cos \theta + \kappa _2(s)\sin \theta . \end{aligned}$$
(A.3)
Direct computation of the commutators yields
$$\begin{aligned}{}[\mathrm{{div}\,},\partial _\theta ]{\varvec{u}}&= \frac{(\partial _\theta \widehat{\kappa })}{1-\rho \widehat{\kappa }}\bigg ( \rho \,\mathrm{{div}\,}{\varvec{u}}- \frac{1}{\rho }\frac{\partial }{\partial \rho } \big (\rho ^2 u_\rho \big ) - \frac{\partial u_\theta }{\partial \theta } \bigg ) - \frac{(\partial _\theta ^2\widehat{\kappa })}{1-\rho \widehat{\kappa }}u_\theta , \\ [\mathrm{{div}\,},\partial _s]{\varvec{u}}&= \frac{(\partial _s\widehat{\kappa })}{1-\rho \widehat{\kappa }}\bigg ( \rho \,\mathrm{{div}\,}{\varvec{u}}- \frac{1}{\rho }\frac{\partial }{\partial \rho } \big (\rho ^2 u_\rho \big ) - \frac{\partial u_\theta }{\partial \theta } \bigg ) - \frac{(\partial _\theta \partial _s\widehat{\kappa })}{1-\rho \widehat{\kappa }}u_\theta , \\ [\nabla ,\partial _\theta ]{\varvec{u}}&= {\varvec{e}}_\theta \frac{\partial {\varvec{u}}}{\partial \rho }^{\mathrm{T}} - {\varvec{e}}_\rho \frac{1}{\rho }\frac{\partial {\varvec{u}}}{\partial \theta }^{\mathrm{T}} + {\varvec{e}}_t\frac{\rho (\partial _\theta \widehat{\kappa })}{(1-\rho \widehat{\kappa })^2} \bigg (\frac{\partial {\varvec{u}}}{\partial s} -\kappa _3 \frac{\partial {\varvec{u}}}{\partial \theta } \bigg )^{\mathrm{T}}, \\ [\nabla ,\partial _s]{\varvec{u}}&= (\partial _s{\varvec{e}}_\rho )\frac{\partial {\varvec{u}}}{\partial \rho }^{\mathrm{T}} + (\partial _s{\varvec{e}}_\theta )\frac{1}{\rho }\frac{\partial {\varvec{u}}}{\partial \theta }^{\mathrm{T}} + \bigg ({\varvec{e}}_t \frac{\rho (\partial _s\widehat{\kappa })}{1-\rho \widehat{\kappa }}+(\partial _s{\varvec{e}}_t) \bigg )\\&\qquad \frac{1}{1-\rho \widehat{\kappa }} \bigg (\frac{\partial {\varvec{u}}}{\partial s} -\kappa _3 \frac{\partial {\varvec{u}}}{\partial \theta } \bigg )^{\mathrm{T}}. \end{aligned}$$
Using (A.3) and the orthonormal frame ODEs (2.2), we have
$$\begin{aligned} \left|\partial _\theta \widehat{\kappa } \right|&= \left|-\kappa _1\sin \theta + \kappa _2\cos \theta \right|\le \kappa _{\max }, \quad \left|\partial _s \widehat{\kappa } \right| = \left|\kappa _1'\cos \theta +\kappa _2'\sin \theta \right|\\&\le \xi _{\max } + 2(\kappa _{\max }+\pi ), \\ \left|\partial _\theta ^2\widehat{\kappa } \right|&= \left|-\widehat{\kappa } \right|\le \kappa _{\max }, \quad \left|\partial _\theta \partial _s \widehat{\kappa } \right| = \left|-\kappa _1'\sin \theta + \kappa _2'\cos \theta \right|\\&\le \xi _{\max }+ 2(\kappa _{\max }+\pi ), \\ \left|\partial _s {\varvec{e}}_\rho \right|&= \left|-\widehat{\kappa }{\varvec{e}}_t + \kappa _3{\varvec{e}}_\theta \right|\le \kappa _{\max } +\pi , \quad \left|\partial _s{\varvec{e}}_\theta \right| = \left|-(\partial _\theta \widehat{\kappa }){\varvec{e}}_t -\kappa _3{\varvec{e}}_t \right|\\&\le \kappa _{\max } +\pi , \\ \left|\frac{1}{1-\rho \widehat{\kappa }} \right|&\le \frac{1}{1- r_{\max }\kappa _{\max }(\cos \theta +\sin \theta ) } \le \frac{1}{1- \frac{1}{2\kappa _{\max }}\kappa _{\max }\sqrt{2} } \le 4 . \end{aligned}$$
Finally, noting that, by Lemma 11,
$$\begin{aligned} \left\Vert u_\theta \right\Vert _{L^2(\mathcal {O})} \le \left|\mathcal {O} \right|^{1/3} \left\Vert {\varvec{u}} \right\Vert _{L^6(\mathcal {O})} \le C\left\Vert \nabla {\varvec{u}} \right\Vert _{L^2(\mathcal {O})}, \end{aligned}$$
the desired \(L^2(\varOmega )\) bounds follow for each of \(D=\mathrm{{div}\,},\nabla \). The estimate for the symmetric gradient \(\mathcal {E}({\varvec{u}})\) then follows from the gradient commutator bound. \(\square \)
Now, to derive an estimate for \(\nabla (\partial _s{\varvec{u}}^{\mathrm{p}})\), we will make use of Definition 3 with a particular test function \({\varvec{\varphi }}\), which we will construct here. First, we want our test function to be supported only within \(\mathcal {O}\). We define a smooth cutoff function
$$\begin{aligned} \psi (\rho ) = {\left\{ \begin{array}{ll} 1, &{} \rho < r_{\max }/4, \\ 0, &{} \rho > r_{\max }/2, \end{array}\right. } \quad \left|\frac{\partial \psi }{\partial \rho } \right| \le C, \end{aligned}$$
(A.4)
where C depends only on \(r_{\max }\). Note that \(\psi (\rho )\) commutes with both \(\partial _\theta \) and \(\partial _s\).
We would like to use \(\partial _s^2(\psi {\varvec{u}}^{\mathrm{p}})\) as a test function in Definition 3, but it will be more convenient to work with a function which vanishes on \(\Gamma _\epsilon \). We therefore construct a correction \({\varvec{g}}\in C^2(\varOmega _\epsilon )\) supported only in \(\mathcal {O}\) and satisfying
$$\begin{aligned} {\varvec{g}}\big |_{\Gamma _\epsilon } = (\partial _s {\varvec{u}}^{\mathrm{p}})\big |_{\Gamma _\epsilon } = {\varvec{\omega }}^{\mathrm{p}}\times {\varvec{e}}_t(s), \quad \left\Vert \nabla {\varvec{g}} \right\Vert _{L^2(\mathcal {O})} \le C\left|{\varvec{\omega }} \right|, \end{aligned}$$
(A.5)
where C depends on \(c_\Gamma \) and \(\kappa _{\max }\). To build \({\varvec{g}}\), we follow a similar construction used in Section 4.1 of [18]. We define
$$\begin{aligned} {\varvec{g}}_0(\rho ,\theta ,s) = {\left\{ \begin{array}{ll} {\varvec{\omega }}^{\mathrm{p}}\times {\varvec{e}}_t(s) &{} \text {if } \rho <4\epsilon , \\ 0 &{} \text {otherwise} \end{array}\right. } \end{aligned}$$
and take
$$\begin{aligned} {\varvec{g}}(\rho ,\theta ,s):= \phi _\epsilon (\rho ){\varvec{g}}_0(\rho ,\theta ,s), \end{aligned}$$
where \(\phi _\epsilon (\rho )\) is the smooth cutoff defined in (4.3)–(4.4). Note that \({\varvec{g}}\in C^2\) and is supported within the region
$$\begin{aligned} \mathcal {O}_\epsilon := \big \{ {\varvec{X}}(s) + \rho {\varvec{e}}_\rho (s,\theta ) \; : \; s\in \mathbb {T}, \, \epsilon \le \rho \le 4\epsilon , \, 0\le \theta <2\pi \big \}, \end{aligned}$$
where \(\left|\mathcal {O}_\epsilon \right| \le C\epsilon ^2\). Then, using (4.4) and (2.2), we have
$$\begin{aligned} \left\Vert \nabla {\varvec{g}} \right\Vert _{L^2(\mathcal {O})}&\le \sqrt{\left|\mathcal {O}_\epsilon \right|}\left\Vert \nabla {\varvec{g}} \right\Vert _{C(\mathcal {O}_\epsilon )} \\&\le \sqrt{\left|\mathcal {O}_\epsilon \right|}\bigg ( \left\Vert \frac{\partial \phi _\epsilon }{\partial \rho } \right\Vert _{C(\mathcal {O}_\epsilon )}\left\Vert {\varvec{g}}_0 \right\Vert _{C(\mathcal {O}_\epsilon )}+ \left\Vert \frac{1}{1-\rho \widehat{\kappa }}\frac{\partial {\varvec{g}}_0}{\partial s} \right\Vert _{C(\mathcal {O}_\epsilon )} \bigg ) \le C\left|{\varvec{\omega }}^{\mathrm{p}} \right|. \end{aligned}$$
Now, we could just use \(\partial _s(\partial _s(\psi {\varvec{u}}^{\mathrm{p}}) -{\varvec{g}})\) as a test function in Definition 3, but it will actually be useful to include a second correction term in the following way. We consider \({\varvec{z}}\in D^{1,2}_0(\mathcal {O})\) satisfying
$$\begin{aligned} \begin{aligned} \mathrm{{div}\,}{\varvec{z}}&= \mathrm{{div}\,}(\psi \partial _s{\varvec{u}}^{\mathrm{p}} -{\varvec{g}}) \quad \text {in } \mathcal {O}, \\ \left\Vert \nabla {\varvec{z}} \right\Vert _{L^2(\mathcal {O})}&\le C\left\Vert \mathrm{{div}\,}(\psi \partial _s{\varvec{u}}^{\mathrm{p}} -{\varvec{g}}) \right\Vert _{L^2(\mathcal {O})} \end{aligned} \end{aligned}$$
(A.6)
for C depending only on \(c_\Gamma \) and \(\kappa _{\max }\). We know that such a \({\varvec{z}}\) exists due to [6], Section III.3, and the constant C is independence of \(\epsilon \) due to Appendix A.2.5 of [18]. Furthermore, since \(\mathrm{{div}\,}{\varvec{u}}^{\mathrm{p}}=0\), by Proposition 1 we have
$$\begin{aligned} \left\Vert \mathrm{{div}\,}(\psi \partial _s{\varvec{u}}^{\mathrm{p}}-{\varvec{g}}) \right\Vert _{L^2(\mathcal {O})}&\le \left\Vert \mathrm{{div}\,}(\partial _\theta {\varvec{u}}^{\mathrm{p}}) \right\Vert _{L^2(\mathcal {O})}+ C\left\Vert \partial _\theta {\varvec{u}}^{\mathrm{p}} \right\Vert _{L^2(\mathcal {O})}+\left\Vert \nabla {\varvec{g}} \right\Vert _{L^2(\mathcal {O})} \\&\le \left\Vert [\mathrm{{div}\,},\partial _\theta ]{\varvec{u}}^{\mathrm{p}} \right\Vert _{L^2(\mathcal {O})} + C\left\Vert \partial _\theta {\varvec{u}}^{\mathrm{p}} \right\Vert _{L^2(\mathcal {O})} + C\left|{\varvec{\omega }}^{\mathrm{p}} \right| \\&\le C\left\Vert \nabla {\varvec{u}}^{\mathrm{p}} \right\Vert _{L^2(\mathcal {O})} + C\left|{\varvec{\omega }}^{\mathrm{p}} \right|. \end{aligned}$$
Here, we have also used that \(\left\Vert \partial _\theta {\varvec{u}}^{\mathrm{p}} \right\Vert _{L^2(\mathcal {O})} \le \left\Vert \rho \nabla {\varvec{u}}^{\mathrm{p}} \right\Vert _{L^2(\mathcal {O})} \le r_{\max }\left\Vert \nabla {\varvec{u}}^{\mathrm{p}} \right\Vert _{L^2(\mathcal {O})}\). In particular, \({\varvec{z}}\) satisfying (A.6) also satisfies
$$\begin{aligned} \left\Vert \nabla {\varvec{z}} \right\Vert _{L^2(\mathcal {O})} \le C\left\Vert \nabla {\varvec{u}}^{\mathrm{p}} \right\Vert _{L^2(\mathcal {O})} + C\left|{\varvec{\omega }}^{\mathrm{p}} \right|. \end{aligned}$$
(A.7)
Using extension by zero to consider \({\varvec{z}}\) as a function over all \(\varOmega _\epsilon \), we can now construct our desired test function for use in Definition 3. In particular, we will use the function \(\partial _s(\partial _s(\psi {\varvec{u}}^{\mathrm{p}})-{\varvec{g}}-{\varvec{z}})\) in place of \({\varvec{\varphi }}\) in Definition 3. Note that by definition of \({\varvec{z}}\), this function may only belong to \(L^2(\varOmega _\epsilon )\). In this case, we can make sense of the following integration-by-parts argument using finite differences rather than full derivatives (see [2], Section III.2.7 for construction of finite difference operators along a curved boundary). Thus, we really only need \(\partial _s(\psi {\varvec{u}}^{\mathrm{p}})-{\varvec{g}}-{\varvec{z}}\in D^{1,2}(\varOmega _\epsilon )\) to make sense of the following result. Note that in integrating by parts, we will also need to make use of the fact that, for \(i=s,\theta \),
$$\begin{aligned} \partial _i ({\text {d}}{\varvec{x}}) = -\frac{\rho \partial _i\widehat{\kappa }}{1-\rho \widehat{\kappa }} {\text {d}}{\varvec{x}}:= \mathcal {J}_i \, {\text {d}}{\varvec{x}}, \quad \left|\mathcal {J}_i \right| \le C; \quad i=s,\theta , \end{aligned}$$
(A.8)
where C depends on \(c_\Gamma \), \(\kappa _{\max }\), and \(\xi _{\max }\).
Then, using \(\partial _s(\partial _s(\psi {\varvec{u}}^{\mathrm{p}})-{\varvec{g}}-{\varvec{z}})\) in Definition 3, we have
$$\begin{aligned} 0&= \int _{\mathcal {O}} \bigg (2\mathcal {E}({\varvec{u}}^{\mathrm{p}}): \mathcal {E}\big (\partial _s(\partial _s(\psi {\varvec{u}}^{\mathrm{p}})-{\varvec{g}}-{\varvec{z}}) \big ) - p^{\mathrm{p}} \,\mathrm{{div}\,}(\partial _s(\partial _s(\psi {\varvec{u}}^{\mathrm{p}})-{\varvec{g}}-{\varvec{z}})) \bigg ) \, {\text {d}}{\varvec{x}}\\&= \int _{\mathcal {O}} 2\mathcal {E}({\varvec{u}}^{\mathrm{p}}): \partial _s\mathcal {E}(\partial _s(\psi {\varvec{u}}^{\mathrm{p}})-{\varvec{g}}-{\varvec{z}}) \, {\text {d}}{\varvec{x}}+ \int _{\mathcal {O}} 2\mathcal {E}({\varvec{u}}^{\mathrm{p}}): [\mathcal {E}(\cdot ),\partial _s](\partial _s(\psi {\varvec{u}}^{\mathrm{p}})-{\varvec{g}}-{\varvec{z}}) \, {\text {d}}{\varvec{x}}\\&\qquad - \int _{\mathcal {O}} p^{\mathrm{p}} \,\partial _s(\mathrm{{div}\,}(\partial _s(\psi {\varvec{u}}^{\mathrm{p}})-{\varvec{g}}-{\varvec{z}})) \, {\text {d}}{\varvec{x}}- \int _{\mathcal {O}} p^{\mathrm{p}} \,[\mathrm{{div}\,},\partial _s](\partial _s(\psi {\varvec{u}}^{\mathrm{p}})- {\varvec{g}}-{\varvec{z}}) \, {\text {d}}{\varvec{x}}\\&= -\int _{\mathcal {O}} 2\partial _s\mathcal {E}({\varvec{u}}^{\mathrm{p}}): \mathcal {E}(\partial _s(\psi {\varvec{u}}^{\mathrm{p}})-{\varvec{g}}-{\varvec{z}}) \, {\text {d}}{\varvec{x}}-\int _{\mathcal {O}} 2\mathcal {E}({\varvec{u}}^{\mathrm{p}}): \mathcal {E}(\partial _s(\psi {\varvec{u}}^{\mathrm{p}})-{\varvec{g}}-{\varvec{z}}) \, \mathcal {J}_s \, {\text {d}}{\varvec{x}}\\&\qquad + \int _{\mathcal {O}} 2\mathcal {E}({\varvec{u}}^{\mathrm{p}}): [\mathcal {E}(\cdot ),\partial _s](\partial _s(\psi {\varvec{u}}^{\mathrm{p}})-{\varvec{g}}-{\varvec{z}}) \, {\text {d}}{\varvec{x}}- \int _{\mathcal {O}} p^{\mathrm{p}} \,[\mathrm{{div}\,},\partial _s](\partial _s(\psi {\varvec{u}}^{\mathrm{p}})- {\varvec{g}}-{\varvec{z}}) \, {\text {d}}{\varvec{x}}\\&= -\int _{\mathcal {O}} 2\mathcal {E}(\partial _s{\varvec{u}}^{\mathrm{p}}):\mathcal {E}(\partial _s(\psi {\varvec{u}}^{\mathrm{p}})-{\varvec{g}}-{\varvec{z}}) \, {\text {d}}{\varvec{x}}- \int _{\mathcal {O}} 2\mathcal {E}({\varvec{u}}^{\mathrm{p}}): \mathcal {E}(\partial _s(\psi {\varvec{u}}^{\mathrm{p}})-{\varvec{g}}-{\varvec{z}}) \, \mathcal {J}_s \, {\text {d}}{\varvec{x}}\\&\qquad +\int _{\mathcal {O}} 2[\mathcal {E}(\cdot ),\partial _s]{\varvec{u}}^{\mathrm{p}}: \mathcal {E}(\partial _s(\psi {\varvec{u}}^{\mathrm{p}})- {\varvec{g}}-{\varvec{z}}) \, {\text {d}}{\varvec{x}}\\&\qquad + \int _{\mathcal {O}} 2\mathcal {E}({\varvec{u}}^{\mathrm{p}}): [\mathcal {E}(\cdot ),\partial _s](\partial _s(\psi {\varvec{u}}^{\mathrm{p}})-{\varvec{g}}-{\varvec{z}}) \, {\text {d}}{\varvec{x}}\\&\qquad - \int _{\mathcal {O}} p^{\mathrm{p}} \,[\mathrm{{div}\,},\partial _s](\partial _s(\psi {\varvec{u}}^{\mathrm{p}})- {\varvec{g}}-{\varvec{z}}) \, {\text {d}}{\varvec{x}}. \end{aligned}$$
Note that the first integral in the third line vanishes due to the definition of \({\varvec{z}}\). In this way, we can avoid having to deal with a \(\partial _s p^{\mathrm{p}}\) term in the resulting estimate.
Then, using Proposition 1, estimates (A.7) and (A.5), and Lemma 6, we have
$$\begin{aligned}&\left\Vert \mathcal {E}(\partial _s{\varvec{u}}^{\mathrm{p}}) \right\Vert _{L^2(\mathcal {O})}^2 \\&\quad \le C\left\Vert \mathcal {E}(\partial _s{\varvec{u}}^{\mathrm{p}}) \right\Vert _{L^2(\mathcal {O})} \big ( \left\Vert \partial _s {\varvec{u}}^{\mathrm{p}} \right\Vert _{L^2(\mathcal {O})} + \left\Vert \mathcal {E}({\varvec{z}}) \right\Vert _{L^2(\mathcal {O})} + \left\Vert \mathcal {E}({\varvec{g}}) \right\Vert _{L^2(\mathcal {O})} \big ) \\&\qquad + C\left\Vert \mathcal {E}({\varvec{u}}^{\mathrm{p}}) \right\Vert _{L^2(\mathcal {O})} \big (\left\Vert \mathcal {E}(\psi \partial _s{\varvec{u}}^{\mathrm{p}}) \right\Vert _{L^2(\mathcal {O})} +\left\Vert \mathcal {E}({\varvec{g}}) \right\Vert _{L^2(\mathcal {O})} +\left\Vert \mathcal {E}({\varvec{z}}) \right\Vert _{L^2(\mathcal {O})} \big ) \\&\qquad + 2\left\Vert [\mathcal {E}(\cdot ),\partial _s]{\varvec{u}}^{\mathrm{p}} \right\Vert _{L^2(\mathcal {O})}\big ( \left\Vert \mathcal {E}(\psi \partial _s{\varvec{u}}^{\mathrm{p}}) \right\Vert _{L^2(\mathcal {O})} + \left\Vert \mathcal {E}({\varvec{z}}) \right\Vert _{L^2(\mathcal {O})} + \left\Vert \mathcal {E}({\varvec{g}}) \right\Vert _{L^2(\mathcal {O})} \big ) \\&\qquad +2\left\Vert \mathcal {E}({\varvec{u}}^{\mathrm{p}}) \right\Vert _{L^2(\mathcal {O})} \big ( \left\Vert [\mathcal {E}(\cdot ),\partial _s](\psi \partial _s{\varvec{u}}^{\mathrm{p}}) \right\Vert _{L^2(\mathcal {O})} + \left\Vert [\mathcal {E}(\cdot ),\partial _s]({\varvec{z}}) \right\Vert _{L^2(\mathcal {O})} \\&\qquad + \left\Vert [\mathcal {E}(\cdot ),\partial _s]({\varvec{g}}) \right\Vert _{L^2(\mathcal {O})} \big ) \\&\qquad + \left\Vert p^{\mathrm{p}} \right\Vert _{L^2(\mathcal {O})} \big ( \left\Vert [\mathrm{{div}\,},\partial _s](\psi \partial _s{\varvec{u}}^{\mathrm{p}}) \right\Vert _{L^2(\mathcal {O})} + \left\Vert [\mathrm{{div}\,},\partial _s]({\varvec{z}}) \right\Vert _{L^2(\mathcal {O})} +\left\Vert [\mathrm{{div}\,},\partial _s]({\varvec{g}}) \right\Vert _{L^2(\mathcal {O})} \big ) \\&\quad \le C(\left\Vert \mathcal {E}(\partial _s{\varvec{u}}^{\mathrm{p}}) \right\Vert _{L^2(\mathcal {O})} + \left\Vert \nabla {\varvec{u}}^{\mathrm{p}} \right\Vert _{L^2(\mathcal {O})} +\left|{\varvec{\omega }} \right|)\big (\left\Vert \nabla {\varvec{u}}^{\mathrm{p}} \right\Vert _{L^2(\mathcal {O})}+\left\Vert p^{\mathrm{p}} \right\Vert _{L^2(\mathcal {O})} +\left|{\varvec{\omega }}^{\mathrm{p}} \right| \big ) \\&\quad \le \delta \left\Vert \mathcal {E}(\partial _s{\varvec{u}}^{\mathrm{p}}) \right\Vert _{L^2(\mathcal {O})}^2 + C(\delta ) \big (\left\Vert \nabla {\varvec{u}}^{\mathrm{p}} \right\Vert _{L^2(\mathcal {O})}^2+\left\Vert p^{\mathrm{p}} \right\Vert _{L^2(\mathcal {O})}^2 + \left|{\varvec{\omega }}^{\mathrm{p}} \right|^2\big ) \end{aligned}$$
for any \(0<\delta \in \mathbb {R}\), by Young’s inequality. Taking \(\delta =\frac{1}{2}\) and using Lemma 6, we obtain
$$\begin{aligned} \begin{aligned} \left\Vert \nabla (\partial _s{\varvec{u}}^{\mathrm{p}}) \right\Vert _{L^2(\mathcal {O})}&\le \left\Vert \mathcal {E}(\partial _s{\varvec{u}}^{\mathrm{p}}) \right\Vert _{L^2(\mathcal {O})} \le C \big (\left\Vert \nabla {\varvec{u}}^{\mathrm{p}} \right\Vert _{L^2(\mathcal {O})}+\left\Vert p^{\mathrm{p}} \right\Vert _{L^2(\mathcal {O})} + \left|{\varvec{\omega }}^{\mathrm{p}} \right| \big ) \\&\le C\left|\log \epsilon \right|^{1/2} \big (\left\Vert \nabla {\varvec{u}}^{\mathrm{p}} \right\Vert _{L^2(\varOmega _\epsilon )}+\left\Vert p^{\mathrm{p}} \right\Vert _{L^2(\varOmega _\epsilon )} \big ), \end{aligned} \end{aligned}$$
(A.9)
where we have used Corollary 1 to bound \(\left|{\varvec{\omega }}^{\mathrm{p}} \right|\). Here C depends only on \(c_\Gamma \), \(\kappa _{\max }\), and \(\xi _{\max }\).
We may estimate \(\partial _\theta {\varvec{u}}^{\mathrm{p}}\) in a similar way. In fact, the construction of the analogous test function is simpler since \((\partial _\theta {\varvec{u}}^{\mathrm{p}})\big |_{\Gamma _\epsilon } = \partial _\theta ({\varvec{v}}+{\varvec{\omega }}\times {\varvec{X}}(s))=0\) and thus we do not need to correct for a nonzero boundary value. Following the same steps used to estimate \(\partial _s{\varvec{u}}^{\mathrm{p}}\), we obtain
$$\begin{aligned} \left\Vert \nabla (\partial _\theta {\varvec{u}}^{\mathrm{p}}) \right\Vert _{L^2(\mathcal {O})} \le C \big (\left\Vert \nabla {\varvec{u}}^{\mathrm{p}} \right\Vert _{L^2(\varOmega _\epsilon )}+\left\Vert p^{\mathrm{p}} \right\Vert _{L^2(\varOmega _\epsilon )} \big ), \end{aligned}$$
(A.10)
where C depends only on \(c_\Gamma \), \(\kappa _{\max }\), and \(\xi _{\max }\).
In addition to estimates (A.9) and (A.10), we need bounds for the tangential derivatives \(\partial _s p^{\mathrm{p}}\) and \(\partial _\theta p^{\mathrm{p}}\) of the pressure. We begin by estimating \(\partial _s p^{\mathrm{p}}\); the bound for \(\partial _\theta p^{\mathrm{p}}\) is similar. Since we already know that \(\partial _s p^{\mathrm{p}}\in L^2(\varOmega _\epsilon )\), we may consider \(\widetilde{{\varvec{z}}}\in D^{1,2}_0(\mathcal {O})\) satisfying
$$\begin{aligned} \begin{aligned} \mathrm{{div}\,}\widetilde{{\varvec{z}}}&= \psi \partial _s p^{\mathrm{p}} \quad \text {in }\mathcal {O}, \\ \left\Vert \nabla \widetilde{{\varvec{z}}} \right\Vert _{L^2(\mathcal {O})}&\le C\left\Vert \psi \partial _s p^{\mathrm{p}} \right\Vert _{L^2(\mathcal {O})}, \end{aligned} \end{aligned}$$
(A.11)
where \(\psi \) is as in (A.4). Again, we know that such a \(\widetilde{{\varvec{z}}}\) exists due to [6], Section III.3 and [18], Appendix A.2.5.
Using \(\partial _s\widetilde{{\varvec{z}}}\) as a test function in Definition 3 (again, we can make sense of the following computation using finite differences, and thus only require \(\widetilde{{\varvec{z}}}\in D^{1,2}(\mathcal {O})\)), we have
$$\begin{aligned} 0&= \int _{\mathcal {O}} \bigg (2\mathcal {E}({\varvec{u}}^{\mathrm{p}}): \mathcal {E}(\partial _s \widetilde{{\varvec{z}}}) - p^{\mathrm{p}}\, \mathrm{{div}\,}(\partial _s\widetilde{{\varvec{z}}})\bigg ) \, {\text {d}}{\varvec{x}}= \int _{\mathcal {O}}2\mathcal {E}({\varvec{u}}^{\mathrm{p}}): \partial _s\mathcal {E}(\widetilde{{\varvec{z}}}) \, {\text {d}}{\varvec{x}}\\&\quad + \int _{\mathcal {O}}2\mathcal {E}({\varvec{u}}^{\mathrm{p}}): [\mathcal {E}(\cdot ),\partial _s]\widetilde{{\varvec{z}}}\, {\text {d}}{\varvec{x}}- \int _{\mathcal {O}} p^{\mathrm{p}} \,\partial _s\mathrm{{div}\,}\widetilde{{\varvec{z}}}\, {\text {d}}{\varvec{x}}- \int _{\mathcal {O}} p^{\mathrm{p}} \, [\mathrm{{div}\,},\partial _s]\widetilde{{\varvec{z}}}\, {\text {d}}{\varvec{x}}\\&= -\int _{\mathcal {O}}2\partial _s\mathcal {E}({\varvec{u}}^{\mathrm{p}}): \mathcal {E}(\widetilde{{\varvec{z}}}) \, {\text {d}}{\varvec{x}}- \int _{\mathcal {O}}2\mathcal {E}({\varvec{u}}^{\mathrm{p}}): \mathcal {E}(\widetilde{{\varvec{z}}}) \, \mathcal {J}_s \, {\text {d}}{\varvec{x}}+ \int _{\mathcal {O}}2\mathcal {E}({\varvec{u}}^{\mathrm{p}}): [\mathcal {E}(\cdot ),\partial _s]\widetilde{{\varvec{z}}}\, {\text {d}}{\varvec{x}}\\&\quad - \int _{\mathcal {O}} p^{\mathrm{p}} \, [\mathrm{{div}\,},\partial _s]\widetilde{{\varvec{z}}}\, {\text {d}}{\varvec{x}}+ \int _{\mathcal {O}}(\partial _s p)\mathrm{{div}\,}\widetilde{{\varvec{z}}}\, {\text {d}}{\varvec{x}}+ \int _{\mathcal {O}} p^{\mathrm{p}} \,\mathrm{{div}\,}\widetilde{{\varvec{z}}}\, \mathcal {J}_s \, {\text {d}}{\varvec{x}}\\&= \int _{\mathcal {O}}\psi (\partial _s p)^2 \, {\text {d}}{\varvec{x}}-\int _{\mathcal {O}}2\partial _s\mathcal {E}({\varvec{u}}^{\mathrm{p}}): \mathcal {E}(\widetilde{{\varvec{z}}}) \, {\text {d}}{\varvec{x}}- \int _{\mathcal {O}}2\mathcal {E}({\varvec{u}}^{\mathrm{p}}): \mathcal {E}(\widetilde{{\varvec{z}}}) \, \mathcal {J}_s \, {\text {d}}{\varvec{x}}\\&\quad + \int _{\mathcal {O}}2\mathcal {E}({\varvec{u}}^{\mathrm{p}}): [\mathcal {E}(\cdot ),\partial _s]\widetilde{{\varvec{z}}}\, {\text {d}}{\varvec{x}}- \int _{\mathcal {O}} p^{\mathrm{p}} \, [\mathrm{{div}\,},\partial _s]\widetilde{{\varvec{z}}}\, {\text {d}}{\varvec{x}}+ \int _{\mathcal {O}} p^{\mathrm{p}} \,\mathrm{{div}\,}\widetilde{{\varvec{z}}}\, \mathcal {J}_s \, {\text {d}}{\varvec{x}}, \end{aligned}$$
where \(\mathcal {J}_s \, {\text {d}}{\varvec{x}}\) is as in (A.8) and we have used (A.11). Then, using that \(\psi ^2\le \psi \), we have
$$\begin{aligned} \left\Vert \psi \partial _s p^{\mathrm{p}} \right\Vert _{L^2(\mathcal {O})}^2&\le 2\left\Vert \mathcal {E}(\partial _s{\varvec{u}}^{\mathrm{p}}) \right\Vert _{L^2(\mathcal {O})} \left\Vert \mathcal {E}(\widetilde{{\varvec{z}}}) \right\Vert _{L^2(\mathcal {O})} + 2\left\Vert [\mathcal {E}(\cdot ),\partial _s]{\varvec{u}}^{\mathrm{p}} \right\Vert _{L^2(\mathcal {O})} \left\Vert \mathcal {E}(\widetilde{{\varvec{z}}}) \right\Vert _{L^2(\mathcal {O})} \\&\quad + C\left\Vert \mathcal {E}({\varvec{u}}^{\mathrm{p}}) \right\Vert _{L^2(\mathcal {O})} \left\Vert \mathcal {E}(\widetilde{{\varvec{z}}}) \right\Vert _{L^2(\mathcal {O})} + 2\left\Vert \mathcal {E}({\varvec{u}}^{\mathrm{p}}) \right\Vert _{L^2(\mathcal {O})}\left\Vert [\mathcal {E}(\cdot ),\partial _s]\widetilde{{\varvec{z}}} \right\Vert _{L^2(\mathcal {O})} \\&\quad +\left\Vert p^{\mathrm{p}} \right\Vert _{L^2(\mathcal {O})} \left\Vert [\mathrm{{div}\,},\partial _s]\widetilde{{\varvec{z}}} \right\Vert _{L^2(\mathcal {O})} + C\left\Vert p^{\mathrm{p}} \right\Vert _{L^2(\mathcal {O})} \left\Vert \mathrm{{div}\,}\widetilde{{\varvec{z}}} \right\Vert _{L^2(\mathcal {O})}\\&\le C\big (\left\Vert \nabla (\partial _s{\varvec{u}}^{\mathrm{p}}) \right\Vert _{L^2(\mathcal {O})} + \left\Vert \nabla {\varvec{u}}^{\mathrm{p}} \right\Vert _{L^2(\mathcal {O})} +\left\Vert p^{\mathrm{p}} \right\Vert _{L^2(\mathcal {O})} \big ) \left\Vert \psi \partial _s p^{\mathrm{p}} \right\Vert _{L^2(\mathcal {O})}\\&\le \delta \left\Vert \psi \partial _s p^{\mathrm{p}} \right\Vert _{L^2(\mathcal {O})}^2 + C(\delta )\big (\left\Vert \nabla (\partial _s{\varvec{u}}^{\mathrm{p}}) \right\Vert _{L^2(\mathcal {O})}^2 + \left\Vert \nabla {\varvec{u}}^{\mathrm{p}} \right\Vert _{L^2(\mathcal {O})}^2 +\left\Vert p^{\mathrm{p}} \right\Vert _{L^2(\mathcal {O})}^2 \big ) \end{aligned}$$
for \(0<\delta \in \mathbb {R}\). Here, we have used (A.8), (A.11), Proposition 1, and Young’s inequality. Taking \(\delta =\frac{1}{2}\) and using (A.9), we obtain
$$\begin{aligned} \left\Vert \psi \partial _s p^{\mathrm{p}} \right\Vert _{L^2(\mathcal {O})} \le C\left|\log \epsilon \right|^{1/2}\big ( \left\Vert \nabla {\varvec{u}}^{\mathrm{p}} \right\Vert _{L^2(\varOmega _\epsilon )} +\left\Vert p^{\mathrm{p}} \right\Vert _{L^2(\varOmega _\epsilon )} \big ). \end{aligned}$$
Then, using (A.4), within the region
$$\begin{aligned} \mathcal {O}' = \bigg \{{\varvec{x}}\in \varOmega _{\epsilon } \; : \; {\varvec{x}}= {\varvec{X}}(s) + \rho {\varvec{e}}_{\rho }(s,\theta ), \quad \epsilon< \rho <\frac{r_{\max }}{4} \bigg \}, \end{aligned}$$
we have
$$\begin{aligned} \left\Vert \partial _s p^{\mathrm{p}} \right\Vert _{L^2(\mathcal {O}')} \le C\left|\log \epsilon \right|^{1/2}\big ( \left\Vert \nabla {\varvec{u}}^{\mathrm{p}} \right\Vert _{L^2(\varOmega _\epsilon )} +\left\Vert p^{\mathrm{p}} \right\Vert _{L^2(\varOmega _\epsilon )} \big ) \end{aligned}$$
(A.12)
for C depending only on \(c_\Gamma \), \(\kappa _{\max }\), and \(\xi _{\max }\).
We can similarly use (A.10) to show
$$\begin{aligned} \left\Vert \partial _\theta p^{\mathrm{p}} \right\Vert _{L^2(\mathcal {O}')} \le C\big ( \left\Vert \nabla {\varvec{u}}^{\mathrm{p}} \right\Vert _{L^2(\varOmega _\epsilon )} +\left\Vert p^{\mathrm{p}} \right\Vert _{L^2(\varOmega _\epsilon )} \big ). \end{aligned}$$
(A.13)
Now we can use the tangential bounds (A.9), (A.10), (A.12), and (A.13) to obtain an estimate for derivatives \(\nabla (\partial _\rho {\varvec{u}}^{\mathrm{p}})\) normal to \(\Gamma _\epsilon \). For this, we will use the full Stokes Eqs. (1.8), written with respect to the orthonormal frame \({\varvec{e}}_t\), \({\varvec{e}}_\rho \), \({\varvec{e}}_\theta \) in \(\mathcal {O}\) as
$$\begin{aligned} - \varDelta {\varvec{u}}^{\mathrm{p}} +\nabla p^{\mathrm{p}}&= -\varDelta {\varvec{u}}^{\mathrm{p}} + \frac{\partial p^{\mathrm{p}}}{\partial \rho }{\varvec{e}}_{\rho } + \frac{1}{\rho }\frac{\partial p^{\mathrm{p}}}{\partial \theta }{\varvec{e}}_{\theta } + \frac{1}{1-\rho \widehat{\kappa }}\bigg (\frac{\partial p^{\mathrm{p}}}{\partial s}-\kappa _3\frac{\partial p^{\mathrm{p}}}{\partial \theta }\bigg ){\varvec{e}}_t =0, \\ \mathrm{{div}\,}{\varvec{u}}^{\mathrm{p}}&= \frac{1}{1-\rho \widehat{\kappa }}\bigg (\frac{1}{\rho }\frac{\partial (\rho (1-\rho \widehat{\kappa }) u_{\rho })}{\partial \rho }+\frac{1}{\rho }\frac{\partial ((1-\rho \widehat{\kappa }) u_{\theta })}{\partial \theta } + \frac{\partial u_s}{\partial s} \bigg ) = 0. \end{aligned}$$
Here, \(\widehat{\kappa }\) is as in (A.3) and we recall the notation \(u_\rho = {\varvec{u}}^{\mathrm{p}}\cdot {\varvec{e}}_\rho \), \(u_\theta ={\varvec{u}}^{\mathrm{p}}\cdot {\varvec{e}}_\theta \), \(u_s={\varvec{u}}^{\mathrm{p}}\cdot {\varvec{e}}_t\).
From the divergence-free condition on \({\varvec{u}}^{\mathrm{p}}\), after multiplying through by \(\rho (1-\rho \widehat{\kappa })\) and differentiating once with respect to \(\rho \), we obtain
$$\begin{aligned} \left\Vert \frac{\partial ^2 u_{\rho }}{\partial ^2 \rho } \right\Vert _{L^2(\mathcal {O})}&\le C\bigg (\left\Vert \frac{1}{\rho } \nabla {\varvec{u}}^{\mathrm{p}} \right\Vert _{L^2(\mathcal {O})} + \bigg \Vert \frac{1}{\rho }\bigg \Vert _{L^{\infty }(\mathcal {O})}|\mathcal {O}|^{1/3}\big \Vert {\varvec{u}}^{\mathrm{p}} \big \Vert _{L^6(\mathcal {O})} \\&\quad + \bigg \Vert \frac{1}{\rho }\frac{\partial }{\partial \rho }\bigg (\frac{\partial u_{\theta }}{\partial \theta }\bigg )\bigg \Vert _{L^2(\mathcal {O})} +\bigg \Vert \frac{\partial }{\partial \rho }\bigg (\frac{\partial u_s}{\partial s}\bigg )\bigg \Vert _{L^2(\mathcal {O})} \bigg )\\&\le \frac{C}{\epsilon }\left|\log \epsilon \right|^{1/2}\big ( \Vert \nabla {\varvec{u}}^{\mathrm{p}}\Vert _{L^2(\varOmega _\epsilon )} +\left\Vert p^{\mathrm{p}} \right\Vert _{L^2(\varOmega _\epsilon )} \big ), \end{aligned}$$
where we have used (A.9) and (A.10) along with the Sobolev inequality on \(\varOmega _\epsilon \).
Furthermore, using the \({\varvec{e}}_\rho \) component of \(-\varDelta {\varvec{u}}^{\mathrm{p}} +\nabla p=0\), we have
$$\begin{aligned} \frac{\partial p^{\mathrm{p}}}{\partial \rho }&= (\varDelta {\varvec{u}}^{\mathrm{p}}) \cdot {\varvec{e}}_{\rho } \\&= \frac{1}{\rho (1-\rho \widehat{\kappa })}\frac{\partial }{\partial \rho }\left( \rho (1-\rho \widehat{\kappa })\frac{\partial {\varvec{u}}^{\mathrm{p}}}{\partial \rho }\right) \cdot {\varvec{e}}_{\rho } +\frac{1}{\rho ^2(1-\rho \widehat{\kappa })}\frac{\partial }{\partial \theta }\bigg ((1-\rho \widehat{\kappa })\frac{\partial {\varvec{u}}^{\mathrm{p}}}{\partial \theta }\bigg )\cdot {\varvec{e}}_{\rho } \\&\quad +\frac{1}{1-\rho \widehat{\kappa }} \frac{\partial }{\partial s}\bigg ( \frac{1}{1-\rho \widehat{\kappa }}\bigg [ \frac{\partial {\varvec{u}}^{\mathrm{p}}}{\partial s}- \kappa _3\frac{\partial {\varvec{u}}^{\mathrm{p}}}{\partial \theta } \bigg ] \bigg )\cdot {\varvec{e}}_{\rho } \\&= \frac{1}{\rho (1-\rho \widehat{\kappa })}\frac{\partial }{\partial \rho }\left( \rho (1-\rho \widehat{\kappa })\frac{\partial u_{\rho }}{\partial \rho }\right) +\frac{1}{\rho ^2(1-\rho \widehat{\kappa })}\frac{\partial }{\partial \theta }\bigg ((1-\rho \widehat{\kappa })\frac{\partial {\varvec{u}}^{\mathrm{p}}}{\partial \theta }\bigg )\cdot {\varvec{e}}_{\rho } \\&\quad +\frac{1}{1-\rho \widehat{\kappa }} \frac{\partial }{\partial s}\bigg ( \frac{1}{1-\rho \widehat{\kappa }}\bigg [ \frac{\partial {\varvec{u}}^{\mathrm{p}}}{\partial s}- \kappa _3\frac{\partial {\varvec{u}}^{\mathrm{p}}}{\partial \theta } \bigg ] \bigg )\cdot {\varvec{e}}_{\rho }, \end{aligned}$$
since \({\varvec{e}}_{\rho }(s,\theta )\) does not vary with \(\rho \). Therefore, using (A.9), (A.10), (A.12), and (A.13), along with the bound on \(\frac{\partial ^2 u_{\rho }}{\partial \rho ^2}\), we have
$$\begin{aligned} \Vert \nabla p^{\mathrm{p}}\Vert _{L^2(\mathcal {O}')} \le \frac{C}{\epsilon }\left|\log \epsilon \right|^{1/2}\big ( \Vert \nabla {\varvec{u}}^{\mathrm{p}}\Vert _{L^2(\varOmega _\epsilon )} +\left\Vert p^{\mathrm{p}} \right\Vert _{L^2(\varOmega _\epsilon )} \big ). \end{aligned}$$
Finally, to estimate \(\frac{\partial ^2 u_j}{\partial \rho ^2}\), \(j=\theta ,s\), we again use that
$$\begin{aligned} \nabla p^{\mathrm{p}}\cdot {\varvec{e}}_j&= (\varDelta {\varvec{u}}^{\mathrm{p}})\cdot {\varvec{e}}_j(s,\theta ) \\&= \frac{1}{\rho (1-\rho \widehat{\kappa })}\frac{\partial }{\partial \rho }\bigg (\rho (1-\rho \widehat{\kappa })\frac{\partial u_j}{\partial \rho }\bigg ) +\frac{1}{\rho ^2(1-\rho \widehat{\kappa })}\frac{\partial }{\partial \theta }\bigg ((1-\rho \widehat{\kappa })\frac{\partial {\varvec{u}}^{\mathrm{p}}}{\partial \theta }\bigg )\cdot {\varvec{e}}_j \\&\quad +\frac{1}{1-\rho \widehat{\kappa }} \frac{\partial }{\partial s}\bigg ( \frac{1}{1-\rho \widehat{\kappa }}\bigg [ \frac{\partial {\varvec{u}}^{\mathrm{p}}}{\partial s}- \kappa _3\frac{\partial {\varvec{u}}^{\mathrm{p}}}{\partial \theta } \bigg ] \bigg )\cdot {\varvec{e}}_j , \quad j=\theta ,s, \end{aligned}$$
since each of \({\varvec{e}}_t(s)\), \({\varvec{e}}_\rho (s,\theta )\) and \({\varvec{e}}_\theta (s,\theta )\) are independent of \(\rho \). Then, we have
$$\begin{aligned} \bigg \Vert \frac{\partial ^2 u_j}{\partial \rho ^2}\bigg \Vert _{L^2(\mathcal {O}')}&\le C \bigg ( \bigg \Vert \frac{1}{\rho }\bigg \Vert _{L^{\infty }(\mathcal {O}')} \Vert \nabla {\varvec{u}}^{\mathrm{p}}\Vert _{L^2(\mathcal {O}')} + \bigg \Vert \frac{\partial ^2{\varvec{u}}^{\mathrm{p}}}{\partial s^2}\bigg \Vert _{L^2(\mathcal {O}')} \\&\quad + \bigg \Vert \frac{\partial ^2{\varvec{u}}^{\mathrm{p}}}{\partial s\partial \theta }\bigg \Vert _{L^2(\mathcal {O}')} +\bigg \Vert \frac{\partial ^2{\varvec{u}}^{\mathrm{p}}}{\partial \theta ^2}\bigg \Vert _{L^2(\mathcal {O}')}+\Vert \nabla p^{\mathrm{p}}\Vert _{L^2(\mathcal {O}')} \bigg ) \\&\le \frac{C}{\epsilon }\left|\log \epsilon \right|^{1/2} \big (\left\Vert \nabla {\varvec{u}}^{\mathrm{p}} \right\Vert _{L^2(\varOmega _\epsilon )} + \left\Vert p^{\mathrm{p}} \right\Vert _{L^2(\varOmega _\epsilon )} \big ), \quad j=\theta , s, \end{aligned}$$
where C depends only on \(c_\Gamma \), \(\kappa _{\max }\), and \(\xi _{\max }\). Altogether, we obtain Lemma 9. \(\square \)
Remark 2
We note that the factor of \(\frac{1}{\epsilon }\) in Lemma 9 is necessary. As a heuristic, we consider an infinite straight cylinder of radius \(\epsilon \) and take \({\varvec{u}}= (\frac{1}{\rho }-\frac{1}{\epsilon }) {\varvec{e}}_{\theta }\), where \({\varvec{e}}_{\theta }\) is now the (constant) angular vector in straight cylindrical coordinates, and \(p\equiv \) constant. Ignoring decay conditions toward infinity along the cylinder, \(({\varvec{u}},p)\) solves the Stokes equations with \({\varvec{u}}=0\) on the cylinder surface. Then,
$$\begin{aligned} |\nabla ^2{\varvec{u}}| =\bigg | \frac{\partial ^2}{\partial \rho ^2} \frac{1}{\rho }\bigg | = \bigg |\frac{2}{\rho ^3}\bigg | = \frac{2}{\rho }\big | \nabla {\varvec{u}}\big |, \end{aligned}$$
and within the region \(\epsilon < \rho \le 2 \epsilon \), we have \(|\nabla ^2{\varvec{u}}| \ge \frac{1}{\epsilon }|\nabla {\varvec{u}}|\).