Abstract
A subgroup A is called seminormal in a group G if there exists a subgroup B such that G = AB and AX is a subgroup of G for every subgroup X of B. Studying a group of the form G = AB with seminormal supersoluble subgroups A and B, we prove that \(G^{\mathfrak{U}}=\left(G^{\prime}\right)^{\mathfrak{N}}\). Moreover, if the indices of the subgroups A and B of G are coprime then \(G^{\mathfrak{U}}=\left(G^{\mathfrak{N}}\right)^{2}\). Here \(\mathfrak{N}\), \(\mathfrak{U}\), and \(\mathfrak{N}^2\) are the formations of all nilpotent, supersoluble, and metanilpotent groups respectively, while \(H^{\mathfrak{X}}\) is the \(\mathfrak{X}\)-residual of H. We also prove the supersolubility of G = AB when all Sylow subgroups of A and B are seminormal in G.
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Russian Text © The Author(s), 2020, published in Sibirskii Matematicheskii Zhurnal, 2020, Vol. 61, No. 1, pp. 148–159.
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Monakhov, V.S., Trofimuk, A.A. On Supersolubility of a Group with Seminormal Subgroups. Sib Math J 61, 118–126 (2020). https://doi.org/10.1134/S0037446620010103
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DOI: https://doi.org/10.1134/S0037446620010103