On the generalized Krull property in power series rings☆
Introduction
Let R be an integral domain. An overring of R is a ring lying between R and its quotient field. Consider the following properties on a family of valuation overrings of R.
- (a)
.
- (b)
The family has finite character, i.e., if , then a is a unit in all but finitely many .
- (c)
Each is essential for R, i.e., is the localization of R at , where is the maximal ideal of .
- (d)
Each is one-dimensional.
- (d')
Each is one-dimensional and discrete.
Krull domains play an important role in commutative algebra. They are a generalization of Dedekind domains. A Krull domain is a Dedekind domain if and only if its Krull dimension is at most one. By Mori-Nagata theorem, the integral closure of a Noetherian domain is a Krull domain. Let R be an integral domain and let be the power series ring over R. Gilmer [7], [8] showed that R is a Krull domain if and only if is a Krull domain.
An application of generalized Krull domains appears in Field Arithmetic and Galois Theory. According to Weissauer's theorem, the quotient field of a generalized Krull domain of dimension exceeding one is Hilbertian [6, Theorem 15.4.6]. Further use of the theorem in Field Arithmetic can be found for example in [15], [17]. Jarden asked: Is the power series ring a generalized Krull domain if R is (see [6, Problem 15.5.9 (a)])? A counterexample was constructed by Paran and Temkin [16]. In fact, they proved that if R is a generalized Krull domain, then is a generalized Krull domain if and only if is a Krull domain [16]. In this paper, we show that the concepts “generalized Krull domain” and “Krull domain” are the same for the power series ring without the assumption that R is a generalized Krull domain. Combining this with Gilmer's result, we get is a generalized Krull domain if and only if is a Krull domain if and only if R is a Krull domain. Therefore, this gives a complete answer to the question: “When is the power series ring a generalized Krull domain?”
Section snippets
The main result
The main result of this paper is as follows:
Theorem 1 The following are equivalent for an integral domain R. R is a Krull domain. is a Krull domain. is a generalized Krull domain.
To prove this theorem, we only need to prove that (3) implies (1). This is by the discussion in the Introduction. Before doing this, we introduce some concepts that will appear later in the proof.
Definition 2 Let R be a commutative ring with identity. An ideal I of R is called an SFT (strong finite type) ideal if there exist a
Acknowledgements
The authors would like to thank the referee and editor for comments and suggestions, which greatly helped us improve the presentation and the organization of the paper.
References (19)
- et al.
When and are Prufer domains
J. Pure Appl. Algebra
(2012) - et al.
The Krull dimension of power series rings over almost Dedekind domains
J. Algebra
(2015) - et al.
Krull-dimension of the power series ring over a nondiscrete valuation domain is uncountable
J. Algebra
(2013) - et al.
The Krull dimension of power series rings over non-SFT rings
J. Pure Appl. Algebra
(2013) - et al.
Constructing chains of primes in power series rings
J. Algebra
(2011) - et al.
Power series over generalized Krull domains
J. Algebra
(2010) - et al.
Krull dimension of power series rings over non-SFT domains
J. Algebra
(2018) - et al.
Krull dimension of a power series ring over a valuation domain
J. Algebra
(2019) Krull dimension in power series rings
Trans. Am. Math. Soc.
(1973)
Cited by (1)
Power series over integral domains of Krull type
2023, Journal of Algebra and its Applications
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The second author was supported by the National Research Foundation (NRF) grant NRF-2016R1D1A1B01006847.