Solvent plays a vital role in the recrystallization process and resulting crystallinity of materials. This role is of such importance that it can control the stability and utility of materials. In this work, the inclusion of a solvent in the crystalline lattice, specifically water, drastically affects the overall stability of two platinum polymorphs. [Pt(tpy)Cl]BF₄ (tpy = 2,2′;6′2″-terpyridine) crystallizes in three forms, red (1R) and blue (1B) polymorphs and a yellow nonsolvated form (2). 1R is the more stable of the two polymorphs, whereas 1B loses crystallinity upon dehydration at ambient conditions resulting in the formation of 2. Close examination of the solid-state extended structures of the two polymorphs reveals that 1R has a lattice arrangement that is more conducive to stronger intermolecular interactions compared to 1B, thereby promoting greater stability. In addition, these two polymorphs exhibit unique vapochromic responses when exposed to various solvents.

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水在多晶型铂 (II) 配合物中的作用

溶剂在再结晶过程和材料的结晶度中起着至关重要的作用。这个角色非常重要，它可以控制材料的稳定性和实用性。在这项工作中，晶格中包含溶剂，特别是水，极大地影响了两种铂多晶型物的整体稳定性。[Pt(tpy)Cl]BF ₄ (tpy = 2,2';6'2"-terpyridine) 以三种形式结晶，红色 ( 1R ) 和蓝色 ( 1B ) 多晶型物以及黄色非溶剂化形式 ( 2 )。1R是两种多晶型物中更稳定的，而1B在环境条件下脱水时失去结晶度，导致形成2. 对两种多晶型物的固态扩展结构的仔细检查表明，与1B相比，1R的晶格排列更有利于更强的分子间相互作用，从而提高了稳定性。此外，当暴露于各种溶剂时，这两种多晶型物表现出独特的蒸汽变色响应。