To describe n +12C interactions with production of three α-particles at incident neutron kinetic energy of 14 MeV in a nuclear (photo) emulsion, a Monte Carlo model is proposed for four channels of decay of an excited carbon-12 nucleus into three α-particles. The Monte Carlo calculation results describe well the experimental data on the distribution of the angle between the three-dimensional momenta of all pairs of α-particles in a collision event, on the distribution of the angle between the projections of the momentum vectors of all pairs of α-particles in collision event on each of the coordinate planes, on the distribution of the sum of the kinetic energies of all pairs of α-particles in a collision event, and the distribution of projections of the momenta of α-particles on the coordinate planes. The best agreement of the Monte Carlo model results with the experimental data is achieved if the direct decay C12∗→ 3α and decay through the formation of an intermediate beryllium nucleus C12∗→ α + Be8∗→ 3α are generated with equal probabilities, while the excitation energies of 3.04 MeV, 1.04 MeV, and 0.1 MeV for the beryllium nucleus are generated with relative weights of 75%, 15%, and 10%, respectively.

中文翻译：

---

低能 n +12C 相互作用中三个 α 粒子产生的蒙特卡罗建模

来描述n +12C与生产三者的互动α-在核（照片）乳液中入射中子动能为 14 MeV 的粒子，提出了一个蒙特卡罗模型，用于将激发的碳 12 核衰变成三个通道的四个通道α-粒子。蒙特卡罗计算结果很好地描述了所有对的三维动量之间夹角分布的实验数据。α-碰撞事件中的粒子，关于所有对的动量向量的投影之间的角度分布α-在每个坐标平面上的碰撞事件中的粒子，在所有对的动能之和的分布上α-碰撞事件中的粒子，以及动量的投影分布α- 坐标平面上的粒子。如果直接衰减，则可以实现蒙特卡罗模型结果与实验数据的最佳一致性C12*→ 3α并通过中间铍核的形成而衰变C12*→ α + 是8*→ 3α以相等的概率产生，而铍核的激发能量分别为 3.04 MeV、1.04 MeV 和 0.1 MeV，相对权重分别为 75%、15% 和 10%。