A computational model is generated to analyse the influence of shrinkage on convective drying problems. The object considered here is cranberry which is assumed as 100% spherical. The drying air temperatures were considered from 313 to 348 K. There were four models used in this study, namely one-dimensional models without and with shrinkage, two-dimensional models without and with shrinkage. A finite difference scheme was used to discretize the heat and mass transport equations. Four separate computer codes were written in MATLAB to solve the discretized equations. The Arrhenius model is used to couple the heat and moisture transport equations and solve them simultaneously. The Gauss–Seidel iterative method was used to solve the equations. An empirical shrinkage model was used to calculate the shrinkage effect. The temperature and moisture distributions of cranberry were obtained with drying time. Moisture distributions without and with shrinkage results were calculated and compared to identify the effect of shrinkage. The cranberry lost a maximum of 35% of its size during drying. There was not much variation found in the results between 1- and 2D models. The maximum difference in centre moisture content of cranberry without shrinkage model was 56%, and the difference in mean moisture content was 49.2%. The numerical outcomes were validated with experimental data, and the model with shrinkage was a good fit with them than without shrinkage. Therefore, shrinkage needs to be considered in convective drying phenomena.

生成计算模型来分析收缩对对流干燥问题的影响。此处考虑的对象是蔓越莓，假定为 100% 球形。干燥空气温度被认为是从 313 到 348 K。本研究使用了四种模型，即无收缩和有收缩的一维模型，无收缩和有收缩的二维模型。使用有限差分格式来离散热和质量传输方程。在 MATLAB 中编写了四个独立的计算机代码来求解离散方程。Arrhenius 模型用于耦合热量和水分传输方程并同时求解它们。使用高斯-赛德尔迭代法求解方程。使用经验收缩模型来计算收缩效应。蔓越莓的温度和水分分布随干燥时间而变化。计算和比较没有和有收缩结果的水分分布，以确定收缩的影响。蔓越莓在干燥过程中最多损失了 35% 的大小。一维模型和二维模型之间的结果没有太大差异。无收缩模型蔓越莓的中心含水量最大差异为56%，平均含水量差异为49.2%。数值结果用实验数据验证，有收缩的模型比没有收缩的模型更适合它们。因此，在对流干燥现象中需要考虑收缩。计算和比较没有和有收缩结果的水分分布，以确定收缩的影响。蔓越莓在干燥过程中最多损失了 35% 的大小。一维模型和二维模型之间的结果没有太大差异。无收缩模型蔓越莓的中心含水量最大差异为56%，平均含水量差异为49.2%。数值结果用实验数据验证，有收缩的模型比没有收缩的模型更适合它们。因此，在对流干燥现象中需要考虑收缩。计算和比较没有和有收缩结果的水分分布，以确定收缩的影响。蔓越莓在干燥过程中最多损失了 35% 的大小。一维模型和二维模型之间的结果没有太大差异。无收缩模型蔓越莓的中心含水量最大差异为56%，平均含水量差异为49.2%。数值结果用实验数据验证，有收缩的模型比没有收缩的模型更适合它们。因此，在对流干燥现象中需要考虑收缩。无收缩模型蔓越莓的中心含水量最大差异为56%，平均含水量差异为49.2%。数值结果用实验数据验证，有收缩的模型比没有收缩的模型更适合它们。因此，在对流干燥现象中需要考虑收缩。无收缩模型蔓越莓的中心含水量最大差异为56%，平均含水量差异为49.2%。数值结果用实验数据验证，有收缩的模型比没有收缩的模型更适合它们。因此，在对流干燥现象中需要考虑收缩。