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Entanglement Witnesses Constructed By Permutation Pairs
Acta Mathematica Scientia ( IF 1 ) Pub Date : 2021-04-19 , DOI: 10.1007/s10473-021-0313-z
Jinchuan Hou , Wenli Wang

For n ≥ 3, we construct a class \(\left\{{{W_{n,{\pi _1},{\pi _2}}}} \right\}\) of n2 × n2 hermitian matrices by the permutation pairs and show that, for a pair {π1, π2} of permutations on (1, 2, …, n), \({{W_{n,{\pi _1},{\pi _2}}}}\) is an entanglement witness of the nn system if {π1, π2} has the property (C). Recall that a pair {π1, π2} of permutations of (1, 2, …, n) has the property (C) if, for each i, one can obtain a permutation of (1, …, i − 1, i + 1, …, n) from (π1 (1), …, π1 (i − 1), π1(i + 1), …, π1(n)) and (π2(1), …, π2(i − 1), π2(i + 1), …, π2(n)). We further prove that \({{W_{n,{\pi _1},{\pi _2}}}}\) is not comparable with Wn,π, which is the entanglement witness constructed from a single permutation π; \({{W_{n,{\pi _1},{\pi _2}}}}\) is decomposable if π1π2 = id or π 21 = π 22 = id. For the low dimensional cases n ∈ {3, 4}, we give a sufficient and necessary condition on π1, π2 for \({{W_{n,{\pi _1},{\pi _2}}}}\) to be an entanglement witness. We also show that, for n ∈ {3, 4}, \({{W_{n,{\pi _1},{\pi _2}}}}\) is decomposable if and only if π1π2 = id or π 21 = π 22 ; = id; \({{W_{3,{\pi _1},{\pi _2}}}}\) is optimal if and only if (π1, π2) = (π, π2), where π = (2, 3,1). As applications, some entanglement criteria for states and some decomposability criteria for positive maps are established.



中文翻译:

置换对构造的纠缠证人

对于Ñ ≥3,构造一个类\(\左\ {{{W_ {N,{\ PI _1},{\ PI _2}}}} \右\} \)Ñ 2 × Ñ 2埃尔米特矩阵由置换对和表明,对于一对{ π 1π 2 }的排列上(1,2,...,ñ),\({{W_ {N,{\ PI _1},{\ PI _2}} }} \)是的缠结证人ññ系统如果{ π 1π 2 }具有如下性质:(C)。回想一下,在一对{ π 1π 2 2的排列(1},...,Ñ)具有以下属性:(C)如果,对于每个,可以得到的置换(1,...,- 1,+ 1,...,Ñ)从(π 1(1),...,π 1- 1),π 1+ 1),...,π 1ñ))及(π 2(1),...,π 2- 1),π 2+ 1),...,π 2n))。我们进一步证明\({{W_ {n,{\ pi _1},{\ pi _2}}}} \)W n,π不具有可比性,W n,π是由单个排列π构造的纠缠证人;\({{{W_ N,{\ PI _1},{\ PI _2}}}} \)可分解如果π 1 π 2 = ID或π 2 1 = π 2 2 = ID。对于低维例Ñ ∈{3,4},我们给出的充分必要条件π 1π 2\({{W_ {N,{\ PI _1},{\ PI _2}}}} \ )成为纠缠证人。我们还表明,对于Ñ ∈{3,4}, \({{{W_ N,{\ PI _1},{\ PI _2}}}} \)可分解当且仅当π 1 π 2 = ID或π 2 1 = π 2 2 ; = id; \({{W_ {3 {\ PI _1},{\ PI _2}}}} \)是最佳的,当且仅当(π 1π 2)=(π,π 2),其中,π =(2 ,3,1)。作为应用,建立了一些状态的纠缠标准和正图的一些可分解性标准。

更新日期:2021-04-19
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