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Solving the Absolute 1-Center Problem in the Quickest Path Case
Bulletin of the Iranian Mathematical Society ( IF 0.7 ) Pub Date : 2021-04-08 , DOI: 10.1007/s41980-021-00536-4
Mehdi Ghiyasvand , Iman Keshtkar

An undirected graph \(G=(V,A)\) by a set V of n nodes, a set A of m edges, and a set \(D\subseteq V\) consists of h demand nodes are given. Peeters (Eur J Oper Res 104:299–309, 1998) presented the absolute 1-center problem, which finds a point x placed on nodes or edges of the graph G with the property that the cost distance from the most expensive demand node to x is as cheap as possible. In the absolute 1-center problem, the distance between two nodes is computed through a shortest path between them. This paper expands the idea of Peeters (1998) and presents a new version of the absolute 1-center problem, which is called the absolute quickest 1-center problem. A value \(\sigma \) is given, and the problem finds a point \(x^*\) placed on nodes or edges of the graph G with the property that the transmission time of the quickest path to send \(\sigma \) units of data from the farthest demand node to \(x^*\) is the minimum value. We presented an \(O(r|D|(m+n\mathrm{{log}}\ n))\) time algorithm to solve the absolute quickest 1-center problem, where r is the number of distinct capacity values.



中文翻译:

解决最快路径情况下的绝对一中心问题

给出了一个无向图\(G =(V,A)\),该图由n个节点的集合Vm个边的集合A和由h个需求节点组成的集合\(D \ subseteq V \)组成。Peeters(Eur J Oper Res 104:299–309,1998)提出了绝对的1中心问题,该问题找到位于图G的节点或边缘上的点x,其属性为从最昂贵的需求节点到成本点的距离X尽可能便宜。在绝对1中心问题中,通过两个节点之间的最短路径来计算两个节点之间的距离。本文扩展了Peeters(1998)的思想,并提出了绝对一中心问题的新版本,称为绝对最快一中心问题。给定值\(\ sigma \),问题发现位于图G的节点或边缘上的点\(x ^ * \)具有以下特性:最快路径的发送时间为\(\ sigma \)从最远需求节点到\(x ^ * \)的数据单位为最小值。我们提出了一个\(O(r | D |(m + n \ mathrm {{log}} \ n))\)时间算法来解决绝对最快的1中心问题,其中r是不同容量值的数量。

更新日期:2021-04-08
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