The thermodynamic properties of the kotulskite (PdTe)/merenskyite (PdTe₂) equilibrium in the Ag-Pd-Te system were determined for the first time by the electromotive force (EMF) method. The thermodynamic properties were calculated from the temperature dependence of the EMF in a completely solid-state electrochemical cell with a common gas space:\(\left( - \right){\text{C}}_{{({\text{graphite}})}} \left| {{\text{Ag}}} \right|{\text{RbAg}}_{{4}} {\text{I}}_{{5}} \left| {{\text{Ag}}_{{2}} {\text{Te}},{\text{PdTe}},{\text{PdTe}}_{{2}} } \right|{\text{C}}_{{({\text{graphite}})}} \left( + \right),\) following a virtual chemical reaction: \({\text{2Ag}} + {\text{PdTe}}_{{2}} \leftrightarrow {\text{Ag}}_{{2}} {\text{Te}} + {\text{PdTe}}.\) The measurements were carried out in the temperature range of 371–488 K at the atmospheric pressure of pure argon. As a result, the thermodynamic properties for the reaction PdTe + Te = PdTe₂ at a pressure of 1 bar (10⁵ Pa) were determined as: Δ_rG^o/J·mol⁻¹ = − 27,639; Δ_rS/J mol⁻¹ K⁻¹ = − 21.98; Δ_rH^o/J·mol⁻¹ = − 34,176. Fugacity of gaseous tellurium (Te₂) over the PdTe + 1/2Te₂ ↔ PdTe₂ equilibrium was also calculated: log f Te₂ = (9.205 ± 0.072) − (11.44 ± 0.03)·(1000/T), (371.7 < T/K < 493.6).

首次通过电动势（EMF）方法确定了在Ag-Pd-Te体系中的白云母（PdTe）/水母（PdTe ₂）平衡的热力学性质。根据具有共同气体空间的完全固态电化学电池中EMF的温度依赖性计算热力学性质：\（\ left（-\ right）{\ text {C}} _​​ {{{{{text {石墨}}）}} \ left | {{\ text {Ag}}} \ right | {\ text {RbAg}} _ {{4}} {\ text {I}} _ {{5}} \ left | {{\ text {Ag}} _ {{2}} {\ text {Te}}，{\ text {PdTe}}，{\ text {PdTe}} _ {{2}}} \ right | {\ text {C}} _​​ {{（{\ text {graphite}}）}} \ left（+ \ right），\）经过虚拟化学反应后：\（{\ text {2Ag}} + {\ text {PdTe} } _ {{{2}} \ leftrightarrow {\ text {Ag}} _ {{2}} {\ text {Te}} + {\ text {PdTe}}。\）在纯氩的大气压下，在371–488 K的温度范围内进行测量。结果，在1巴（10 ⁵  Pa）的压力下，反应PdTe + Te = PdTe ₂的热力学性质确定为：_Δr G ^o / J·mol ^-1  =-27,639；ΔrG ^o / J·mol ^-1 =-27,639；ΔrG ^o / J·mol ^-1 =-27,639。Δ _ř小号/ J摩尔^-1  ķ ^-1  = - 21.98; Δ _{- [R} ħ ^ö / J·摩尔^-1  = - 34176。气态碲的逸度（TE ₂）在PdTe + 1 / 2TE ₂  ↔PdTe ₂平衡也被计算：日志 ˚F 碲₂ ＝（9.205±0.072）-（11.44±0.03）·（1000 / T），（371.7 ＜  T / K ＜493.6）。