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Fibonacci or Lucas Numbers Which are Products of Two Repdigits in Base b
Bulletin of the Brazilian Mathematical Society, New Series ( IF 0.7 ) Pub Date : 2021-02-11 , DOI: 10.1007/s00574-021-00243-y
Zafer Şiar , Refik Keskin , Fatih Erduvan

In this study, we find all Fibonacci and Lucas numbers which can be expressible as a product of two repdigits in the base b. It is shown that the largest Fibonacci and Lucas numbers which can be expressible as a product of two repdigits are \(F_{12}=144\) and \(L_{15}=1364\), respectively. Also, we have the presentation

$$\begin{aligned} F_{12}=144=6\times (3+3\cdot 7)=(6)_{7}\times (33)_{7}=4\times (4+4\cdot 8)=(4)_{8}\times (44)_{8} \end{aligned}$$

and

$$\begin{aligned} L_{15}=1364\times (22222)_{4}=2\times (2+2\cdot 4+2\cdot 4^{2}+2\cdot 4^{3}+2\cdot 4^{4}). \end{aligned}$$


中文翻译:

Fibonacci或Lucas数是基数b中两个Repdigits的乘积

在这项研究中,我们找到了所有可表示为以b为基的两个表示数字的乘积的斐波那契数和卢卡斯数。结果表明,可以表示为两个数字的乘积的最大斐波那契数和卢卡斯数分别为\(F_ {12} = 144 \)\(L_ {15} = 1364 \)。另外,我们有演讲

$$ \ begin {aligned} F_ {12} = 144 = 6 \ times(3 + 3 \ cdot 7)=(6)_ {7} \ times(33)_ {7} = 4 \ times(4 + 4 \ cdot 8)=(4)_ {8} \次(44)_ {8} \ end {aligned} $$

$$ \ begin {aligned} L_ {15} = 1364 \ times(22222)_ {4} = 2 \ times(2 + 2 \ cdot 4 + 2 \ cdot 4 ^ {2} +2 \ cdot 4 ^ {3 } +2 \ cdot 4 ^ {4})。\ end {aligned} $$
更新日期:2021-02-11
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