A co-crystal of cobalt(II) complexes, Co(AMTTO)₂(CH₃CN)₂]²⁺(NO₃)₂. [Co(AMTTO)₂(H₂O)₂]²⁺(NO₃)₂, compound (1) was isolated from the reaction of Co(NO₃)₂⋅6H₂O and 4-amino-3-mercapto-6-methyl-5-oxo-1,2,4-triazine (AMTTO) in acetonitrile as solvent. Isolated crystals were characterized by elemental analyses, IR spectroscopy as well as X-ray diffraction studies. Crystal data for 1 at 95 K revealed a monoclinic space group P2₁/n, a = 11.7903(5), b = 12.1279(5), c = 14.1443(6) Å, β = 99.244(4)°, Z = 2, R₁ = 0.0339. Compound 1 consists of two co-crystallized Co(II) complexes [Co(AMTTO)₂(CH₃CN)₂]²⁺ and [Co(AMTTO)₂(H₂O)₂]²⁺ and four nitrate counter anions In both complexes, cobalt(II) ions are in an octahedral arrangement. Two S, N bidentate AMTTO ligands are coordinated to both Co(II) ions. The coordination sphere of Co1 is completed by two acetonitrile molecules, and these positions are occupied by water molecules for Co2.

Graphic Abstract

A co-crystal of cobalt(II) compound was isolated from the reaction of Co(NO₃)₂⋅6H₂O and 4-amino-3-mercapto-6-methyl-5-oxo-1,2,4-triazine in acetonitrile as solvent.

中文翻译：

---

[Co（AMTTO）2（H 2 O）2]（NO 3）2和[Co（AMTTO）2（CH 3 CN）2]（NO 3）2（AMTTO = 4）的共晶体的独特例子-氨基-5-甲基-1,2,4-三唑-3（2H）-硫酮）

钴（II）配合物Co（AMTTO）₂（CH ₃ CN）₂ ] ²⁺（NO ₃）₂的共晶体。[Co（AMTTO）₂（H ₂ O）₂ ] ²⁺（NO ₃）₂，从Co（NO ₃）_2· 6H ₂ O与4-氨基-3-巯基-的反应中分离出化合物（1）。在乙腈中的6-甲基-5-氧代-1,2,4-三嗪（AMTTO）作为溶剂。通过元素分析，红外光谱以及X射线衍射研究对分离出的晶体进行表征。1的水晶数据在95 K时揭示了一个单斜空间群P 2 ₁ / n，a  = 11.7903（5），b  = 12.1279（5），c  = 14.1443（6）Å，β= 99.244（4）°，Z  = 2，R ₁  = 0.0339。化合物1由两种共结晶的Co（II）配合物[Co（AMTTO）₂（CH ₃ CN）₂ ] ²⁺和[Co（AMTTO）₂（H ₂ O）₂ ] ^2+组成。和四个硝酸根抗衡阴离子在两种配合物中，钴（II）离子呈八面体排列。两个S，N二齿AMTTO配体与两个Co（II）离子配位。Co1的配位球由两个乙腈分子完成，这些位置被Co2的水分子占据。

图形摘要

（NO钴（II）化合物的共结晶从Co的反应中分离₃）₂ ⋅6H ₂ O和4-氨基-3-巯基-6-甲基-5-氧代-1,2,4-三嗪在乙腈中作为溶剂。