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The electrochemical reduction mechanism of Fe3O4 in NaCl-CaCl2 melts
International Journal of Chemical Reactor Engineering ( IF 1.6 ) Pub Date : 2020-12-25 , DOI: 10.1515/ijcre-2020-0179 Hui Li 1 , Lei Jia 1 , Weigang Cao 1 , Jinglong Liang 1 , Le Wang 1 , Hongyan Yan 1
International Journal of Chemical Reactor Engineering ( IF 1.6 ) Pub Date : 2020-12-25 , DOI: 10.1515/ijcre-2020-0179 Hui Li 1 , Lei Jia 1 , Weigang Cao 1 , Jinglong Liang 1 , Le Wang 1 , Hongyan Yan 1
Affiliation
In order to study the process of Fe3O4 reduction by melt electro-deoxidation. Electrochemical method was used to analyze the reduction mechanism of Fe3O4 in NaCl-CaCl2 melts. The effects of cell voltage and time on the product were discussed through constant cell voltage electrolysis. The results showed: (1) The reduction of solid Fe3O4 to metallic Fe is a two-step process for obtaining electrons. (2) The transformation process (600 min, 0–1.0 V) of the electrolysis products with the increase of the cell voltage is as follows: Fe3O4 → FeO → FeO + Fe → Fe. (3) The intermediate product Ca2Fe2O5 was formed (2.0 V, 10–300 min), which inhibited the deoxygenation process in the early stage of the reaction. When the electrolysis time exceeds 60 min, the main reaction is the reduction of Ca2Fe2O5 to Fe.
中文翻译:
NaCl-CaCl2熔体中Fe3O4的电化学还原机理
为了研究熔融电脱氧还原Fe 3 O 4的过程。用电化学方法分析了NaCl-CaCl 2熔体中Fe 3 O 4的还原机理。通过恒定的电池电压电解讨论了电池电压和时间对产物的影响。结果表明:(1)固体Fe 3 O 4还原为金属Fe是获得电子的两步过程。(2)随着电解池电压的升高,电解产物的转变过程(600 min,0–1.0 V)如下:Fe 3 O 4 →FeO→FeO + Fe→Fe。(3)中间产物Ca 2Fe 2 O 5的形成(2.0 V,10–300分钟),在反应的早期抑制了脱氧过程。当电解时间超过60分钟时,主要反应是将Ca 2 Fe 2 O 5还原为Fe。
更新日期:2020-12-25
中文翻译:
NaCl-CaCl2熔体中Fe3O4的电化学还原机理
为了研究熔融电脱氧还原Fe 3 O 4的过程。用电化学方法分析了NaCl-CaCl 2熔体中Fe 3 O 4的还原机理。通过恒定的电池电压电解讨论了电池电压和时间对产物的影响。结果表明:(1)固体Fe 3 O 4还原为金属Fe是获得电子的两步过程。(2)随着电解池电压的升高,电解产物的转变过程(600 min,0–1.0 V)如下:Fe 3 O 4 →FeO→FeO + Fe→Fe。(3)中间产物Ca 2Fe 2 O 5的形成(2.0 V,10–300分钟),在反应的早期抑制了脱氧过程。当电解时间超过60分钟时,主要反应是将Ca 2 Fe 2 O 5还原为Fe。