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Sets without k‐term progressions can have many shorter progressions
Random Structures and Algorithms ( IF 1 ) Pub Date : 2020-12-15 , DOI: 10.1002/rsa.20984
Jacob Fox 1 , Cosmin Pohoata 2
Affiliation  

Let fs, k(n) be the maximum possible number of s‐term arithmetic progressions in a set of n integers which contains no k‐term arithmetic progression. For all fixed integers k > s ≥ 3, we prove that fs, k(n) = n2 − o(1), which answers an old question of Erdős. In fact, we prove upper and lower bounds for fs, k(n) which show that its growth is closely related to the bounds in Szemerédi's theorem.

中文翻译:

没有k项级数的集合可以具有许多较短的级数

f s,  kn是一组不包含k项算术级数的n个整数中s项算术级数的最大可能数目。对于所有的固定整数ķ  > 小号 ≥3 ,我们证明了˚F小号,  ķÑ)=  ñ 2 -  Ö(1) ,其答案ERDOS的一个老问题。实际上,我们证明了f s,  kn)的上下界 这表明其增长与Szemerédi定理的界线密切相关。
更新日期:2020-12-15
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