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Tris(pentafluoroethyl)difluorophosphorane: A Versatile Fluoride Acceptor for Transition Metal Chemistry
Chemistry - A European Journal ( IF 4.3 ) Pub Date : 2020-11-26 , DOI: 10.1002/chem.202004885
Steffen A Föhrenbacher 1 , Mirjam J Krahfuss 1 , Ludwig Zapf 1, 2 , Alexandra Friedrich 1, 2 , Nikolai V Ignat'ev 1, 2, 3 , Maik Finze 1, 2 , Udo Radius 1
Affiliation  

Fluoride abstraction from different types of transition metal fluoride complexes [LnMF] (M=Ti, Ni, Cu) by the Lewis acid tris(pentafluoroethyl)difluorophosphorane (C2F5)3PF2 to yield cationic transition metal complexes with the tris(pentafluoroethyl)trifluorophosphate counterion (FAP anion, [(C2F5)3PF3]) is reported. (C2F5)3PF2 reacted with trans‐[Ni(iPr2Im)2(ArF)F] (iPr2Im=1,3‐diisopropylimidazolin‐2‐ylidene; ArF=C6F5, 1 a; 4‐CF3‐C6F4, 1 b; 4‐C6F5‐C6F4, 1 c) through fluoride transfer to form the complex salts trans‐[Ni(iPr2Im)2(solv)(ArF)]FAP (2 ac[solv]; solv=Et2O, CH2Cl2, THF) depending on the reaction medium. In the presence of stronger Lewis bases such as carbenes or PPh3, solvent coordination was suppressed and the complexes trans‐[Ni(iPr2Im)2(PPh3)(C6F5)]FAP (trans‐2 a[PPh3]) and cis‐[Ni(iPr2Im)2(Dipp2Im)(C6F5)]FAP (cis‐2 a[Dipp2Im]) (Dipp2Im=1,3‐bis(2,6‐diisopropylphenyl)imidazolin‐2‐ylidene) were isolated. Fluoride abstraction from [(Dipp2Im)CuF] (3) in CH2Cl2 or 1,2‐difluorobenzene led to the isolation of [{(Dipp2Im)Cu}2]2+2 FAP (4). Subsequent reaction of 4 with PPh3 and different carbenes resulted in the complexes [(Dipp2Im)Cu(LB)]FAP (5 ae, LB=Lewis base). In the presence of C6Me6, fluoride transfer afforded [(Dipp2Im)Cu(C6Me6)]FAP (5 f), which serves as a source of [(Dipp2Im)Cu)]+. Fluoride abstraction of [Cp2TiF2] (7) resulted in the formation of dinuclear [FCp2Ti(μ‐F)TiCp2F]FAP (8) (Cp=η5‐C5H5) with one terminal fluoride ligand at each titanium atom and an additional bridging fluoride ligand.

中文翻译:

三(五氟乙基)二氟正膦:过渡金属化学的多功能氟化物受体

通过路易斯酸三(五氟乙基)二氟正膦(C 2 F 5 ) 3 PF 2从不同类型的过渡金属氟化物络合物[L n MF] (M=Ti, Ni, Cu)中提取氟化物,生成阳离子过渡金属络合物报道了三(五氟乙基)三氟磷酸盐抗衡离子( FAP阴离子,[(C 2 F 5 ) 3 PF 3 ] - )。(C 2 F 5 ) 3 PF 2反式-[Ni( i Pr 2 Im) 2 (Ar F )F] ( i Pr 2 Im=1,3-二异丙基咪唑啉-2-亚基; Ar F =C 6 F 5 , 1 a ; 4-CF 3 ‐C 6 F 4 , 1 b ; 4-C 6 F 5 ‐C 6 F 4 , 1 c ) 通过氟化物转移形成复合盐trans -[Ni( i Pr 2 Im ) 2 (solv)(Ar F )] FAP ( 2 a - c[solv] ; solv=Et 2 O, CH 2 Cl 2 , THF) 取决于反应介质。在较强的路易斯碱(如卡宾或 PPh 3 )存在下,溶剂配位受到抑制,配合物trans ‐[Ni( i Pr 2 Im) 2 (PPh 3 )(C 6 F 5 )] FAP ( trans ‐2 a[ PPh 3 ] ) 和cis ‐[Ni( i Pr 2 Im) 2 (Dipp 2 Im)(C 6 F 5 )] FAP ( cis ‐2 a[Dipp 2 Im] ) (Dipp 2 Im=1,3‐bis分离出(2,6-二异丙基苯基)咪唑啉-2-亚基)。在 CH 2 Cl 2或 1,2-二氟苯中从 [(Dipp 2 Im)CuF] ( 3 ) 中提取氟化物,从而分离出 [{(Dipp 2 Im)Cu} 2] 2+ 2  FAP - ( 4 )。随后4与 PPh 3和不同的卡宾反应生成了配合物 [(Dipp 2 Im)Cu(LB)] FAP ( 5 ae , LB=路易斯碱)。在C 6 Me 6存在下,氟化物转移得到[(Dipp 2 Im)Cu(C 6 Me 6 )] FAP ( 5 f ),其充当[(Dipp 2 Im)Cu)] +的来源。[Cp 2 TiF 2 ] ( 7 )的氟化物提取导致形成具有一个末端氟化物的双核 [FCp 2 Ti(μ‐F)TiCp 2 F] FAP ( 8 ) (Cp=η 5 ‐C 5 H 5 )每个钛原子上有一个配体和一个额外的桥联氟化物配体。
更新日期:2020-11-26
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