Revista Matemática Iberoamericana ( IF 1.2 ) Pub Date : 2019-09-26 , DOI: 10.4171/rmi/1145 David Iglesias 1 , Jesús Yepes Nicolás 1
In this paper we obtain a discrete analog for the sum over finite subsets of the integer lattice $\mathbb Z^n$: under the same assumption as before, for $A,B\subset\mathbb{Z}^n$}, then $\sum_{A+B}h\geq[(\sum_{\mathrm {r}{f}(A)} f)^q+(\sum_B g)^q]^{1/q}$, where $\mathrm{r}_{\!f}(A)$ is obtained by removing points from $A$ in a particular way, and depending on $f$. We also prove that the classical Borell–Brascamp–Lieb inequality for Riemann integrable functions can be obtained as a consequence of this new discrete version.
中文翻译:
关于离散的Borell–Brascamp–Lieb不等式
如果$ f,g,h \冒号\ mathbb {R} ^ n \ longrightarrow \ mathbb {R} _ {\ geq 0} $是非负可测量函数,则$ h(x + y)$大于或等于$ f(x)$和$ g(y)$的$ p $ -sum,其中$ -1 / n \ leq p \ leq \ infty $,$ p \ neq0 $,然后是Borell–Brascamp– Lieb不等式断言,对于$ q = p /(np + 1)$,$ h $的积分不小于$ f $和$ g $的积分的$ q $-和。
在本文中,我们为整数格$ \ mathbb Z ^ n $的有限子集上的总和获得了一个离散模拟,在与以前相同的假设下,对于$ A,B \ subset \ mathbb {Z} ^ n $},然后$ \ sum_ {A + B} h \ geq [(\ sum _ {\ mathrm {r} {f}(A)} f)^ q +(\ sum_B g)^ q] ^ {1 / q} $,其中$ \ mathrm {r} _ {\!f}(A)$是通过以特定方式并根据$ f $从$ A $中删除点而获得的。我们还证明,由于这种新的离散形式,可以得到Riemann可积函数的经典Borell-Brascamp-Lieb不等式。