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Dissecting the $$\Delta I=1/2$$ΔI=1/2 rule at large $$N_c$$Nc
The European Physical Journal C ( IF 4.4 ) Pub Date : 2020-07-18 , DOI: 10.1140/epjc/s10052-020-8192-3
Andrea Donini , Pilar Hernández , Carlos Pena , Fernando Romero-López

We study the scaling of kaon decay amplitudes with the number of colours, \(N_c\), in a theory with four degenerate flavours, \(N_f=4\). In this scenario, two current-current operators, \(Q^\pm \), mediate \(\Delta S=1\) transitions, such as the two isospin amplitudes of non-leptonic kaon decays for \(K\rightarrow (\pi \pi )_{I=0,2}\), \(A_0\) and \(A_2\). In particular, we concentrate on the simpler \(K\rightarrow \pi \) amplitudes, \(A^\pm \), mediated by these two operators. A diagrammatic analysis of the large-\(N_c\) scaling of these observables is presented, which demonstrates the anticorrelation of the leading \({{\mathcal {O}}}(1/N_c)\) and \({{\mathcal {O}}}(N_f/N_c^2)\) corrections in both amplitudes. Using our new \(N_f=4\) and previous quenched data, we confirm this expectation and show that these corrections are naturally large and may be at the origin of the \(\Delta I=1/2\) rule. The evidence for the latter is indirect, based on the matching of the amplitudes to their prediction in Chiral Perturbation Theory, from which the LO low-energy couplings of the chiral weak Hamiltonian, \(g^\pm \), can be determined. A NLO estimate of the \(K \rightarrow (\pi \pi )_{I=0,2}\) isospin amplitudes can then be derived, which is in good agreement with the experimental value.



中文翻译:

在大型$$ N_c $$ Nc处剖析$$ \ Delta I = 1/2 $$ΔI= 1/2规则

我们在具有四种简并味\\(N_f = 4 \)的理论中研究了随着颜色数\(N_c \)缩放的kaon衰减幅度。在这种情况下,两个电流-电流算子\(Q ^ \ pm \)介导\(\ Delta S = 1 \)跃迁,例如\(K \ rightarrow( \ pi \ pi)_ {I = 0,2} \)\(A_0 \)\(A_2 \)。特别地,我们专注于由这两个算子介导的更简单的\(K \ rightarrow \ pi \)振幅\(A ^ \ pm \)。大(\(N_c \))的图解分析提出了这些可观测对象的缩放比例,它证明了前导\({{\ mathcal {O}}}(1 / N_c)\)\({{\ mathcal {O}}}}(N_f / N_c ^ 2 )\)校正两个振幅。使用我们的新\(N_f = 4 \)和先前的淬火数据,我们证实了这一预期,并表明这些校正量自然很大,并且可能是\(\ Delta I = 1/2 \)规则的起源。后者的证据是间接的,基于振幅与手性扰动理论中预测的匹配,由此可以确定手性弱哈密顿量的LO低能耦合\(g ^ \ pm \)\(K \ rightarrow(\ pi \ pi)_ {I = 0,2} \)的NLO估计 然后可以推导出同位旋振幅,这与实验值非常吻合。

更新日期:2020-07-18
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