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Ligand Exchange Reactions of [(tmeda)NiR2] (R = CH2CMe3, CH2SiMe3, CH2CMe2Ph) with N-Heterocyclic Carbenes and Bidentate Phosphines
Organometallics ( IF 2.8 ) Pub Date : 2020-06-26 , DOI: 10.1021/acs.organomet.0c00262
Andreea Enachi 1 , Matthias Freytag 1 , Jan Raeder 1 , Peter G. Jones 1 , Marc D. Walter 1
Affiliation  

Bis(alkyl)nickel(II) complexes [(tmeda)NiR2] (R = CH2SiMe3 (1a), CH2CMe3 (1b), CH2CMe2Ph (1c)) can be prepared from [(tmeda)Ni(acac)2] and MgR2. This approach is equivalent to and, in some cases, even superior to the frequently employed reaction of [(py)4NiR2] with Grignard reagents. With [(tmeda)NiR2] as the starting material, ligand exchange reactions with N-heterocyclic carbenes and bidentate phosphines were explored. The reaction of [(tmeda)NiR2] with IiPr2Me2 (IiPr2Me = 1,3-diisopropyl-4,5-dimethylimidazol-2-ylidene) yields three different classes of products: (a) [cis-(IiPr2Me2)2Ni(CH2SiMe3)2] (2a-cis) derived from NHC by tmeda replacement, (b) [(IiPr2Me2)(κ-C:C-IiPr2MeCH2)Ni(CH2SiMe3)] (3a) as a result of C–H bond activation of one iPr group of the NHC ligand, and (c) [cis-(IiPr2Me2)2Ni(κ-C:C-CH2CMe2C6H4)] (4c-cis), in which an o-C–H bond of the neophyl ligand has been activated. Addition of depe (depe = Et2PCH2CH2PEt2) to 1a,c results in a clean tmeda replacement to give the corresponding complexes [(dppe)NiR2] (R = CH2SiMe3 (5a), CH2CMe2Ph (5c)). All compounds have been fully characterized by various spectroscopic methods and in most cases by single-crystal X-ray diffraction.

中文翻译:

[(tmeda)NiR 2 ](R = CH 2 CMe 3,CH 2 SiMe 3,CH 2 CMe 2 Ph)与N-杂环卡宾和双齿膦的配体交换反应

双(烷基)镍(II)配合物[(tmeda)NiR 2 ](R = CH 2 SiMe 31a),CH 2 CMe 31b),CH 2 CMe 2 Ph(1c))可以由[[ tmeda)Ni(acac)2 ]和MgR 2。该方法等效于并且在某些情况下甚至优于[[py] 4 NiR 2 ]与Grignard试剂的常用反应。以[(tmeda)NiR 2 ]为起始原料,研究了N-杂环卡宾与二齿膦的配体交换反应。[(tmeda)NiR的反应2 ]与I22(I2我= 1,3-二异丙基-4,5-二甲基咪唑烷-2-亚基)产生三种不同类别的产品:(A)[顺式- (I222的Ni(CH 2森达32 ](2A-顺式)通过TMEDA置换,(b)由衍生NHC [(I22)(κ- çç -I2机甲2镍(CH2 SiMe 3)](3a)是NHC配体的一个i Pr基团通过C–H键活化的结果,以及(c)[顺式-(I i Pr 2 Me 22 Ni(κ- CC -CH 2 CMe 2 C 6 H 4)](4c- cis),其中新叶配体的o -C–H键已被激活。将depe(depe = Et 2 PCH 2 CH 2 PEt 2)加到1ac结果得到干净的tmeda替代品,得到相应的络合物[(dppe)NiR 2 ](R = CH 2 SiMe 35a),CH 2 CMe 2 Ph(5c))。所有化合物均已通过各种光谱方法进行了充分表征,并且在大多数情况下已通过单晶X射线衍射进行了表征。
更新日期:2020-07-13
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