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When optimal foragers meet in a game theoretical conflict: A model of kleptoparasitism.
Journal of Theoretical Biology ( IF 2 ) Pub Date : 2020-05-05 , DOI: 10.1016/j.jtbi.2020.110306
József Garay 1 , Ross Cressman 2 , Fei Xu 2 , Mark Broom 3 , Villő Csiszár 4 , Tamás F Móri 5
Affiliation  

Kleptoparasitism can be considered as a game theoretical problem and a foraging tactic at the same time, so the aim of this paper is to combine the basic ideas of two research lines: evolutionary game theory and optimal foraging theory. To unify these theories, firstly, we take into account the fact that kleptoparasitism between foragers has two consequences: the interaction takes time and affects the net energy intake of both contestants. This phenomenon is modeled by a matrix game under time constraints. Secondly, we also give freedom to each forager to avoid interactions, since in optimal foraging theory foragers can ignore each food type (we have two prey types: either a prey item in possession of another predator or a free prey individual is discovered). The main question of the present paper is whether the zero-one rule of optimal foraging theory (always or never select a prey type) is valid or not, in the case where foragers interact with each other?

In our foraging game we consider predators who engage in contests (contestants) and those who never do (avoiders), and in general those who play a mixture of the two strategies. Here the classical zero-one rule does not hold. Firstly, the pure avoider phenotype is never an ESS. Secondly, the pure contestant can be a strict ESS, but we show this is not necessarily so. Thirdly, we give an example when there is mixed ESS.



中文翻译:

当最佳觅食者在游戏中遇到理论冲突时:kleptoparasitism模型。

割肉寄生病可以同时视为博弈论问题和觅食策略,因此,本文的目的是结合进化博弈论和最优觅食论这两个研究方向的基本思想。为了统一这些理论,首先,我们考虑到觅食者之间的贪食性寄生虫有两个后果:相互作用需要时间,并且会影响两个参赛者的净能量摄入。这种现象是在时间约束下通过矩阵博弈建模的。其次,我们还给每个觅食者提供自由,以避免相互作用,因为在最佳觅食理论中,觅食者可以忽略每种食物类型(我们有两种猎物类型:要么发现拥有另一个捕食者的猎物,要么发现一个自由​​捕食者)。

在我们的觅食游戏中,我们考虑参加比赛的掠食者(参赛者)和从未参加比赛的掠食者(避免者),以及通常将两种策略混合使用的捕食者。这里经典的零一规则不成立。首先,纯回避型表型永远不是ESS。其次,纯粹的参赛者可以是严格的ESS,但是我们证明并非一定如此。第三,我们举一个混合ESS的例子。

更新日期:2020-06-27
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