There is considerable genetic gain of tree volume from clonal deployment in Norway spruce (Picea abies(L.) H. Karst) and clonal deployment will have at least 50% more or double genetic gain than the seedling deployment. Genetic parameters and genetic gains for wood quality and growth traits were estimated in six large clonal progeny trials. Develop the optimal clonal deployment strategy of Norway spruce in Sweden. Wood quality and growth traits were measured in all clonal trials and additive and non-additive genetic variances are partitioned. Additive and non-additive genetic variances were equally important for growth traits while non-additive variance was small or not significant for wood quality trait. The genetic gain predicted for clonal deployment was greater than any of the other four deployment strategies. Selecting the top 1% of tested clones (clonal forestry) would have 48.4% and 134.6% more gain than the gain predicted for the seedling deployment of selected full-sib families and half-sib family (family forestry), respectively, at the same selection intensity. This study highlights that testing of 30–40 clones per family would maximize the realized genetic gain for different clonal selection scenarios, either selecting the best ten or 20 clones without any co-ancestry restrictions or selecting the best single clone from each of the best ten or 20 families (e.g., co-ancestry restriction). Clonal mean selection and vegetative deployment are the most effective.

中文翻译：

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挪威云杉（Picea abies (L.) H. Karst）克隆部署的优势

挪威云杉 (Picea abies(L.) H. Karst) 的克隆部署可显着提高树木体积的遗传增益，并且克隆部署将比幼苗部署至少多出 50% 或两倍的遗传增益。在六个大型克隆后代试验中估计了木材质量和生长性状的遗传参数和遗传增益。制定挪威云杉在瑞典的最佳克隆部署策略。在所有克隆试验中都测量了木材质量和生长性状，并划分了加性和非加性遗传变异。加性和非加性遗传变异对生长性状同样重要，而非加性变异对木材品质性状来说很小或不显着。克隆部署预测的遗传增益大于其他四种部署策略中的任何一种。选择前 1% 的测试克隆（克隆林业）将分别比选定的全同胞家族和半同胞家族（家族林业）的幼苗部署预测的收益多 48.4% 和 134.6%。选择强度。这项研究强调，每​​个家庭测试 30-40 个克隆将使不同克隆选择方案的实现遗传增益最大化，要么选择最好的 10 个或 20 个没有任何共同祖先限制的克隆，要么从最好的 10 个克隆中的每一个中选择最好的单个克隆或 20 个家庭（例如，共同祖先限制）。克隆均值选择和营养部署是最有效的。分别以相同的选择强度。这项研究强调，每​​个家庭测试 30-40 个克隆将最大限度地提高不同克隆选择方案的实现遗传增益，要么选择最好的 10 个或 20 个克隆，没有任何共同祖先限制，要么从最好的 10 个克隆中的每一个中选择最好的单个克隆或 20 个家庭（例如，共同祖先限制）。克隆均值选择和营养部署是最有效的。分别以相同的选择强度。这项研究强调，每​​个家庭测试 30-40 个克隆将使不同克隆选择方案的实现遗传增益最大化，要么选择最好的 10 个或 20 个没有任何共同祖先限制的克隆，要么从最好的 10 个克隆中的每一个中选择最好的单个克隆或 20 个家庭（例如，共同祖先限制）。克隆均值选择和营养部署是最有效的。