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Polar Codes with Higher-Order Memory
Problems of Information Transmission ( IF 1.2 ) Pub Date : 2019-01-28 , DOI: 10.1134/s0032946018040014 H. Afşer , H. Deliç
Problems of Information Transmission ( IF 1.2 ) Pub Date : 2019-01-28 , DOI: 10.1134/s0032946018040014 H. Afşer , H. Deliç
We introduce a construction of a set of code sequences {Cn(m) : n ≥ 1, m ≥ 1} with memory order m and code length N(n). {Cn(m)} is a generalization of polar codes presented by Arıkan in [1], where the encoder mapping with length N(n) is obtained recursively from the encoder mappings with lengths N(n − 1) and N(n − m), and {Cn(m)} coincides with the original polar codes when m = 1. We show that {Cn(m)} achieves the symmetric capacity I(W) of an arbitrary binary-input, discrete-output memoryless channel W for any fixed m. We also obtain an upper bound on the probability of block-decoding error Pe of {Cn(m)} and show that \({P_e} = O({2^{ - {N^\beta }}})\) is achievable for β < 1/[1+m(ϕ − 1)], where ϕ ∈ (1, 2] is the largest real root of the polynomial F(m, ρ) = ρm − ρm − 1 − 1. The encoding and decoding complexities of {Cn(m)} decrease with increasing m, which proves the existence of new polar coding schemes that have lower complexity than Arıkan’s construction.
中文翻译:
具有高阶记忆的Polar码
我们引入了组码序列的结构{ Ç Ñ(米):Ñ ≥1,米≥1}与存储器顺序米和码长Ñ(Ñ)。{ C n(m) }是Arıkan在[1]中提出的极性码的一般化,其中从长度为N(n − 1)和N(n的编码器映射中递归获得长度为N(n)的编码器映射。− m)和{ C n(米) }与原来的极性一致的代码时米= 1我们表明,{ Ç Ñ(米) }达到对称容量我( w ^)任意的二进制输入,离散输出无记忆信道的W ^对于任何固定米。我们还获得{ C n(m) }的块解码错误概率P e的上限,并证明\({P_e} = O({2 ^ {-{N ^ \ beta}}})\ )对于β <1 / [1+ m( ϕ − 1)]是可实现的,其中ϕ∈(1,2]是多项式的最大实根˚F(米,ρ)= ρ米- ρ米- 1 - 1编码和解码{的复杂Ç Ñ(米) }减小随米,这证明了存在比Arıkan的结构复杂度更低的新极性编码方案。
更新日期:2019-01-28
中文翻译:
具有高阶记忆的Polar码
我们引入了组码序列的结构{ Ç Ñ(米):Ñ ≥1,米≥1}与存储器顺序米和码长Ñ(Ñ)。{ C n(m) }是Arıkan在[1]中提出的极性码的一般化,其中从长度为N(n − 1)和N(n的编码器映射中递归获得长度为N(n)的编码器映射。− m)和{ C n(米) }与原来的极性一致的代码时米= 1我们表明,{ Ç Ñ(米) }达到对称容量我( w ^)任意的二进制输入,离散输出无记忆信道的W ^对于任何固定米。我们还获得{ C n(m) }的块解码错误概率P e的上限,并证明\({P_e} = O({2 ^ {-{N ^ \ beta}}})\ )对于β <1 / [1+ m( ϕ − 1)]是可实现的,其中ϕ∈(1,2]是多项式的最大实根˚F(米,ρ)= ρ米- ρ米- 1 - 1编码和解码{的复杂Ç Ñ(米) }减小随米,这证明了存在比Arıkan的结构复杂度更低的新极性编码方案。