The reaction of rhodium(I) complexes [Rh(E)(PEt₃)₃] (E = H (2), Si(OEt)₃ (4)) with 1,1-difluoroallene provides the rhodium (III) complexes [Rh(η²-CH₂CCF₂)(η³-CH₂C(E)CF₂)(PEt₃)₂] (E = H (3), Si(OEt)₃ (5)). The conversions involve the coordination of one equivalent of difluoroallene to form a rhodiumcyclopropane and the insertion of a second equivalent into the Rh-E bond. X-ray crystallography as well as DFT calculations support the suggested structures as well as the arrangement of the fluorinated ligands. In contrast, when [Rh{Si(OEt)₃}(PEt₃)₃] (4) reacted with hexafluoropropene, only the coordination of the fluorinated olefin was observed resulting in the formation of [Rh(CF₂CFCF₃){Si(OEt)₃}(PEt₃)₂] (6).

铑（I）配合物[Rh（E）（PEt ₃）₃ ]（E = H（2），Si（OEt）₃（4））与1,1-二氟丙二烯的反应提供了铑（III）配合物[的Rh（η ² -CH ₂ ç CF ₂）（η ³ -CH ₂ C（E）CF ₂）（PET ₃）₂ ]（E = H（3），硅（OET）₃（5））。所述转化涉及一当量的二氟丙二烯的配位以形成铑环丙烷，以及第二当量的二氟环戊烯插入Rh-E键中。X射线晶体学以及DFT计算都支持建议的结构以及氟化配体的排列。相反，当[Rh {Si（OEt）₃ }（PEt ₃）₃ ]（4）与六氟丙烯反应时，仅观察到氟化烯烃的配位，导致形成[Rh（CF ₂ CFCF ₃）{Si （OEt）₃ }（PEt ₃）₂ ]（6）。