Reactions between NH₄F/nHF and gaseous ClF₃ were examined at temperatures of 280–320 K under various n-values (n = 2.2, 2.3, 2.4, 2.7, 2.8, 3.0, 3.1, and 4.0) at which NH₄F/nHF was a molten salt, with three ClF₃ gas flow rates (20, 50 and 100 standard cc min⁻¹). From a direct reaction, NF₂Cl and NFCl₂ gases were obtained as products. With high NF₂Cl and NFCl₂ selectivity for N₂, such as higher than 90% selectivity as the nitrogen containing molecule base at temperatures below 298 K, an n value of around 2.2–2.3 was obtained. The selectivity of NF₂Cl and NFCl₂ decreased to less than 70% at temperatures higher than 318 K because of increased amounts of N₂ by-product. High selectivity of NF₂Cl and NFCl₂ were obtainable with the reaction mechanism in which [NH₃ClF₂]⁺(FH)nF- is formed as an intermediate.

NH之间的反应₄ F / Ñ HF和气态的ClF ₃在各种在280-320的K的温度下进行了检查ñ -值（Ñ 在该NH = 2.2，2.3，2.4，2.7，2.8，3.0，3.1和4.0）₄ F / n HF是一种熔融盐，具有三种ClF ₃气体流速（20、50和100标准cc min ^-1）。通过直接反应，获得了作为产物的NF ₂ Cl和NFCl ₂气体。NF ₂ Cl和NFCl ₂对N _2的选择性高例如，在低于298 K的温度下，作为含氮分子碱的选择性高于90％时，n值约为2.2–2.3。在高于318 K的温度下，由于N ₂副产物的量增加，NF ₂ Cl和NFCl ₂的选择性降至70％以下。通过以[NH ₃ ClF ₂ ] ⁺（FH）n F-作为中间体形成的反应机理，可以得到高选择性的NF ₂ Cl和NFCl ₂。