Styrenes serve as unique aryl or arylcarboxymethylene source towards aryl isocyanides in the presence of Cu(II)/TBHP, and yield N‐arylbenzamides or benzoyloxyacetanilides respectively. The chemoselectivity of the reaction is controlled by the nature of the substituents present on styrene ring. Whereas styrenes substituted with electron‐releasing alkyl and alkoxy groups yield N‐arylbenzamides, unsubstituted styrene and those with electron‐withdrawing substituents furnish benzoyloxyacetanilides as the major product. With benzylamines as the substrate, N‐arylbenzamides are formed exclusively as they act only as an aryl donor. TBHP serves as a promoter and oxygen source. Both the pathways are believed to proceed through an initial oxidative C−C bond cleavage of styrene.

中文翻译：

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从芳基异氰化物：苯乙烯作为芳基和芳基羧亚甲基的化学选择合成N-芳基苯甲酰胺和苯甲氧基乙氧基苯胺

在存在Cu（II）/ TBHP的情况下，苯乙烯可作为朝着芳基异氰酸酯的唯一芳基或芳基羧亚甲基来源，分别产生N-芳基苯甲酰胺或苯甲酰氧基乙酰苯胺。反应的化学选择性由苯乙烯环上存在的取代基的性质控制。用释放电子的烷基和烷氧基取代的苯乙烯会生成N-芳基苯甲酰胺，而未取代的苯乙烯和具有吸电子取代基的苯乙烯会提供苯甲酰氧基乙酰苯胺作为主要产物。以苄胺为底物，N‐芳基苯甲酰胺仅由于它们仅用作芳基供体而形成。TBHP用作促进剂和氧气源。据信这两种途径都是通过苯乙烯的初始氧化C-C键裂解来进行的。